- Picture consecutive integers on a number line. - The previous integer is one unit to the left. - Complete one row at a time from the value already shown.

1. In Row 1, the integer immediately before \(-45\) is \(-46\), and the integer immediately after it is \(-44\). 2. In Row 2, the integer after \(-101\) is \(-100\), and the next integer is \(-99\). 3. In Row 3, the integer before \(1\) is \(0\), and the integer before \(0\) is \(-1\).

Row 1: \(-46,-45,-44\) Row 2: \(-101,-100,-99\) Row 3: \(-1,0,1\)

- List the integers to the right of \(-6\) and to the left of \(3\). - Include zero when it lies in the interval. - Do not include the endpoints.

1. The integers greater than \(-6\) and less than \(3\) are \(-5,-4,-3,-2,-1,0,1,2\). 2. There are \(8\) integers in the list.

There are \(8\) integers: \(-5,-4,-3,-2,-1,0,1,2\).

- Look for integers to the right of \(-103\) and to the left of \(-97\). - Do not include the endpoints. - As negative integers increase, their absolute values decrease.

1. The integers must be greater than \(-103\) and less than \(-97\). 2. Listing the consecutive integers gives \(-102,-101,-100,-99,-98\).

\(-102,-101,-100,-99,-98\)

- Picture the integers on a number line. - Which integer is one unit to the left? - Which integer is one unit to the right? - Subtract or add \(1\) as appropriate.

1. The integer immediately before \(x\) is \(x-1\), and the integer immediately after \(x\) is \(x+1\). 2. For \(-15\), the integers are \(-16\) and \(-14\). 3. For \(-1\), the integers are \(-2\) and \(0\). 4. For \(0\), the integers are \(-1\) and \(1\).

For \(-15\): before \(-16\), after \(-14\) For \(-1\): before \(-2\), after \(0\) For \(0\): before \(-1\), after \(1\)

- Use the sign to decide which side of zero the point belongs on. - Determine how much distance one tick interval represents. - Count equal intervals from zero until the total distance is \(1.75\).

1. Negative numbers lie to the left of \(0\), so move left. 2. Each tick interval represents \(0.25\). Seven intervals represent \(7\times0.25=1.75\). 3. Move \(7\) tick intervals left from \(0\) to reach \(-1.75\).

Move left \(7\) tick intervals; the point is at \(-1.75\).

- Count intervals, not just the printed labels. - Use the two known coordinates to find the value of one interval. - Move from zero to P.

1. From \(-2\) to \(0\) there are two equal intervals, so each interval represents \(1\). 2. Point P is one interval to the right of zero. 3. P represents \(1\).

\(1\)

- Identify two labeled coordinates on each line. - Count the equal spaces between the labeled values. - Compare the changes represented by one space on each line.

1. In a), neighboring ticks differ by \(2\). 2. In b), neighboring ticks differ by \(5\). 3. A single tick interval represents a larger change on line b).

Line a): \(2\) units per tick. Line b): \(5\) units per tick. Line b) has the larger interval.

- Decide whether each pair lies on the same side of zero or on opposite sides. - Use distances from zero to determine each separation. - Compare the four distances.

1. In a), the points are on opposite sides of zero, so the distance is \(12+1=13\). 2. In b), both points are negative. Their distances from zero are \(13\) and \(1\), so the distance between them is \(13-1=12\). 3. In c), the points are on opposite sides of zero, so the distance is \(10+2=12\). 4. In d), the points are on opposite sides of zero, so the distance is \(5+7=12\). 5. The greatest distance is \(13\).

a) \(-12\) and \(1\)

- Locate each number between two consecutive integers. - Convert a fraction to a decimal when useful. - Compare the distances to the two neighboring integers.

1. For a), \(12\frac{4}{9}\) lies between \(12\) and \(13\). Since \(\frac{4}{9}<\frac{1}{2}\), it is closer to \(12\). 2. For b), \(-8.7\) is \(0.3\) from \(-9\) and \(0.7\) from \(-8\), so the nearest integer is \(-9\). 3. For c), \(-\frac{21}{5}=-4.2\), which is \(0.2\) from \(-4\), so the nearest integer is \(-4\). 4. For d), \(-\frac{15}{4}=-3.75\), which is \(0.25\) from \(-4\), so the nearest integer is \(-4\).

a) \(12\) b) \(-9\) c) \(-4\) d) \(-4\)

- A midpoint is the same distance from both endpoints. - Find the distance from \(-5\) to each number in a pair. - Which pair gives equal distances?

