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Grade 7 math worksheets

Build your own math worksheets from 35,000+ problems for grades 3 to 12, from fractions to AP Calculus. Every problem comes with step-by-step solutions.

Add and subtract rational numbers

Learning goals

  • Adds signed rational numbers.
  • Subtracts signed rational numbers.
  • Uses number-line distances or number properties to explain a sum or difference.
  • Checks results using inverse operations, estimation, or structure.

Click problems to add them to your worksheet.

Add and subtract rational numbers 1
Evaluate. a) \(-14-19\) b) \(22-(-11)\) c) \(-35-(-15)\) d) \(8-23\)

Hints

- Rewrite subtraction as adding the opposite. - Decide the sign before calculating. - Picture the movement on a number line.

Solution

1. \(-14-19=-33\). 2. Subtracting a negative is adding its opposite: \(22-(-11)=22+11=33\). 3. \(-35-(-15)=-35+15=-20\). 4. \(8-23=-15\).

Answer

a) \(-33\) b) \(33\) c) \(-20\) d) \(-15\)
Add and subtract rational numbers 2
A submarine is at \(-150\,\text{m}\) relative to sea level and then descends another \(75\,\text{m}\). Write an integer addition equation and find its new position.

Hints

- Positions below sea level are negative. - Descending makes the position more negative. - Represent the change as a signed number.

Solution

1. The starting position is \(-150\,\text{m}\). 2. Descending \(75\,\text{m}\) is represented by adding \(-75\). 3. \(-150+(-75)=-225\), so the new position is \(-225\,\text{m}\).

Answer

\(-150+(-75)=-225\). The submarine is at \(-225\,\text{m}\).
Add and subtract rational numbers 3
Evaluate each expression and simplify the result. a) \(45-72\) b) \(-18+(-12)\) c) \(\frac{5}{6}-\frac{1}{6}\) d) \(-\frac{3}{8}-\frac{1}{8}\)

Hints

- Determine the sign before calculating. - When adding two negative numbers, add their absolute values and keep the negative sign. - With like denominators, combine the numerators. - Simplify fraction results.

Solution

1. For a), \(45-72=-27\). 2. For b), \(-18+(-12)=-30\). 3. For c), \(\frac{5}{6}-\frac{1}{6}=\frac{4}{6}=\frac{2}{3}\). 4. For d), \(-\frac{3}{8}-\frac{1}{8}=-\frac{4}{8}=-\frac{1}{2}\).

Answer

a) \(-27\) b) \(-30\) c) \(\frac{2}{3}\) d) \(-\frac{1}{2}\)
Add and subtract rational numbers 4
A weather station records a temperature of \(-9\,^\circ\text{F}\) one winter morning. During the morning, the temperature rises by \(14\,^\circ\text{F}\). What temperature does the station now show?

Hints

- Picture a thermometer as a vertical number line. - Which direction represents an increase in temperature? - First determine how far it is from \(-9\) to \(0\).

Solution

1. Represent the increase by adding a positive number: \(-9+14\). 2. Calculate: \(-9+14=5\), so the temperature is \(5\,^\circ\text{F}\).

Answer

The station now shows \(5\,^\circ\text{F}\).
Add and subtract rational numbers 5
Mr. Weber's checking account has a balance of \(-\$180\). He deposits \(\$250\) in cash. What is the new account balance?

Hints

- A negative account balance represents money owed to the bank. - What happens to the amount owed when money is deposited? - Will the account still have a negative balance after the deposit?

Solution

1. Add the deposit to the current balance: \(-180+250\). 2. Calculate: \(-180+250=70\).

Answer

The new account balance is \(\$70\).
Add and subtract rational numbers 6
A type of plastic loses its flexibility and becomes brittle at \(-35\,^\circ\text{C}\). A new material mixture raises this threshold by \(12\) degrees. At what temperature does the new plastic become brittle?

Hints

- Picture the temperatures on a thermometer or number line. - Does raising a temperature threshold make the value greater or less? - Which direction do you move on the number line when a temperature increases?

Solution

1. The original threshold is \(-35\,^\circ\text{C}\). 2. Raising the threshold by \(12\) degrees means adding \(12\): \(-35+12=-23\).

Answer

The new plastic becomes brittle at \(-23\,^\circ\text{C}\).
Add and subtract rational numbers 7
A hiker begins a climb in a valley where the temperature is \(4\,^\circ\text{F}\). By the time the hiker reaches a mountain shelter, the temperature has dropped a total of \(15\) degrees. What is the temperature at the shelter?

Hints

- Decide whether the final temperature should be positive or negative. - You are subtracting a number greater than the starting value. - A thermometer sketch can help you cross zero.

Solution

1. A drop of \(15\) degrees means subtracting \(15\) from the initial temperature. 2. Calculate: \(4-15=-11\), so the temperature is \(-11\,^\circ\text{F}\).

Answer

The temperature at the shelter is \(-11\,^\circ\text{F}\).
Add and subtract rational numbers 8
What number is \(58\) greater than \(-33\)? Write and evaluate an equation.

Hints

- Increasing a number means moving right on a number line. - Translate “greater than” into addition. - Check whether the result should be positive or negative.

Solution

1. “\(58\) greater than” means add \(58\) to \(-33\). 2. \(-33+58=25\).

Answer

\(-33+58=25\)
Add and subtract rational numbers 9
Point \(A\) is your starting position. Move \(\frac{1}{2}\) unit right. What fraction do you land on? Write an addition equation.
Figure for problem 559513

Hints

- Find \(A\) by counting the equal tick marks from zero. - How many quarter-unit steps make one half? - Check where the move ends relative to zero.

Solution

1. Point \(A\) is one quarter to the left of zero, so \(A=-\frac{1}{4}\). 2. Moving right half a unit means adding \(\frac{1}{2}\). 3. \(-\frac{1}{4}+\frac{1}{2}=-\frac{1}{4}+\frac{2}{4}=\frac{1}{4}\).

Answer

\(-\frac{1}{4}+\frac{1}{2}=\frac{1}{4}\)
Add and subtract rational numbers 10
Find \(\frac{3}{8}+\left(-\frac{5}{8}\right)\). Is the result positive or negative?

Hints

- Adding a negative means the total decreases. - Compare the sizes of the positive and negative parts. - Keep the sign when simplifying the fraction.

Solution

1. The parts have the same denominator: \(\frac{3}{8}-\frac{5}{8}=\frac{-2}{8}\). 2. Simplify: \(-\frac{1}{4}\). The result is negative because the negative part has greater magnitude.

Answer

\(-\frac{1}{4}\); negative
Add and subtract rational numbers 11
Calculate \(-\frac{1}{2}-\left(-\frac{1}{4}\right)\). Explain whether the result is to the left or right of \(-\frac{1}{2}\) on a number line.

Hints

- How does subtracting a negative change the direction of movement? - Write both fractional parts in fourths. - A move right does not always end at a positive number.

Solution

1. Subtracting \(-\frac{1}{4}\) means adding \(\frac{1}{4}\). 2. \(-\frac{1}{2}+\frac{1}{4}=-\frac{2}{4}+\frac{1}{4}=-\frac{1}{4}\). 3. Adding a positive amount moves right, so the result is to the right of \(-\frac{1}{2}\).

Answer

\(-\frac{1}{4}\), to the right of \(-\frac{1}{2}\)
Add and subtract rational numbers 12
a) Read the coordinates of \(A\) and \(B\). b) Write their sum. Explain your answer using the number line.
Figure for problem 559516

Hints

- Use the spacing between the labeled values and the smaller ticks. - Compare the two positions relative to zero. - Think about what happens when a number and its opposite are added.

Solution

1. The points are \(A=-\frac{3}{4}\) and \(B=\frac{3}{4}\). 2. Their sum is \(-\frac{3}{4}+\frac{3}{4}=0\), since equal distances on opposite sides of zero cancel.

Answer

a) \(A=-\frac{3}{4}\), \(B=\frac{3}{4}\) b) \(-\frac{3}{4}+\frac{3}{4}=0\); they are opposites.
Add and subtract rational numbers 13
Complete the equation: \(-\frac{2}{5}+\square=0\).

Hints

- What number would cancel the negative fraction? - Think of moving back to zero from a negative position. - Check by adding your value to the given fraction.

Solution

1. A number and its opposite add to zero. 2. The opposite of \(-\frac{2}{5}\) is \(\frac{2}{5}\).

Answer

\(\frac{2}{5}\)
Add and subtract rational numbers 14
Which expression is another way to write \(-\frac{4}{9}-\left(-\frac{1}{9}\right)\)? a) \(-\frac{4}{9}+\left(-\frac{1}{9}\right)\) b) \(-\frac{4}{9}+\frac{1}{9}\) c) \(\frac{4}{9}-\frac{1}{9}\) Explain why your chosen expression has the same value.

Hints

- Change only the operation involving the second number. - Does the first fraction change when you rewrite the subtraction? - Check whether the proposed expression gives the same result.

Solution

1. Subtracting a negative number means adding its positive opposite. 2. Keep the first number negative and change \(-(-\frac{1}{9})\) to \(+\frac{1}{9}\).

Answer

b) \(-\frac{4}{9}+\frac{1}{9}\); subtracting a negative becomes adding its opposite.
Add and subtract rational numbers 15
At dawn, an outdoor thermometer reads \(-\frac{1}{4}\,^{\circ}\text{C}\). The temperature drops by \(\frac{1}{2}\,^{\circ}\text{C}\). What is the new temperature? Write the calculation.

Hints

- What operation represents a drop in temperature? - Keep the sign of the starting temperature. - Write both fractions in the same-sized parts.

Solution

1. A temperature drop is subtraction: \(-\frac{1}{4}-\frac{1}{2}\). 2. Convert to fourths: \(-\frac{1}{4}-\frac{2}{4}=-\frac{3}{4}\,^{\circ}\text{C}\).

Answer

\(-\frac{1}{4}-\frac{1}{2}=-\frac{3}{4}\,^{\circ}\text{C}\)
Add and subtract rational numbers 16
Calculate \(-\frac{2}{7}+\left(-\frac{3}{7}\right)\). Explain why the answer is not positive.

Hints

- Imagine both terms as movements on a number line. - What do their directions tell you about the final position? - Keep the denominator when adding seventh parts.

Solution

1. Both terms are negative, so their sum is negative. 2. Add the magnitudes: \(\frac{2}{7}+\frac{3}{7}=\frac{5}{7}\). 3. Hence the result is \(-\frac{5}{7}\).

Answer

\(-\frac{5}{7}\); adding two negative values moves farther below zero.
Add and subtract rational numbers 17
Evaluate the expression. Show the value of the quantity in parentheses before finding the final value. \(7 \frac{5}{12} - \left(3 \frac{5}{6} + 2 \frac{1}{2}\right)\)

Hints

- Evaluate the grouped expression before doing the outside subtraction. - Use a common denominator when adding the fractional parts. - Keep the exact fractional value of the grouped expression for the final subtraction.

Solution

1. Evaluate the parentheses: \(3\frac{5}{6}+2\frac{1}{2}=3\frac{5}{6}+2\frac{3}{6}=6\frac{1}{3}\). 2. Rewrite \(6\frac{1}{3}=6\frac{4}{12}\). 3. Subtract: \(7\frac{5}{12}-6\frac{4}{12}=1\frac{1}{12}\).

Answer

Quantity in parentheses: \(6\frac{1}{3}\) Final value: \(1\frac{1}{12}\)
Add and subtract rational numbers 18
Which number is exactly halfway between \(-2.4\) and \(3.6\)? a) \(0.6\) b) \(0.8\) c) \(1.0\) d) \(1.2\)

Hints

- The midpoint is the average of the two endpoints. - Add the two values first. - Divide the sum by \(2\).

Solution

1. Find the midpoint by adding the two numbers and dividing by \(2\): \(\frac{-2.4+3.6}{2}\). 2. The sum is \(-2.4+3.6=1.2\). 3. Divide by \(2\): \(1.2\div2=0.6\).

Answer

a) \(0.6\)
Add and subtract rational numbers 19
Calculate the value of the expression and write the result in simplest form: \(\frac{5}{12} - \left(\frac{1}{4} + \frac{1}{3}\right)\)

Hints

- Which part of the expression should you evaluate first? - How can you rewrite fractions with different denominators so they have a common denominator? - Check whether the final fraction can be simplified.

Solution

1. Evaluate the parentheses first: \(\frac{1}{4} + \frac{1}{3} = \frac{3}{12} + \frac{4}{12} = \frac{7}{12}\). 2. Subtract: \(\frac{5}{12} - \frac{7}{12} = -\frac{2}{12}\). 3. Simplify: \(-\frac{2}{12} = -\frac{1}{6}\).

Answer

\(-\frac{1}{6}\)
Add and subtract rational numbers 20
Calculate: \(\left(\frac{3}{8} - \frac{5}{6}\right) + \frac{11}{12}\)

Hints

- First rewrite the fractions inside the parentheses with a common denominator. - What sign should the result have when the larger fraction is subtracted from the smaller fraction? - How do you add a negative fraction and a positive fraction?

Solution

1. Evaluate the parentheses using a common denominator of \(24\): \(\frac{3}{8} - \frac{5}{6} = \frac{9}{24} - \frac{20}{24} = -\frac{11}{24}\). 2. Rewrite \(\frac{11}{12}\) as \(\frac{22}{24}\). 3. Add: \(-\frac{11}{24} + \frac{22}{24} = \frac{11}{24}\).

Answer

\(\frac{11}{24}\)
Add and subtract rational numbers 21
Calculate each expression. Write each answer as a fraction in simplest form or as a mixed number. a) \(3 \frac{5}{12}+1 \frac{1}{4}\) b) \(6 \frac{2}{5}-4 \frac{7}{10}\) c) \(2 \frac{3}{4}+0.125\)

Hints

- Rewrite fractional parts with common denominators before adding or subtracting. - For the decimal, consider an equivalent fraction. - If the fractional part of a mixed number is too small to subtract, regroup one whole.

Solution

1. For a), rewrite \(1 \frac{1}{4}\) as \(1 \frac{3}{12}\). Then \(3 \frac{5}{12}+1 \frac{3}{12}=4 \frac{8}{12}=4 \frac{2}{3}\). 2. For b), rewrite \(6 \frac{2}{5}\) as \(6 \frac{4}{10}\). Regroup one whole: \(6 \frac{4}{10}=5 \frac{14}{10}\). Then \(5 \frac{14}{10}-4 \frac{7}{10}=1 \frac{7}{10}\). 3. For c), rewrite \(0.125\) as \(\frac{1}{8}\) and \(2 \frac{3}{4}\) as \(2 \frac{6}{8}\). Then \(2 \frac{6}{8}+\frac{1}{8}=2 \frac{7}{8}\).

Answer

a) \(4 \frac{2}{3}\) b) \(1 \frac{7}{10}\) c) \(2 \frac{7}{8}\)
Add and subtract rational numbers 22
Calculate each expression. Write each answer as a mixed number in simplest form. a) \(3 \frac{2}{5}+4 \frac{5}{6}\) b) \(8 \frac{1}{4}-5 \frac{5}{8}\) c) \(10-\left(2 \frac{1}{3}+4 \frac{3}{5}\right)\)

Hints

- Rewrite fractions with unlike denominators using a common denominator. - In a mixed-number subtraction, you may need to regroup one whole. - Evaluate expressions inside parentheses before the rest of the calculation. - A whole number can be rewritten as a fraction or mixed number when that makes the subtraction easier.

Solution

1. For a), use denominator \(30\): \(3 \frac{12}{30}+4 \frac{25}{30}=7 \frac{37}{30}=8 \frac{7}{30}\). 2. For b), rewrite \(8 \frac{1}{4}\) as \(8 \frac{2}{8}\), then regroup: \(7 \frac{10}{8}-5 \frac{5}{8}=2 \frac{5}{8}\). 3. For c), evaluate the parentheses: \(2 \frac{1}{3}+4 \frac{3}{5}=2 \frac{5}{15}+4 \frac{9}{15}=6 \frac{14}{15}\). Then \(10-6 \frac{14}{15}=3 \frac{1}{15}\).

Answer

a) \(8 \frac{7}{30}\) b) \(2 \frac{5}{8}\) c) \(3 \frac{1}{15}\)
Add and subtract rational numbers 23
Rearrange and group the terms to make the calculation efficient. Write the equivalent regrouped expression you use, then evaluate it. \(5\frac{3}{8} + 4\frac{2}{5} - 2\frac{3}{8} + 1\frac{3}{5}\)

Hints

- Keep each sign attached to its term when changing the order. - Look for terms whose fractional parts combine without introducing a new denominator. - Your response should show the regrouping, not only the final number.

Solution

1. Rewrite subtraction as addition of the opposite and regroup: \(\left(5\frac{3}{8}-2\frac{3}{8}\right)+\left(4\frac{2}{5}+1\frac{3}{5}\right)\). 2. The groups are \(3\) and \(6\). 3. Therefore, the value is \(9\).

Answer

One efficient regrouping is \(\left(5\frac{3}{8}-2\frac{3}{8}\right)+\left(4\frac{2}{5}+1\frac{3}{5}\right)\), which equals \(9\).
Add and subtract rational numbers 24
For each expression, rewrite any fraction as a terminating decimal before evaluating. If an expression has no fraction, state that no conversion is needed. a) \(0.25 + \frac{1}{2}\) b) \(0.4 - \frac{3}{5}\) c) \(0.75 - 1\) d) \(1.1 + \frac{9}{10}\)

Hints

- Write each fraction with a denominator of \(10\) or \(100\) when possible. - Keep the converted decimal visible in your response before evaluating. - Check the sign of each result against the relative sizes of the terms.

Solution

1. a) \(\frac{1}{2}=0.5\), so \(0.25+0.5=0.75\). 2. b) \(\frac{3}{5}=0.6\), so \(0.4-0.6=-0.2\). 3. c) No conversion is needed: \(0.75-1=-0.25\). 4. d) \(\frac{9}{10}=0.9\), so \(1.1+0.9=2\).

Answer

a) \(\frac{1}{2}=0.5\); result \(0.75\) b) \(\frac{3}{5}=0.6\); result \(-0.2\) c) No fraction is present, so no conversion is needed; result \(-0.25\) d) \(\frac{9}{10}=0.9\); result \(2\)
Add and subtract rational numbers 25
Evaluate \(\frac{5}{6} + 0.4 + \frac{1}{6} + 1.1\). Decide whether to convert every value to fractions or decimals, or to combine compatible terms separately. Briefly justify your choice.

Hints

- Compare the work created by converting the sixths to decimals with the work created by keeping them as fractions. - Look for terms that can combine exactly without introducing a new representation. - Your justification should refer to the actual numbers in this expression.

Solution

1. Converting the sixths to decimals would create repeating decimals, so keep them as fractions. 2. Group the fractions: \(\frac{5}{6} + \frac{1}{6} = 1\). 3. Group the decimals: \(0.4 + 1.1 = 1.5\). 4. Add the partial sums: \(1 + 1.5 = 2.5\).

Answer

One particularly efficient choice is to combine the fractions and decimals separately. Converting the sixths to decimals would introduce repeating decimals, while \(\frac{5}{6}+\frac{1}{6}=1\) exactly and \(0.4+1.1=1.5\), so the value is \(2.5\). Another exact strategy is acceptable if it is shown correctly and the efficiency justification refers to the actual conversions and arithmetic required.
Add and subtract rational numbers 26
Evaluate the expression by converting the fractions to terminating decimals and then showing one regrouping that creates convenient decimal pairs. \(\frac{2}{5} + 1.35 - \frac{3}{4} + 0.1\)

Hints

- Convert each fraction exactly before doing the addition or subtraction. - Keep each sign attached to its term when regrouping. - Show the regrouped decimal expression in your answer.

Solution

1. Convert: \(\frac{2}{5}=0.4\) and \(\frac{3}{4}=0.75\). 2. Regroup: \((0.4+0.1)+(1.35-0.75)\). 3. Evaluate: \(0.5+0.6=1.1\).

Answer

\(\frac{2}{5}=0.4\), \(\frac{3}{4}=0.75\), and \((0.4+0.1)+(1.35-0.75)=1.1\).
Add and subtract rational numbers 27
Evaluate the expression by switching strategically between fractions and decimals. \(4.5 - \left(1.25 + \frac{1}{3}\right) + \frac{1}{12}\)

Hints

- Distribute the subtraction sign before regrouping. - Combine the decimal terms separately from the fractional terms. - Convert the resulting fraction to a decimal only at the final step.

Solution

1. Remove the parentheses: \(4.5 - 1.25 - \frac{1}{3} + \frac{1}{12}\). 2. Combine the decimals: \(4.5 - 1.25 = 3.25\). 3. Combine the fractions: \(-\frac{1}{3} + \frac{1}{12} = -\frac{4}{12} + \frac{1}{12} = -\frac{1}{4} = -0.25\). 4. Add: \(3.25 - 0.25 = 3\).

Answer

\(3\)
Add and subtract rational numbers 28
Estimate the value first, then calculate the exact value. \(18.75 - \left(4\frac{1}{2} + 3.2\right) + 1\frac{1}{4}\)

Hints

- Round to convenient whole numbers for the estimate. - Convert the mixed numbers to terminating decimals for the exact calculation. - Follow the grouping symbols before adding the final term.

Solution

1. Estimate by rounding to convenient whole numbers: \(19 - (5 + 3) + 1 = 12\). 2. Convert the mixed numbers: \(4\frac{1}{2} = 4.5\) and \(1\frac{1}{4} = 1.25\). 3. Evaluate the parentheses: \(4.5 + 3.2 = 7.7\). 4. Calculate exactly: \(18.75 - 7.7 + 1.25 = 11.05 + 1.25 = 12.3\).

Answer

Estimate: about \(12\) Exact value: \(12.3\)
Add and subtract rational numbers 29
Evaluate the expression and write the result as a decimal: \(\frac{7}{10}-\left(\frac{2}{5}+\frac{1}{2}\right)\)

Hints

- Evaluate the parentheses first. - Fractions need a common denominator before you add them. - How do you write tenths as decimals?

Solution

1. Add inside the parentheses: \(\frac{2}{5}+\frac{1}{2}=\frac{4}{10}+\frac{5}{10}=\frac{9}{10}\). 2. Subtract: \(\frac{7}{10}-\frac{9}{10}=-\frac{2}{10}\). 3. Convert to a decimal: \(-\frac{2}{10}=-0.2\).

Answer

\(-0.2\)
Add and subtract rational numbers 30
Find the error in the calculation and give the correct result. \(7\frac{1}{4} - 2.5 = (7 - 2) + (0.25 + 0.5) = 5 + 0.75 = 5.75\)

Hints

- The entire second number must be subtracted. - Track the subtraction sign when decomposing a number into whole-number and decimal parts. - Rewrite both numbers as decimals or both as fractions.

Solution

1. The error is that \(0.5\), which is part of the number being subtracted, was added instead of subtracted. 2. Convert the mixed number: \(7\frac{1}{4} = 7.25\). 3. Subtract correctly: \(7.25 - 2.5 = 4.75\).

Answer

The \(0.5\) was added instead of subtracted. The correct calculation is \(7.25 - 2.5 = 4.75\).
Add and subtract rational numbers 31
For each expression, choose a fraction or decimal form that avoids unnecessary work. Write the conversion or rewrite you chose before evaluating. a) \(\frac{3}{4} + 0.15\) b) \(0.8 - \frac{1}{5}\) c) \(-\frac{2}{3} + 0.5\) d) \(1.125 - \frac{1}{8}\)

Hints

- Ask whether the fraction has a short terminating decimal before converting it. - A repeating decimal is often less convenient than keeping a fraction exact. - Show the representation change you actually use.

Solution

1. a) \(\frac{3}{4}=0.75\), so \(0.75+0.15=0.9\). 2. b) \(\frac{1}{5}=0.2\), so \(0.8-0.2=0.6\). 3. c) \(0.5=\frac{1}{2}\), so \(-\frac{2}{3}+\frac{1}{2}=-\frac{1}{6}\). 4. d) \(\frac{1}{8}=0.125\), so \(1.125-0.125=1\).

Answer

a) \(\frac{3}{4}=0.75\); result \(0.9\) b) \(\frac{1}{5}=0.2\); result \(0.6\) c) \(0.5=\frac{1}{2}\); result \(-\frac{1}{6}\) d) \(\frac{1}{8}=0.125\); result \(1\)
Add and subtract rational numbers 32
Evaluate each expression. For every part, first write the exact fraction-to-decimal conversion you use; then calculate. a) \(0.45 + \frac{3}{20}\) b) \(\frac{5}{8} - 0.125\) c) \(-1.2 + \frac{1}{5}\)

Hints

- Rewrite each fraction with denominator \(10\), \(100\), or \(1000\) when possible. - Keep the conversion visible before combining the values. - Check the sign of the final sum or difference.

Solution

1. a) \(\frac{3}{20}=0.15\), so \(0.45+0.15=0.6\). 2. b) \(\frac{5}{8}=0.625\), so \(0.625-0.125=0.5\). 3. c) \(\frac{1}{5}=0.2\), so \(-1.2+0.2=-1\).

Answer

a) \(\frac{3}{20}=0.15\); \(0.45+0.15=0.6\) b) \(\frac{5}{8}=0.625\); \(0.625-0.125=0.5\) c) \(\frac{1}{5}=0.2\); \(-1.2+0.2=-1\)
Add and subtract rational numbers 33
Before evaluating, show an equivalent rearrangement and regrouping that creates two whole-number partial sums. Then evaluate and name the properties that justify changing the order and grouping. \(3.7 + \frac{2}{3} + 1.3 + 1\frac{1}{3}\)

Hints

- Keep each addend unchanged when you reorder the sum. - Look for pairs that produce especially simple partial sums. - Name the properties that permit changing order and grouping.

Solution

1. Use the commutative and associative properties of addition to write \((3.7+1.3)+\left(\frac{2}{3}+1\frac{1}{3}\right)\). 2. The decimal group is \(5\). 3. The fraction group is \(\frac{2}{3}+\frac{4}{3}=2\). 4. Therefore, the sum is \(7\).

