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Build your own math worksheets from 21,000 problems for grades 3 to 12, from fractions to calculus. Every problem includes step-by-step solutions.

Compare decimals

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5158334
Order the prices from least to greatest: \(\$1.49\), \(\$1.94\), \(\$1.44\), \(\$1.99\)

Hints

- Compare the whole-dollar amounts first. - If those are equal, compare the tenths digits. - If the tenths digits are also equal, compare the hundredths digits.

Solution

1. All four prices have \(1\) in the ones place. 2. Compare the tenths digits. Prices with \(4\) tenths are less than prices with \(9\) tenths. 3. Within each pair, compare the hundredths digits. 4. The order is \(\$1.44 < \$1.49 < \$1.94 < \$1.99\).

Answer

\(\$1.44 < \$1.49 < \$1.94 < \$1.99\)
5158364
Write \(<\), \(>\), or \(=\) in each circle. a) \(\$14.80 \bigcirc \$18.40\) b) \(\$6.07 \bigcirc \$6.70\) c) \(\$22.55 \bigcirc \$22.55\)

Hints

- Compare the whole-dollar amounts first. - If the dollars are equal, compare the cents. - Pay attention to place value.

Solution

1. For a), compare the whole-dollar amounts. Since \(14 < 18\), \(\$14.80 < \$18.40\). 2. For b), the whole-dollar amounts are equal. Compare the cents: \(7 < 70\), so \(\$6.07 < \$6.70\). 3. For c), the amounts are identical, so they are equal.

Answer

a) \(<\) b) \(<\) c) \(=\)
5197644
Write \(<\), \(>\), or \(=\) to compare each pair of money amounts. a) \(400\,\text{cents} \;\dots\; \$4\) b) \(\$6 \;\dots\; 60\,\text{cents}\) c) \(250\,\text{cents} \;\dots\; \$2\)

Hints

- Convert both amounts to the same unit. - One dollar equals \(100\) cents. - Check carefully whether each amount is written in dollars or cents.

Solution

1. Convert each dollar amount to cents. 2. \(\$4 = 400\) cents, so the amounts are equal. 3. \(\$6 = 600\) cents, and \(600 > 60\). 4. \(\$2 = 200\) cents, and \(250 > 200\).

Answer

a) \(=\) b) \(>\) c) \(>\)
5119284
Insert \(<\), \(>\), or \(=\). First rewrite the decimals as fractions with denominator \(100\). a) \(0.3 \;\square\; 0.03\) b) \(0.05 \;\square\; \frac{5}{100}\) c) \(1.2 \;\square\; \frac{120}{100}\) d) \(0.08 \;\square\; 0.01\)

Hints

- Rewrite each decimal in hundredths. - Once the denominators match, compare the numerators. - Pay close attention to place value and zeros.

Solution

1. For a), \(0.3 = \frac{30}{100}\) and \(0.03 = \frac{3}{100}\). Since \(30 > 3\), \(0.3 > 0.03\). 2. For b), \(0.05 = \frac{5}{100}\), so the values are equal. 3. For c), \(1.2 = \frac{12}{10} = \frac{120}{100}\), so the values are equal. 4. For d), \(0.08 = \frac{8}{100}\) and \(0.01 = \frac{1}{100}\). Since \(8 > 1\), \(0.08 > 0.01\).

Answer

a) \(0.3 > 0.03\) b) \(0.05 = \frac{5}{100}\) c) \(1.2 = \frac{120}{100}\) d) \(0.08 > 0.01\)
5158344
Order these prices from greatest to least. Pay attention to dollars and cents: \(30\) cents, \(\$0.03\), \(\$3.03\), \(\$3.30\), \(33\) cents

Hints

- Convert all amounts to the same unit. - One dollar equals \(100\) cents. - Compare the resulting whole numbers.

Solution

1. Express every amount in cents: \(30\), \(3\), \(303\), \(330\), and \(33\) cents. 2. Order the values: \(330 > 303 > 33 > 30 > 3\). 3. Match them to the original forms.

Answer

\(\$3.30 > \$3.03 > 33\,\text{cents} > 30\,\text{cents} > \$0.03\)
5158354
Order the prices from least to greatest: \(\$5.50\), \(500\) cents, \(\$0.55\), \(\$5.05\), \(5\) cents

Hints

- Convert every amount to cents. - Pay attention to the zero in the tenths place of \(\$5.05\). - Compare the cent values as whole numbers.

Solution

1. Express each amount in cents: \(550\), \(500\), \(55\), \(505\), and \(5\) cents. 2. Order the values: \(5 < 55 < 500 < 505 < 550\). 3. Match the ordered values to the original forms.

Answer

\(5\,\text{cents} < \$0.55 < 500\,\text{cents} < \$5.05 < \$5.50\)
5158374
Write \(<\), \(>\), or \(=\) to compare each pair. a) \(\$1.05 \bigcirc 105\,\text{cents}\) b) \(\$3.80 \bigcirc 38\,\text{cents}\) c) \(\$0.09 \bigcirc 90\,\text{cents}\)

Hints

- Convert both amounts in each pair to cents. - One dollar equals \(100\) cents. - Watch the zero placeholders in decimal notation.

Solution

1. \(\$1.05 = 105\) cents, so the amounts are equal. 2. \(\$3.80 = 380\) cents, and \(380 > 38\). 3. \(\$0.09 = 9\) cents, and \(9 < 90\).

Answer

a) \(=\) b) \(>\) c) \(<\)
5103184
Find a fraction with denominator \(10\) that is greater than \(\frac{1}{4}\) and less than \(\frac{2}{5}\). Explain why there is exactly one solution.

Hints

- Convert the two boundary fractions to decimals. - List the tenths near those decimals. - Remember that the fraction must be strictly greater than one boundary and strictly less than the other.

Solution

1. Write the boundary fractions as decimals: \(\frac{1}{4}=0.25\) and \(\frac{2}{5}=0.4\). 2. Fractions with denominator \(10\) represent tenths. The tenths near this interval are \(\frac{2}{10}=0.2\), \(\frac{3}{10}=0.3\), and \(\frac{4}{10}=0.4\). 3. Only \(0.3\) is strictly between \(0.25\) and \(0.4\). Therefore, the only solution is \(\frac{3}{10}\).

Answer

\(\frac{3}{10}\). It is the only tenth strictly between \(0.25\) and \(0.4\).

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