1. For Pair A, the distance from \(-5\) to \(-12\) is \(7\), while the distance from \(-5\) to \(0\) is \(5\). The distances are not equal. 2. For Pair B, the distance from \(-5\) to \(-9\) is \(4\), and the distance from \(-5\) to \(-1\) is also \(4\). The distances are equal. 3. For Pair C, the distance from \(-5\) to \(-7\) is \(2\), while the distance from \(-5\) to \(-1\) is \(4\). The distances are not equal.

Pair B: \(-9\) and \(-1\)

- Use zero as an intermediate point to count the full distance. - The physical scale is \(1\,\text{cm}\) per unit interval. - The midpoint is half the total number of intervals from either endpoint.

1. From \(-14\) to \(0\) is \(14\) intervals, and from \(0\) to \(6\) is \(6\) more, for \(20\) intervals total. The segment is \(20\,\text{cm}\) long. 2. Half of \(20\) intervals is \(10\). Counting \(10\) intervals right from \(-14\) lands at \(-4\).

a) \(20\,\text{cm}\) b) \(-4\)

- Picture the temperatures on a vertical number line. - Use zero to split the total rise into two easy parts. - The halfway temperature is the midpoint of the two positions.

1. From \(-9\) to \(0\) is a rise of \(9\) degrees, and from \(0\) to \(3\) is \(3\) more, so the total rise is \(12\,\text{°F}\). 2. Half of \(12\) degrees is \(6\) degrees. Starting at \(-9\) and moving halfway toward \(3\) lands at \(-3\,\text{°F}\).

a) \(12\,\text{°F}\) b) \(-3\,\text{°F}\)

- For part a), find the total distance and move halfway from one endpoint. - What does it mean for two integers to be consecutive?

1. The distance from \(-5\) to \(1\) is \(6\) units. Half of \(6\) is \(3\), and \(-5+3=-2\). 2. The integers \(-40\) and \(-39\) are consecutive, so no integer lies strictly between them.

a) \(-2\) b) No. The numbers \(-40\) and \(-39\) are consecutive integers.

- List the integers between the endpoints of each pair. - Do not include the endpoints themselves. - Compare the two counts.

1. Between \(-10\) and \(-7\) are \(-9\) and \(-8\), so Pair A has \(2\) integers between its endpoints. 2. Between \(-2\) and \(2\) are \(-1,0,1\), so Pair B has \(3\) integers between its endpoints. 3. Since \(3>2\), Pair B has more integers between its endpoints.

Pair B has more integers between its endpoints. Pair A has \(2\), and Pair B has \(3\).

- Decide whether each pair lies on the same side of zero or on opposite sides. - Across zero, add the two distances to zero. - On the same side, compare the magnitudes.

1. In a), both points are negative. Their distances from zero are \(7\) and \(22\), so the separation is \(22-7=15\). 2. In b), the segment crosses zero, so the distance is \(18+12=30\). 3. In c), the points are opposites, each \(55\) units from zero, so the distance is \(55+55=110\). 4. In d), both points are negative. Their magnitudes differ by \(140-95=45\), so the distance is \(45\).

a) \(15\) b) \(30\) c) \(110\) d) \(45\)

- Find the distance represented by the first \(4\) equal intervals. - Moving right means the coordinate increases. - For part b, compare the remaining distance to zero with the size of one interval.

1. Moving right on a number line moves toward greater numbers. 2. Four intervals of \(15\) units cover \(4\times15=60\) units. 3. Starting at \(-90\) and moving \(60\) units right reaches \(-30\). 4. From \(-30\) to \(0\) is \(30\) units, which is \(2\) more intervals of \(15\) units.

a) \(-30\) b) \(2\) intervals

- Determine the value of one small interval first. - Values to the left of \(0\) are negative, and values to the right are positive. - Count from the nearest labeled tick.

1. From \(0\) to \(1\), there are \(10\) equal intervals, so each small interval represents \(1\div10=0.1\). 2. Point \(A\) is two intervals left of \(-1\), so \(A=-1-2\times0.1=-1.2\). 3. Point \(B\) is four intervals left of \(0\), so \(B=-0.4\). 4. Point \(C\) is three intervals right of \(0\), so \(C=0.3\). 5. Point \(D\) is one interval right of \(1\), so \(D=1.1\).

\(A=-1.2\), \(B=-0.4\), \(C=0.3\), \(D=1.1\)

- Use the labeled ticks to determine the value of one small interval. - A point left of zero represents a negative number, and a point right of zero represents a positive number. - Count from a nearby labeled value to each point.

1. There are \(5\) equal intervals from \(0\) to \(5\), so each tick interval represents \(1\). 2. Point \(A\) is \(7\) units left of \(0\), so \(A=-7\). 3. Point \(B\) is \(3\) units right of \(0\), so \(B=3\).

Point \(A\) represents \(-7\), and point \(B\) represents \(3\).

- Count the intervals between two consecutive integers. - Points left of \(0\) have negative values. - Count small intervals from the nearest labeled integer.