Answer

A valid regrouping is \((3.7+1.3)+\left(\frac{2}{3}+1\frac{1}{3}\right)=5+2=7\). The commutative and associative properties of addition justify the changed order and grouping.
Add and subtract rational numbers 34
Evaluate each expression. a) \(-4.8-2.35\) b) \(-\frac{5}{6}+\frac{1}{3}\) c) \(0.75+(-1.2)\) d) \(-\left(\frac{1}{4}-\frac{5}{8}\right)\)

Hints

- Pay attention to signs when removing parentheses. - Use common denominators before adding or subtracting fractions. - Before calculating with decimals, decide whether the result should be positive or negative.

Solution

1. For a), \(-4.8-2.35=-7.15\). 2. For b), \(-\frac{5}{6}+\frac{1}{3}=-\frac{5}{6}+\frac{2}{6}=-\frac{1}{2}\). 3. For c), \(0.75+(-1.2)=-0.45\). 4. For d), \(\frac{1}{4}-\frac{5}{8}=\frac{2}{8}-\frac{5}{8}=-\frac{3}{8}\). The leading negative changes the sign, giving \(\frac{3}{8}\).

Answer

a) \(-7.15\) b) \(-\frac{1}{2}\) c) \(-0.45\) d) \(\frac{3}{8}\)
Add and subtract rational numbers 35
Evaluate the expression: \((-4.2+1.7)-(0.8-2.3)\)

Hints

- Evaluate both sets of parentheses first. - What happens when you subtract a negative number? - A number line can help you check the final sign.

Solution

1. First parentheses: \(-4.2+1.7=-2.5\). 2. Second parentheses: \(0.8-2.3=-1.5\). 3. Subtract: \(-2.5-(-1.5)=-1\).

Answer

\(-1\)
Add and subtract rational numbers 36
Calculate the value of the expression and write the result as a mixed number: \(\left(5 \frac{3}{4}-1 \frac{1}{2}\right)+2 \frac{5}{8}\)

Hints

- Evaluate the expression inside the parentheses first. - Rewrite the fractional parts with common denominators before subtracting or adding. - Simplify the result inside the parentheses before continuing. - Convert the intermediate result to eighths before the final addition.

Solution

1. Evaluate the parentheses: \(5 \frac{3}{4}-1 \frac{1}{2}=5 \frac{3}{4}-1 \frac{2}{4}=4 \frac{1}{4}\). 2. Rewrite \(4 \frac{1}{4}\) as \(4 \frac{2}{8}\). 3. Add: \(4 \frac{2}{8}+2 \frac{5}{8}=6 \frac{7}{8}\).

Answer

\(6 \frac{7}{8}\)
Add and subtract rational numbers 37
A point starts at \(-2.3\) on a number line. It moves \(4.5\) units to the right and then \(1.4\) units to the left. Where does the point end?

Hints

- A move to the right corresponds to addition. - A move to the left corresponds to subtraction. - Carry out the moves in order.

Solution

1. Moving right means add: \(-2.3+4.5=2.2\). 2. Moving left means subtract: \(2.2-1.4=0.8\). 3. The point ends at \(0.8\).

Answer

\(0.8\)
Add and subtract rational numbers 38
Evaluate and write the result as a fraction in simplest form: \(\frac{2}{5}+\frac{1}{2}-\frac{3}{10}\)

Hints

- Find a common denominator for \(5\), \(2\), and \(10\). - Rewrite all three fractions before adding and subtracting. - Simplify the final fraction.

Solution

1. Use denominator \(10\): \(\frac{2}{5}=\frac{4}{10}\) and \(\frac{1}{2}=\frac{5}{10}\). 2. Calculate: \(\frac{4}{10}+\frac{5}{10}-\frac{3}{10}=\frac{6}{10}=\frac{3}{5}\).

Answer

\(\frac{3}{5}\)
Add and subtract rational numbers 39
Evaluate each sum or difference of rational numbers. a) \(-8.7+(-13.5)\) b) \(4.2-9.8\) c) \(-\frac{5}{9}+\frac{1}{6}\) d) \(\frac{2}{3}-\frac{3}{4}+\left(-\frac{1}{2}\right)\)

Hints

- What sign results when two negative numbers are added? - For unlike signs, compare absolute values. - Use a common denominator for fractions. - You can rewrite subtraction as addition of the opposite.

Solution

1. For a), \(-8.7+(-13.5)=-22.2\). 2. For b), \(4.2-9.8=-5.6\). 3. For c), use denominator \(18\): \(-\frac{10}{18}+\frac{3}{18}=-\frac{7}{18}\). 4. For d), use denominator \(12\): \(\frac{8}{12}-\frac{9}{12}-\frac{6}{12}=-\frac{7}{12}\).

Answer

a) \(-22.2\) b) \(-5.6\) c) \(-\frac{7}{18}\) d) \(-\frac{7}{12}\)
Add and subtract rational numbers 40
Evaluate each expression. Write the result as either a decimal or a fraction. a) \(\frac{3}{4}-1.25\) b) \(-0.6-\left(-\frac{1}{5}\right)\) c) \(2-\frac{1}{2}-0.75\) d) \(-\frac{1}{8}-0.125\)

Hints

- Choose fractions or decimals and convert values to the same form. - Recall common fraction-decimal equivalents such as \(\frac{1}{2}\) and \(\frac{1}{5}\). - Pay close attention to subtracting a negative number.

Solution

1. For a), \(0.75-1.25=-0.5=-\frac{1}{2}\). 2. For b), \(-0.6-(-0.2)=-0.4=-\frac{2}{5}\). 3. For c), \(2-0.5-0.75=0.75=\frac{3}{4}\). 4. For d), \(-0.125-0.125=-0.25=-\frac{1}{4}\).

Answer

a) \(-0.5\), or \(-\frac{1}{2}\) b) \(-0.4\), or \(-\frac{2}{5}\) c) \(0.75\), or \(\frac{3}{4}\) d) \(-0.25\), or \(-\frac{1}{4}\)
Add and subtract rational numbers 41
The expressions are \(A=x-5.4\) and \(B=-3.2-y\). Evaluate them for \(x=2.1\) and \(y=-1.8\). Which value is greater?

Hints

- Substitute each given value into its expression. - Subtracting a negative number is equivalent to adding its opposite. - On a number line, the number farther to the right is greater.

Solution

1. \(A=2.1-5.4=-3.3\). 2. \(B=-3.2-(-1.8)=-3.2+1.8=-1.4\). 3. Since \(-1.4>-3.3\), \(B\) has the greater value.

Answer

\(A=-3.3\) and \(B=-1.4\). The value of \(B\) is greater.
Add and subtract rational numbers 42
During a winter night, the temperature drops to \(-12\,^\circ\text{C}\). By noon the next day, the temperature has risen to \(7\,^\circ\text{C}\). By how many degrees Celsius did the temperature increase?

Hints

- Picture the temperatures on a number line. - Find the distance from the negative temperature to zero. - Find the distance from zero to the positive temperature. - Which operation finds the change from an initial value to a final value?

Solution

1. The initial temperature is \(-12\,^\circ\text{C}\). 2. The final temperature is \(7\,^\circ\text{C}\). 3. Subtract the initial temperature from the final temperature: \(7-(-12)=7+12=19\).

Answer

The temperature increased by \(19\,^\circ\text{C}\).
Add and subtract rational numbers 43
Ms. Weber's bank account balance is \(-\$75.20\). She wants the balance to be exactly \(\$120.00\). How much money must she deposit?

Hints

- A negative balance is below \(0\). - First think about how much is needed to reach \(0\), then how much more is needed to reach \(120\). - Subtract the current signed balance from the target balance.

Solution

1. The current balance is \(-\$75.20\), and the target balance is \(\$120.00\). 2. The required deposit is the change from \(-75.20\) to \(120.00\): \(120.00-(-75.20)=195.20\). 3. Therefore, she must deposit \(\$195.20\).

Answer

\(\$195.20\)
Add and subtract rational numbers 44
Ms. Schneider's checking account balance is \(-\$125.50\). In the morning, she deposits \(\$350.00\). In the afternoon, she pays an \(\$80.00\) bill from the account. Find the end-of-day balance using one expression with rational numbers.

Hints

- A deposit increases the account balance. - A bill payment decreases the account balance. - Write all three amounts in one signed-number expression before calculating.

Solution

1. Represent the transactions in one expression: \(-125.50+350.00-80.00\). 2. Calculate: \(-125.50+350.00=224.50\), then \(224.50-80.00=144.50\). 3. The end-of-day balance is \(\$144.50\).

Answer

\(-125.50+350.00-80.00=144.50\). The end-of-day balance is \(\$144.50\).
Add and subtract rational numbers 45
Evaluate \(T(a,b)=a-b\) for each pair of rational numbers. Complete the table using fractions in simplest form or mixed numbers. <table> <tr><td>\(a-b\)</td><td>\(-\frac{2}{3}\)</td><td>\(\frac{5}{6}\)</td></tr> <tr><td>\(-\frac{1}{2}\)</td><td></td><td></td></tr> <tr><td>\(\frac{3}{4}\)</td><td></td><td></td></tr> </table>

Hints

- Use a common denominator before subtracting fractions. - Subtracting a negative number means adding. - Simplify each result or write it as a mixed number.

Solution

1. \(-\frac{1}{2}-\left(-\frac{2}{3}\right)=-\frac{3}{6}+\frac{4}{6}=\frac{1}{6}\). 2. \(-\frac{1}{2}-\frac{5}{6}=-\frac{3}{6}-\frac{5}{6}=-\frac{8}{6}=-\frac{4}{3}=-1\frac{1}{3}\). 3. \(\frac{3}{4}-\left(-\frac{2}{3}\right)=\frac{9}{12}+\frac{8}{12}=\frac{17}{12}=1\frac{5}{12}\). 4. \(\frac{3}{4}-\frac{5}{6}=\frac{9}{12}-\frac{10}{12}=-\frac{1}{12}\).

Answer

<table> <tr><td>\(a-b\)</td><td>\(-\frac{2}{3}\)</td><td>\(\frac{5}{6}\)</td></tr> <tr><td>\(-\frac{1}{2}\)</td><td>\(\frac{1}{6}\)</td><td>\(-1\frac{1}{3}\)</td></tr> <tr><td>\(\frac{3}{4}\)</td><td>\(1\frac{5}{12}\)</td><td>\(-\frac{1}{12}\)</td></tr> </table>
Add and subtract rational numbers 46
Determine whether each result is positive or negative without finding its exact value. For each part, give a sign rule or an absolute-value comparison that proves your choice; an exact numerical result alone is not a justification. a) \(-12+(-15)\) b) \(24-(-10)\) c) \(-0.5+0.3\) d) \(\frac{1}{2}-\frac{3}{4}\) e) \(-8-(-5)\)

Hints

- Base each decision on signs, opposites, or relative magnitudes rather than exact arithmetic. - For unlike signs, compare absolute values. - Rewrite subtraction of a negative before deciding its effect.

Solution

1. a) The sum of two negative numbers is negative. 2. b) Subtracting a negative is adding a positive, so the result is positive. 3. c) The addends have unlike signs and \(0.5>0.3\), so the sign is negative. 4. d) Since \(\frac{3}{4}>\frac{1}{2}\), subtracting the larger positive number gives a negative result. 5. e) Rewrite as \(-8+5\). Since \(8>5\), the result is negative.

Answer

a) negative — both addends are negative b) positive — subtracting a negative adds a positive c) negative — \(|-0.5|>|0.3|\) d) negative — \(\frac{3}{4}>\frac{1}{2}\) e) negative — \(-8-(-5)=-8+5\) and \(8>5\)
Add and subtract rational numbers 47
Rewrite the expression as an equivalent sum that groups compatible fractions, then evaluate it. \(\frac{7}{15} - \frac{3}{4} + \frac{8}{15} - \frac{1}{4}\)

Hints

- First view every subtraction as addition of a signed term. - Which terms can be combined without creating a new denominator? - Include the regrouped expression in your response.

Solution

1. Rewrite and regroup: \(\left(\frac{7}{15}+\frac{8}{15}\right)+\left(-\frac{3}{4}-\frac{1}{4}\right)\). 2. The groups are \(1\) and \(-1\). 3. Their sum is \(0\).

Answer

\(\left(\frac{7}{15}+\frac{8}{15}\right)+\left(-\frac{3}{4}-\frac{1}{4}\right)=0\)
Add and subtract rational numbers 48
Evaluate without converting every number to the same form. Show an equivalent grouping that lets the decimals combine with decimals and the fractions combine with fractions. \(2.7 + \frac{2}{9} - 1.7 + \frac{16}{9}\)

Hints

- Keep each sign attached to its term when changing order. - Look for same-form terms that combine exactly as written. - Do not convert a repeating fraction to a decimal just to make every term look alike.

Solution

1. Regroup as \((2.7-1.7)+\left(\frac{2}{9}+\frac{16}{9}\right)\). 2. The groups equal \(1\) and \(2\). 3. Therefore, the value is \(3\).

Answer

\((2.7-1.7)+\left(\frac{2}{9}+\frac{16}{9}\right)=1+2=3\)
Add and subtract rational numbers 49
For each expression, write a regrouped equivalent expression that creates convenient pairs, then evaluate. a) \(12.3 - 4.5 - 2.3 + 1.5\) b) \(\frac{3}{8} - 1.4 + \frac{5}{8} - 0.6\)

Hints

- Rewrite each subtraction as addition of a signed term before changing order. - Look for pairs whose sum or difference is a whole number. - Show the regrouping explicitly.

Solution

1. a) Regroup as \((12.3-2.3)+(-4.5+1.5)=10-3=7\). 2. b) Regroup as \(\left(\frac{3}{8}+\frac{5}{8}\right)+(-1.4-0.6)=1-2=-1\).

Answer

a) \((12.3-2.3)+(-4.5+1.5)=7\) b) \(\left(\frac{3}{8}+\frac{5}{8}\right)+(-1.4-0.6)=-1\)
Add and subtract rational numbers 50
For each expression, rearrange and group terms to create at least one multiple of \(10\) or \(100\). Write the regrouped expression, then evaluate. a) \(34 + 128 - 134\) b) \(12.5 - 6.7 - 2.5 + 1.7\) c) \(-48 + 56 - 52 + 44\)

Hints

- Keep each sign attached to its term when rearranging. - Search for pairs whose combined value has a zero in the ones place. - Your response must display the convenient grouping.

Solution

1. a) \((34-134)+128=-100+128=28\). 2. b) \((12.5-2.5)+(-6.7+1.7)=10-5=5\). 3. c) \((-48-52)+(56+44)=-100+100=0\).

Answer

a) \((34-134)+128=28\) b) \((12.5-2.5)+(-6.7+1.7)=5\) c) \((-48-52)+(56+44)=0\)
Add and subtract rational numbers 51
For each expression, show one regrouping that creates a whole-number partial sum or difference, then evaluate. a) \(15.6 - 7.8 - 2.2\) b) \(-4.9 + 12.5 - 5.1\) c) \(24.3 + 8.7 - 14.3 + 1.3\)

Hints

- Look for decimal pairs whose sum or difference is a whole number. - Preserve the sign of every term when changing grouping. - Include the regrouped expression in your answer.

Solution

1. a) \(15.6-(7.8+2.2)=15.6-10=5.6\). 2. b) \((-4.9-5.1)+12.5=-10+12.5=2.5\). 3. c) \((24.3-14.3)+(8.7+1.3)=10+10=20\).

Answer

a) \(15.6-(7.8+2.2)=5.6\) b) \((-4.9-5.1)+12.5=2.5\) c) \((24.3-14.3)+(8.7+1.3)=20\)
Add and subtract rational numbers 52
Use properties of addition to evaluate efficiently. \(7.25-4.8+\frac{11}{4}-1.2\)

Hints

- Convert the fraction to a decimal. - Look for values whose decimal parts combine to whole numbers. - Rewrite the expression as a sum before reordering terms.

Solution

1. Write \(\frac{11}{4}=2.75\). 2. Rewrite subtraction as addition and regroup: \((7.25+2.75)+(-4.8-1.2)\). 3. Evaluate the grouped sums: \(10+(-6)=4\).

Answer

\(4\)
Add and subtract rational numbers 53
Rearrange and group the terms to create convenient multiples of \(100\). Write the regrouped expression, then evaluate. \(-250 + 68 + 145 - 50 + 32 - 45\)

Hints

- Keep the sign attached to each term when rearranging. - Look for pairs that combine to exact hundreds. - Show the regrouping before the final total.

Solution

1. Regroup as \((-250-50)+(68+32)+(145-45)\). 2. The groups are \(-300\), \(100\), and \(100\). 3. The total is \(-100\).

Answer

\((-250-50)+(68+32)+(145-45)=-300+100+100=-100\)
Add and subtract rational numbers 54
a) Start at \(-1.25\) on a number line and move \(0.75\) unit to the right. Where do you land? b) From your new position, move \(1.25\) units left. Where do you land? Write an addition equation for each move.

Hints

- Think about which direction each move takes you. - Use the landing point from a) as the starting point for b). - A move to the left can be written as adding a negative number.

Solution

1. Moving right means adding a positive amount: \(-1.25+0.75=-0.5\). 2. Moving left means adding a negative amount: \(-0.5+(-1.25)=-1.75\).

Answer

a) \(-1.25+0.75=-0.5\) b) \(-0.5+(-1.25)=-1.75\)
Add and subtract rational numbers 55
For each expression, write one equivalent regrouping that produces convenient whole-number partial results, then evaluate. a) \(14.7 - 3.9 + 5.3 - 6.1\) b) \(-\frac{3}{8} + 12.5 - 5.5 + 0.375\) c) \(8.4 - (2.4 + 3.9) + 0.9\)

Hints

- Search for pairs that make whole numbers or additive inverses. - A fraction-decimal conversion is useful only if it creates such a pair. - Keep signs attached to terms when regrouping.

Solution

1. a) \((14.7+5.3)+(-3.9-6.1)=20-10=10\). 2. b) Since \(-\frac{3}{8}=-0.375\), \((-0.375+0.375)+(12.5-5.5)=7\). 3. c) Remove the parentheses and regroup: \((8.4-2.4)+(0.9-3.9)=6-3=3\).

Answer

a) \((14.7+5.3)+(-3.9-6.1)=10\) b) \((-0.375+0.375)+(12.5-5.5)=7\) c) \((8.4-2.4)+(0.9-3.9)=3\)
Add and subtract rational numbers 56
Evaluate the expression: \(\frac{2}{3}-\left(-\frac{1}{4}\right)+\frac{5}{6}-1\)

Hints

- What happens when you subtract a negative number? - Use a common denominator for all fractions. - Write \(1\) as a fraction with the same denominator.

Solution

1. Subtracting a negative gives addition: \(\frac{2}{3}+\frac{1}{4}+\frac{5}{6}-1\). 2. Use denominator \(12\): \(\frac{8}{12}+\frac{3}{12}+\frac{10}{12}-\frac{12}{12}=\frac{9}{12}\). 3. Simplify: \(\frac{9}{12}=\frac{3}{4}=0.75\).

Answer

\(\frac{3}{4}\), or \(0.75\)
Add and subtract rational numbers 57
Evaluate each expression. Use common denominators where needed. a) \(\frac{4}{5}+\left(-\frac{1}{2}\right)\) b) \(-\frac{3}{4}-\frac{5}{6}\) c) \(-1.5+\frac{1}{4}\) d) \(\frac{7}{9}-\left(-\frac{2}{3}\right)\)

Hints

- Subtracting a negative number is the same as adding its opposite. - Fractions need common denominators before addition or subtraction. - Convert between fractions and decimals when helpful. - Simplify or write improper fractions as mixed numbers if useful.

Solution

1. For a), \(\frac{4}{5}-\frac{1}{2}=\frac{8}{10}-\frac{5}{10}=\frac{3}{10}\). 2. For b), \(-\frac{3}{4}-\frac{5}{6}=-\frac{9}{12}-\frac{10}{12}=-\frac{19}{12}=-1 \frac{7}{12}\). 3. For c), \(-1.5+0.25=-1.25=-\frac{5}{4}\). 4. For d), subtracting a negative gives addition: \(\frac{7}{9}+\frac{2}{3}=\frac{7}{9}+\frac{6}{9}=\frac{13}{9}=1 \frac{4}{9}\).

Answer

a) \(\frac{3}{10}\) b) \(-\frac{19}{12}\), or \(-1 \frac{7}{12}\) c) \(-1.25\), or \(-\frac{5}{4}\) d) \(\frac{13}{9}\), or \(1 \frac{4}{9}\)
Add and subtract rational numbers 58
Complete each statement about how the result of a subtraction changes. a) If the first number increases by \(14\) and the number being subtracted stays the same, the result \(\square\) by \(\square\). b) If the first number stays the same and the number being subtracted decreases by \(9\), the result \(\square\) by \(\square\). c) If both numbers increase by \(20\), what happens to the result?

Hints

- Try changing one number at a time in a simple subtraction example. - What happens when you subtract less? - If you move both numbers equally on a number line, does the gap change?

Solution

1. Increasing the first number by \(14\) increases the difference by \(14\). 2. Decreasing the number being subtracted by \(9\) means subtracting \(9\) less, so the difference increases by \(9\). 3. Adding \(20\) to both numbers does not change the difference: \((a+20)-(b+20)=a-b\).

Answer

a) Increases by \(14\). b) Increases by \(9\). c) The result stays the same.
Add and subtract rational numbers 59
Ms. Meyer has \(\$150\) in her checking account. A debit of \(\$215\) is then posted for a new desk. Explain why the new balance must be negative, and calculate the balance.

Hints

- What happens when more money is withdrawn than the account contains? - Compare the two amounts. Which is greater? - How can you represent the debit when calculating the new balance?

Solution

1. The debit is greater than the current balance because \(215>150\), so the account becomes overdrawn and the new balance is negative. 2. Subtract the debit from the balance: \(150-215=-65\).

Answer

The new balance is negative because the debit is greater than the amount in the account. \(\$150-\$215=-\$65\), so the new balance is \(-\$65\).
Add and subtract rational numbers 60
At \(6{:}00\) p.m. on a winter day, the temperature is \(4\,^\circ\text{F}\). By midnight, it drops \(7\,^\circ\text{F}\). During the early morning, it drops another \(2\,^\circ\text{F}\). What is the temperature in the morning?

Hints

- Represent each change on a number line. - Which direction do you move when the temperature drops? - Calculate the first drop, then use that result as the starting value for the second drop.

Solution

1. Find the temperature at midnight: \(4-7=-3\), so it is \(-3\,^\circ\text{F}\). 2. Subtract the second drop: \(-3-2=-5\), so it is \(-5\,^\circ\text{F}\).

Answer

The temperature in the morning is \(-5\,^\circ\text{F}\).
Add and subtract rational numbers 61
For each sum, give a sign prediction and a brief rule or magnitude comparison that supports it. Then calculate the exact sum. a) \(-14+25\) b) \(18+(-30)\) c) \(-22+(-18)\) d) \(-45+45\)

Hints

- Separate the sign decision from the magnitude calculation. - With unlike signs, compare absolute values. - Opposites have equal magnitude and opposite signs.

Solution

1. a) The signs differ and \(25>14\), so predict positive; the sum is \(11\). 2. b) The signs differ and \(30>18\), so predict negative; the sum is \(-12\). 3. c) Both addends are negative, so predict negative; the sum is \(-40\). 4. d) The addends are opposites, so predict zero; the sum is \(0\).

Answer

a) positive because \(25>14\); \(11\) b) negative because \(30>18\); \(-12\) c) negative because both addends are negative; \(-40\) d) zero because the addends are opposites; \(0\)
Add and subtract rational numbers 62
Find the integer that makes each equation true. a) \(-12+\square=5\) b) \(\square+(-8)=-20\) c) \(15+\square=0\) d) \(\square+10=-3\)

Hints

- Think of moving from the known addend to the sum on a number line. - Use subtraction to find a missing addend. - A number and its opposite add to zero.

Solution

1. In part a), the missing addend is \(5-(-12)=17\). 2. In part b), the missing addend is \(-20-(-8)=-12\). 3. In part c), the missing addend is the opposite of \(15\), so it is \(-15\). 4. In part d), the missing addend is \(-3-10=-13\).

Answer

a) \(17\) b) \(-12\) c) \(-15\) d) \(-13\)
Add and subtract rational numbers 63
Replace each box with \(<\), \(>\), or \(=\). For each part, give the sign rule or magnitude comparison that lets you decide without finding the exact sum. a) \(-35+40\mathbin{\square}0\) b) \(-12+(-15)\mathbin{\square}0\) c) \(25+(-25)\mathbin{\square}0\) d) \(-50+30\mathbin{\square}0\)

Hints

- Do not compute the sums; use signs and absolute values. - For unlike signs, the larger magnitude determines the sign. - Equal opposite magnitudes produce zero.

Solution

1. a) The positive addend has greater magnitude, so the sum is greater than \(0\). 2. b) Both addends are negative, so the sum is less than \(0\). 3. c) The addends are opposites, so the sum equals \(0\). 4. d) The negative addend has greater magnitude, so the sum is less than \(0\).

Answer

a) \(>\) — \(40>35\) b) \(<\) — both addends are negative c) \(=\) — the addends are opposites d) \(<\) — \(50>30\) and the larger magnitude is negative
Add and subtract rational numbers 64
Find each sum. a) \(-38+92\) b) \(54+(-117)\) c) \(-256+(-144)\) d) \(-1025+375\)

Hints

- First identify whether the signs are alike or different. - With unlike signs, compare absolute values. - With two negative addends, add the absolute values and keep the negative sign.

Solution

1. For unlike signs, subtract absolute values and use the sign of the addend with the greater absolute value. 2. \(-38+92=54\). 3. \(54+(-117)=-(117-54)=-63\). 4. \(-256+(-144)=-(256+144)=-400\). 5. \(-1025+375=-(1025-375)=-650\).

Answer

a) \(54\) b) \(-63\) c) \(-400\) d) \(-650\)
Add and subtract rational numbers 65
Evaluate \(-120+450+(-380)\) from left to right. Report the intermediate sum after the first addition and the final sum.

Hints

- The stated order requires you to combine the first two terms first. - Keep the sign of the third term when adding it to the intermediate result.

Solution

1. First, \(-120+450=330\). 2. Then \(330+(-380)=-50\).

Answer

Intermediate sum: \(330\) Final sum: \(-50\)
Add and subtract rational numbers 66
Compare the values of Expressions A and B. Which is greater? Expression A: \(-1500+850\) Expression B: \(2100+(-2800)\)

Hints

- Evaluate each expression separately. - Compare the two negative results on a number line. - Among negative numbers, the value closer to zero is greater.

