Free Math Worksheets

- Which number in the matching multiplication fact belongs in each blank? - You can use a related division fact to find a missing factor. - Say the known factor’s products in order until you reach the given product.

1. Since \(6 \times 7 = 42\), the missing factor in part a is \(6\). 2. Since \(9 \times 8 = 72\), the missing factor in part b is \(8\). 3. Compute \(4 \times 6 = 24\), so the missing product in part c is \(24\). 4. Since \(9 \times 3 = 27\), the missing factor in part d is \(9\).

a) \(6\) b) \(8\) c) \(24\) d) \(9\)

- Think of the total as equal groups of \(\$4\). - Use a multiplication fact with an unknown factor. - Check that the contributions add to \(\$24\).

1. Let \(n\) be the number of sponsors. The equal contributions give \(4 \times n = 24\). 2. Since \(4 \times 6 = 24\), \(n = 6\).

\(6\) sponsors are needed.

- Find Ben's number first. - Use division to undo multiplication by \(3\). - Then add \(4\).

1. Find Ben's number using the inverse operation: \(30 \div 3 = 10\). 2. Mia's number is \(10 + 4 = 14\).

Mia is thinking of \(14\).

- Use division to find an unknown factor. - Write \(8 \times \square = 320\). - Check with multiplication.

1. Divide the product by the known factor: \(320 \div 8 = 40\). 2. Check: \(8 \times 40 = 320\).

The other factor is \(40\).

- Translate “four times” into multiplication. - Translate “difference” into subtraction. - Evaluate the side without the unknown first, then use the inverse operation.

1. “Four times an unknown number” is \(4 \times \Box\), and “the difference between \(50\) and \(10\)” is \(50 - 10\). 2. The equation is \(4 \times \Box = 50 - 10\). 3. Evaluate the right side: \(50 - 10 = 40\). 4. Solve \(4 \times \Box = 40\): \(40 \div 4 = 10\), so \(\Box = 10\).

1. \(4 \times \Box = 50 - 10\) 2. \(\Box = 10\)

- Think about reversing the repeated subtraction. - In part a), find four groups of \(150\). - In part b), find the unknown factor in \(7 \times \square = 630\). - Decide whether multiplication or division is the most direct operation in each part.

1. a) Four equal groups of \(150\) make the starting number: \(4 \times 150 = 600\). 2. b) The number subtracted each time is an unknown factor in \(7 \times x = 630\). Divide: \(630 \div 7 = 90\).

a) \(600\) b) \(90\)

- Use division to find a missing factor when the product and the other factor are known. - Check by multiplying from the bottom upward.

1. For the bottom-left value, solve \(x \times 2 = 8\): \(x = 8 \div 2 = 4\). 2. For the right value in the second row, solve \(8 \times y = 48\): \(y = 48 \div 8 = 6\). 3. For the bottom-right value, solve \(2 \times z = 6\): \(z = 6 \div 2 = 3\).

Bottom row: \(4\), \(2\), \(3\) Second row: \(8\), \(6\) Top: \(48\)

- Use division to find a missing factor when the product is known. - Start with a small triangle in which two of the three values are known. - Check that every multiplication from bottom to top is correct.

1. For the left brick in the second row, solve \(x \times 10 = 80\), so \(x = 8\). 2. For the middle bottom value, solve \(4 \times y = 8\), so \(y = 2\). 3. For the right bottom value, solve \(2 \times z = 10\), so \(z = 5\).

Bottom row: \(4\), \(2\), \(5\) Second row: \(8\), \(10\) Top: \(80\)