1. Each interval between consecutive integers is divided into \(10\) equal parts, so each small interval represents \(0.1\). 2. Point \(P\) is seven intervals left of \(-1\), so \(P=-1.7\). 3. Point \(Q\) is eight intervals left of \(0\), so \(Q=-0.8\). 4. Point \(R\) is three intervals left of \(0\), so \(R=-0.3\). 5. Point \(S\) is four intervals right of \(0\), so \(S=0.4\).

\(P=-1.7\), \(Q=-0.8\), \(R=-0.3\), \(S=0.4\)

- Determine the value of one small interval. - Values left of \(0\) are negative. - Count from the nearest labeled integer.

1. From \(0\) to \(1\), there are \(10\) equal intervals, so each small interval represents \(0.1\). 2. Point \(P\) is two intervals right of \(-2\), so \(P=-1.8\). 3. Point \(Q\) is three intervals right of \(-1\), so \(Q=-0.7\). 4. Point \(R\) is one interval left of \(0\), so \(R=-0.1\). 5. Point \(S\) is six intervals right of \(0\), so \(S=0.6\). 6. Point \(T\) is three intervals right of \(1\), so \(T=1.3\).

\(P=-1.8\), \(Q=-0.7\), \(R=-0.1\), \(S=0.6\), \(T=1.3\)

- Count the equal intervals from \(0\) to \(1\). - Determine the value of one small interval. - Use the point’s direction from \(0\) to determine its sign.

1. There are \(5\) equal intervals from \(0\) to \(1\), so each small interval represents \(\frac{1}{5}=0.2\). 2. Point \(A\) is two intervals left of \(-1\), so \(A=-1-2\times0.2=-1.4\). 3. Point \(B\) is three intervals left of \(0\), so \(B=-3\times0.2=-0.6\). 4. Point \(C\) is four intervals right of \(0\), so \(C=4\times0.2=0.8\).

\(A=-1.4\), \(B=-0.6\), \(C=0.8\)

- Determine the value of one small tick interval. - Points left of zero are negative. - Count from zero or from the nearest labeled tick. - Values decrease as you move left.

1. There are \(10\) equal intervals from \(0\) to \(10\), so each small interval represents \(1\). 2. Counting from nearby labeled ticks gives \(A=-14\), \(B=-2\), \(C=8\), and \(D=17\).

\(A=-14\), \(B=-2\), \(C=8\), and \(D=17\)

- Count the equal intervals between consecutive integers. - Values left of \(0\) are negative. - Count from the nearest labeled integer.

1. There are \(10\) equal intervals between consecutive integers, so each small interval represents \(0.1\). 2. Point \(A\) is six intervals left of \(-1\), so \(A=-1.6\). 3. Point \(B\) is three intervals left of \(0\), so \(B=-0.3\). 4. Point \(C\) is five intervals right of \(0\), so \(C=0.5\). 5. Point \(D\) is two intervals right of \(1\), so \(D=1.2\). 6. Point \(E\) is nine intervals right of \(1\), so \(E=1.9\).

\(A=-1.6\), \(B=-0.3\), \(C=0.5\), \(D=1.2\), \(E=1.9\)

- Determine the fraction represented by one interval. - Values left of \(0\) are negative. - Simplify each fraction.

1. The interval from \(0\) to \(1\) is divided into \(4\) equal parts, so each interval represents \(\frac{1}{4}\). 2. Point \(X\) is three intervals left of \(0\), so \(X=-\frac{3}{4}\). 3. Point \(Y\) is one interval left of \(0\), so \(Y=-\frac{1}{4}\). 4. Point \(Z\) is two intervals right of \(0\), so \(Z=\frac{2}{4}=\frac{1}{2}\).

\(X=-\frac{3}{4}\), \(Y=-\frac{1}{4}\), \(Z=\frac{1}{2}\)

- Count the equal intervals between the labeled whole numbers. - Count from \(0\) to each marker. - Use a negative sign for points to the left of \(0\), then simplify.

1. In a), the interval from \(0\) to \(1\) is divided into tenths. Thus, \(A=\frac{3}{10}\), \(B=\frac{5}{10}=\frac{1}{2}\), and \(C=\frac{8}{10}=\frac{4}{5}\). 2. In b), the interval from \(-1\) to \(0\) is divided into fourths. Thus, \(D=-\frac{3}{4}\), \(E=-\frac{2}{4}=-\frac{1}{2}\), and \(F=-\frac{1}{4}\).

a) \(A=\frac{3}{10}\), \(B=\frac{1}{2}\), \(C=\frac{4}{5}\) b) \(D=-\frac{3}{4}\), \(E=-\frac{1}{2}\), \(F=-\frac{1}{4}\)

- Use two labeled ticks to determine the value of one interval. - Values decrease as you move left on the number line. - Count the intervals from a labeled value to \(P\).