Solution

1. Expression A is \(-1500+850=-650\). 2. Expression B is \(2100+(-2800)=-700\). 3. Since \(-650>-700\), Expression A is greater.

Answer

Expression A is greater because \(-650>-700\).
Add and subtract rational numbers 67
A research submarine is \(450\,\text{m}\) below sea level. It rises \(185\,\text{m}\) to take a measurement. How far below sea level is the submarine after it rises?

Hints

- Represent positions below sea level with negative numbers. - When the submarine rises, does its position become greater or less? - Express the final negative position as a depth below sea level.

Solution

1. Represent the initial position as \(-450\,\text{m}\). 2. Rising \(185\,\text{m}\) means adding \(185\): \(-450+185=-265\). 3. A position of \(-265\,\text{m}\) is \(265\,\text{m}\) below sea level.

Answer

The submarine is \(265\,\text{m}\) below sea level.
Add and subtract rational numbers 68
Choose \(+\) or \(-\) for each box to make the equation true. a) \((\mathbin{\square}17)+13=30\) b) \(-24+(\mathbin{\square}16)=-40\) c) \(35+(\mathbin{\square}50)=-15\) d) \((\mathbin{\square}12)+(-28)=-16\)

Hints

- Check whether the result must increase or decrease from the known addend. - Compare the absolute values when the signs differ. - Substitute each possible sign and test the equation.

Solution

1. \(17+13=30\), so part a) needs \(+\). 2. \(-24+(-16)=-40\), so part b) needs \(-\). 3. \(35+(-50)=-15\), so part c) needs \(-\). 4. \(12+(-28)=-16\), so part d) needs \(+\).

Answer

a) \(+\) b) \(-\) c) \(-\) d) \(+\)
Add and subtract rational numbers 69
Choose the missing sign in each equation. a) \(-42+12=\mathbin{\square}30\) b) \(15+(-45)=\mathbin{\square}30\) c) \((\mathbin{\square}60)+(-25)=35\) d) \(-11+(\mathbin{\square}11)=-22\)

Hints

- Identify whether the missing sign belongs to an addend or the result. - For unlike signs, subtract the absolute values. - Test the completed equation.

Solution

1. \(-42+12=-30\), so part a) needs \(-\). 2. \(15+(-45)=-30\), so part b) needs \(-\). 3. \(60+(-25)=35\), so part c) needs \(+\). 4. \(-11+(-11)=-22\), so part d) needs \(-\).

Answer

a) \(-\) b) \(-\) c) \(+\) d) \(-\)
Add and subtract rational numbers 70
For each sum, state the predicted sign and the rule or magnitude comparison that determines it. Then calculate the exact value. a) \(-415+625\) b) \(-874+(-126)\) c) \(2500+(-3750)\) d) \(-999+1001\)

Hints

- Decide the sign using sign rules and absolute values before reporting the exact sum. - With unlike signs, compare magnitudes. - With like negative signs, the sum remains negative.

Solution

1. a) Unlike signs with \(625>415\) give a positive result: \(210\). 2. b) Two negative addends give a negative result: \(-1000\). 3. c) Unlike signs with \(3750>2500\) give a negative result: \(-1250\). 4. d) Unlike signs with \(1001>999\) give a positive result: \(2\).

Answer

a) positive because \(625>415\); \(210\) b) negative because both addends are negative; \(-1000\) c) negative because \(3750>2500\); \(-1250\) d) positive because \(1001>999\); \(2\)
Add and subtract rational numbers 71
Evaluate each sum from left to right. For each part, report the intermediate sum after the first addition and then the final sum. a) \(-120+250+(-80)\) b) \(500+(-750)+250\)

Hints

- Follow the stated order rather than regrouping. - Keep the intermediate value visible before using the final term.

Solution

1. a) \(-120+250=130\), then \(130-80=50\). 2. b) \(500-750=-250\), then \(-250+250=0\).

Answer

a) Intermediate: \(130\); final: \(50\) b) Intermediate: \(-250\); final: \(0\)
Add and subtract rational numbers 72
Evaluate both sides and replace each box with \(<\), \(>\), or \(=\). a) \(-45+20\mathbin{\square}-30+5\) b) \(100+(-150)\mathbin{\square}-80+20\) c) \(-12+(-13)\mathbin{\square}5+(-30)\)

Hints

- Evaluate the left and right expressions separately. - Compare negative results carefully. - Among two negative values, the one closer to zero is greater.

Solution

1. In part a), both sides equal \(-25\), so use \(=\). 2. In part b), the left side is \(-50\) and the right side is \(-60\), so use \(>\). 3. In part c), both sides equal \(-25\), so use \(=\).

Answer

a) \(=\) b) \(>\) c) \(=\)
Add and subtract rational numbers 73
Find the integer \(z\) that makes each equation true. a) \(50+z=-10\) b) \(z+(-120)=-200\) c) \(-15+25+z=0\)

Hints

- Use subtraction to find a missing addend. - Simplify known addends first. - A number and its opposite sum to zero.

Solution

1. In part a), \(z=-10-50=-60\). 2. In part b), \(z=-200-(-120)=-80\). 3. In part c), \(-15+25=10\), so \(10+z=0\) and \(z=-10\).

Answer

a) \(z=-60\) b) \(z=-80\) c) \(z=-10\)
Add and subtract rational numbers 74
A frozen-food warehouse has several storage zones. Zone A is kept at \(-18\,^\circ\text{C}\). Zone B is \(7\) degrees colder than Zone A. Zone C is \(12\) degrees warmer than Zone B. What are the temperatures in Zones B and C?

Hints

- Find the temperature in Zone B first. - How do “colder” and “warmer” translate into operations? - Check the sign of your intermediate result before completing the second calculation.

Solution

1. Zone B is \(7\) degrees colder than Zone A, so \(-18-7=-25\). Zone B is \(-25\,^\circ\text{C}\). 2. Zone C is \(12\) degrees warmer than Zone B, so \(-25+12=-13\). Zone C is \(-13\,^\circ\text{C}\).

Answer

Zone B is \(-25\,^\circ\text{C}\), and Zone C is \(-13\,^\circ\text{C}\).
Add and subtract rational numbers 75
Insert \(+\) or \(-\) in each circle to make the equation true. a) \((\bigcirc 75)+(-25)=-100\) b) \((\bigcirc 120)+(+80)=-40\) c) \((+15)+(\bigcirc 50)=+65\) d) \((\bigcirc 9)+(+21)=+12\)

Hints

- Test whether each unknown number must be positive or negative. - Think about movement to the left or right on a number line. - Adding a negative number moves the value left.

Solution

1. In a), \(-75+(-25)=-100\), so the sign is \(-\). 2. In b), \(-120+80=-40\), so the sign is \(-\). 3. In c), \(15+50=65\), so the sign is \(+\). 4. In d), \(-9+21=12\), so the sign is \(-\).

Answer

a) \(-\) b) \(-\) c) \(+\) d) \(-\)
Add and subtract rational numbers 76
Find the missing addend in each equation. a) \(15+\square=8\) b) \(15+\square=-2\) c) \(15+\square=0\) d) \(15+\square=16\)

Hints

- Decide whether the missing addend moves the value left or right on a number line. - Use subtraction to find a missing addend. - Substitute your answer to check each equation.

Solution

1. In each equation \(15+x=s\), calculate \(x=s-15\). 2. The results are \(8-15=-7\), \(-2-15=-17\), \(0-15=-15\), and \(16-15=1\).

Answer

a) \(-7\) b) \(-17\) c) \(-15\) d) \(1\)
Add and subtract rational numbers 77
For each equation \(a+x=s\), find \(x\). a) \(-7+x=-15\) b) \(-7+x=4\) c) \(-7+x=-7\) d) \(-7+x=20\)

Hints

- Find a missing addend by subtracting the known addend from the sum. - Subtracting \(-7\) is the same as adding \(7\). - Check each result in the original equation.

Solution

1. Use \(x=s-a=s-(-7)=s+7\). 2. The values are \(-15+7=-8\), \(4+7=11\), \(-7+7=0\), and \(20+7=27\).

Answer

a) \(-8\) b) \(11\) c) \(0\) d) \(27\)
Add and subtract rational numbers 78
Find the missing addend. a) What number added to \(10\) gives \(-5\)? b) What number added to \(-20\) gives \(0\)? c) What number added to \(-4\) gives \(-12\)? d) What number added to \(0\) gives \(-8\)?

Hints

- Write an addition equation for each question. - Use subtraction to find the unknown addend. - Opposites add to zero.

Solution

1. \(10+x=-5\), so \(x=-15\). 2. \(-20+x=0\), so \(x=20\). 3. \(-4+x=-12\), so \(x=-8\). 4. \(0+x=-8\), so \(x=-8\).

Answer

a) \(-15\) b) \(20\) c) \(-8\) d) \(-8\)
Add and subtract rational numbers 79
Evaluate \(154+(-289)+45\).

Hints

- Combine the positive addends first. - Compare the absolute values of the remaining terms. - The term with the greater absolute value determines the sign.

Solution

1. Combine the positive addends: \(154+45=199\). 2. Then \(199+(-289)=-(289-199)=-90\).

Answer

\(-90\)
Add and subtract rational numbers 80
Evaluate \(-72+[148+(-205)]\).

Hints

- Evaluate the bracketed expression first. - Use the rule for adding integers with unlike signs. - Then add the two negative values.

Solution

1. Evaluate inside the brackets: \(148+(-205)=-57\). 2. Then \(-72+(-57)=-(72+57)=-129\).

Answer

\(-129\)
Add and subtract rational numbers 81
Evaluate \(-120+55+(-80)+145\).

Hints

- Regroup addends to make convenient sums. - Combine negative and positive terms separately. - Opposites add to zero.

Solution

1. Group like-signed terms: \([-120+(-80)]+[55+145]\). 2. The negative terms total \(-200\), and the positive terms total \(200\). 3. Therefore, \(-200+200=0\).

Answer

\(0\)
Add and subtract rational numbers 82
Which choice is closest to the value of \(-748+102+(-251)\)? A) \(-1100\) B) \(-900\) C) \(-400\) D) \(-650\)

Hints

- Round to convenient hundreds or fifties. - Combine the negative terms first. - Compare your estimate with the choices.

Solution

1. Round the terms to \(-750\), \(100\), and \(-250\). 2. The estimated sum is \(-750+100-250=-900\). 3. The exact value is \(-897\), confirming that \(-900\) is closest.

Answer

B) \(-900\)
Add and subtract rational numbers 83
Decide whether each statement is true or false. Justify with an example or counterexample. a) The sum of two negative numbers is always positive. b) Adding the opposite of \(0\) to any number leaves the number unchanged.

Hints

- Test the first claim with two specific negative integers. - Find the opposite of zero. - One counterexample disproves an “always” claim.

Solution

1. Statement a) is false. For example, \(-3+(-5)=-8\), which is negative. 2. Statement b) is true. The opposite of \(0\) is \(0\), and \(a+0=a\) for every number \(a\).

Answer

a) False; for example, \(-3+(-5)=-8\). b) True; the opposite of \(0\) is \(0\), and adding \(0\) does not change a number.
Add and subtract rational numbers 84
Find the missing addend. a) \(-520+\square=180\) b) \(75+\square=-25\)

Hints

- Decide whether the movement is left or right on a number line. - Determine whether the move crosses zero. - Subtract the starting value from the target value.

Solution

1. In part a), the move from \(-520\) to \(180\) is \(520+180=700\), so the missing addend is \(700\). 2. In part b), the move from \(75\) to \(-25\) is \(-(75+25)=-100\), so the missing addend is \(-100\).

Answer

a) \(700\) b) \(-100\)
Add and subtract rational numbers 85
Find \(x\). a) \(x+(-150)=-200\) b) \(x+300=50\)

Hints

- Undo the added number to find the starting value. - Adding a negative number can be undone by adding its opposite. - Check each solution in the original equation.

Solution

1. In part a), add \(150\) to both sides: \(x=-200+150=-50\). 2. In part b), subtract \(300\) from both sides: \(x=50-300=-250\).

Answer

a) \(x=-50\) b) \(x=-250\)
Add and subtract rational numbers 86
Find \(x\). a) \(-12+x=-12\) b) \(44+x=0\)

Hints

- Which addend leaves a number unchanged? - Which addend makes a sum of zero? - Use the additive identity and additive inverse.

Solution

1. In part a), adding \(0\) leaves \(-12\) unchanged, so \(x=0\). 2. In part b), the number that adds to \(44\) to make zero is its opposite, so \(x=-44\).

Answer

a) \(x=0\) b) \(x=-44\)
Add and subtract rational numbers 87
For each pair, find \(s=a+b\), then decide whether \(s>a\). a) \(a=12\), \(b=-5\) b) \(a=-6\), \(b=-4\) c) \(a=-9\), \(b=10\)

Hints

- Calculate each sum first. - Compare the result with the first addend. - Consider how a positive or negative second addend changes the first.

Solution

1. a) \(12+(-5)=7\), and \(7>12\) is false. 2. b) \(-6+(-4)=-10\), and \(-10>-6\) is false. 3. c) \(-9+10=1\), and \(1>-9\) is true.

Answer

a) \(s=7\); no b) \(s=-10\); no c) \(s=1\); yes
Add and subtract rational numbers 88
On a winter afternoon, the temperature drops by \(9\,^\circ\text{F}\). That evening, the thermometer reads \(-5\,^\circ\text{F}\). What was the temperature before the drop?

Hints

- Was it warmer or colder before the temperature dropped? - Sketch the situation on a number line or thermometer. - Starting with the final value, use the inverse of the temperature change.

Solution

1. Let the initial temperature be the value that becomes \(-5\,^\circ\text{F}\) after a decrease of \(9\) degrees. 2. Undo the decrease by adding \(9\): \(-5+9=4\), so the initial temperature was \(4\,^\circ\text{F}\).

Answer

The temperature before the drop was \(4\,^\circ\text{F}\).
Add and subtract rational numbers 89
Mr. Weber checks his banking app. A credit of \(\$125\) has been added, and his current balance is \(-\$240\). What was his balance immediately before the credit?

Hints

- What effect does a credit have on an account balance? - Which inverse operation undoes the credit? - Remember that the current balance is already negative.

Solution

1. The credit increased the account balance by \(\$125\). 2. Undo the credit by subtracting \(125\) from the current balance: \(-240-125=-365\).

Answer

The balance before the credit was \(-\$365\).
Add and subtract rational numbers 90
A remotely operated underwater vehicle descends \(150\,\text{m}\) from its initial position. It ends at \(-620\,\text{m}\), where sea level is \(0\,\text{m}\). What was the vehicle's position before it descended?

Hints

- Treat sea level as \(0\); positions below it are negative. - Descending makes the position less, or more negative. - To find the earlier position, reverse the descent.

Solution

1. The final position is \(-620\,\text{m}\). 2. Undo the \(150\,\text{m}\) descent by adding \(150\): \(-620+150=-470\). 3. Check: \(-470-150=-620\).

Answer

The vehicle's initial position was \(-470\,\text{m}\), or \(470\,\text{m}\) below sea level.
Add and subtract rational numbers 91
Rewrite each subtraction as addition of the opposite, and then evaluate. a) \(45-17\) b) \(-32-(-58)\) c) \(12-(-88)\) d) \(-74-26\)

Hints

- Subtracting a number means adding its opposite. - Change the operation and the sign of the second number together. - Then use integer addition rules.

Solution

1. \(45-17=45+(-17)=28\). 2. \(-32-(-58)=-32+58=26\). 3. \(12-(-88)=12+88=100\). 4. \(-74-26=-74+(-26)=-100\).

Answer

a) \(45+(-17)=28\) b) \(-32+58=26\) c) \(12+88=100\) d) \(-74+(-26)=-100\)
Add and subtract rational numbers 92
Complete each equation by rewriting subtraction as addition of the opposite. a) \(-120-85=-120+(\square)=\square\) b) \(215-(-45)=215+(\square)=\square\) c) \(-63-(-163)=-63+(\square)=\square\) d) \(19-50=19+(\square)=\square\)

Hints

- Replace subtraction with addition. - Use the opposite of the number after the subtraction sign. - Evaluate the resulting sum.

Solution

1. \(-120-85=-120+(-85)=-205\). 2. \(215-(-45)=215+45=260\). 3. \(-63-(-163)=-63+163=100\). 4. \(19-50=19+(-50)=-31\).

Answer

a) \(-120+(-85)=-205\) b) \(215+45=260\) c) \(-63+163=100\) d) \(19+(-50)=-31\)
Add and subtract rational numbers 93
Rewrite each expression as a sum, evaluate it, and decide which value is greater. Expression A: \(-240-160\) Expression B: \(-240-(-160)\)

Hints

- Rewrite each subtraction as adding the opposite. - Evaluate both expressions separately. - The negative value closer to zero is greater.

Solution

1. Expression A becomes \(-240+(-160)=-400\). 2. Expression B becomes \(-240+160=-80\). 3. Since \(-80>-400\), Expression B is greater.

Answer

Expression A equals \(-400\). Expression B equals \(-80\). Expression B is greater.
Add and subtract rational numbers 94
Order the expressions by value. Which expressions have equal values? 1. \(3-8\) 2. \(-2-3\) 3. \(12-4\) 4. \(-2-(-10)\) 5. \(0-5\) 6. \(15-7\)

Hints

- Rewrite subtraction as adding the opposite. - Evaluate each expression separately. - Group expressions with equal results.

Solution

1. Evaluate each expression: 1, 2, and 5 give \(-5\); 3, 4, and 6 give \(8\). 2. The expressions numbered 1, 2, and 5 have the same value. The expressions numbered 3, 4, and 6 have the same value. 3. Since \(-5<8\), the first group comes before the second group.

Answer

From least to greatest: expressions 1, 2, and 5 (all \(-5\)); then expressions 3, 4, and 6 (all \(8\)). Expressions in each group have equal values.
Add and subtract rational numbers 95
Evaluate both sides and replace each box with \(<\), \(>\), or \(=\). a) \(-8-2\mathbin{\square}-8-(-2)\) b) \(5-5\mathbin{\square}-3-(-3)\) c) \(-12-4\mathbin{\square}-10-10\)

Hints

- Evaluate each side separately. - Subtracting a negative is adding a positive. - Compare negative values on a number line.

Solution

1. In a), the values are \(-10\) and \(-6\), so \(-10<-6\). 2. In b), both values are \(0\), so they are equal. 3. In c), the values are \(-16\) and \(-20\), so \(-16>-20\).

Answer

a) \(<\) b) \(=\) c) \(>\)
Add and subtract rational numbers 96
Evaluate both sides and replace each box with \(<\), \(>\), or \(=\). a) \(-58-22\mathbin{\square}-90+10\) b) \(72+(-84)\mathbin{\square}-5-(-7)\) c) \(-200+150\mathbin{\square}-10-45\)

Hints

- Evaluate left and right sides separately. - Rewrite subtraction of a negative before calculating. - The negative value closer to zero is greater.

Solution

1. In a), both sides equal \(-80\), so use \(=\). 2. In b), the left side is \(-12\) and the right side is \(2\), so use \(<\). 3. In c), the left side is \(-50\) and the right side is \(-55\), so use \(>\).

Answer

a) \(=\) b) \(<\) c) \(>\)
Add and subtract rational numbers 97
Insert \(+\) or \(-\) in each box to make the equation true. a) \((\square14)+(-26)=-40\) b) \((-55)-(\square25)=-30\) c) \((+12)+(\square18)=-6\)

Hints

- Determine whether each unknown number must be positive or negative. - Subtracting a negative number increases the value. - Substitute each possible sign and verify the equation.

Solution

1. In a), \(-14+(-26)=-40\), so the sign is \(-\). 2. In b), \(-55-(-25)=-30\), so the sign is \(-\). 3. In c), \(12+(-18)=-6\), so the sign is \(-\).

Answer

a) \(-\) b) \(-\) c) \(-\)
Add and subtract rational numbers 98
A research submarine is \(85\,\text{m}\) below sea level. It descends another \(40\,\text{m}\). Give its new position relative to sea level as an integer.

Hints

- How do you represent a position below sea level with a signed number? - Does descending make the position greater or less? - Is the submarine moving closer to or farther from sea level?

Solution

1. Represent the initial position as \(-85\). 2. A descent of \(40\,\text{m}\) means subtracting \(40\): \(-85-40=-125\).

Answer

The new position is \(-125\), or \(125\,\text{m}\) below sea level.
Add and subtract rational numbers 99
Evaluate each difference. First rewrite the subtraction as addition of the opposite. a) \((-410)-(+590)\) b) \((+1200)-(-800)\) c) \((-33)-(-33)\) d) \((-75)-(+25)\)

Hints

- To subtract a number, add its opposite. - Pay attention to what happens when a number is subtracted from itself. - Subtracting a positive number from a negative number makes the result more negative.

Solution

1. \((-410)-(+590)=(-410)+(-590)=-1000\). 2. \((+1200)-(-800)=(+1200)+(+800)=2000\). 3. \((-33)-(-33)=(-33)+(+33)=0\). 4. \((-75)-(+25)=(-75)+(-25)=-100\).

Answer

a) \((-410)+(-590)=-1000\) b) \((+1200)+(+800)=2000\) c) \((-33)+(+33)=0\) d) \((-75)+(-25)=-100\)
Add and subtract rational numbers 100
For each value of \(x\), evaluate \((-150)-x\). First rewrite the subtraction as addition. a) \(x=50\) b) \(x=-50\) c) \(x=150\) d) \(x=-200\)

Hints

- Substitute each signed value for \(x\). - To subtract a number, add its opposite. - The result can be positive when a negative number is subtracted.

Solution

1. For \(x=50\), \((-150)-50=(-150)+(-50)=-200\). 2. For \(x=-50\), \((-150)-(-50)=(-150)+50=-100\). 3. For \(x=150\), \((-150)-150=(-150)+(-150)=-300\). 4. For \(x=-200\), \((-150)-(-200)=(-150)+200=50\).

Answer

a) \((-150)+(-50)=-200\) b) \((-150)+50=-100\) c) \((-150)+(-150)=-300\) d) \((-150)+200=50\)
Add and subtract rational numbers 101
Ms. Meyer's checking account balance was \(-\$45\) yesterday. Today, two more debits were posted: a \(\$30\) bill and a \(\$25\) shipping charge. What is her current balance?

Hints

- Do debits increase or decrease an account balance? - On a number line, which direction represents a debit? - Apply the two debits one at a time.

Solution

1. After the first debit, the balance is \(-45-30=-75\). 2. After the second debit, the balance is \(-75-25=-100\).

Answer

Her current balance is \(-\$100\).
Add and subtract rational numbers 102
Find each value. a) Find the sum of \(-42\) and \(-18\). b) Find the difference of \(-25\) and \(35\), with \(-25\) as the starting number.

Hints

- A sum uses addition, while a difference uses subtraction. - Pay close attention to the signs of both numbers. - A number line can help you check the direction of each operation.

Solution

1. In a), \(-42+(-18)=-60\). 2. In b), \(-25-35=-60\).

Answer

a) \(-60\) b) \(-60\)
Add and subtract rational numbers 103
Decide whether each statement is true or false. a) The sum of \(-15\) and \(15\) is \(0\). b) The difference of \(-40\) and \(-10\) is \(-50\). c) The sum of \(-9\) and \(-11\) is \(-20\).

Hints

- Write an expression for each statement. - Subtracting a negative number is the same as adding its opposite. - Compare each calculated value with the value in the statement.

Solution

1. In a), \(-15+15=0\), so the statement is true. 2. In b), \(-40-(-10)=-30\), not \(-50\), so the statement is false. 3. In c), \(-9+(-11)=-20\), so the statement is true.

Answer

a) True b) False c) True
Add and subtract rational numbers 104
A number plus \(-67\) equals \(25\). What is the number?

Hints

- Write an equation with a variable. - Undo the added negative number. - Check the result in the original equation.

Solution

1. Write \(x+(-67)=25\). 2. Undo adding \(-67\) by adding \(67\): \(x=25+67=92\).

Answer

\(92\)
Add and subtract rational numbers 105
Evaluate \((-45)-(-18)+(-32)\).

Hints

- Subtracting a negative number is the same as adding a positive number. - Work from left to right. - At each step, decide whether the value should increase or decrease.

Solution

1. Rewrite the subtraction: \(-45-(-18)=-45+18=-27\). 2. Then add the last term: \(-27+(-32)=-59\).

Answer

\(-59\)
Add and subtract rational numbers 106
Which subtraction expressions have a value of \(-24\)? Write all corresponding letters. A) \(16-40\) B) \(-12-13\) C) \(-30-(-7)\) D) \(0-(-24)\) E) \(-10-14\) F) \(-48-(-24)\)

Hints

- Rewrite subtraction of a negative as addition. - Evaluate each expression separately, even if several results are negative. - Check that each result equals the target value exactly.

Solution

1. A: \(16-40=-24\). 2. B: \(-12-13=-25\). 3. C: \(-30-(-7)=-30+7=-23\). 4. D: \(0-(-24)=24\). 5. E: \(-10-14=-24\). 6. F: \(-48-(-24)=-48+24=-24\).

Answer

A, E, and F
Add and subtract rational numbers 107
First rewrite each expression without parentheses using simplified notation. Then evaluate. a) \((+56)+(-14)\) b) \((-33)-(-17)\) c) \((-120)+(-80)\) d) \((+200)-(+45)\)

Hints

- Distinguish the operation sign from the sign attached to a number. - Adding a negative is subtraction, and subtracting a negative is addition. - A number line can help you check each result.

Solution

1. In a), \(56-14=42\). 2. In b), \(-33+17=-16\). 3. In c), \(-120-80=-200\). 4. In d), \(200-45=155\).

Answer

a) \(56-14=42\) b) \(-33+17=-16\) c) \(-120-80=-200\) d) \(200-45=155\)
Add and subtract rational numbers 108
Rewrite the expression as a sum. Then show an equivalent rearrangement or grouping that makes the calculation efficient before evaluating. \(-140+512-(-40)\)

Hints

- Rewrite subtraction of a negative number as addition of its opposite. - Keep the signs attached to the addends when changing their order. - Look for a pair that is simpler to combine before adding the remaining term.