1. The labeled values \(-4\) and \(0\) are two tick intervals apart, so each interval represents \(2\,\text{°C}\). 2. Point \(P\) is three intervals to the left of \(-4\). Counting left by twos gives \(-6,-8,-10\). 3. Therefore, \(P\) marks \(-10\,\text{°C}\).

\(-10\,\text{°C}\)

- Decide whether the move crosses zero. - Use part of the distance to reach zero first. - Place the remaining distance on the correct side of zero.

1. From \(0.4\), move \(0.4\) unit left to reach \(0\). 2. Of the \(1.2\)-unit move, \(0.8\) unit remains. 3. Move \(0.8\) unit farther left from \(0\). The coordinate is \(-0.8\).

Move \(0.4\) unit left to \(0\), then \(0.8\) unit farther left. The point is at \(-0.8\).

- Use the labeled numbers to work out the scale. - Does one tick space always represent one unit? - Compare the Mary's claimed value with the value at B.

1. The labeled numbers show that each tick space represents \(2\) units. 2. B is two tick spaces to the left of zero, so its coordinate is \(-4\). 3. Mary counted the spaces correctly but treated each space as one unit. The claim is incorrect.

No. B is two tick spaces left of zero, but each space represents \(2\) units, so B is at \(-4\), not \(-2\).

- Read the coordinates at both ends of the band. - Split the distance at zero. - Add the two parts; distance cannot be negative.

1. The colored interval begins at \(-2\) and ends at \(3\). 2. There are \(2\) units from \(-2\) to zero and \(3\) units from zero to \(3\). 3. Its length is \(2+3=5\) units.

\(5\) units: \(2\) to the left of zero and \(3\) to the right.

- Find the point halfway between \(-2\) and \(-3\). - Use that midpoint to sort the candidates by which endpoint is nearer. - Describe each selected fraction's distance from both neighboring integers.

1. The point halfway between \(-2\) and \(-3\) is \(-2.5\). Numbers to the right of \(-2.5\) are closer to \(-2\), and numbers to the left are closer to \(-3\). 2. Convert or estimate the fractions: \(-\frac{11}{4}=-2.75\), \(-\frac{7}{3}=-2\frac{1}{3}\), \(-\frac{13}{5}=-2.6\), and \(-\frac{9}{4}=-2.25\). 3. The values to the right of \(-2.5\) are \(-\frac{7}{3}\) and \(-\frac{9}{4}\). 4. The number \(-\frac{7}{3}\) is \(\frac{1}{3}\) unit from \(-2\) and \(\frac{2}{3}\) unit from \(-3\). The number \(-\frac{9}{4}\) is \(\frac{1}{4}\) unit from \(-2\) and \(\frac{3}{4}\) unit from \(-3\). Each is therefore closer to \(-2\).

\(-\frac{7}{3}\) and \(-\frac{9}{4}\)

- Locate each number between its two neighboring integers. - Decide which neighboring integer is closer. - Express the gap as a nonnegative distance.

1. For a), \(3.8\) is between \(3\) and \(4\) and is \(0.2\) unit from \(4\), so the distance is \(0.2\). 2. For b), \(-1\frac{1}{4}=-1.25\). It is one quarter unit from \(-1\), so the distance is \(0.25\). 3. For c), \(-\frac{22}{7}=-3\frac{1}{7}\). It is \(\frac{1}{7}\) unit to the left of \(-3\), so the distance is \(\frac{1}{7}\). 4. For d), \(0.45\) is closer to \(0\) than to \(1\), and its distance from \(0\) is \(0.45\).

a) \(0.2\) b) \(0.25\) c) \(\frac{1}{7}\) d) \(0.45\)

- Think of distance as the length of the interval between each number and \(1\). - If an interval crosses zero, split the distance at zero. - Compare the two nonnegative distances in each part.

1. For a), \(\frac{3}{7}\) is \(\frac{4}{7}\approx0.571\) unit from \(1\), while \(1.6\) is \(0.6\) unit from \(1\). Since \(\frac{4}{7}<0.6\), \(\frac{3}{7}\) is closer. 2. For b), the distance from \(-\frac{1}{4}\) to \(0\) is \(\frac{1}{4}\), and from \(0\) to \(1\) is \(1\), for a total of \(1\frac{1}{4}\) units. The distance from \(2.1\) to \(1\) is \(1.1\) units. 3. Since \(1.1<1.25\), \(2.1\) is closer to \(1\).

a) \(\frac{3}{7}\) b) \(2.1\)

- Convert the percent and fraction to forms that make their positions near \(-2\) easy to see. - Describe how far each point lies to the left or right of \(-2\). - The smallest distance identifies the closest number.