Solution

1. Rewrite subtraction of a negative as addition: \(-140+512+40\). 2. Rearrange and group: \((-140+40)+512\). 3. Evaluate: \(-100+512=412\).

Answer

Sum form: \(-140+512+40\) One valid efficient regrouping: \((-140+40)+512\) Value: \(412\)
Add and subtract rational numbers 109
Rewrite the expression as a sum. Then show an equivalent rearrangement or grouping that makes the calculation efficient before evaluating. \(385-119+615\)

Hints

- Rewrite subtraction as addition of the opposite. - Keep each sign attached to its addend when rearranging. - Look for a pair whose sum is especially convenient before using the remaining addend.

Solution

1. Rewrite subtraction as addition of the opposite: \(385+(-119)+615\). 2. Rearrange and group: \((385+615)+(-119)\). 3. Evaluate: \(1000-119=881\).

Answer

Sum form: \(385+(-119)+615\) One valid efficient regrouping: \((385+615)+(-119)\) Value: \(881\)
Add and subtract rational numbers 110
Evaluate the expressions. Then group the expressions that have equal values. a) \(24-37\) b) \(37-24\) c) \(-(37-24)\) d) \(-24+37\) e) \(-24-(-37)\) f) \(-37+24\)

Hints

- Evaluate each expression separately. - A negative sign outside parentheses takes the opposite of the parenthetical value. - Subtracting a negative number is the same as adding a positive number.

Solution

1. The values are: a) \(-13\), b) \(13\), c) \(-13\), d) \(13\), e) \(13\), and f) \(-13\). 2. Therefore, a), c), and f) have value \(-13\), while b), d), and e) have value \(13\).

Answer

Value \(-13\): a), c), f) Value \(13\): b), d), e)
Add and subtract rational numbers 111
Rewrite without parentheses using simplified notation, and then evaluate: \((-432)-(-218)\).

Hints

- What number would undo subtracting a negative amount? - Check whether your rewritten expression is greater or smaller than \(-432\). - Compare distances from zero to decide the sign of the result.

Solution

1. Rewrite the subtraction: \(-432+218\). 2. The difference between the absolute values is \(432-218=214\). 3. Since \(432\) has the greater absolute value and is negative, the result is \(-214\).

Answer

\(-432+218=-214\)
Add and subtract rational numbers 112
Rewrite without parentheses using simplified notation, and then evaluate: \((+675)+(-280)-(+145)\).

Hints

- Rewrite each signed number without parentheses. - You may add the two amounts being subtracted before subtracting their total. - Keep careful track of each operation sign.

Solution

1. Rewrite the expression as \(675-280-145\). 2. Evaluate: \(675-280=395\), and \(395-145=250\).

Answer

\(675-280-145=250\)
Add and subtract rational numbers 113
Rewrite each expression as a sum by replacing subtraction with addition of the opposite. Then evaluate. a) \(-215-(-45)-30\) b) \(-128-72+100\)

Hints

- To subtract a number, add its opposite. - The opposite of a positive number is negative, and the opposite of a negative number is positive. - Group addends with the same sign when that makes the calculation easier.

Solution

1. In a), \((-215)+45+(-30)=-170-30=-200\). 2. In b), \((-128)+(-72)+100=-200+100=-100\).

Answer

a) \((-215)+45+(-30)=-200\) b) \((-128)+(-72)+100=-100\)
Add and subtract rational numbers 114
Rewrite each expression using addition only, and then evaluate. a) \(440-600-(-160)\) b) \(-19-(-81)-100\)

Hints

- Rewrite each subtraction as addition of the opposite. - A subtraction sign before a positive number becomes addition of a negative number. - Opposites add to zero.

Solution

1. In a), \(440+(-600)+160=-160+160=0\). 2. In b), \((-19)+81+(-100)=62-100=-38\).

Answer

a) \(440+(-600)+160=0\) b) \((-19)+81+(-100)=-38\)
Add and subtract rational numbers 115
Evaluate \(48+(52-315)\).

Hints

- Use the order of operations and evaluate the parentheses first. - Adding a negative number is the same as subtracting its absolute value. - Keep track of the sign of the intermediate result.

Solution

1. Evaluate inside the parentheses: \(52-315=-263\). 2. Add the result: \(48+(-263)=-215\).

Answer

\(-215\)
Add and subtract rational numbers 116
Which expressions have equal values? Group expressions with the same value, and give that value. A: \(45-(-5)\) B: \(45+5\) C: \(45+(-5)\) D: \(45-5\) E: \(50-0\) F: \(50-10\)

Hints

- Evaluate each expression separately. - Pay close attention to addition or subtraction of a negative number. - Group the letters after comparing all results.

Solution

1. A, B, and E each have value \(50\): \(45-(-5)=50\), \(45+5=50\), and \(50-0=50\). 2. C, D, and F each have value \(40\): \(45+(-5)=40\), \(45-5=40\), and \(50-10=40\).

Answer

Value \(50\): A, B, E Value \(40\): C, D, F
Add and subtract rational numbers 117
Evaluate each expression. a) \(-2500+100{,}500\) b) \(-340{,}000-12{,}500\) c) \(50{,}200+(-45{,}200)\) d) \(12{,}300-(-7700)\)

Hints

- Decide whether each result should be positive or negative before calculating. - Adding a negative is subtraction, and subtracting a negative is addition. - Align place values carefully when working with large integers.

Solution

1. In a), \(100{,}500-2500=98{,}000\). 2. In b), \(-340{,}000-12{,}500=-352{,}500\). 3. In c), \(50{,}200-45{,}200=5000\). 4. In d), \(12{,}300+7700=20{,}000\).

Answer

a) \(98{,}000\) b) \(-352{,}500\) c) \(5000\) d) \(20{,}000\)
Add and subtract rational numbers 118
Consider the expression \((560 - 140) + (320 + 180)\). Without fully evaluating the new expression, determine how its value changes if each of the four numbers is increased by \(15\). Explain your reasoning from the structure of the expression.

Hints

- Analyze each set of parentheses separately. - What happens to a difference when both numbers increase by the same amount? - What happens to a sum when both addends increase by \(15\)?

Solution

1. In \(560 - 140\), increasing both numbers by \(15\) does not change the difference. 2. In \(320 + 180\), increasing both addends by \(15\) increases the sum by \(15 + 15 = 30\). 3. Therefore, the value of the entire expression increases by \(30\). The original value is \(920\), and the new value is \(950\).

Answer

The value increases by \(30\).
Add and subtract rational numbers 119
Consider the expression \((1200 + 800) - (600 - 200)\). Determine how its value changes if each of the four numbers is increased by \(25\). Explain your reasoning from the structure of the expression.

Hints

- Determine how the first set of parentheses changes. - Determine how the second set of parentheses changes. - Use those two changes to determine the change in the entire expression.

Solution

1. Increasing both addends in \(1200 + 800\) by \(25\) increases that sum by \(50\). 2. Increasing both numbers in \(600 - 200\) by \(25\) leaves that difference unchanged. 3. Therefore, the value of the entire expression increases by \(50\). The original value is \(1600\), and the new value is \(1650\).

Answer

The value increases by \(50\).
Add and subtract rational numbers 120
At an Arctic weather station, the outdoor temperature is \(-46\,^\circ\text{C}\) early in the morning. By noon, it has risen to \(-19\,^\circ\text{C}\). By how many degrees Celsius did the temperature increase?

Hints

- Picture the temperatures on a vertical number line. - Did the temperature increase or decrease? - How can you find the distance between the two values?

Solution

1. Subtract the initial temperature from the final temperature: \(-19-(-46)\). 2. Calculate: \(-19+46=27\).

Answer

The temperature increased by \(27\,^\circ\text{C}\).
Add and subtract rational numbers 121
An unmanned research submarine is at \(-780\,\text{m}\) relative to sea level. It must rise to a maintenance station at \(-125\,\text{m}\). How many meters must the submarine rise?

Hints

- What does \(0\) represent in this situation? - Sketch the two positions on a vertical number line. - Which operation finds the change from the starting position to the ending position?

Solution

1. Find the change from the starting position to the ending position: \(-125-(-780)\). 2. Calculate: \(-125+780=655\).

Answer

The submarine must rise \(655\,\text{m}\).
Add and subtract rational numbers 122
Solve for \(x\). a) \(x+85=42\) b) \(-14+x=36\) c) \(x-55=-19\) d) \(-72+x=-110\)

Hints

- Undo the operation applied to \(x\). - Subtract a known addend to find the missing one. - Check each solution by substitution.

Solution

1. In part a), \(x=42-85=-43\). 2. In part b), \(x=36-(-14)=50\). 3. In part c), \(x=-19+55=36\). 4. In part d), \(x=-110-(-72)=-38\).

Answer

a) \(x=-43\) b) \(x=50\) c) \(x=36\) d) \(x=-38\)
Add and subtract rational numbers 123
Evaluate each expression. a) \(72-115+43\) b) \(-56+88-32\) c) \(105-(-45)-200\)

Hints

- Work from left to right. - Distinguish signs attached to numbers from operation signs. - Subtracting a negative number is the same as adding a positive number.

Solution

1. In a), \(72-115=-43\), and \(-43+43=0\). 2. In b), \(-56+88=32\), and \(32-32=0\). 3. In c), \(105-(-45)-200=105+45-200=-50\).

Answer

a) \(0\) b) \(0\) c) \(-50\)
Add and subtract rational numbers 124
Evaluate \(88-(112-45)\).

Hints

- Use the order of operations. - Evaluate the parentheses first, and then subtract that result from \(88\).

Solution

1. Evaluate inside the parentheses: \(112-45=67\). 2. Subtract the result: \(88-67=21\).

Answer

\(21\)
Add and subtract rational numbers 125
Evaluate \(-135-(62-140)\).

Hints

- Evaluate the parentheses first. - Subtracting a negative number becomes addition. - Compare the absolute values to determine the sign of the final sum.

Solution

1. Evaluate inside the parentheses: \(62-140=-78\). 2. Substitute the result: \(-135-(-78)=-135+78\). 3. Evaluate: \(-135+78=-57\).

Answer

\(-57\)
Add and subtract rational numbers 126
Evaluate \(-135+48+35-18\) by regrouping efficiently.

Hints

- Look for pairs that make convenient tens or hundreds. - Keep each sign attached to its number when reordering. - Add the partial sums last.

Solution

1. Regroup as \((-135+35)+(48-18)\). 2. The partial sums are \(-100\) and \(30\). 3. Therefore, the value is \(-100+30=-70\).

Answer

\((-135+35)+(48-18)=-70\)
Add and subtract rational numbers 127
Simplify the operation signs and signs attached to numbers, and then evaluate: \(-12-(-18)+(-25)\).

Hints

- What operation reverses subtracting a negative number? - Compare \(+(-25)\) with subtracting \(25\). - Check your sign changes before adding the numbers.

Solution

1. Rewrite the expression as \(-12+18-25\). 2. Evaluate: \(-12+18=6\), and \(6-25=-19\).

Answer

\(-12+18-25=-19\)
Add and subtract rational numbers 128
Imagine moving on a number line. Subtracting a positive number means moving left. Write and evaluate the subtraction for each situation. a) Start at \(20\) and subtract \(55\). b) Start at \(-15\) and subtract \(30\).

Hints

- Subtracting a positive number moves left on a number line. - You can first move to zero and then count the remaining distance. - Starting negative and subtracting a positive number makes the result more negative.

Solution

1. In a), move \(55\) units left from \(20\): \(20-55=-35\). 2. In b), move \(30\) units left from \(-15\): \(-15-30=-45\).

Answer

a) \(20-55=-35\) b) \(-15-30=-45\)
Add and subtract rational numbers 129
Evaluate each expression. a) \((-75)+(-25)\) b) \((-75)-(-25)\) c) \(75+(-25)\) d) \(75-(-25)\)

Hints

- Adding a negative number is the same as subtraction. - Subtracting a negative number is the same as addition. - Use a number line to check whether each value moves left or right.

Solution

1. In a), \(-75+(-25)=-100\). 2. In b), \(-75-(-25)=-75+25=-50\). 3. In c), \(75+(-25)=50\). 4. In d), \(75-(-25)=75+25=100\).

Answer

a) \(-100\) b) \(-50\) c) \(50\) d) \(100\)
Add and subtract rational numbers 130
Find the missing value in each addition equation. a) \(-18+30=\square\) b) \(\square+(-12)=-20\) c) \(-45+\square=-15\)

Hints

- Write an addition equation for each part. - Use subtraction to find a missing addend. - Check each completed equation.

Solution

1. In a), \(-18+30=12\). 2. In b), \(A+(-12)=-20\), so \(A=-20-(-12)=-8\). 3. In c), \(-45+B=-15\), so \(B=-15-(-45)=30\).

Answer

a) \(12\) b) \(-8\) c) \(30\)
Add and subtract rational numbers 131
Rewrite subtraction as addition of the opposite. Then use the commutative and associative properties to show a grouping that creates \(100\), and evaluate. \(47 - 19 + 53\)

Hints

- First express every operation as addition of a signed number. - Which two positive addends form a convenient benchmark number? - Show the property-based rewrite in the answer.

Solution

1. Rewrite: \(47+(-19)+53\). 2. Reorder and regroup: \((47+53)+(-19)\). 3. Evaluate: \(100-19=81\).

Answer

\(47+(-19)+53=(47+53)+(-19)=100-19=81\)
Add and subtract rational numbers 132
A coastal research team measures heights above sea level as positive and depths below it as negative. a) Its submarine is at \(-250\,\text{m}\) and rises \(85\,\text{m}\). What is its new position? b) Its weather balloon is at \(+1850\,\text{m}\) and descends \(240\,\text{m}\). What is its new position? c) A research diver is at \(-15\,\text{m}\) and descends another \(10\,\text{m}\). What is the new position? d) A seabird is at \(+12\,\text{m}\), and a fish is at \(-8\,\text{m}\). What signed change takes you from the bird's position to the fish's position?

Hints

- A rise increases the signed position even when the starting position is negative. - A descent decreases the signed position. - For a signed change from one position to another, compare the ending position with the starting position.

Solution

1. The submarine rises, so its new position is \(-250+85=-165\,\text{m}\). 2. The weather balloon descends, so its new position is \(1850-240=1610\,\text{m}\). 3. The diver descends farther: \(-15-10=-25\,\text{m}\). 4. Subtract the starting position from the ending position: \(-8-(+12)=-20\,\text{m}\). The change is downward.

Answer

a) \(-165\,\text{m}\) b) \(1610\,\text{m}\) c) \(-25\,\text{m}\) d) \(-20\,\text{m}\)
Add and subtract rational numbers 133
A parking garage labels street level as Level \(0\). Levels below street level are negative, and levels above street level are positive. a) A car is parked on Level \(-3\). Describe its location. b) A visitor parks on Level \(-1\) and takes the elevator up \(4\) levels. On which level does the visitor exit? c) Later, the visitor rides directly from that level to Level \(-2\). Represent the elevator's change in level with a signed number.

Hints

- Picture the levels on a vertical number line. - Moving up is a positive change, and moving down is a negative change. - Count the change from Level \(3\) through Level \(0\) to Level \(-2\).

Solution

1. Level \(-3\) is \(3\) levels below street level. 2. Moving up \(4\) levels gives \(-1+4=3\), so the visitor exits on Level \(3\). 3. The change from Level \(3\) to Level \(-2\) is \(-2-3=-5\), representing a trip down \(5\) levels.

Answer

a) The car is \(3\) levels below street level. b) The visitor exits on Level \(3\). c) The change is \(-5\), meaning \(5\) levels down.
Add and subtract rational numbers 134
A mountain weather station tracks temperature changes during the day. In the morning, the temperature rises by \(x\,^{\circ}\text{C}\). In the afternoon, it falls by \(y\,^{\circ}\text{C}\). a) Write an expression for the net temperature change. b) Find the net change on each day. 1) Day 1: \(x=5.4\), \(y=3.1\) 2) Day 2: \(x=2.8\), \(y=4.5\) c) Explain what the sign of each result means.

Hints

- Think about the direction of each change on a thermometer. - Subtract the amount of the decrease from the amount of the increase. - Interpret a negative result as an overall drop.

Solution

1. The net change is the increase minus the decrease: \(x-y\). 2. Day 1: \(5.4-3.1=2.3\), so the temperature rises by \(2.3\,^{\circ}\text{C}\) overall. 3. Day 2: \(2.8-4.5=-1.7\), so the temperature falls by \(1.7\,^{\circ}\text{C}\) overall. 4. A positive result indicates a net warming, and a negative result indicates a net cooling.

Answer

a) \(x-y\) b) Day 1: \(2.3\,^{\circ}\text{C}\); Day 2: \(-1.7\,^{\circ}\text{C}\) c) A positive value means the day ends warmer than it began; a negative value means it ends cooler.
Add and subtract rational numbers 135
A class fund starts the month with some savings. During the month, it earns \(\$e\) from a bake sale and spends \(\$a\) on art supplies. a) Write an expression for the change in the fund balance. b) Find the change when \(e=54\) and \(a=38\). Explain the result. c) Find the change when \(e=25\) and \(a=42\). Compare the ending balance with the starting balance.

Hints

- Income adds to the fund, while spending removes money. - If spending is greater than income, the change is negative. - A positive value represents an increase; a negative value represents a decrease.

Solution

1. The change is income minus spending: \(e-a\). 2. For \(e=54\) and \(a=38\), \(54-38=16\). The balance increases by \(\$16\). 3. For \(e=25\) and \(a=42\), \(25-42=-17\). The balance ends \(\$17\) lower than it began.

Answer

a) \(e-a\) b) \(\$16\); the balance increases by \(\$16\). c) \(-\$17\); the ending balance is \(\$17\) less than the starting balance.
Add and subtract rational numbers 136
A reservoir helps regulate a river. Each hour, \(z\,\text{m}^3\) of water flows into the reservoir, and \(a\,\text{m}^3\) flows out through the gates. a) Write an expression for the change in water volume after one hour. b) What does a value of \(0\) mean in this context? c) What does a negative value mean? d) Find the hourly change when \(z=1250\) and \(a=1310\).

Hints

- Think of a container with both an inlet and an outlet. - The level stays constant when inflow equals outflow. - The volume decreases when more water leaves than enters.

Solution

1. The net change is inflow minus outflow: \(z-a\). 2. If \(z-a=0\), inflow equals outflow, so the water volume stays constant. 3. If \(z-a<0\), outflow exceeds inflow, so the water volume decreases. 4. For \(z=1250\) and \(a=1310\), \(1250-1310=-60\). The volume decreases by \(60\,\text{m}^3\) per hour.

Answer

a) \(z-a\) b) The water volume remains constant. c) The reservoir's water volume is decreasing. d) \(-60\,\text{m}^3\) per hour
Add and subtract rational numbers 137
Tim is saving for a skateboard that costs \(\$85\). He has already saved \(\$y\). a) Write an expression for the signed difference “price minus savings.” b) Evaluate the expression for \(y=62\) and for \(y=90\). Explain what each result means.

Hints

- Consider what happens when the savings exceed the price. - Start by imagining a specific savings amount below \(85\). - Interpret the sign of the result in the context.

Solution

1. The signed difference is \(85-y\). 2. For \(y=62\), \(85-62=23\). Tim still needs \(\$23\). 3. For \(y=90\), \(85-90=-5\). Tim has saved \(\$5\) more than the price.

Answer

a) \(85-y\) b) For \(y=62\): \(23\), so Tim needs \(\$23\) more. For \(y=90\): \(-5\), so Tim has \(\$5\) extra.
Add and subtract rational numbers 138
A hiker is at an elevation of \(h\) feet. The destination lodge is at an elevation of \(4000\) feet. a) Write an expression for the signed elevation difference “destination elevation minus current elevation.” b) Evaluate the difference for \(h=3200\) and for \(h=4500\). Interpret each result as an uphill or downhill change.

Hints

- Picture elevation on a vertical number line. - A destination above the current elevation gives a positive difference. - A negative result indicates that the destination is below the current elevation.

Solution

1. The signed elevation difference is \(4000-h\). 2. For \(h=3200\), \(4000-3200=800\). The hiker must climb \(800\) feet. 3. For \(h=4500\), \(4000-4500=-500\). The hiker is \(500\) feet above the lodge and must descend \(500\) feet.

Answer

a) \(4000-h\) b) For \(h=3200\): \(800\) feet uphill. For \(h=4500\): \(-500\) feet, meaning \(500\) feet downhill.
Add and subtract rational numbers 139
A bank account has a current balance of \(\$x\). A bill of \(\$y\) is withdrawn. a) Write an expression for the new account balance. b) Find the balance when \(x=125\) and \(y=40\). c) Find the balance when \(x=50\) and \(y=85\). Explain what a negative result means for the account holder.

Hints

- A withdrawal decreases the account balance. - Spending more than the current balance produces a negative result.

Solution

1. Subtract the withdrawal from the current balance: \(x-y\). 2. For \(x=125\) and \(y=40\), \(125-40=85\). 3. For \(x=50\) and \(y=85\), \(50-85=-35\). 4. A negative balance means the account is overdrawn by that amount.

Answer

a) \(x-y\) b) \(\$85\) c) \(-\$35\); the account is overdrawn by \(\$35\).
Add and subtract rational numbers 140
Evaluate by rearranging and grouping the addends. Show the reordered expression, the two grouped partial sums, and the final value. \(17.4 + (-5.9) + 2.6 + (-4.1)\) Which property allows you to change the order of the addends?

Hints

- Look for decimal pairs whose sum is a whole number. - Separate changing the order from changing the grouping. - The answer must show both the reordered expression and the resulting groups.

Solution

1. Reorder: \(17.4+2.6+(-5.9)+(-4.1)\). 2. Group: \((17.4+2.6)+((-5.9)+(-4.1))\). 3. The partial sums are \(20\) and \(-10\), so the final value is \(10\). 4. The commutative property of addition allows the order to change.

Answer

Reordered expression: \(17.4+2.6+(-5.9)+(-4.1)\) Grouped expression: \((17.4+2.6)+((-5.9)+(-4.1))\) Partial sums: \(20\) and \(-10\) Final value: \(10\) Property: commutative property of addition
Add and subtract rational numbers 141
Find each sum of rational numbers. 1) \((-17)+(+25)+(-13)\) 2) \((+4.8)+(-6.3)+(-2.5)\) 3) \(\left(-\frac{3}{10}\right)+0.75\) 4) \(\left(-2 \frac{1}{4}\right)+\left(-1 \frac{5}{8}\right)\)

Hints

- Pay close attention to signs when adding rational numbers. - You can combine several addends step by step. - When fractions and decimals appear together, convert them to a common form if that makes the calculation easier. - Fractions need a common denominator before they can be added.

Solution

1. For 1), \(-17+25=8\), then \(8+(-13)=-5\). 2. For 2), \(4.8+(-6.3)=-1.5\), then \(-1.5+(-2.5)=-4\). 3. For 3), \(-\frac{3}{10}=-0.3\), so \(-0.3+0.75=0.45\). Equivalently, \(-\frac{6}{20}+\frac{15}{20}=\frac{9}{20}\). 4. For 4), write the mixed numbers with denominator \(8\): \(-2 \frac{2}{8}+\left(-1 \frac{5}{8}\right)=-3 \frac{7}{8}\).

Answer

1) \(-5\) 2) \(-4\) 3) \(0.45\), or \(\frac{9}{20}\) 4) \(-3 \frac{7}{8}\)
Add and subtract rational numbers 142
For each pair of values, find \(c\) so that \(a+b+c=0\). a) \(a=-8.5\), \(b=3\frac{1}{4}\) b) \(a=\frac{2}{3}\), \(b=-\frac{1}{6}\) c) \(a=15.7\), \(b=-20\)

Hints

- First find \(a+b\). - The total is zero when \(c\) is the opposite of \(a+b\). - Use a common denominator when adding or subtracting fractions.

Solution

1. For a), \(a+b=-8.5+3.25=-5.25\). The opposite of \(-5.25\) is \(5.25\), so \(c=5.25\). 2. For b), \(a+b=\frac{2}{3}-\frac{1}{6}=\frac{4}{6}-\frac{1}{6}=\frac{1}{2}\). Its opposite is \(-\frac{1}{2}\), so \(c=-\frac{1}{2}\). 3. For c), \(a+b=15.7-20=-4.3\). Its opposite is \(4.3\), so \(c=4.3\).

Answer

a) \(c=5.25\) b) \(c=-\frac{1}{2}\) c) \(c=4.3\)
Add and subtract rational numbers 143
A weather station records morning and noon temperatures. Calculate each temperature change as \(\text{noon temperature}-\text{morning temperature}\), and enter a positive number, a negative number, or zero in the table. <table> <thead> <tr> <th>Day</th> <th>Morning temperature</th> <th>Noon temperature</th> <th>Temperature change</th> </tr> </thead> <tbody> <tr> <td>Monday</td> <td>\(+2\,^\circ\text{C}\)</td> <td>\(-3\,^\circ\text{C}\)</td> <td></td> </tr> <tr> <td>Tuesday</td> <td>\(-5\,^\circ\text{C}\)</td> <td>\(+1\,^\circ\text{C}\)</td> <td></td> </tr> <tr> <td>Wednesday</td> <td>\(-4\,^\circ\text{C}\)</td> <td>\(-4\,^\circ\text{C}\)</td> <td></td> </tr> <tr> <td>Thursday</td> <td>\(0\,^\circ\text{C}\)</td> <td>\(-6\,^\circ\text{C}\)</td> <td></td> </tr> </tbody> </table>

Hints

- Decide whether each temperature became warmer or colder. - A decrease is represented by a negative change. - An increase is represented by a positive change. - No change is represented by zero.

Solution

1. Monday: \(-3-2=-5\,^\circ\text{C}\). 2. Tuesday: \(1-(-5)=+6\,^\circ\text{C}\). 3. Wednesday: \(-4-(-4)=0\,^\circ\text{C}\). 4. Thursday: \(-6-0=-6\,^\circ\text{C}\).

Answer

Monday: \(-5\,^\circ\text{C}\) Tuesday: \(+6\,^\circ\text{C}\) Wednesday: \(0\,^\circ\text{C}\) Thursday: \(-6\,^\circ\text{C}\)
Add and subtract rational numbers 144
Evaluate each expression. 1) \((-18)-(+12)-(-20)\) 2) \((-5.4)-(-2.6)-(+1.2)\) 3) \((+3.7)-(+8.7)-(-5)\)

Hints

- What happens to the sign of a number in parentheses when a minus sign is directly before it? - Can you rewrite subtraction as addition of the opposite? - After rewriting, work from left to right. - Keep decimal place values aligned and track the signs at each step.

Solution

1. For 1), rewrite subtraction of a negative as addition: \(-18-12+20=-30+20=-10\). 2. For 2), \(-5.4-(-2.6)-1.2=-5.4+2.6-1.2=-2.8-1.2=-4\). 3. For 3), \(3.7-8.7-(-5)=3.7-8.7+5=-5+5=0\).

Answer

1) \(-10\) 2) \(-4\) 3) \(0\)
Add and subtract rational numbers 145
For each sum, write the grouping that creates an additive inverse or a whole-number partial sum, then evaluate. 1) \((-34) + 57 + 34\) 2) \(12.4 + (-6.8) + (-3.2)\) 3) \(-2\frac{1}{5} + 8 - 1\frac{4}{5}\)

Hints

- Search for opposites or terms that combine to an integer. - Keep each sign with its term when grouping. - Include the grouping that makes the arithmetic short.

Solution

1. \((-34+34)+57=57\). 2. \(12.4+(-6.8-3.2)=12.4-10=2.4\). 3. \(\left(-2\frac{1}{5}-1\frac{4}{5}\right)+8=-4+8=4\).

Answer

1) \((-34+34)+57=57\) 2) \(12.4+(-6.8-3.2)=2.4\) 3) \(\left(-2\frac{1}{5}-1\frac{4}{5}\right)+8=4\)
Add and subtract rational numbers 146
Calculate \(x-y\) for each pair. a) \(x=-2.4\), \(y=5.6\) b) \(x=\frac{3}{5}\), \(y=-\frac{7}{10}\) c) \(x=-1\frac{1}{2}\), \(y=-2\frac{1}{4}\) d) \(x=-0.75\), \(y=0.75\)

Hints

- Subtracting a negative number is the same as adding its opposite. - Use a common denominator before subtracting fractions. - For decimal differences, think about the expected sign before calculating.

Solution

1. For a), \(x-y=-2.4-5.6=-8.0\). 2. For b), \(x-y=\frac{3}{5}-\left(-\frac{7}{10}\right)=\frac{6}{10}+\frac{7}{10}=\frac{13}{10}=1\frac{3}{10}\). 3. For c), \(x-y=-1\frac{1}{2}-\left(-2\frac{1}{4}\right)=-\frac{6}{4}+\frac{9}{4}=\frac{3}{4}\). 4. For d), \(x-y=-0.75-0.75=-1.5\).

Answer

a) \(-8.0\) b) \(1\frac{3}{10}\), or \(1.3\) c) \(\frac{3}{4}\), or \(0.75\) d) \(-1.5\)
Add and subtract rational numbers 147
The number lines show integer jumps. Find the missing numbers in each part.
Figure for problem 531913

Hints

- A positive jump goes right, and a negative jump goes left. - To find a missing start, undo the jump from the ending value. - For multiple jumps, find each landing in order.

Solution

1. In a), \(-24+35=11\). 2. In b), the starting value satisfies \(x+(-42)=-15\), so \(x=-15-(-42)=27\). 3. In c), \(15+(-23)=-8\), and then \(-8+12=4\).

Answer

a) \(11\) b) \(27\) c) First value: \(-8\); second value: \(4\)
Add and subtract rational numbers 148
The number lines show integer jumps. Find the number in the box in each part. a) Find the ending value. b) Find the starting value. c) Find the missing intermediate value.
Figure for problem 531915

Hints

- Positive jumps move right. - To find a missing start, subtract the jump from the ending value. - For multiple jumps, calculate the first landing before the next jump.

Solution

1. In a), \(-14+32=18\). 2. In b), the starting value satisfies \(x+45=15\), so \(x=15-45=-30\). 3. In c), \(-28+18=-10\). The check \(-10+22=12\) matches the shown ending value.

Answer

a) \(18\) b) \(-30\) c) \(-10\)
Add and subtract rational numbers 149
Find the number in the box on each number line.
Figure for problem 531937

Hints

- Follow the direction and signed size of each jump. - Add the jump when the ending value is missing. - Subtract the jump when the starting value is missing.

Solution

1. In a), \(-15+(-18)=-33\). 2. In b), \(x+(-24)=-32\), so \(x=-32-(-24)=-8\). 3. In c), \(-45+60=15\). 4. In d), \(x+(-35)=-23\), so \(x=-23-(-35)=12\).

Answer

a) \(-33\) b) \(-8\) c) \(15\) d) \(12\)
Add and subtract rational numbers 150
A school snack stand tracks its monthly finances. The bar chart shows the profit (positive values) or loss (negative values), in dollars, for the first six months of the year. a) Find the total profit or loss after the six months. b) Were there more months with a profit or more months with a loss?
Figure for problem 535045

Hints

- Treat profits as positive values and losses as negative values. - Use the zero line to tell whether each month shows a profit or a loss. - Count the bars above zero and compare that count with the bars below zero.

Solution

1. Read the monthly values from the chart: Jan. \(\$35\), Feb. \(-\$20\), Mar. \(\$55\), Apr. \(-\$45\), May \(\$90\), and Jun. \(\$35\). 2. For a), add the signed values: \(35-20+55-45+90+35=150\). The six-month total is a profit of \(\$150\). 3. For b), four months have positive values and two months have negative values, so there were more months with a profit.

Answer

a) A profit of \(\$150\) b) More months had a profit: \(4\) profit months and \(2\) loss months.
Add and subtract rational numbers 151
Find each ending value on the number lines. Write an addition equation for each jump.
Figure for problem 535153

Hints

- Identify the starting value. - A rightward jump is positive, and a leftward jump is negative. - Add the signed jump to the start.

Solution

1. In a), \(15+(-22)=-7\). 2. In b), \(-12+18=6\). 3. In c), \(-10+(-15)=-25\).

Answer

a) \(15+(-22)=-7\) b) \(-12+18=6\) c) \(-10+(-15)=-25\)
Add and subtract rational numbers 152
Find each missing value on the number lines.
Figure for problem 535169

Hints

- Add the jump when the ending value is unknown. - Use the inverse operation when the starting value is unknown. - Check the direction of each signed jump.

Solution

1. In a), \(-125+75=-50\). 2. In b), \(240+(-380)=-140\). 3. In c), \(x+(-150)=-400\), so \(x=-250\). 4. In d), \(x+220=50\), so \(x=-170\).

Answer

a) \(-50\) b) \(-140\) c) \(-250\) d) \(-170\)
Add and subtract rational numbers 153
Find the missing ending value for each negative jump.
Figure for problem 535189

Hints

- Read the signed size printed on each jump. - A negative jump moves left from the displayed starting value. - Combine the starting value with the signed jump to find the landing.

Solution

1. a) \(20+(-45)=-25\). 2. b) \(12+(-30)=-18\). 3. c) \(5+(-15)=-10\).

Answer

a) \(-25\) b) \(-18\) c) \(-10\)
Add and subtract rational numbers 154
Use the number line to find the missing ending value.
Figure for problem 535254

Hints

- Read the starting value and signed jump from the diagram. - Combine the signed jump with the start to locate the landing.

Solution

1. The diagram starts at \(-42\) and shows a jump of \(+65\). 2. \(-42+65=23\).

Answer

\(23\)
Add and subtract rational numbers 155
The number line shows the peak elevation and the vertical distance from the base to the peak of an underwater mountain. How deep is the base of the mountain below sea level?
Figure for problem 535257

Hints

- Read the peak elevation and the mountain's vertical height from the number line. - The base is lower than the peak, so represent the change with subtraction. - Report depth as a positive distance below sea level.

Solution

1. The number line shows the peak at \(-50\,\text{m}\). 2. The base is \(2600\,\text{m}\) lower, so its elevation is \(-50-2600=-2650\,\text{m}\). 3. Therefore, the base is \(2650\,\text{m}\) below sea level.

Answer

The base is \(2650\,\text{m}\) below sea level.
Add and subtract rational numbers 156
The number-line diagram shows Max’s starting bank account balance and a deposit. What is his new balance?
Figure for problem 535258

Hints

- Read the starting balance from the diagram. - A deposit is represented by a positive jump. - Combine the starting balance with the change shown by the jump.

Solution

1. The diagram shows a starting balance of \(-\$15\) and a positive change of \(\$40\). 2. Add the deposit: \(-15+40=25\).

Answer

His new balance is \(\$25\).
Add and subtract rational numbers 157
The number line shows the change produced by subtracting \(-5\) from the displayed starting value. a) Find the missing ending value. b) Write the subtraction equation represented by the diagram. c) Explain why the move is to the right even though the operation is subtraction.
Figure for problem 554551

Hints

- Read the start and signed jump from the diagram. - Compare the diagram's positive jump with the effect of subtracting a negative number. - Your explanation should connect the subtraction expression to the direction shown.

Solution

1. The displayed start is \(-3\), and the diagram shows a jump of \(+5\). 2. Subtracting \(-5\) is equivalent to adding \(+5\), so \(-3-(-5)=-3+5=2\). 3. Adding a positive value moves right on the number line.

Answer

a) \(2\) b) \(-3-(-5)=2\) c) Subtracting \(-5\) is equivalent to adding \(5\), so the movement is to the right.
Add and subtract rational numbers 158
Point \(A\) is a starting position and point \(B\) is an ending position on the number line. a) Read \(A\) and \(B\) as fractions in simplest form. b) Write the signed change from \(A\) to \(B\) as \(B-A\), and evaluate it. c) Does the sign of the change match the direction of movement? Explain.
Figure for problem 554552

Hints

- Determine the value of one small tick interval from the labeled integers. - Read both coordinates before forming the signed difference. - Relate the sign of \(B-A\) to the direction from the starting point to the ending point.

Solution

1. The ticks divide each unit into eighths, so \(A=-\frac{5}{8}\) and \(B=\frac{1}{4}\). 2. \(B-A=\frac{1}{4}-\left(-\frac{5}{8}\right)=\frac{2}{8}+\frac{5}{8}=\frac{7}{8}\). 3. The change is positive, matching movement to the right from \(A\) to \(B\).

Answer

a) \(A=-\frac{5}{8}\), \(B=\frac{1}{4}\) b) \(B-A=\frac{7}{8}\) c) Yes. The positive change matches movement to the right.
Add and subtract rational numbers 159
Calculate \(0.3-0.85\). Explain why your result is negative.

Hints

- Line up tenths and hundredths before subtracting. - Predict whether the result is above or below zero. - Check that your answer is less than the starting value.

Solution

1. Rewrite \(0.3\) as \(0.30\). 2. \(0.30-0.85=-0.55\). 3. The amount being subtracted is greater than the starting number, so the result is below zero.

Answer

\(-0.55\); \(0.85\) is greater than \(0.30\).
Add and subtract rational numbers 160
Find the missing addend in \(-\frac{1}{4}+x=\frac{3}{8}\). Show how you check it.

Hints

- What could you add to undo the negative quarter? - Use eighths to compare the two fractions. - Put the found value back into the original equation.

Solution

1. Add \(\frac{1}{4}\) to the right side: \(x=\frac{3}{8}+\frac{1}{4}\). 2. \(x=\frac{3}{8}+\frac{2}{8}=\frac{5}{8}\). 3. Check: \(-\frac{1}{4}+\frac{5}{8}=-\frac{2}{8}+\frac{5}{8}=\frac{3}{8}\).

Answer

\(x=\frac{5}{8}\). Check: \(-\frac{1}{4}+\frac{5}{8}=\frac{3}{8}\).
Add and subtract rational numbers 161
Malik writes \(-\frac{1}{3}-\frac{2}{3}=1\). What mistake did he make? Give the correct value.

Hints

- Predict the sign before computing. - Subtracting a positive number makes the result smaller. - Combine thirds without changing the sign.

Solution

1. Subtracting a positive fraction from a negative fraction moves farther below zero; it cannot produce a positive result. 2. \(-\frac{1}{3}-\frac{2}{3}=-\frac{3}{3}=-1\).

Answer

Malik lost the negative sign. The correct result is \(-\frac{1}{3}-\frac{2}{3}=-1\).
Add and subtract rational numbers 162
Calculate \(\frac{7}{8}-\left(-\frac{1}{4}\right)\). Explain why the result must be greater than \(1\), then check it using addition.

Hints

- Think about what subtracting a negative does. - Compare your expected result with the whole-number benchmark. - Use the inverse of the original subtraction to check.

Solution

1. Subtracting a negative gives \(\frac{7}{8}+\frac{1}{4}=\frac{7}{8}+\frac{2}{8}=\frac{9}{8}\). 2. Since \(\frac{7}{8}\) is only \(\frac{1}{8}\) below \(1\), adding \(\frac{2}{8}\) passes \(1\). 3. Check by adding the subtracted number to the result: \(\frac{9}{8}+\left(-\frac{1}{4}\right)=\frac{9}{8}-\frac{2}{8}=\frac{7}{8}\).

Answer

\(\frac{9}{8}=1\frac{1}{8}\), which is above \(1\). Check: \(\frac{9}{8}+\left(-\frac{1}{4}\right)=\frac{7}{8}\).
Add and subtract rational numbers 163
Find the fraction exactly halfway between \(\frac{2}{3}\) and \(\frac{4}{5}\). Write your answer in simplest form.

Hints

- The number halfway between two values is their mean. - Use a common denominator before adding the fractions. - Divide the sum by \(2\).

Solution

1. The midpoint is the mean: \(\frac{\frac{2}{3}+\frac{4}{5}}{2}\). 2. Use a common denominator: \(\frac{2}{3}=\frac{10}{15}\) and \(\frac{4}{5}=\frac{12}{15}\). 3. Add: \(\frac{10}{15}+\frac{12}{15}=\frac{22}{15}\). 4. Divide by \(2\): \(\frac{22}{15}\div2=\frac{22}{15}\cdot\frac{1}{2}=\frac{11}{15}\).

Answer

\(\frac{11}{15}\)
Add and subtract rational numbers 164
Evaluate each expression. Pay attention to signs and grouping symbols. a) \(-18+42-(-15)\) b) \(125-(250-75)\) c) \(-15-[-40+(12-22)]\)

Hints

- Subtracting a negative is equivalent to adding its opposite. - Work from the innermost grouping symbols outward. - Simplify signs before doing the arithmetic when helpful.

Solution

1. For a), \(-18+42-(-15)=-18+42+15=39\). 2. For b), evaluate the parentheses first: \(250-75=175\). Then \(125-175=-50\). 3. For c), \(12-22=-10\), then \(-40+(-10)=-50\), and finally \(-15-(-50)=35\).

Answer

a) \(39\) b) \(-50\) c) \(35\)
Add and subtract rational numbers 165
Compare the structure of expressions \(A\) and \(B\) before calculating. \(A=-15+(30-45)\) \(B=-15+30-45\) 1) Find the value of each expression. 2) What rule about removing parentheses is illustrated here? 3) How would \(B\) need to change if \(A\) were \(-15-(30-45)\) instead?

Hints

- Compare the signs inside the parentheses with the signs after the parentheses are removed. - Think about the difference between a plus sign and a minus sign before parentheses. - State the pattern in your own words.

Solution

1. \(A=-15+(-15)=-30\), and \(B=-15+30-45=-30\). 2. A plus sign before parentheses allows the parentheses to be removed without changing the signs inside. 3. With a minus sign before the parentheses, the signs inside change when the parentheses are removed: \(-15-30+45\).

Answer

1) \(A=-30\), \(B=-30\) 2) A plus sign before parentheses allows the parentheses to be removed without changing the signs inside. 3) \(-15-30+45\)
Add and subtract rational numbers 166
Point \(P\) is at \(-3.4\) on a number line, and point \(Q\) is at \(1.2\). a) Find the number \(m\) exactly halfway between \(P\) and \(Q\). b) Is \(m\) an integer? Is it a rational number? c) List all integers strictly between \(-3.4\) and \(1.2\).

Hints

- Find the midpoint by adding the endpoints and dividing by \(2\). - A terminating decimal can be written as a fraction. - Move from left to right on the number line and record each integer between the endpoints.

Solution

1. Find the midpoint: \(m=\frac{-3.4+1.2}{2}=\frac{-2.2}{2}=-1.1\). 2. The value \(-1.1\) is not an integer. It is rational because \(-1.1=-\frac{11}{10}\). 3. The integers satisfying \(-3.4<z<1.2\) are \(-3, -2, -1, 0, 1\).

Answer

a) \(m=-1.1\) b) \(m\) is not an integer, but it is rational. c) \(-3, -2, -1, 0, 1\)
Add and subtract rational numbers 167
Compare \(\frac{19}{8}\) and \(2.37\). a) Which number is greater? b) Find the decimal exactly halfway between the two numbers.

Hints

- Convert the fraction to a decimal. - Add a trailing zero when comparing \(2.37\) with a number having three decimal places. - The number halfway between two values is their average.

Solution

1. Convert the fraction: \(\frac{19}{8}=2.375\). 2. Compare \(2.375\) and \(2.370\). Therefore, \(\frac{19}{8}>2.37\). 3. Find the midpoint: \(\frac{2.375+2.37}{2}=\frac{4.745}{2}=2.3725\).

Answer

a) \(\frac{19}{8}\) is greater. b) \(2.3725\)
Add and subtract rational numbers 168
Find the number exactly halfway between each pair. a) Between \(\frac{5}{8}\) and \(0.63\). Give the answer as a decimal. b) Between \(0.7\) and \(0.71\). Give the answer as a fraction in simplest form.

Hints

- The number exactly halfway between two values is their average. - Convert the fraction in part a) to a decimal. - In part b), use equivalent fractions with a denominator large enough to leave a numerator between the two endpoints.

Solution

1. For a), \(\frac{5}{8}=0.625\). The midpoint is \(\frac{0.625+0.63}{2}=\frac{1.255}{2}=0.6275\). 2. For b), write the endpoints as fractions: \(0.7=\frac{140}{200}\) and \(0.71=\frac{142}{200}\). 3. The fraction halfway between them is \(\frac{141}{200}\), which is already in simplest form.

Answer

a) \(0.6275\) b) \(\frac{141}{200}\)
Add and subtract rational numbers 169
Find the decimal exactly halfway between \(\frac{1}{5}\) and \(\frac{1}{4}\). Then give one decimal greater than \(\frac{1}{5}\) but less than your midpoint.

Hints

- Convert both fractions to decimals. - Find the average of the two endpoint values. - Choose a value strictly between the lower endpoint and the midpoint.

Solution

1. Convert the fractions: \(\frac{1}{5} = 0.2\) and \(\frac{1}{4} = 0.25\). 2. Average the endpoints: \(\frac{0.2 + 0.25}{2} = \frac{0.45}{2} = 0.225\). 3. Any decimal strictly between \(0.2\) and \(0.225\) works, such as \(0.21\).

Answer

The midpoint is \(0.225\). One possible additional decimal is \(0.21\).
Add and subtract rational numbers 170
Let \(x=\frac{5}{8}\) and \(y=0.62\overline{5}\). 1. Compare \(x\) and \(y\) using \(<\), \(>\), or \(=\). 2. Find the rational number \(z\) exactly halfway between \(0.62\) and \(x\). Write \(z\) as a decimal.

Hints

- Put \(x\) and \(y\) into forms that can be compared digit by digit. - For the halfway value, think about what it means for the two distances from \(z\) to be equal. - Check that your proposed \(z\) is the same distance from both endpoints.

Solution

1. Convert \(x\): \(\frac{5}{8}=0.625\). 2. Since \(y=0.62555\ldots\), it follows that \(x<y\). 3. Find the midpoint by averaging: \(z=\frac{0.62+0.625}{2}\). 4. Compute \(z=\frac{1.245}{2}=0.6225\).

Answer

1. \(x<y\) 2. \(z=0.6225\)
Add and subtract rational numbers 171
Find the rational number \(x\) exactly halfway between \(-\frac{1}{2}\) and \(0.3\). Then determine whether \(x\) is greater than or less than \(-\frac{1}{8}\). Justify your comparison.

Hints

- The number halfway between two values is their average. - Convert the fractions and decimals to a common form. - On a number line, the value farther right is greater.

Solution

1. Convert \(-\frac{1}{2}\) to \(-0.5\). 2. Find the midpoint: \(x=\frac{-0.5+0.3}{2}=\frac{-0.2}{2}=-0.1\). 3. Convert the comparison value: \(-\frac{1}{8}=-0.125\). 4. Since \(-0.1>-0.125\), \(x> -\frac{1}{8}\).

Answer

\(x=-0.1\), and \(x> -\frac{1}{8}\).
Add and subtract rational numbers 172
Calculate each expression. Write each answer as a fraction in simplest form or as a mixed number. a) \(1 \frac{3}{8} + \frac{7}{8} - \frac{5}{8}\) b) \(\frac{4}{15} - \left(\frac{7}{15} + \frac{12}{15}\right)\) c) \(2 \frac{1}{12} - \frac{5}{12} - \frac{11}{12}\)

Hints

- How can you rewrite a mixed number before calculating? - Remember to evaluate the expression inside parentheses first. - A subtraction involving fractions can have a negative result. - At the end, simplify the fraction or rewrite an improper fraction as a mixed number when appropriate.

Solution

1. For a), rewrite \(1 \frac{3}{8}\) as \(\frac{11}{8}\). Then \(\frac{11+7-5}{8} = \frac{13}{8} = 1 \frac{5}{8}\). 2. For b), evaluate the parentheses first: \(\frac{7}{15} + \frac{12}{15} = \frac{19}{15}\). Then \(\frac{4}{15} - \frac{19}{15} = -\frac{15}{15} = -1\). 3. For c), rewrite \(2 \frac{1}{12}\) as \(\frac{25}{12}\). Then \(\frac{25-5-11}{12} = \frac{9}{12} = \frac{3}{4}\).

Answer

a) \(1 \frac{5}{8}\) b) \(-1\) c) \(\frac{3}{4}\)
Add and subtract rational numbers 173
Calculate the value of the nested expression: \(\frac{2}{5} - \left(\frac{1}{2} - \left(\frac{3}{10} + \frac{1}{4}\right)\right)\)

Hints

- With nested parentheses, work from the innermost parentheses outward. - Subtracting a negative number is the same as adding its opposite. - Find a useful common denominator at each step.

Solution

1. Start with the innermost parentheses: \(\frac{3}{10} + \frac{1}{4} = \frac{6}{20} + \frac{5}{20} = \frac{11}{20}\). 2. Evaluate the next parentheses: \(\frac{1}{2} - \frac{11}{20} = \frac{10}{20} - \frac{11}{20} = -\frac{1}{20}\). 3. Subtract the negative fraction: \(\frac{2}{5} - \left(-\frac{1}{20}\right) = \frac{2}{5} + \frac{1}{20}\). 4. Use denominator \(20\): \(\frac{8}{20} + \frac{1}{20} = \frac{9}{20}\).

Answer

\(\frac{9}{20}\)
Add and subtract rational numbers 174
Compare the results of calculations \(A\) and \(B\). Insert \(<\), \(>\), or \(=\), and justify your answer with calculations. \(A=5 \frac{1}{3}-2 \frac{1}{2}\) \(B=1 \frac{3}{4}+1 \frac{1}{6}\)

Hints

- Calculate \(A\) and \(B\) separately first. - To compare fractional parts, rewrite them with a common denominator. - When subtracting mixed numbers, check whether you need to regroup one whole.

Solution

1. Calculate \(A\): \(5 \frac{1}{3}-2 \frac{1}{2}=5 \frac{2}{6}-2 \frac{3}{6}=4 \frac{8}{6}-2 \frac{3}{6}=2 \frac{5}{6}\). 2. Calculate \(B\): \(1 \frac{3}{4}+1 \frac{1}{6}=1 \frac{9}{12}+1 \frac{2}{12}=2 \frac{11}{12}\). 3. Rewrite \(A\) with denominator \(12\): \(2 \frac{5}{6}=2 \frac{10}{12}\). Since \(2 \frac{10}{12}<2 \frac{11}{12}\), \(A<B\).

Answer

\(A<B\), because \(A=2 \frac{5}{6}=2 \frac{10}{12}\) and \(B=2 \frac{11}{12}\).
Add and subtract rational numbers 175
Evaluate the expression using the correct order of operations. Write the answer as a mixed number. \(7 \frac{1}{5}-\left(2 \frac{1}{2}+1 \frac{3}{4}\right)+0.8\)

Hints

- Evaluate the expression inside the parentheses first. - Before changing the order of terms, rewrite subtraction in a form that can be regrouped using addition properties. - You can rewrite the decimal as a fraction before calculating.

Solution

1. Evaluate the parentheses: \(2 \frac{1}{2}+1 \frac{3}{4}=2 \frac{2}{4}+1 \frac{3}{4}=4 \frac{1}{4}\). 2. Rewrite \(0.8\) as \(\frac{4}{5}\), and rewrite subtraction as addition of the opposite: \(7 \frac{1}{5}+\left(-4 \frac{1}{4}\right)+\frac{4}{5}\). 3. Use the commutative and associative properties of addition to group the fifths: \(\left(7 \frac{1}{5}+\frac{4}{5}\right)+\left(-4 \frac{1}{4}\right)=8-4 \frac{1}{4}\). 4. Subtract: \(8-4 \frac{1}{4}=3 \frac{3}{4}\).

Answer

\(3 \frac{3}{4}\)
Add and subtract rational numbers 176
Amani writes \(6 \frac{1}{4}-2 \frac{2}{3}=(6-2)+\left(\frac{2}{3}-\frac{1}{4}\right)=4+\left(\frac{8}{12}-\frac{3}{12}\right)=4 \frac{5}{12}\). Explain the error, then calculate the correct result.

Hints

- Check whether the fractional subtraction in the written work keeps the same order as the original expression. - If the fractional part of the first mixed number is smaller, consider how an equivalent regrouping could help. - Verify your corrected result in the original subtraction.

Solution

1. Amani reversed the order of the fractional parts. In the original subtraction, the fractional difference is \(\frac{1}{4}-\frac{2}{3}\), not \(\frac{2}{3}-\frac{1}{4}\). 2. Rewrite with denominator \(12\): \(6 \frac{3}{12}-2 \frac{8}{12}\). 3. Regroup one whole: \(5 \frac{15}{12}-2 \frac{8}{12}=3 \frac{7}{12}\).