1. Write the values in useful forms: \(A=-2\frac{1}{3}\) and \(D=-1.75\). 2. Point \(A\) is \(\frac{1}{3}\approx0.333\) unit from \(-2\). Point \(B\) is \(0.35\) unit from \(-2\). Point \(C\) is \(0.2\) unit from \(-2\). Point \(D\) is \(0.25\) unit from \(-2\). 3. The smallest distance is \(0.2\), so \(C=-2.2\) is closest to \(-2\).

\(C=-2.2\)

- Write every value as a decimal so their positions are easy to compare. - Picture each value near \(-2\) on a number line. - Compare the lengths of the small intervals from each value to \(-2\).

1. Write each value as a decimal: \(A=-2.25\), \(B=-1.8\), \(C=-2.1\), \(D=-2.2\), and \(E=-1.95\). 2. Their distances from \(-2\) are \(0.25\), \(0.2\), \(0.1\), \(0.2\), and \(0.05\), respectively, as seen from their positions around \(-2\) on a number line. 3. The smallest distance is \(0.05\), so \(E=-1.95\) is closest to \(-2\).

The number \(E=-1.95\) is closest to \(-2\).

- First find how many integer intervals lie between the two values. - Use zero as an intermediate point when the values have different signs. - Each number-line interval represents \(2\,\text{cm}\).

1. In a), the segment crosses zero. There are \(5\) unit intervals from \(-5\) to \(0\) and \(8\) from \(0\) to \(8\), for \(13\) intervals total. The physical length is \(13\times2\,\text{cm}=26\,\text{cm}\). 2. In b), both points are left of zero. Their magnitudes differ by \(12-3=9\), so they are \(9\) unit intervals apart. The physical length is \(9\times2\,\text{cm}=18\,\text{cm}\).

a) \(26\,\text{cm}\) b) \(18\,\text{cm}\)

- A fixed distance can extend in either direction from a point. - Use zero as a reference when a move crosses from negative to positive. - Moving left from a negative number increases its distance from zero.

1. Moving \(25\) units to the right from \(-14\), it takes \(14\) units to reach \(0\) and \(11\) more units to reach \(11\). 2. Moving \(25\) units to the left makes the distance from zero \(14+25=39\), so the coordinate is \(-39\).

The two possible coordinates are \(11\) and \(-39\).

- Decide whether each segment crosses zero. - Across zero, combine the two distances to zero. - On the same side of zero, compare the two magnitudes.

1. From \(R=-18\) to \(S=4\), the segment crosses zero, so the distance is \(18+4=22\) units. 2. From \(S=4\) to \(T=22\), both points are on the positive side, so the distance is \(22-4=18\) units. 3. Since \(22>18\), point \(R\) is farther from \(S\). 4. From \(R=-18\) to \(T=22\), the segment crosses zero, so the distance is \(18+22=40\) units.

a) Point \(R\) is farther from \(S\): \(22\) units compared with \(18\) units. b) \(40\) units

- Picture each pair on a number line. - Find the total number of unit intervals between the endpoints. - The midpoint is half that many intervals from either endpoint.

1. In a), the endpoints are \(12\) unit intervals apart. Half is \(6\) intervals, and counting six intervals right from \(-14\) lands at \(-8\). 2. In b), the distance is \(3+9=12\) units across zero. Half is \(6\) units, and the halfway point is \(3\). 3. In c), the endpoints are opposites, so their midpoint is \(0\). 4. In d), the distance is \(10+20=30\) units across zero. Half is \(15\) units, placing the midpoint at \(5\).

a) \(-8\) b) \(3\) c) \(0\) d) \(5\)

- If \(M\) is the midpoint, the distances \(AM\) and \(MB\) are equal. - Use zero to find the distance from \(A\) to \(M\). - Continue the same distance and direction from \(M\).

1. From \(-6\) to \(0\) is \(6\) units, and from \(0\) to \(2\) is \(2\) more, so \(A\) and \(M\) are \(8\) units apart. 2. Because \(M\) is the midpoint, \(B\) must be \(8\) units on the other side of \(M\). 3. Counting \(8\) units right from \(2\) gives \(10\).

Point \(B\) is at \(10\).

- Convert the physical length to number-line units first. - Each endpoint is the same distance from the midpoint. - Count the same number of units left and right from \(-5\).

1. A \(6\,\text{cm}\) segment represents \(6\times2=12\) number-line units. 2. Each endpoint is half of \(12\), or \(6\) units, from the midpoint. 3. Counting \(6\) units left from \(-5\) gives \(-11\). Counting \(6\) units right from \(-5\) gives \(1\).

The endpoints are \(-11\) and \(1\).