Answer

Amani incorrectly reversed \(\frac{1}{4}-\frac{2}{3}\) to \(\frac{2}{3}-\frac{1}{4}\). The correct result is \(3 \frac{7}{12}\).
Add and subtract rational numbers 177
Simplify and remove the parentheses, then write an equivalent expression whose grouping makes the final calculation efficient. Evaluate the expression. \(\left(6\frac{4}{15} + \frac{18}{24}\right) - \left(1\frac{4}{15} - \frac{1}{4}\right)\)

Hints

- Reduce any fraction that is not in simplest form. - When a minus sign is in front of parentheses, track the sign of every term inside. - Look for an equivalent grouping that creates whole numbers.

Solution

1. Simplify \(\frac{18}{24}=\frac{3}{4}\) and distribute the subtraction: \(6\frac{4}{15}+\frac{3}{4}-1\frac{4}{15}+\frac{1}{4}\). 2. Regroup: \(\left(6\frac{4}{15}-1\frac{4}{15}\right)+\left(\frac{3}{4}+\frac{1}{4}\right)\). 3. The groups equal \(5\) and \(1\), so the value is \(6\).

Answer

After simplifying and removing parentheses: \(6\frac{4}{15}+\frac{3}{4}-1\frac{4}{15}+\frac{1}{4}\). One efficient regrouping is \(\left(6\frac{4}{15}-1\frac{4}{15}\right)+\left(\frac{3}{4}+\frac{1}{4}\right)=6\).
Add and subtract rational numbers 178
Rewrite the subtraction as addition of opposites. Then show an equivalent rearranged and regrouped sum that makes the calculation efficient, evaluate it, and name the properties that justify changing the order and grouping. \(\left(15\frac{5}{6} + 3\frac{1}{4}\right) - \left(2\frac{5}{6} + 1\frac{1}{2} + 1\frac{3}{4}\right)\)

Hints

- Rewrite each subtraction as addition of the opposite before changing the order. - Keep each sign attached to its term when rearranging. - Look for groups whose fractional parts cancel or combine to whole numbers.

Solution

1. Rewrite subtraction as addition of opposites: \(15\frac{5}{6}+3\frac{1}{4}+\left(-2\frac{5}{6}\right)+\left(-1\frac{1}{2}\right)+\left(-1\frac{3}{4}\right)\). 2. Use the commutative and associative properties of addition to regroup: \(\left(15\frac{5}{6}-2\frac{5}{6}\right)+\left(3\frac{1}{4}-1\frac{1}{2}-1\frac{3}{4}\right)\). 3. The first group is \(13\), and the second group is \(0\). 4. Therefore, the value is \(13\).

Answer

One valid regrouping is \(\left(15\frac{5}{6}-2\frac{5}{6}\right)+\left(3\frac{1}{4}-1\frac{1}{2}-1\frac{3}{4}\right)=13+0=13\). The commutative and associative properties of addition justify the rearrangement and regrouping after subtraction is rewritten as addition of opposites.
Add and subtract rational numbers 179
Evaluate each expression. Before calculating, state which representation you will use for each nonmatching pair and show the first rewritten expression. a) \(\left(\frac{1}{4} + 0.5\right) - 1\) b) \(2.75 - \left(1\frac{1}{2} + 0.25\right)\) c) \(\frac{1}{3} + 0.2 + \frac{1}{6}\)

Hints

- Inspect whether a fraction terminates before deciding to convert it. - A useful representation should reduce, not increase, the amount of computation. - Your answer must show the rewritten expression that reflects your choice.

Solution

1. a) Use decimals: \((0.25+0.5)-1=-0.25\). 2. b) Use decimals: \(2.75-(1.5+0.25)=1\). 3. c) Keep the thirds and sixths as fractions first: \(\left(\frac{1}{3}+\frac{1}{6}\right)+0.2=0.5+0.2=0.7\).

Answer

a) Decimals: \((0.25+0.5)-1=-0.25\) b) Decimals: \(2.75-(1.5+0.25)=1\) c) Fractions first: \(\left(\frac{1}{3}+\frac{1}{6}\right)+0.2=0.7\)
Add and subtract rational numbers 180
Lucas and Mia evaluate \(0.125 + \frac{3}{4} + 0.25 + \frac{1}{8}\) in different ways. Lucas converts the fractions to decimals. Mia converts the decimals to fractions and rearranges the addends. Carry out both methods. Which method seems more efficient here? Explain.

Hints

- Convert only values whose equivalents you know exactly. - Look for pairs that combine to a whole number. - Rearranging addends does not change their sum.

Solution

1. Lucas’s method: \(\frac{3}{4} = 0.75\) and \(\frac{1}{8} = 0.125\). Then \(0.125 + 0.75 + 0.25 + 0.125 = 1.25\). 2. Mia’s method: \(0.125 = \frac{1}{8}\) and \(0.25 = \frac{1}{4}\). Then \(\frac{1}{8} + \frac{3}{4} + \frac{1}{4} + \frac{1}{8}\). 3. Regroup: \(\left(\frac{1}{8} + \frac{1}{8}\right) + \left(\frac{3}{4} + \frac{1}{4}\right) = \frac{1}{4} + 1 = 1.25\). 4. Both methods are efficient. Mia’s grouping immediately creates a whole number from the fourths.

Answer

Both methods give \(1.25\). Mia’s method is especially efficient because \(\frac{3}{4} + \frac{1}{4} = 1\).
Add and subtract rational numbers 181
Evaluate the expression. Briefly explain why fractions or decimals are the better representation. \(1\frac{1}{3} + 0.25 - \frac{7}{12}\)

Hints

- Consider the decimal representation of \(\frac{1}{3}\). - Convert the terminating decimal to a fraction. - Rewrite the fractions with a common denominator.

Solution

1. Fractions are more efficient because \(\frac{1}{3}\) has a repeating decimal representation. 2. Convert \(0.25 = \frac{1}{4}\) and \(1\frac{1}{3} = \frac{4}{3}\). 3. Use denominator \(12\): \(\frac{16}{12} + \frac{3}{12} - \frac{7}{12} = \frac{12}{12} = 1\).

Answer

\(1\). Fractions are preferable because \(\frac{1}{3}\) is a repeating decimal.
Add and subtract rational numbers 182
Evaluate the expression. Follow the grouping symbols and choose an efficient representation for the numbers. \(12.8 - \left(3\frac{1}{8} + 4.025\right) + 2\frac{1}{5}\)

Hints

- Evaluate the grouped sum first. - The fractions \(\frac{1}{8}\) and \(\frac{1}{5}\) have terminating decimal forms. - Align decimal places carefully when adding and subtracting.

Solution

1. Convert the mixed numbers to decimals: \(3\frac{1}{8} = 3.125\) and \(2\frac{1}{5} = 2.2\). 2. Evaluate inside the parentheses: \(3.125 + 4.025 = 7.15\). 3. Substitute and evaluate: \(12.8 - 7.15 + 2.2 = 5.65 + 2.2 = 7.85\).

Answer

\(7.85\)
Add and subtract rational numbers 183
Evaluate the expression efficiently. Use an estimate to check the result. \(\left(12\frac{3}{8} + 4.55\right) - \left(2.375 - 1\frac{9}{20}\right)\)

Hints

- Convert the fractional parts to terminating decimals. - A subtraction sign before parentheses changes both signs inside. - Look for decimal pairs that combine to whole numbers.

Solution

1. Estimate: \((12 + 5) - (2 - 1) = 16\). 2. Convert the mixed numbers: \(12\frac{3}{8} = 12.375\) and \(1\frac{9}{20} = 1.45\). 3. Remove the parentheses and regroup: \(12.375 + 4.55 - 2.375 + 1.45\). 4. Evaluate: \((12.375 - 2.375) + (4.55 + 1.45) = 10 + 6 = 16\). 5. The exact result agrees with the estimate.

Answer

Estimate: \(16\) Exact value: \(16\)
Add and subtract rational numbers 184
Estimate first, then calculate the exact value. Decide whether fractions or decimals are more useful for the exact calculation. \(4\frac{2}{3} - \left(1.5 + \frac{1}{6}\right) + 0.2\)

Hints

- Use nearby decimals for a quick estimate. - For an exact result, avoid replacing repeating decimals with rounded values. - Convert the terminating decimals to fractions and use common denominators.

Solution

1. Estimate using nearby convenient values: \(4.7 - 1.7 + 0.2 \approx 3.2\). 2. Fractions are useful because \(\frac{2}{3}\) and \(\frac{1}{6}\) have repeating decimal representations. 3. Convert the decimals: \(1.5 = \frac{3}{2}\) and \(0.2 = \frac{1}{5}\). 4. Evaluate the parentheses: \(\frac{3}{2} + \frac{1}{6} = \frac{10}{6} = \frac{5}{3}\). 5. Calculate: \(\frac{14}{3} - \frac{5}{3} + \frac{1}{5} = 3 + \frac{1}{5} = 3.2\).

Answer

Estimate: about \(3.2\) Exact value: \(3\frac{1}{5}\), or \(3.2\)
Add and subtract rational numbers 185
Consider \(\frac{3}{4}+\frac{2}{3}-\frac{1}{2}\). a) Give a benchmark estimate that decides whether the result is greater than or less than \(1\). Show the benchmark values you used. b) Calculate the exact value as a fraction. c) State whether the exact result is consistent with your estimate.

Hints

- Use simple benchmark decimal values rather than doing the exact fraction computation first. - For the exact calculation, choose a common denominator for \(2\), \(3\), and \(4\). - Compare the exact result with the claim made by your estimate.

Solution

1. A benchmark estimate is \(0.75+0.67-0.5\approx0.92\), so the result should be less than \(1\). 2. With denominator \(12\), the exact value is \(\frac{9}{12}+\frac{8}{12}-\frac{6}{12}=\frac{11}{12}\). 3. Since \(\frac{11}{12}<1\), the estimate is consistent.

Answer

a) For example, \(0.75+0.67-0.5\approx0.92<1\). b) \(\frac{11}{12}\) c) Yes. The exact value is less than \(1\), as predicted.
Add and subtract rational numbers 186
Check the following work for an error: \(\frac{4}{5}-\left(\frac{1}{2}-\frac{1}{10}\right)=\frac{4}{5}-\frac{1}{2}-\frac{1}{10}=\frac{8}{10}-\frac{5}{10}-\frac{1}{10}=\frac{1}{5}\). Explain whether the work is correct. If it is not, identify the error and calculate the correct result.

Hints

- Try evaluating the expression inside the parentheses before doing anything else. - What quantity is being subtracted from \(\frac{4}{5}\)? - Check each equality in the student's chain.

Solution

1. The work is incorrect. Subtracting the entire quantity \(\frac{1}{2}-\frac{1}{10}\) is not the same as subtracting both terms separately. 2. Evaluate the parentheses first: \(\frac{1}{2}-\frac{1}{10}=\frac{5}{10}-\frac{1}{10}=\frac{4}{10}\). 3. Then \(\frac{4}{5}-\frac{4}{10}=\frac{8}{10}-\frac{4}{10}=\frac{4}{10}=\frac{2}{5}\).

Answer

The work is incorrect because the subtraction of the quantity in parentheses was handled incorrectly. The correct result is \(\frac{2}{5}\).
Add and subtract rational numbers 187
Evaluate the expression: \(\left(\frac{2}{3}-1.5\right)+\left(-\frac{5}{6}+0.25\right)\)

Hints

- Decide whether fractions or decimals will be easier to use consistently. - Fractions need common denominators before addition or subtraction. - Evaluate the expressions inside parentheses first.

Solution

1. First parentheses: \(\frac{2}{3}-1.5=\frac{2}{3}-\frac{3}{2}=\frac{4}{6}-\frac{9}{6}=-\frac{5}{6}\). 2. Second parentheses: \(-\frac{5}{6}+0.25=-\frac{5}{6}+\frac{1}{4}=-\frac{10}{12}+\frac{3}{12}=-\frac{7}{12}\). 3. Add: \(-\frac{5}{6}-\frac{7}{12}=-\frac{10}{12}-\frac{7}{12}=-\frac{17}{12}=-1 \frac{5}{12}\).

Answer

\(-\frac{17}{12}\), or \(-1 \frac{5}{12}\)
Add and subtract rational numbers 188
Two students evaluate \(4.8+2\frac{1}{4}+1.2+\frac{3}{4}\). - Jordan converts the fractions to decimals and adds from left to right. - Maya reorders and groups the addends as \((4.8+1.2)+(2\frac{1}{4}+\frac{3}{4})\). a) Evaluate the expression both ways. b) Explain which method is easier to do mentally.

Hints

- Complete both methods before comparing them. - Look for addends that combine to whole numbers. - Consider how reordering and regrouping affect the value of a sum.

Solution

1. Jordan’s method: \(2\frac{1}{4}=2.25\) and \(\frac{3}{4}=0.75\). Then \(4.8+2.25=7.05\), \(7.05+1.2=8.25\), and \(8.25+0.75=9\). 2. Maya’s method: \(4.8+1.2=6\) and \(2\frac{1}{4}+\frac{3}{4}=3\). Then \(6+3=9\). 3. Maya’s method is easier mentally because the commutative and associative properties create whole-number sums.

Answer

a) Both methods give \(9\). b) Maya’s method is generally easier mentally because the grouped addends make \(6\) and \(3\).
Add and subtract rational numbers 189
Decide whether each statement is true or false. Justify your decision by evaluating both sides of the equation. a) \(-12.5+7.5=-(12.5-7.5)\) b) \(\frac{1}{2}-\left(\frac{1}{4}+\frac{1}{8}\right)=\frac{1}{2}-\frac{1}{4}+\frac{1}{8}\)

Hints

- Evaluate each side separately. - Apply parentheses first. - What happens to every term inside parentheses when a negative sign is distributed?

Solution

1. For a), the left side is \(-12.5+7.5=-5\). The right side is \(-(12.5-7.5)=-5\). The statement is true. 2. For b), the left side is \(\frac{1}{2}-\left(\frac{1}{4}+\frac{1}{8}\right)=\frac{4}{8}-\frac{3}{8}=\frac{1}{8}\). 3. The right side is \(\frac{1}{2}-\frac{1}{4}+\frac{1}{8}=\frac{4}{8}-\frac{2}{8}+\frac{1}{8}=\frac{3}{8}\). Since the two sides differ, the statement is false.

Answer

a) True; both sides equal \(-5\). b) False; the left side is \(\frac{1}{8}\) and the right side is \(\frac{3}{8}\).
Add and subtract rational numbers 190
Evaluate the expression. Write the result as a fraction in simplest form or as a mixed number: \(10-\left(3 \frac{1}{4}+2 \frac{5}{6}\right)-1 \frac{1}{12}\)

Hints

- Evaluate the parentheses first. - When subtracting a mixed number from a whole number, you may need to regroup one whole. - Simplify the fractional part of the final answer. - After the parentheses are resolved, keep the remaining subtractions in their original order.

Solution

1. Evaluate the parentheses using denominator \(12\): \(3 \frac{1}{4}+2 \frac{5}{6}=3 \frac{3}{12}+2 \frac{10}{12}=5 \frac{13}{12}=6 \frac{1}{12}\). 2. Subtract from \(10\): \(10-6 \frac{1}{12}=3 \frac{11}{12}\). 3. Subtract the last mixed number: \(3 \frac{11}{12}-1 \frac{1}{12}=2 \frac{10}{12}=2 \frac{5}{6}\).

Answer

\(2 \frac{5}{6}\)
Add and subtract rational numbers 191
Evaluate the expression. Write the answer as a fraction in simplest form or as a mixed number: \(2 \frac{1}{4}-\frac{5}{6}-\frac{3}{8}\)

Hints

- Rewrite the mixed number as an improper fraction. - Find one common denominator for all three fractions. - Perform the subtractions from left to right, then convert the result to a mixed number if needed. - Estimate whether the final value should be greater than \(1\) as a reasonableness check.

Solution

1. Rewrite \(2 \frac{1}{4}\) as \(\frac{9}{4}\). 2. Use denominator \(24\): \(\frac{9}{4}=\frac{54}{24}\), \(\frac{5}{6}=\frac{20}{24}\), and \(\frac{3}{8}=\frac{9}{24}\). 3. Subtract from left to right: \(\frac{54}{24}-\frac{20}{24}-\frac{9}{24}=\frac{25}{24}=1 \frac{1}{24}\).

Answer

\(1 \frac{1}{24}\)
Add and subtract rational numbers 192
Find the missing value of \(a\), \(b\), or \(a+b\) in each part. a) \(a=-4.5\), \(b=2.1\), \(a+b=\square\) b) \(a=\square\), \(b=-7.8\), \(a+b=-3.2\) c) \(a=\frac{3}{4}\), \(b=\square\), \(a+b=-\frac{1}{8}\)

Hints

- When the sum and one addend are known, subtract the known addend to find the other one. - Subtraction is the inverse of addition. - For the fractions, first write them with a common denominator.

Solution

1. In a), add the two values: \(-4.5+2.1=-2.4\). 2. In b), subtract the known addend from the sum: \(a=-3.2-(-7.8)=-3.2+7.8=4.6\). 3. In c), subtract the known addend from the sum: \(b=-\frac{1}{8}-\frac{3}{4}=-\frac{1}{8}-\frac{6}{8}=-\frac{7}{8}\).

Answer

a) \(a+b=-2.4\) b) \(a=4.6\) c) \(b=-\frac{7}{8}\)
Add and subtract rational numbers 193
Complete the subtraction table and find \(x\) and \(y\). Each entry is the value at the left of its row minus the value at the top of its column. <table> <tr><td>\(-\)</td><td>\(1.2\)</td><td>\(y\)</td><td>\(-3.5\)</td></tr> <tr><td>\(4.5\)</td><td>\(3.3\)</td><td>\(7.2\)</td><td></td></tr> <tr><td>\(-2.8\)</td><td></td><td>\(-0.1\)</td><td>\(0.7\)</td></tr> <tr><td>\(x\)</td><td>\(-5.5\)</td><td></td><td>\(-0.8\)</td></tr> </table>

Hints

- First determine how each table entry is calculated. - Use a simple equation to find a missing row or column heading. - Pay close attention when subtracting a negative number.

Solution

1. From the row headed by \(4.5\), \(4.5-y=7.2\). Therefore, \(y=4.5-7.2=-2.7\). 2. From the row headed by \(x\), \(x-1.2=-5.5\). Therefore, \(x=-5.5+1.2=-4.3\). 3. Fill the remaining cells: \(4.5-(-3.5)=8.0\), \(-2.8-1.2=-4.0\), and \(-4.3-(-2.7)=-1.6\).

Answer

\(x=-4.3\); \(y=-2.7\) Completed table: <table> <tr><td>\(-\)</td><td>\(1.2\)</td><td>\(-2.7\)</td><td>\(-3.5\)</td></tr> <tr><td>\(4.5\)</td><td>\(3.3\)</td><td>\(7.2\)</td><td>\(8.0\)</td></tr> <tr><td>\(-2.8\)</td><td>\(-4.0\)</td><td>\(-0.1\)</td><td>\(0.7\)</td></tr> <tr><td>\(-4.3\)</td><td>\(-5.5\)</td><td>\(-1.6\)</td><td>\(-0.8\)</td></tr> </table>
Add and subtract rational numbers 194
Insert \(<\), \(>\), or \(=\) to make each statement true. For each part, justify the comparison using a rational-number rule or magnitude comparison without giving the exact value of the expression. a) \(-4.5+4.5\;\square\;0\) b) \(-123-(-122)\;\square\;0\) c) \(-\frac{2}{3}+\left(-\frac{1}{3}\right)\;\square\;0\) d) \(0.01-0.1\;\square\;0\)

Hints

- Use structural facts such as opposites and sign rules before doing arithmetic. - When signs differ, compare magnitudes. - Your explanation should establish the comparison with \(0\), not report an exact result.

Solution

1. Opposites sum to \(0\), so use \(=\). 2. Rewrite the expression as \(-123+122\). The negative magnitude is larger, so the result is less than \(0\). 3. A sum of two negative numbers is negative, so use \(<\). 4. The larger positive number is subtracted from the smaller, so the result is negative and use \(<\).

Answer

a) \(=\) — the addends are opposites b) \(<\) — \(-123+122\) has the larger magnitude on the negative term c) \(<\) — two negative addends have a negative sum d) \(<\) — \(0.1>0.01\), so the difference is negative
Add and subtract rational numbers 195
For each pair, decide which expression has the greater value. Justify the choice using signs, direction on a number line, or relative magnitude; do not give the exact final values. a) \((-15)+(-20)\) or \((-15)-(-20)\) b) \(0.4-0.6\) or \(-0.4+0.6\) c) \(-\frac{1}{8}-\frac{1}{4}\) or \(-\frac{1}{8}+\frac{1}{4}\)

Hints

- Look for a sign comparison that settles the question before exact calculation. - Rewrite subtraction of a negative as addition. - For the fraction pair, think about movement from the same starting point.

Solution

1. a) The first expression is a sum of negatives. The second rewrites as \(-15+20\), which is positive, so the second is greater. 2. b) Subtracting a larger positive from a smaller gives a negative result, while adding \(0.6\) to \(-0.4\) gives a positive result, so the second is greater. 3. c) From \(-\frac{1}{8}\), subtracting \(\frac{1}{4}\) moves left while adding it moves right, so the second is greater.

Answer

a) \((-15)-(-20)\) — it is positive while the other expression is negative b) \(-0.4+0.6\) — it is positive while \(0.4-0.6\) is negative c) \(-\frac{1}{8}+\frac{1}{4}\) — adding the positive fraction moves right while subtracting it moves left
Add and subtract rational numbers 196
Choose exactly three different numbers from the list whose sum is \(0\). Find two different solutions. \(0.7,\ -0.3,\ \frac{1}{5},\ -0.4,\ 0.1,\ -0.5\)

Hints

- Convert the fraction to a decimal. - For each positive number, look for two numbers whose sum is its opposite. - Use each selected number only once in a solution.

Solution

1. Write \(\frac{1}{5}=0.2\). 2. One solution is \(0.7+(-0.3)+(-0.4)=0\). 3. A second solution is \(0.2+0.1+(-0.3)=0\).

Answer

For example: \(0.7, -0.3, -0.4\) \(\frac{1}{5}, 0.1, -0.3\)
Add and subtract rational numbers 197
Choose exactly four numbers from the list. Place a plus or minus sign between consecutive chosen numbers so that the result is \(0.5\). \(1.2,\ -0.5,\ \frac{1}{4},\ -0.8,\ 0.1,\ -0.2\)

Hints

- Convert \(\frac{1}{4}\) to a decimal if you use it. - Estimate combinations before calculating exactly. - Remember that subtracting a negative number adds its opposite.

Solution

1. One valid choice is \(1.2, -0.8, 0.1, -0.2\). 2. Insert signs: \(1.2+(-0.8)-0.1-(-0.2)\). 3. Evaluate: \(1.2-0.8-0.1+0.2=0.5\).

Answer

One possible solution is \(1.2+(-0.8)-0.1-(-0.2)=0.5\).
Add and subtract rational numbers 198
Two students evaluate \(-0.5 + \frac{3}{4} - 0.25 + \frac{1}{2}\) in different ways. Mia works from left to right. Lucas groups values that combine easily. a) Evaluate the expression using Mia’s method. b) Show an efficient grouping Lucas could use. c) Compare the original expression with \(-0.5 + \left(\frac{3}{4} - 0.25\right) + \frac{1}{2}\). Do the parentheses change the value? Explain.

Hints

- Convert a fraction to a decimal only when it helps with a particular step. - Look for additive inverses or pairs that make a simple decimal. - Parentheses preceded by a plus sign can be removed without changing the signs inside.

Solution

1. Mia’s method: \(-0.5 + 0.75 = 0.25\), then \(0.25 - 0.25 = 0\), and finally \(0 + 0.5 = 0.5\). 2. Lucas can group \(-0.5\) with \(\frac{1}{2}\), and \(\frac{3}{4}\) with \(-0.25\): \(\left(-0.5 + \frac{1}{2}\right) + \left(\frac{3}{4} - 0.25\right)\). 3. The groups equal \(0\) and \(0.5\), so the result is \(0.5\). 4. In c), the parentheses are preceded by addition. Removing them does not change any signs, so the value remains \(0.5\).

Answer

a) \(0.5\) b) \(\left(-0.5 + \frac{1}{2}\right) + \left(\frac{3}{4} - 0.25\right) = 0 + 0.5 = 0.5\) c) No. The parentheses are preceded by addition, so removing them does not change the value.
Add and subtract rational numbers 199
For each expression, write an equivalent grouping that combines compatible rational numbers before evaluating. a) \(-\frac{3}{7} + \frac{5}{8} - \frac{4}{7} + \frac{3}{8}\) b) \(1\frac{2}{5} - 3\frac{1}{4} + \frac{3}{5} + \frac{1}{4}\) c) \(\frac{7}{10} - 0.45 + \frac{3}{10} - 0.55\)

Hints

- Identify which terms can combine without introducing new denominators or representations. - Treat subtraction as addition of a signed term before regrouping. - Show the grouping that makes each calculation short.

Solution

1. a) \(\left(-\frac{3}{7}-\frac{4}{7}\right)+\left(\frac{5}{8}+\frac{3}{8}\right)=-1+1=0\). 2. b) \(\left(1\frac{2}{5}+\frac{3}{5}\right)+\left(-3\frac{1}{4}+\frac{1}{4}\right)=2-3=-1\). 3. c) \(\left(\frac{7}{10}+\frac{3}{10}\right)+(-0.45-0.55)=1-1=0\).

Answer

a) \(\left(-\frac{3}{7}-\frac{4}{7}\right)+\left(\frac{5}{8}+\frac{3}{8}\right)=0\) b) \(\left(1\frac{2}{5}+\frac{3}{5}\right)+\left(-3\frac{1}{4}+\frac{1}{4}\right)=-1\) c) \(\left(\frac{7}{10}+\frac{3}{10}\right)+(-0.45-0.55)=0\)
Add and subtract rational numbers 200
Lina and Tim evaluate \(12.5 - 8.3 + 7.5 - 1.7\) in different ways. Lina groups the positive terms and the amounts being subtracted: \((12.5 + 7.5) - (8.3 + 1.7)\). Tim groups consecutive pairs: \((12.5 - 8.3) + (7.5 - 1.7)\). a) Evaluate the expression using both methods. b) Explain why Lina’s method is especially efficient here.

Hints

- Carry out each proposed grouping separately. - Compare the intermediate values produced by the two methods. - An efficient mental method often creates whole numbers.

Solution

1. Lina’s method: \(12.5 + 7.5 = 20\) and \(8.3 + 1.7 = 10\), so \(20 - 10 = 10\). 2. Tim’s method: \(12.5 - 8.3 = 4.2\) and \(7.5 - 1.7 = 5.8\), so \(4.2 + 5.8 = 10\). 3. Lina’s grouping creates whole-number intermediate results, making the mental calculation simpler.

Answer

a) Both methods give \(10\). b) Lina’s method creates the whole-number intermediate results \(20\) and \(10\).
Add and subtract rational numbers 201
Evaluate each expression using properties of rational-number addition. For each part, show the reordered or regrouped expression that makes the calculation efficient. a) \(\frac{5}{9} - \frac{1}{3} + \frac{4}{9}\) b) \(\frac{3}{4} - 2.5 - \frac{7}{4} + 1.5\) c) \(-\frac{2}{7} + \frac{5}{6} + \frac{2}{7} - \frac{1}{6}\)

Hints

- Search for equal denominators, additive inverses, or decimal pairs that make whole numbers. - Keep signs attached to terms while changing order. - The answer must show how the properties were used.

Solution

1. a) \(\left(\frac{5}{9}+\frac{4}{9}\right)-\frac{1}{3}=1-\frac{1}{3}=\frac{2}{3}\). 2. b) \(\left(\frac{3}{4}-\frac{7}{4}\right)+(-2.5+1.5)=-1-1=-2\). 3. c) \(\left(-\frac{2}{7}+\frac{2}{7}\right)+\left(\frac{5}{6}-\frac{1}{6}\right)=\frac{2}{3}\).

Answer

a) \(\left(\frac{5}{9}+\frac{4}{9}\right)-\frac{1}{3}=\frac{2}{3}\) b) \(\left(\frac{3}{4}-\frac{7}{4}\right)+(-2.5+1.5)=-2\) c) \(\left(-\frac{2}{7}+\frac{2}{7}\right)+\left(\frac{5}{6}-\frac{1}{6}\right)=\frac{2}{3}\)
Add and subtract rational numbers 202
Rewrite each expression by removing parentheses or regrouping strategically, then evaluate. a) \(-3.25-(1.75-8)\) b) \(2\frac{1}{5}-\left(4.8+\frac{1}{5}\right)+0.8\) c) \(\left(\frac{5}{8}+1.4\right)-\left(\frac{1}{8}-0.6\right)\)

Hints

- A subtraction sign before parentheses changes the sign of every term inside. - Convert a fraction to a decimal when that creates easy pairs. - Regroup terms to form whole numbers.

Solution

1. For a), remove the parentheses: \(-3.25-1.75+8=-5+8=3\). 2. For b), remove the parentheses and regroup: \(2\frac{1}{5}-4.8-\frac{1}{5}+0.8=(2.2-0.2)+(-4.8+0.8)=2-4=-2\). 3. For c), remove the parentheses: \(\frac{5}{8}+1.4-\frac{1}{8}+0.6\). Regroup: \(\left(\frac{5}{8}-\frac{1}{8}\right)+(1.4+0.6)=0.5+2=2.5\).

Answer

a) \(3\) b) \(-2\) c) \(2.5\)
Add and subtract rational numbers 203
Use all four number cards \(-4\), \(-2\), \(6\), and \(8\), along with addition and subtraction signs, to write an expression with a value of \(0\). You may use parentheses. Then write a different expression using the same four cards that has a value of \(12\).

Hints

- First consider how the absolute values \(4\), \(2\), \(6\), and \(8\) can combine to make each target. - Subtracting a negative number is the same as adding its opposite. - It may help to consider the positive and negative cards separately.

Solution

1. One expression with a value of \(0\) is \(8-6-(-2)+(-4)\). Evaluating gives \(8-6+2-4=0\). 2. One expression with a value of \(12\) is \(8+6-(-2)+(-4)\). Evaluating gives \(8+6+2-4=12\).

Answer

For \(0\): \(8-6-(-2)+(-4)=0\) For \(12\): \(8+6-(-2)+(-4)=12\)
Add and subtract rational numbers 204
Insert an addition or subtraction sign in each blank to make the equation true. a) \(-7\;\square\;(-3)\;\square\;5=-9\) b) \(-7\;\square\;((-3)\;\square\;5)=1\)

Hints

- Test the four possible pairs of operation signs systematically. - In part b), evaluate the expression in parentheses first. - Decide whether the result must be greater than or less than the starting value \(-7\).

Solution

1. For a), using subtraction in both blanks gives \(-7-(-3)-5=-7+3-5=-9\). 2. For b), evaluate the parentheses first. Using subtraction in both blanks gives \(-7-((-3)-5)=-7-(-8)=1\).

Answer

a) \(-7-(-3)-5=-9\) b) \(-7-((-3)-5)=1\)
Add and subtract rational numbers 205
Evaluate each expression using properties of operations. For each part, show the cancellation or regrouping that makes the calculation short. a) \(17.4 - (5.9 + 17.4) + 0.9\) b) \(-\frac{2}{5} + (3.7 + 0.4) - 2.7\)

Hints

- First rewrite any subtraction of a grouped sum carefully. - Look for additive inverses or pairs differing by a whole number. - Show the cancellation or regrouping, not only the result.

Solution

1. a) Remove the parentheses: \(17.4-5.9-17.4+0.9\). Regroup as \((17.4-17.4)+(-5.9+0.9)=-5\). 2. b) Convert \(-\frac{2}{5}=-0.4\). Then regroup as \((-0.4+0.4)+(3.7-2.7)=1\).

Answer

a) \((17.4-17.4)+(-5.9+0.9)=-5\) b) \((-0.4+0.4)+(3.7-2.7)=1\)
Add and subtract rational numbers 206
Rewrite and evaluate each expression. Pay attention to the mixture of fractions and decimals. a) \(\frac{1}{8}-0.25+0.875-1.75\) b) \(\left(\frac{5}{6}+1.2\right)-\left(\frac{1}{6}-0.8\right)\)

Hints

- Choose fraction or decimal forms that make useful pairs. - Combine fractions with the same denominator directly. - Simplify the final fraction.

Solution

1. For a), write \(\frac{1}{8}=0.125\). Regroup: \((0.125+0.875)-(0.25+1.75)=1-2=-1\). 2. For b), remove the parentheses: \(\frac{5}{6}+1.2-\frac{1}{6}+0.8\). 3. Regroup: \(\left(\frac{5}{6}-\frac{1}{6}\right)+(1.2+0.8)=\frac{4}{6}+2=\frac{2}{3}+2=2\frac{2}{3}\).

Answer

a) \(-1\) b) \(2\frac{2}{3}\), or \(\frac{8}{3}\)
Add and subtract rational numbers 207
Place exactly one pair of parentheses in \(40-20-10-5\). The parentheses must contain at least two numbers. a) Find the value without parentheses. b) Place the parentheses so the value does not change. c) Place the parentheses so the value is \(25\).

Hints

- Without parentheses, perform subtraction from left to right. - A minus sign before parentheses changes how the enclosed difference affects the result. - Test possible groups of consecutive numbers.

Solution

1. Without parentheses, calculate from left to right: \(40-20-10-5=5\). 2. One placement that keeps the value is \((40-20)-10-5=5\). Another is \((40-20-10)-5=5\). 3. To obtain \(25\), use \(40-(20-10)-5=25\).

Answer

a) \(5\) b) \((40-20)-10-5\) or \((40-20-10)-5\) c) \(40-(20-10)-5\)
Add and subtract rational numbers 208
Consider the expression \(50-25-10-5\). Determine whether placing exactly one pair of parentheses can make the value \(40\). The parentheses must enclose at least two numbers. Justify your answer by evaluating every possible placement.

Hints

- Count all the ways one pair of parentheses can enclose consecutive numbers in a four-number expression. - Evaluate each possible placement carefully. - Remember to simplify the expression inside parentheses first.

Solution

1. Parentheses around the first two numbers give \((50-25)-10-5=10\). 2. Parentheses around the first three numbers give \((50-25-10)-5=10\). 3. Parentheses around the entire expression give \((50-25-10-5)=10\). 4. Parentheses around the second and third numbers give \(50-(25-10)-5=30\). 5. Parentheses around the second through fourth numbers give \(50-(25-10-5)=40\). 6. Parentheses around the third and fourth numbers give \(50-25-(10-5)=20\). 7. Therefore, it is possible. The required placement is \(50-(25-10-5)\).

Answer

Yes. The placement \(50-(25-10-5)\) gives \(40\).
Add and subtract rational numbers 209
A weather station starts the day at \(45.5\,{}^\circ\text{F}\). The temperature then changes by \(-3.4\,{}^\circ\text{F}\), \(+8.8\,{}^\circ\text{F}\), \(-2.2\,{}^\circ\text{F}\), \(-5.7\,{}^\circ\text{F}\), and \(+6.1\,{}^\circ\text{F}\), in that order. a) What is the final temperature? b) What is the highest temperature reached during the day? c) What is the lowest temperature reached during the day?

Hints

- Make a running list of the temperature after each change. - Include the starting temperature when finding the highest and lowest values. - Pay attention to the signs of the changes.

Solution

1. Track the temperatures in order: \(45.5\), \(42.1\), \(50.9\), \(48.7\), \(43.0\), and \(49.1\), all in degrees Fahrenheit. 2. For a), the final temperature is \(49.1\,{}^\circ\text{F}\). 3. For b), the highest value is \(50.9\,{}^\circ\text{F}\). 4. For c), the lowest value is \(42.1\,{}^\circ\text{F}\).

Answer

a) \(49.1\,{}^\circ\text{F}\) b) \(50.9\,{}^\circ\text{F}\) c) \(42.1\,{}^\circ\text{F}\)
Add and subtract rational numbers 210
A rain barrel holds \(50\) gallons. It starts the week with \(30.75\) gallons of water. During the week, the amount changes in this order: - Rain: \(+8.50\) gallons - Watering: \(-13.20\) gallons - Rain: \(+3.85\) gallons - Watering: \(-22.40\) gallons a) How much water is in the barrel at the end of the week? b) When the barrel reached its highest amount during the week, how many gallons of empty capacity remained?

Hints

- Update the amount after each addition or removal. - For part b), identify the greatest amount reached during the week. - Subtract that maximum amount from the barrel's total capacity.

Solution

1. Track the amounts: \(30.75\), \(39.25\), \(26.05\), \(29.90\), and \(7.50\) gallons. 2. For a), the final amount is \(7.50\) gallons. 3. The highest amount is \(39.25\) gallons. 4. For b), the empty capacity at that point is \(50.00-39.25=10.75\) gallons.

Answer

a) \(7.50\) gallons b) \(10.75\) gallons of empty capacity
Add and subtract rational numbers 211
A checking account starts with a balance of \(\$250.00\). These transactions occur in order: - Withdrawal: \(\$315.50\) - Deposit: \(\$120.00\) - Withdrawal: \(\$85.25\) a) What is the lowest balance reached during the sequence? b) What is the balance after the final transaction? c) How much must be deposited after the final transaction to bring the balance to exactly \(\$100.00\)?

Hints

- Update the account balance after each transaction in order. - A withdrawal decreases the balance, and the balance can become negative. - To move from a negative final balance to a positive target, find the difference between the two signed values.

Solution

1. Track the balances: \(\$250.00\), \(-\$65.50\), \(\$54.50\), and \(-\$30.75\). 2. For a), the lowest balance is \(-\$65.50\). 3. For b), the final balance is \(-\$30.75\). 4. For c), the required deposit is \(100.00-(-30.75)=130.75\), so \(\$130.75\) must be deposited.

Answer

a) \(-\$65.50\) b) \(-\$30.75\) c) \(\$130.75\)
Add and subtract rational numbers 212
Find the rational number that belongs in each blank. a) \(\frac{2}{3}+\square=-\frac{1}{6}\) b) \(\square-\frac{3}{5}=-1\) c) \(-\frac{1}{2}-\square=\frac{1}{8}\)

Hints

- Treat each blank as an unknown value and use the inverse operation. - Use the same inverse-operation reasoning you would use with positive numbers. - Rewrite rational numbers with common denominators before adding or subtracting. - In part c), pay close attention to the subtraction sign before the blank.

Solution

1. For a), the missing value is \(-\frac{1}{6}-\frac{2}{3}=-\frac{1}{6}-\frac{4}{6}=-\frac{5}{6}\). 2. For b), the missing value is \(-1+\frac{3}{5}=-\frac{5}{5}+\frac{3}{5}=-\frac{2}{5}\). 3. For c), the missing value is \(-\frac{1}{2}-\frac{1}{8}=-\frac{4}{8}-\frac{1}{8}=-\frac{5}{8}\).

Answer

a) \(-\frac{5}{6}\) b) \(-\frac{2}{5}\) c) \(-\frac{5}{8}\)
Add and subtract rational numbers 213
Write each expression and find its value. a) Decrease \(-18.5\) by the difference of \(12.4\) and \(15.9\). b) Add the opposite of \(7.2\) to the sum of \(-14.6\) and \(21.3\). c) Subtract three times \(4.5\) from the difference of \(-10\) and \(-25\).

Hints

- In a), decide which subtraction must stay inside parentheses. - In b), what is the signed number opposite to the one given? - In c), find the difference first, then subtract the stated product.

Solution

1. For a), \(-18.5-(12.4-15.9)=-18.5-(-3.5)=-15\). 2. For b), \((-14.6+21.3)+(-7.2)=6.7-7.2=-0.5\). 3. For c), \((-10-(-25))-3\cdot4.5=15-13.5=1.5\).

Answer

a) \(-18.5-(12.4-15.9)=-15\) b) \((-14.6+21.3)+(-7.2)=-0.5\) c) \((-10-(-25))-3\cdot4.5=1.5\)
Add and subtract rational numbers 214
A weather station in Colorado records these temperature changes from one reading to the next. At midnight, the temperature is \(27.5\,{}^\circ\text{F}\). <table> <tr><td>6:00 a.m.</td><td>\(+7.2\,{}^\circ\text{F}\)</td></tr> <tr><td>9:00 a.m.</td><td>\(+6.8\,{}^\circ\text{F}\)</td></tr> <tr><td>12:00 p.m.</td><td>\(+4.4\,{}^\circ\text{F}\)</td></tr> <tr><td>3:00 p.m.</td><td>\(-2.5\,{}^\circ\text{F}\)</td></tr> <tr><td>6:00 p.m.</td><td>\(-8.6\,{}^\circ\text{F}\)</td></tr> <tr><td>9:00 p.m.</td><td>\(-4.3\,{}^\circ\text{F}\)</td></tr> </table> a) Write one expression for the temperature at 9:00 p.m. and calculate it. b) Find the highest and lowest temperatures at the listed reading times, including midnight.

Hints

- Start with the midnight temperature and apply each signed change in order. - Keep a list of the temperature after every change. - Include the starting value when finding the maximum and minimum. - A positive change raises the temperature; a negative change lowers it.

Solution

1. For a), use \(27.5+7.2+6.8+4.4-2.5-8.6-4.3=30.5\). The temperature at 9:00 p.m. is \(30.5\,{}^\circ\text{F}\). 2. The successive temperatures are \(27.5\), \(34.7\), \(41.5\), \(45.9\), \(43.4\), \(34.8\), and \(30.5\) degrees Fahrenheit. 3. For b), the highest temperature is \(45.9\,{}^\circ\text{F}\), and the lowest is \(27.5\,{}^\circ\text{F}\).

Answer

a) \(27.5+7.2+6.8+4.4-2.5-8.6-4.3=30.5\), so the 9:00 p.m. temperature is \(30.5\,{}^\circ\text{F}\). b) Highest: \(45.9\,{}^\circ\text{F}\); lowest: \(27.5\,{}^\circ\text{F}\)
Add and subtract rational numbers 215
Lucas keeps track of money he has and money he owes. A negative balance means he owes money. His starting balance in April is \(\$28.50\). He records these changes: <table> <tr><td>Apr. 4</td><td>Movie and popcorn</td><td>\(-\$14.20\)</td></tr> <tr><td>Apr. 10</td><td>Gift from Grandma</td><td>\(+\$20.00\)</td></tr> <tr><td>Apr. 15</td><td>New video game</td><td>\(-\$35.00\)</td></tr> <tr><td>Apr. 22</td><td>Mowing a neighbor's lawn</td><td>\(+\$12.50\)</td></tr> <tr><td>Apr. 28</td><td>Pizza with friends</td><td>\(-\$6.80\)</td></tr> </table> a) Write an expression and find the account balance at the end of April. b) Determine whether the account balance was ever negative during April. If so, give the lowest balance.

Hints

- Treat income as positive and spending as negative. - Apply the transactions in chronological order. - Keep each intermediate balance to check whether the account ever goes below \(0\).

Solution

1. For a), use \(28.50-14.20+20.00-35.00+12.50-6.80\). 2. The balances in order are \(\$28.50\), \(\$14.30\), \(\$34.30\), \(-\$0.70\), \(\$11.80\), and \(\$5.00\). 3. The end-of-month balance is \(\$5.00\). 4. For b), the balance was negative after the Apr. 15 purchase, and the lowest balance was \(-\$0.70\).

Answer

a) \(28.50-14.20+20.00-35.00+12.50-6.80=5.00\), so the balance is \(\$5.00\). b) Yes. The lowest balance was \(-\$0.70\).
Add and subtract rational numbers 216
A bulk-food store has \(34.0\) pounds of oatmeal on Monday morning. The table shows how many pounds it sells (negative) or receives (positive) each day. <table> <tr><td>Monday</td><td>\(-7.0\,\text{lb}\)</td></tr> <tr><td>Tuesday</td><td>\(-10.0\,\text{lb}\)</td></tr> <tr><td>Wednesday</td><td>\(+44.0\,\text{lb}\) (delivery)</td></tr> <tr><td>Thursday</td><td>\(-16.5\,\text{lb}\)</td></tr> <tr><td>Friday</td><td>\(-20.5\,\text{lb}\)</td></tr> </table> a) How many pounds of oatmeal remain on Friday evening? Write an expression. b) What was the greatest amount of oatmeal in the store at one time during the week?

Hints

- Start with the Monday morning inventory and apply each signed change. - Keep a running list of the inventory after each day. - Compare all the inventory amounts to find the maximum.

Solution

1. For a), \(34.0-7.0-10.0+44.0-16.5-20.5=24.0\). So \(24.0\) pounds remain Friday evening. 2. The successive inventory amounts are \(34.0\), \(27.0\), \(17.0\), \(61.0\), \(44.5\), and \(24.0\) pounds. 3. For b), the greatest inventory amount was \(61.0\) pounds, after Wednesday's delivery.

Answer

a) \(34.0-7.0-10.0+44.0-16.5-20.5=24.0\,\text{lb}\) b) \(61.0\,\text{lb}\)
Add and subtract rational numbers 217
A subtraction expression is written as \(m-s=d\). Describe how \(d\) changes when both changes are made. a) Increase \(m\) by \(30\) and increase \(s\) by \(10\). b) Decrease \(m\) by \(15\) and increase \(s\) by \(15\). c) Increase \(m\) by \(12\) and decrease \(s\) by \(12\).

Hints

- Think about how changing \(m\) affects \(m-s\). - Increasing the number being subtracted lowers the result; decreasing it raises the result. - Combine the two changes to find how much \(d\) moves.

Solution

1. Rewrite: \((m+30)-(s+10)=m-s+20\). The difference increases by \(20\). 2. Rewrite: \((m-15)-(s+15)=m-s-30\). The difference decreases by \(30\). 3. Rewrite: \((m+12)-(s-12)=m-s+24\). The difference increases by \(24\).

Answer

a) The difference increases by \(20\). b) The difference decreases by \(30\). c) The difference increases by \(24\).
Add and subtract rational numbers 218
In \(m-s=d\), the first number \(m\) is increased by \(10\). How must the number being subtracted, \(s\), change so that: a) The difference stays the same. b) The difference is \(15\) greater than before. c) The difference is \(5\) less than before.

Hints

- First find the effect of increasing \(m\) alone. - Subtracting a larger number makes the result smaller. - Work backward from each required change in the difference.

Solution

1. Increasing \(m\) by \(10\) first increases the difference by \(10\). To cancel that change, increase \(s\) by \(10\): \((m+10)-(s+10)=d\). 2. To make the total increase \(15\), decrease \(s\) by \(5\): \((m+10)-(s-5)=d+15\). 3. To make the final difference \(5\) less than before, increase \(s\) by \(15\): \((m+10)-(s+15)=d-5\).

Answer

a) Increase \(s\) by \(10\). b) Decrease \(s\) by \(5\). c) Increase \(s\) by \(15\).
Add and subtract rational numbers 219
Start with \(300-120=180\). Decrease the first number by \(50\) and decrease the number being subtracted by \(30\). Use these changes to find the new difference. How much smaller or greater is it than the original difference?

Hints

- Consider what each change does to the subtraction result. - Subtracting less raises the result; starting with less lowers it. - Combine those effects before changing the original difference.

Solution

1. Decreasing the first number by \(50\) decreases the difference by \(50\). 2. Decreasing the number being subtracted by \(30\) increases the difference by \(30\). 3. The net change is \(-50+30=-20\), so the new difference is \(180-20=160\). 4. The new difference is \(20\) less than before.

Answer

The new difference is \(160\). It is \(20\) less than the original difference.
Add and subtract rational numbers 220
In a subtraction, the first number increases by \(45\). How must the number being subtracted change so that the result is \(60\) greater than before?

Hints

- Think about the change caused by the first number alone. - Determine how much more the difference must rise. - Does subtracting a smaller or a larger number create that rise?

Solution

1. Increasing the first number by \(45\) increases the difference by \(45\). 2. The desired increase is \(60\), so another \(60-45=15\) is needed. 3. Decreasing the second number by \(15\) increases the difference by \(15\). Thus \((a+45)-(b-15)=a-b+60\).

Answer

The number being subtracted must decrease by \(15\).
Add and subtract rational numbers 221
A subtraction has a difference of \(450\). Its first number increases by \(120\), and the number being subtracted increases by \(50\). By how much does the difference change, and what is its new value?

Hints

- Work out the effect of changing the first number. - If you subtract more, how does the result change? - Combine the two effects before updating the original difference.

Solution

1. Increasing the first number by \(120\) increases the difference by \(120\). 2. Increasing the number being subtracted by \(50\) decreases the difference by \(50\). 3. The net change is \(120-50=70\), so the difference increases by \(70\). 4. The new difference is \(450+70=520\).

Answer

The difference increases by \(70\), and its new value is \(520\).
Add and subtract rational numbers 222
In a subtraction, the second number is \(2458\). It is \(1035\) less than the first number. a) Find the first number. b) Keep the first number unchanged. By how much must the second number decrease to make the difference \(150\) greater?

Hints

- Which number is larger, and by how much? - In part b), only the number being subtracted changes. How does that affect the difference? - Can you reason about the change without calculating a new subtraction?

Solution

1. The first number is \(2458+1035=3493\). 2. The difference increases by the same amount that the second number decreases, so the second number must decrease by \(150\).

Answer

a) \(3493\) b) Decrease the second number by \(150\).
Add and subtract rational numbers 223
Three students evaluate \(1000 - 250 - 150 - 100\). - **Leo:** \(1000 - 250 = 750\), \(750 - 150 = 600\), \(600 - 100 = 500\). - **Mia:** \(250 + 150 + 100 = 500\), then \(1000 - 500 = 500\). - **Noah:** \(1000 - 250 = 750\), \(150 - 100 = 50\), then \(750 - 50 = 700\). Decide which methods are correct. Explain Noah’s error if his method is incorrect.

Hints

- Subtraction of several positive amounts can be rewritten by adding the amounts and subtracting their total. - Check whether each rewrite is equivalent to the original expression. - Compare \(-150 - 100\) with \(-(150 - 100)\).

Solution

1. Leo evaluates the subtraction from left to right and obtains \(500\), so his method is correct. 2. Mia combines all three amounts being subtracted: \(1000 - 250 - 150 - 100 = 1000 - (250 + 150 + 100) = 500\). Her method is also correct. 3. Noah replaces subtracting both \(150\) and \(100\) with subtracting their difference. However, \(-150 - 100\) is not equal to \(-(150 - 100)\). His result is incorrect.

Answer

Leo and Mia are correct. Noah is incorrect because he subtracts \(150 - 100\) instead of subtracting both \(150\) and \(100\).
Add and subtract rational numbers 224
A magician says, “Start with my secret number. Add \(2450\), subtract \(1100\), and then add \(325\). The result is the least five-digit whole number.” Find the secret number.

Hints

- First identify the least five-digit whole number. - Work backward and use the inverse of each operation. - Keep the place values aligned when calculating.

Solution

1. The least five-digit whole number is \(10{,}000\). 2. Work backward and undo adding \(325\): \(10{,}000 - 325 = 9675\). 3. Undo subtracting \(1100\): \(9675 + 1100 = 10{,}775\). 4. Undo adding \(2450\): \(10{,}775 - 2450 = 8325\). 5. Check: \(8325 + 2450 - 1100 + 325 = 10{,}000\).

Answer

\(8325\)
Add and subtract rational numbers 225
A research submersible is at \(-120\,\text{m}\), where sea level is \(0\,\text{m}\). It descends another \(150\,\text{m}\) to take a measurement, then rises \(40\,\text{m}\). What is the submersible's final position relative to sea level?

Hints

- Represent sea level with \(0\) on a number line. - How do descending and rising affect a signed number? - Break the motion into two calculations.

Solution

1. After descending, the position is \(-120-150=-270\), or \(-270\,\text{m}\). 2. After rising, the position is \(-270+40=-230\), or \(-230\,\text{m}\).

Answer

The submersible is at \(-230\,\text{m}\), which is \(230\,\text{m}\) below sea level.
Add and subtract rational numbers 226
Choose signs for \(20\) and \(45\) to make each equation true. Write the completed equation. a) \((\mathbin{\square}20)+(\mathbin{\square}45)=65\) b) \((\mathbin{\square}20)+(\mathbin{\square}45)=-25\) c) \((\mathbin{\square}20)+(\mathbin{\square}45)=25\) d) \((\mathbin{\square}20)+(\mathbin{\square}45)=-65\)

Hints

- Decide whether the target uses the sum or difference of the absolute values. - Equal signs add absolute values; unlike signs subtract them. - The addend with the greater absolute value determines the sign of a nonzero sum.