- First list all integers between the two endpoints. - An even integer is divisible by \(2\). - Check each integer in your list.

1. The integers strictly between \(-45\) and \(-39\) are \(-44,-43,-42,-41,-40\). 2. The even integers in this list are \(-44,-42,-40\).

\(-44,-42,-40\)

- Use zero as an intermediate point for distances between opposite signs. - Absolute value gives a number's distance from zero. - Compare the three absolute values in part c).

1. The points \(-32\) and \(12\) lie on opposite sides of zero, so their distance is \(32+12=44\). 2. The points \(12\) and \(-58\) lie on opposite sides of zero, so their distance is \(12+58=70\). 3. The distances from zero are \(|a|=32\), \(|b|=12\), and \(|c|=58\). Since \(58\) is greatest, \(c\) is farthest from zero.

a) \(44\) b) \(70\) c) \(c=-58\), because \(|-58|=58\) is the greatest absolute value.

- Split the distance at \(0\) to find how far apart the endpoints are. - Move half of that distance from one endpoint to find the midpoint. - When counting integers between the endpoints, do not include the endpoints.

1. From \(-8\) to \(0\) is \(8\) units, and from \(0\) to \(4\) is \(4\) units, so the endpoints are \(12\) units apart. 2. Half of \(12\) is \(6\). Moving \(6\) units right from \(-8\) reaches \(-2\), so \(-2\) is the midpoint. 3. The integers strictly between the endpoints are \(-7,-6,-5,-4,-3,-2,-1,0,1,2,3\), for a total of \(11\).

The midpoint is \(-2\), and \(11\) integers lie strictly between the endpoints.

- Determine the value of one tick interval. - Points to the left of zero are negative, and points to the right are positive. - Start at a nearby labeled tick and count intervals to each marker.

1. There are \(5\) equal intervals from \(0\) to \(5\), so each tick interval represents \(1\). 2. Point \(P\) is \(2\) units left of \(-10\), so \(P=-12\). 3. Point \(Q\) is \(1\) unit right of \(-5\), so \(Q=-4\). 4. Point \(R\) is \(3\) units right of \(0\), so \(R=3\). 5. Point \(S\) is \(1\) unit right of \(10\), so \(S=11\).

\(P=-12\) \(Q=-4\) \(R=3\) \(S=11\)

- Find the distance between the two labeled values. - Count the equal intervals between them to determine the scale. - Count right or left from a labeled point.

1. From \(-0.8\) to \(-0.2\) there are \(6\) equal intervals, and the values increase by \(0.6\) altogether, so each interval represents \(0.1\). 2. Starting at \(-0.2\), count seven intervals to the right: \(-0.1, 0, 0.1, 0.2, 0.3, 0.4, 0.5\). Thus, \(A=0.5\). 3. Starting at \(-0.8\), count five intervals to the left: \(-0.9,-1.0,-1.1,-1.2,-1.3\). Thus, \(B=-1.3\).

\(A=0.5\) and \(B=-1.3\)

- Use the labeled major ticks to find the difference between them. - Count the equal small intervals between two labeled ticks. - Divide the major-tick difference by the number of intervals. - Count left for lesser values and right for greater values.

1. On number line a), consecutive labeled values differ by \(10\), with \(5\) equal intervals between them. Each small interval represents \(10\div5=2\). 2. Reading the markers gives \(A=-46\), \(B=-18\), \(C=4\), and \(D=32\). 3. On number line b), consecutive labeled values differ by \(50\), with \(5\) equal intervals between them. Each small interval represents \(50\div5=10\). 4. Reading the markers gives \(E=-730\), \(F=-610\), \(G=-550\), and \(H=-480\).

a) \(A=-46\), \(B=-18\), \(C=4\), \(D=32\) b) \(E=-730\), \(F=-610\), \(G=-550\), \(H=-480\)

- Determine the value of one small interval. - Use the labeled tenths to count by hundredths. - Points left of \(0\) are negative.

1. The interval from \(0\) to \(0.1\) is divided into \(5\) equal parts, so each small interval represents \(0.02\). 2. Point \(P\) is three intervals to the right of \(-0.5\): \(-0.48,-0.46,-0.44\). Thus, \(P=-0.44\). 3. Point \(Q\) is one interval to the right of \(-0.2\), so \(Q=-0.18\). 4. Point \(R\) is three intervals to the right of \(0\), so \(R=0.06\). 5. Point \(S\) is one interval to the right of \(0.3\), so \(S=0.32\).

\(P=-0.44\), \(Q=-0.18\), \(R=0.06\), \(S=0.32\)

- Read the coordinate of each marked point. - For points on the same side of zero, compare their distances from zero. - For a segment that crosses zero, split its length at zero. - Compare the two segment lengths after finding them.

1. Read the coordinates: \(P=-12\), \(Q=-4\), and \(R=9\). 2. Points \(P\) and \(Q\) are on the same side of zero. Their distances from zero are \(12\) and \(4\), so \(PQ\) is \(12-4=8\,\text{cm}\). 3. Segment \(QR\) crosses zero. It is \(4\,\text{cm}\) from \(Q\) to zero and \(9\,\text{cm}\) from zero to \(R\), so \(QR\) is \(4+9=13\,\text{cm}\). 4. Since \(13-8=5\), segment \(QR\) is \(5\,\text{cm}\) longer.

Segment \(QR\) is \(5\,\text{cm}\) longer than segment \(PQ\).

- The number of equal parts from \(0\) to \(1\) gives the denominator. - Values left of \(0\) are negative. - Simplify fractions when possible.

1. The interval from \(0\) to \(1\) is divided into \(4\) equal parts, so each small interval represents \(\frac{1}{4}\). 2. Point \(P\) is at \(-1\frac{3}{4}\). 3. Point \(Q\) is at \(-\frac{2}{4}=-\frac{1}{2}\). 4. Point \(R\) is at \(\frac{3}{4}\). 5. Point \(S\) is at \(1\frac{1}{4}\).

\(P=-1\frac{3}{4}\), \(Q=-\frac{1}{2}\), \(R=\frac{3}{4}\), \(S=1\frac{1}{4}\)

- Compare the values at A and the labeled tick. - How can equal tick spaces help you work out the value of one space? - Check that your proposed zero fits both known values.

1. There are \(8\) tick spaces from A to the tick labeled \(2\). 2. Their values differ by \(2-0.4=1.6\), so each space represents \(1.6\div8=0.2\). 3. Moving left by \(0.4\) takes \(0.4\div0.2=2\) spaces. Therefore, zero is two tick spaces left of A.

Zero is two tick spaces left of A. Each space represents \(0.2\), since the difference between A and \(2\) is \(1.6\) across \(8\) spaces.

- Find the difference in magnitude between the two labeled values. - Divide that change by the number of intervals between them. - Decide whether \(0\) lies to the left or right of the negative values.

1. From \(C=-0.12\) to \(D=-0.04\), the values increase by \(0.08\) across \(8\) equal intervals. 2. Therefore, each interval represents \(0.01\). 3. Starting from \(D=-0.04\), four intervals to the right give \(-0.03,-0.02,-0.01,0\). Thus, \(0\) is four intervals to the right of \(D\).

a) \(0.01\) b) \(0\) is \(4\) intervals to the right of \(D\).

- Determine the value of one small interval on each number line separately. - Count from a nearby labeled value. - Values to the left of \(0\) are negative.

1. On number line a), consecutive labeled thousands are divided into \(4\) equal intervals, so each small interval represents \(1000\div4=250\). 2. Therefore, \(A=-2250\), \(B=-750\), \(C=500\), and \(D=1750\). 3. On number line b), consecutive labeled tenths are divided into \(2\) equal intervals, so each small interval represents \(0.1\div2=0.05\). 4. Therefore, \(E=-0.35\), \(F=-0.15\), \(G=0.1\), and \(H=0.45\).

a) \(A=-2250\), \(B=-750\), \(C=500\), \(D=1750\) b) \(E=-0.35\), \(F=-0.15\), \(G=0.1\), \(H=0.45\)

- Find the value represented by one minor tick mark. - Read each marker carefully, including its sign. - Write each decimal as a fraction with denominator \(10\). - Simplify each fraction.

1. The minor tick marks are spaced by \(0.1\). Reading the marked locations gives \(P = -1.2\), \(Q = -0.4\), and \(R = 0.8\). 2. Convert \(P\): \(-1.2 = -\frac{12}{10} = -\frac{6}{5}\). 3. Convert \(Q\): \(-0.4 = -\frac{4}{10} = -\frac{2}{5}\). 4. Convert \(R\): \(0.8 = \frac{8}{10} = \frac{4}{5}\).

\(P = -1.2 = -\frac{6}{5}\) \(Q = -0.4 = -\frac{2}{5}\) \(R = 0.8 = \frac{4}{5}\)

- Count the equal intervals between the labeled values on each line. - Determine each line's tick value separately; the scales are different. - Compare the eight numerical coordinates, not how far left the markers appear on different drawings.

1. On number line a), there are \(3\) intervals from \(0\) to \(3\), so each interval represents \(1\). Therefore, \(A=-7\), \(B=-2\), \(C=5\), and \(D=9\). 2. On number line b), there are \(2\) intervals from \(0\) to \(20\), so each interval represents \(10\). Therefore, \(E=-50\), \(F=-30\), \(G=10\), and \(H=40\). 3. Comparing the actual coordinates, \(-50\) is the least, so point \(E\) has the least coordinate.

a) \(A=-7\), \(B=-2\), \(C=5\), \(D=9\) b) \(E=-50\), \(F=-30\), \(G=10\), \(H=40\) c) Point \(E\), with coordinate \(-50\)

- Determine the value of one small interval on each number line. - Values to the left of \(0\) are negative. - Opposite numbers have equal distance from \(0\) on different sides.

1. On number line a), each small interval represents \(0.2\). Therefore, \(P=-1.2\), \(Q=-0.6\), and \(R=0.8\). 2. On number line b), each small interval represents \(0.25=\frac{1}{4}\). Therefore, \(S=-1.75=-1\frac{3}{4}\), \(T=-0.5=-\frac{1}{2}\), and \(U=0.5=\frac{1}{2}\). 3. The opposite of \(0.5\) is \(-0.5\), which is point \(T\).

a) \(P=-1.2\), \(Q=-0.6\), \(R=0.8\) b) \(S=-1.75=-1\frac{3}{4}\), \(T=-0.5=-\frac{1}{2}\), \(U=0.5=\frac{1}{2}\) c) Point \(T\)

- Read the coordinates of \(A\) and \(M\) from the number line. - A midpoint is the same distance from both endpoints. - Count the same number of tick intervals from \(M\) in the direction away from \(A\).

1. On the number line, there are six equal tick intervals from \(A=-2.4\) to \(M=-0.6\). 2. Because \(M\) is the midpoint, point \(B\) must be six equal tick intervals to the right of \(M\). 3. Counting six intervals right from \(-0.6\) gives \(-0.3,0,0.3,0.6,0.9,1.2\). Therefore, \(B=1.2\).

\(B=1.2\)

- Read the coordinates of \(A\) and \(C\) from the number line. - Convert \(0.75\) unit into a number of tick intervals. - Find \(B\) before ordering all three points.

1. Point \(A\) is at \(-0.5\), and each tick interval represents \(0.25\) unit. 2. A move of \(0.75\) unit is three tick intervals. Counting three intervals right from \(A\) gives \(-0.25,0,0.25\), so \(B=0.25\). 3. Point \(C\) is at \(-1.25\). Reading the number line from left to right gives \(C,A,B\).

a) \(B=0.25\) b) \(C, A, B\)

- Use the labeled ticks to determine the value of one interval. - Count how many intervals separate \(A\) and \(P\). - Convert the final decimal to a fraction using place value, then simplify.

1. The labeled values show that each tick interval represents \(0.25=\frac{1}{4}\) unit. 2. Point \(P\) is six intervals to the right of \(A=-2.25\). Counting by fourths gives \(-2,-1.75,-1.5,-1.25,-1,-0.75\). 3. Therefore, \(P=-0.75=-\frac{3}{4}\).

\(-0.75=-\frac{3}{4}\)

- Use the number line to identify the direction of the movement. - Rewrite \(\frac{4}{5}\) in tenths to match the tick spacing. - Count the required number of intervals from \(R\), then simplify the final coordinate as a fraction.

1. Rewrite \(\frac{4}{5}\) as \(\frac{8}{10}\). On the displayed number line, that is eight tick intervals. 2. Point \(R\) is at \(0.3\). Counting eight intervals left gives \(0.2,0.1,0,-0.1,-0.2,-0.3,-0.4,-0.5\). 3. Thus, \(S=-0.5=-\frac{1}{2}\).

\(-\frac{1}{2}\)

- Count the equal tick intervals between the endpoints. - A midpoint splits that count into two equal parts. - Count half the intervals from the left endpoint.

1. The tick spacing is \(\frac{1}{6}\) unit. From \(A=-\frac{5}{6}\) to \(B=\frac{1}{6}\) there are six equal intervals. 2. Halfway is three intervals from either endpoint. 3. Counting three intervals right from \(-\frac{5}{6}\) gives \(-\frac{4}{6},-\frac{3}{6},-\frac{2}{6}\). Therefore, the midpoint is \(-\frac{2}{6}=-\frac{1}{3}\).

\(-\frac{1}{3}\)

- Use the two labeled values to find the total distance. - Count the equal intervals between those labels. - Count from a labeled value to \(K\) in the correct direction.

1. From \(-2.7\) to \(0.9\), the number line spans \(3.6\) units across nine equal tick intervals. 2. One interval therefore represents \(3.6\div9=0.4\) unit. 3. Point \(K\) is four intervals to the left of \(0.9\). Counting left by \(0.4\) gives \(0.5,0.1,-0.3,-0.7\). 4. Therefore, \(K=-0.7\).

a) \(0.4\) b) \(-0.7\)