Solution

1. To get \(65\), both addends are positive: \(20+45=65\). 2. To get \(-25\), the greater absolute value must be negative: \(20+(-45)=-25\). 3. To get \(25\), the greater absolute value must be positive: \(-20+45=25\). 4. To get \(-65\), both addends are negative: \(-20+(-45)=-65\).

Answer

a) \(20+45=65\) b) \(20+(-45)=-25\) c) \(-20+45=25\) d) \(-20+(-45)=-65\)
Add and subtract rational numbers 227
Insert either \(+\) or \(-\) in each box to make the equation true. a) \((-18)\mathbin{\square}(-7)=-11\) b) \((+25)\mathbin{\square}(-5)=+30\) c) \((-40)\mathbin{\square}(+10)=-50\) d) \((+12)\mathbin{\square}(-12)=0\)

Hints

- Distinguish the operation sign between the numbers from the sign attached to each number. - Subtracting a negative number is the same as adding its opposite. - Test both operations and check the result.

Solution

1. In a), \(-18-(-7)=-11\), so the operation is subtraction. 2. In b), \(25-(-5)=30\), so the operation is subtraction. 3. In c), \(-40-(+10)=-50\), so the operation is subtraction. 4. In d), \(12+(-12)=0\), so the operation is addition.

Answer

a) \(-\) b) \(-\) c) \(-\) d) \(+\)
Add and subtract rational numbers 228
Insert the missing signs so that each equation is true. a) \((\bigcirc100)+(\bigcirc40)+(-20)=-80\) b) \((+50)+(\bigcirc30)+(\bigcirc10)=+10\)

Hints

- Work through each sum from left to right. - Compare the starting total with the target total. - Combine the terms whose signs are already known before choosing the missing signs.

Solution

1. In a), \(-100+40-20=-80\), so the signs are \(-\) and \(+\). 2. In b), \(50-30-10=10\), so both signs are \(-\).

Answer

a) \((-100)+(+40)+(-20)=-80\) b) \((+50)+(-30)+(-10)=+10\)
Add and subtract rational numbers 229
Estimate to decide which expression has the lesser value. Then calculate both values exactly. Expression 1: \(-3250+(-1780)\) Expression 2: \(-8410+3520\)

Hints

- Round each addend to the nearest thousand for the estimate. - Evaluate the expressions separately. - The negative value farther left is less.

Solution

1. Rounding to the nearest thousand gives about \(-3000+(-2000)=-5000\) for Expression 1 and \(-8000+4000=-4000\) for Expression 2, so Expression 1 should be less. 2. Exactly, Expression 1 is \(-3250-1780=-5030\). 3. Expression 2 is \(-8410+3520=-4890\). 4. Since \(-5030<-4890\), Expression 1 is less.

Answer

Expression 1 is less. Its exact value is \(-5030\), and Expression 2 equals \(-4890\).
Add and subtract rational numbers 230
Estimate by rounding each addend to the nearest thousand, and then evaluate \(-4890+(-3120)+6950\) exactly.

Hints

- Round each number to the nearest thousand. - Add the two negative numbers first. - Check that the exact value is close to the estimate.

Solution

1. The estimate is \(-5000+(-3000)+7000=-1000\). 2. The exact sum of the first two addends is \(-4890+(-3120)=-8010\). 3. Then \(-8010+6950=-1060\).

Answer

Estimate: \(-1000\) Exact value: \(-1060\)
Add and subtract rational numbers 231
Write an expression for each description and evaluate it. a) Find the difference of \(1500\) and \(850\), then subtract the opposite of \(150\). b) Add the absolute value of \(-75\) to the sum of \(-125\) and \(-200\).

Hints

- Evaluate the difference, sum, absolute value, and opposite separately. - Subtracting a negative is adding a positive. - Follow the order stated in each description.

Solution

1. In part a), \(1500-850=650\), and the opposite of \(150\) is \(-150\). Thus, \(650-(-150)=800\). 2. In part b), \(-125+(-200)=-325\), and \(|-75|=75\). Thus, \(-325+75=-250\).

Answer

a) \((1500-850)-(-150)=800\) b) \([-125+(-200)]+|-75|=-250\)
Add and subtract rational numbers 232
Subtract the sum of \(-48\) and \(122\) from the difference of \(300\) and \(-50\). Write and evaluate the expression.

Hints

- Identify which quantity is being subtracted from which. - Evaluate the two grouped expressions separately. - Then subtract the second result from the first.

Solution

1. The difference is \(300-(-50)=350\). 2. The sum is \(-48+122=74\). 3. Subtracting the sum from the difference gives \(350-74=276\).

Answer

\([300-(-50)]-[-48+122]=276\)
Add and subtract rational numbers 233
Match each sum to its exact result. Use estimation to find the pairs efficiently. Sums: a) \(-298+(-405)+(-102)\) b) \(-895+302+198\) c) \(512+(-251)+(-262)\) d) \(-1203+(-395)+(-102)\) Results: 1) \(-1\) 2) \(-1700\) 3) \(-805\) 4) \(-395\)

Hints

- Round to nearby hundreds. - Track the signs carefully. - Match each estimate before checking exactly.

Solution

1. Part a) is about \(-300-400-100=-800\), and exactly equals \(-805\), so it matches 3. 2. Part b) is about \(-900+300+200=-400\), and exactly equals \(-395\), so it matches 4. 3. Part c) is about \(500-250-250=0\), and exactly equals \(-1\), so it matches 1. 4. Part d) is about \(-1200-400-100=-1700\), and exactly equals \(-1700\), so it matches 2.

Answer

a) 3 b) 4 c) 1 d) 2
Add and subtract rational numbers 234
Decide whether each statement is true or false. Briefly explain. a) Start with any number, add \(12\), and then add the opposite of the original number. The result is always \(12\). b) The sum of a negative number and its opposite is always positive.

Hints

- Represent the original number with a variable. - Group a number with its opposite. - Remember that zero is not positive.

Solution

1. For any number \(n\), \(n+12+(-n)=12+[n+(-n)]=12\), so a) is true. 2. A number and its opposite sum to \(0\), which is neither positive nor negative. Therefore, b) is false.

Answer

a) True; \(n+12+(-n)=12\). b) False; a number and its opposite sum to \(0\).
Add and subtract rational numbers 235
Maya claims, “The sum of two negative integers is always less than either addend.” Test the claim using \(-7+(-3)\), and then explain whether it is always true.

Hints

- Calculate the example first. - Compare the sum with both addends. - Think about the direction of movement caused by adding a negative number.

Solution

1. \(-7+(-3)=-10\), and \(-10<-7\) and \(-10<-3\). 2. In general, adding a negative number moves left on a number line. Therefore, the sum of two negative integers lies to the left of each addend and is less than both.

Answer

The example gives \(-10\), which is less than both \(-7\) and \(-3\). The claim is always true because adding a negative integer decreases a number.
Add and subtract rational numbers 236
Let \(a=-8\) in \(a+b=s\). Give one integer value of \(b\) for each condition. a) \(s<a\) b) \(s=a\) c) \(s>a\)

Hints

- A negative addend moves the sum left. - Zero leaves a value unchanged. - A positive addend moves the sum right.

Solution

1. To make the sum less than \(-8\), choose any negative integer, such as \(b=-2\), giving \(-10<-8\). 2. To leave the value unchanged, choose \(b=0\). 3. To make the sum greater than \(-8\), choose any positive integer, such as \(b=5\), giving \(-3>-8\).

Answer

a) One answer is \(b=-2\). b) \(b=0\) c) One answer is \(b=5\).
Add and subtract rational numbers 237
Give one pair of integers with sum \(-32\) for each condition. a) Both addends are negative. b) The first addend is positive, and the second is negative. c) The first addend is negative, and the second is positive.

Hints

- For two negative addends, their absolute values must total \(32\). - With unlike signs, the negative addend must have the greater absolute value. - Many answers are possible.

Solution

1. Two negative addends can be \(-16\) and \(-16\), since \(-16+(-16)=-32\). 2. A positive first addend and negative second addend can be \(8\) and \(-40\), since \(8+(-40)=-32\). 3. A negative first addend and positive second addend can be \(-50\) and \(18\), since \(-50+18=-32\).

Answer

a) \(-16+(-16)=-32\) b) \(8+(-40)=-32\) c) \(-50+18=-32\)
Add and subtract rational numbers 238
A submarine's net vertical change is \(-80\,\text{m}\), where positive changes mean upward movement and negative changes mean downward movement. Give one addition equation for each situation. a) The submarine descends during both stages. b) The submarine rises during the first stage and descends during the second stage.

Hints

- Represent downward movement with a negative change and upward movement with a positive change. - Choose the first change, then find the second change needed for a total of \(-80\,\text{m}\). - Many answers are possible.

Solution

1. Two downward changes can be \(-30\,\text{m}\) and \(-50\,\text{m}\), giving \(-30+(-50)=-80\). 2. An upward change followed by a larger downward change can be \(20\,\text{m}\) and \(-100\,\text{m}\), giving \(20+(-100)=-80\).

Answer

a) One example is \((-30\,\text{m})+(-50\,\text{m})=-80\,\text{m}\). b) One example is \(20\,\text{m}+(-100\,\text{m})=-80\,\text{m}\).
Add and subtract rational numbers 239
Complete each equation so the sum is \(-50\). a) \(25+\square=-50\) b) \(-70+\square=-50\) c) \(\square+\square=-50\), using two identical addends.

Hints

- Use subtraction to find a missing addend. - Check the direction from the known value to \(-50\). - For equal addends, divide the target sum by \(2\).

Solution

1. In part a), the missing addend is \(-50-25=-75\). 2. In part b), the missing addend is \(-50-(-70)=20\). 3. Two equal addends must each be half of \(-50\), so each is \(-25\).

Answer

a) \(25+(-75)=-50\) b) \(-70+20=-50\) c) \(-25+(-25)=-50\)
Add and subtract rational numbers 240
Complete the calculation chain \(-120\xrightarrow{+45}\square\xrightarrow{-30}\square\xrightarrow{-(-60)}\square\).

Hints

- Work from left to right. - Treat each arrow as a new operation. - Subtracting a negative is adding a positive.

Solution

1. \(-120+45=-75\). 2. \(-75-30=-105\). 3. \(-105-(-60)=-105+60=-45\).

Answer

The intermediate values are \(-75\) and \(-105\), and the final value is \(-45\).
Add and subtract rational numbers 241
Each equation is missing both a sign attached to a number and an operation sign. Insert \(+\) or \(-\) to make each equation true. Find all possibilities. a) \((\square8)\mathbin{\bigcirc}(-12)=+20\) b) \((-25)\mathbin{\bigcirc}(\square15)=-10\) c) \((\square40)\mathbin{\bigcirc}(+60)=-20\)

Hints

- Test the possible sign and operation combinations systematically. - Keep the sign attached to the number separate from the operation sign. - Verify every combination that works so you find all solutions.

Solution

1. In a), the only solution is \((+8)-(-12)=20\). 2. In b), both \((-25)+(+15)=-10\) and \((-25)-(-15)=-10\) work. 3. In c), the only solution is \((+40)-(+60)=-20\).

Answer

a) \((+8)-(-12)=+20\) b) \((-25)+(+15)=-10\) or \((-25)-(-15)=-10\) c) \((+40)-(+60)=-20\)
Add and subtract rational numbers 242
Complete the subtraction table. Each entry is the row value minus the column value. <table> <tr><th colspan="2" rowspan="2"></th><th colspan="4">Number being subtracted</th></tr> <tr><th>\(15\)</th><th>\(-10\)</th><th>\(-35\)</th><th>\(60\)</th></tr> <tr><th rowspan="3">Starting number</th><th>\(-20\)</th><td></td><td></td><td></td><td></td></tr> <tr><th>\(45\)</th><td></td><td></td><td></td><td></td></tr> <tr><th>\(-80\)</th><td></td><td></td><td></td><td></td></tr> </table>

Hints

- Subtracting a negative number is the same as adding its opposite. - Think about which direction subtraction moves on a number line. - A result can be negative when the number being subtracted is greater than the starting number. - Work through one row at a time.

Solution

1. For the row beginning with \(-20\): \(-20-15=-35\), \(-20-(-10)=-10\), \(-20-(-35)=15\), and \(-20-60=-80\). 2. For the row beginning with \(45\): \(45-15=30\), \(45-(-10)=55\), \(45-(-35)=80\), and \(45-60=-15\). 3. For the row beginning with \(-80\): \(-80-15=-95\), \(-80-(-10)=-70\), \(-80-(-35)=-45\), and \(-80-60=-140\).

Answer

<table> <tr><th colspan="2" rowspan="2"></th><th colspan="4">Number being subtracted</th></tr> <tr><th>\(15\)</th><th>\(-10\)</th><th>\(-35\)</th><th>\(60\)</th></tr> <tr><th rowspan="3">Starting number</th><th>\(-20\)</th><td>\(-35\)</td><td>\(-10\)</td><td>\(15\)</td><td>\(-80\)</td></tr> <tr><th>\(45\)</th><td>\(30\)</td><td>\(55\)</td><td>\(80\)</td><td>\(-15\)</td></tr> <tr><th>\(-80\)</th><td>\(-95\)</td><td>\(-70\)</td><td>\(-45\)</td><td>\(-140\)</td></tr> </table>
Add and subtract rational numbers 243
Evaluate \((-128)-[(+52)+(-97)]\).

Hints

- Use the order of operations. - Evaluate the expression inside the brackets first. - Replace the bracketed expression with its value before continuing.

Solution

1. Evaluate inside the brackets: \(52+(-97)=-45\). 2. Substitute the result: \(-128-(-45)\). 3. Rewrite the subtraction and evaluate: \(-128+45=-83\).

Answer

\(-83\)
Add and subtract rational numbers 244
Evaluate \([(-34)+(+86)]-[(-42)-(+58)]\) step by step.

Hints

- Break the expression into two smaller calculations. - Evaluate each bracketed expression separately. - Keep track of both intermediate results before the final subtraction. - Subtracting a negative number is the same as adding a positive number.

Solution

1. Evaluate the first bracketed expression: \(-34+86=52\). 2. Evaluate the second bracketed expression: \(-42-58=-100\). 3. Subtract the two results: \(52-(-100)=52+100=152\).

Answer

\(152\)
Add and subtract rational numbers 245
Use the numbers \(-34\) and \(-16\). a) Find their sum. b) Subtract the sum from the opposite of \(50\). What is the result?

Hints

- A sum is the result of addition. - The opposite of a number is the same distance from zero on the other side. - Pay close attention to the signs and parentheses in part b).

Solution

1. The sum is \((-34)+(-16)=-50\). 2. The opposite of \(50\) is \(-50\). 3. Subtract the sum from that number: \(-50-(-50)=0\).

Answer

a) \(-50\) b) \(0\)
Add and subtract rational numbers 246
Use the numbers \(12\) and \(-18\). First find their sum and their difference, in that order. Then subtract the difference from the sum. What is the final result?

Hints

- Find the sum and the difference separately. - Subtracting a negative number is the same as adding a positive number. - Read carefully to determine which value is subtracted from which.

Solution

1. The sum is \(12+(-18)=-6\). 2. The difference is \(12-(-18)=30\). 3. Subtract the difference from the sum: \(-6-30=-36\).

Answer

Sum: \(-6\) Difference: \(30\) Final result: \(-36\)
Add and subtract rational numbers 247
On a cold January day, temperatures are recorded at two locations in the mountains. At noon, the mountain station is \(-11\,^\circ\text{F}\), and at night it is \(-24\,^\circ\text{F}\). In the valley, the temperature is \(4\,^\circ\text{F}\) at noon and \(-6\,^\circ\text{F}\) at night. a) For each location, by how many degrees Fahrenheit did the temperature decrease from noon to night? b) Find the temperature difference between the mountain station and the valley at noon and at night.

Hints

- Picture the temperatures on a vertical number line, like a thermometer. - A temperature difference is the distance between two values. - Notice whether both values are negative or whether the interval crosses zero. - To find the size of a decrease, subtract the lower final value from the higher initial value.

Solution

1. At the mountain station, the decrease is \(-11-(-24)=13\), so the temperature decreased by \(13\,^\circ\text{F}\). 2. In the valley, the decrease is \(4-(-6)=10\), so the temperature decreased by \(10\,^\circ\text{F}\). 3. At noon, the difference is \(4-(-11)=15\,^\circ\text{F}\). 4. At night, the difference is \(-6-(-24)=18\,^\circ\text{F}\).

Answer

a) Mountain station: \(13\,^\circ\text{F}\); valley: \(10\,^\circ\text{F}\) b) Noon: \(15\,^\circ\text{F}\); night: \(18\,^\circ\text{F}\)
Add and subtract rational numbers 248
Complete the account table. In each row, an amount is withdrawn from the previous balance to produce the new balance. <table> <tr><th>Previous balance</th><th>Withdrawal</th><th>New balance</th></tr> <tr><td>\(\$12\)</td><td>\(\$20\)</td><td>(1)</td></tr> <tr><td>\(-\$8\)</td><td>\(\$15\)</td><td>(2)</td></tr> <tr><td>(3)</td><td>\(\$25\)</td><td>\(-\$10\)</td></tr> </table>

Hints

- A withdrawal decreases the balance. - Use an inverse operation to find a missing previous balance. - Pay close attention to the sign when the account already has a negative balance.

Solution

1. For (1), \(12-20=-8\), so the new balance is \(-\$8\). 2. For (2), \(-8-15=-23\), so the new balance is \(-\$23\). 3. For (3), let the previous balance be \(x\). Solve \(x-25=-10\), which gives \(x=15\).

Answer

(1) \(-\$8\) (2) \(-\$23\) (3) \(\$15\)
Add and subtract rational numbers 249
Evaluate each difference, and then insert \(<\), \(>\), or \(=\) to make a true statement. a) \((-12)-8\mathbin{\square}-12\) b) \((-12)-(-8)\mathbin{\square}-12\) c) \(15-15\mathbin{\square}15\) d) \(15-(-15)\mathbin{\square}15\)

Hints

- Evaluate the expression on the left first. - Pay close attention when subtracting a negative number. - On a number line, the number farther right is greater.

Solution

1. In a), \(-12-8=-20\), and \(-20<-12\). 2. In b), \(-12-(-8)=-4\), and \(-4>-12\). 3. In c), \(15-15=0\), and \(0<15\). 4. In d), \(15-(-15)=30\), and \(30>15\).

Answer

a) \(<\) b) \(>\) c) \(<\) d) \(>\)
Add and subtract rational numbers 250
Consider the two expressions. Expression \(A\): \((-40)-25\) Expression \(B\): \((-40)-(-25)\) Without calculating exact values, explain which expression is greater. Use what you know about subtracting integers and compare each result with \(-40\).

Hints

- Think about movement on a number line rather than calculating. - What happens when a positive number is subtracted? - What happens when a negative number is subtracted? - Compare both changes from the same starting value, \(-40\).

Solution

1. In Expression \(A\), a positive number is subtracted from \(-40\), so the result is less than \(-40\). 2. In Expression \(B\), a negative number is subtracted. This is equivalent to adding \(25\), so the result is greater than \(-40\). 3. Therefore, Expression \(B\) is greater.

Answer

Expression \(B\) is greater. Subtracting \(25\) makes \(-40\) smaller, while subtracting \(-25\) is the same as adding \(25\), which makes \(-40\) greater.
Add and subtract rational numbers 251
Evaluate each expression with three numbers. First rewrite it without parentheses using simplified notation. a) \((-15)+(+25)-(-10)\) b) \((+40)-(+60)+(-20)\) c) \((-100)-(-30)-(+70)\)

Hints

- Rewrite all signed numbers before calculating. - Subtracting a negative number becomes addition. - After simplifying the notation, combine the numbers from left to right or in convenient groups.

Solution

1. In a), \(-15+25+10=20\). 2. In b), \(40-60-20=-40\). 3. In c), \(-100+30-70=-140\).

Answer

a) \(-15+25+10=20\) b) \(40-60-20=-40\) c) \(-100+30-70=-140\)
Add and subtract rational numbers 252
Start at \(-50\) and perform these operations in order: 1. Subtract \(-30\). 2. Add \(-45\). 3. Subtract \(+15\). Write one expression with parentheses, simplify it, and find the final value.

Hints

- Translate each instruction into one operation in a single expression. - Subtracting a negative number becomes addition. - Perform the operations in order after simplifying the signs.

Solution

1. The expression is \(-50-(-30)+(-45)-(+15)\). 2. Simplify the signs: \(-50+30-45-15\). 3. Evaluate: \(-50+30=-20\), \(-20-45=-65\), and \(-65-15=-80\).

Answer

Expression: \(-50-(-30)+(-45)-(+15)\) Simplified: \(-50+30-45-15\) Final value: \(-80\)
Add and subtract rational numbers 253
Rewrite the expression as a sum. Then show an equivalent rearrangement and grouping that creates convenient partial sums before finding the final value. \(-2650+1433-350+567\)

Hints

- Rewrite every subtraction as addition of the opposite. - Keep each sign attached to its term while rearranging. - Compare possible pairings and choose ones that make the arithmetic simpler.

Solution

1. Rewrite subtraction as addition of the opposite: \(-2650+1433+(-350)+567\). 2. Rearrange and group: \((-2650-350)+(1433+567)\). 3. Evaluate the groups: \(-3000+2000=-1000\).

Answer

Sum form: \(-2650+1433+(-350)+567\) One valid efficient regrouping: \((-2650-350)+(1433+567)\) Value: \(-1000\)
Add and subtract rational numbers 254
Compare the values and insert \(<\), \(>\), or \(=\) in each box. a) \(18-30\mathbin{\square}-18+30\) b) \(-50-(-20)\mathbin{\square}-50+20\) c) \(45-(10+50)\mathbin{\square}45-10-50\) d) \(-(25-5)\mathbin{\square}-25-5\)

Hints

- Evaluate the left and right sides separately. - Pay close attention to a negative sign outside parentheses. - On a number line, the number farther right is greater.

Solution

1. In a), the values are \(-12\) and \(12\), so use \(<\). 2. In b), both sides equal \(-30\), so use \(=\). 3. In c), both sides equal \(-15\), so use \(=\). 4. In d), the values are \(-20\) and \(-30\), so use \(>\).

Answer

a) \(<\) b) \(=\) c) \(=\) d) \(>\)
Add and subtract rational numbers 255
Three expressions have the same value. Which expression does not belong? Justify your choice by evaluating all four. A) \(-22+10-8\) B) \(-22+(8-10)\) C) \(10-(22+8)\) D) \(-(22-10)-8\)

Hints

- Evaluate each expression carefully using the order of operations. - Record the sign of each intermediate value. - Compare all four final values.

Solution

1. A has value \(-22+10-8=-20\). 2. B has value \(-22+(8-10)=-24\). 3. C has value \(10-(22+8)=-20\). 4. D has value \(-(22-10)-8=-20\). 5. Expression B is the only expression with a different value.

Answer

Expression B does not belong. Its value is \(-24\), while A, C, and D each have value \(-20\).
Add and subtract rational numbers 256
Rewrite each expression as a sum, and then evaluate. a) \(25{,}000-60{,}000\) b) \(-10^4-5000\) c) \(8800-(-1200)\) d) \(-10^6-(-10^5)\)

Hints

- Write each power of ten as an ordinary number first. - Keep track of the zeros in large numbers. - To subtract a number, add its opposite.

Solution

1. In a), \(25{,}000+(-60{,}000)=-35{,}000\). 2. In b), \(-10^4=-10{,}000\), so \((-10{,}000)+(-5000)=-15{,}000\). 3. In c), \(8800+1200=10{,}000\). 4. In d), \(-10^6=-1{,}000{,}000\) and \(-(-10^5)=100{,}000\), so \(-1{,}000{,}000+100{,}000=-900{,}000\).

Answer

a) \(25{,}000+(-60{,}000)=-35{,}000\) b) \(-10^4+(-5000)=-15{,}000\) c) \(8800+1200=10{,}000\) d) \(-10^6+10^5=-900{,}000\)
Add and subtract rational numbers 257
Mr. Schmidt pays a \(\$545\) bill from his checking account. Soon afterward, a credit of \(\$210\) is deposited. His balance is then exactly \(-\$185\). What was his account balance before these two transactions?

Hints

- Determine the combined effect of the two transactions. - You can also undo the transactions in reverse order, starting from the final balance. - A bill decreases the balance, while a credit increases it.

Solution

1. The net change is \(-545+210=-335\). 2. Let \(x\) be the initial balance. Then \(x-335=-185\). 3. Add \(335\) to both sides: \(x=-185+335=150\). 4. Check: \(150-545+210=-185\).

Answer

The account balance before the transactions was \(\$150\).
Add and subtract rational numbers 258
An elevator in a parking garage first travels up \(5\) levels and then down \(8\) levels. It ends on Level \(-2\). On which level did the elevator start?

Hints

- Picture the garage levels as a vertical number line. - Combine the upward and downward movements into one net change. - Starting from the ending level, reverse the net change.

Solution

1. The total change is \(5-8=-3\), so the elevator ends \(3\) levels below where it started. 2. Let \(x\) be the starting level. Then \(x-3=-2\). 3. Add \(3\) to both sides: \(x=1\).

Answer

The elevator started on Level \(1\).
Add and subtract rational numbers 259
First estimate by rounding each number to the nearest ten. Then evaluate efficiently by rearranging and grouping terms. \(48+63-28+36-76\)

Hints

- Look for numbers that combine to make convenient multiples of \(10\) or \(100\). - When rearranging, keep each number together with the sign before it. - Numbers with the same ones digit may be easy to subtract.

Solution

1. Estimate: \(50+60-30+40-80=40\). 2. Rearrange and group: \((48-28)+(63+36)-76\). 3. Evaluate: \(20+99-76=43\).

Answer

Estimate: \(40\) One efficient grouping: \((48-28)+(63+36)-76\) Exact value: \(43\)
Add and subtract rational numbers 260
First make a reasonable estimate. Then evaluate efficiently by grouping positive and negative numbers. \(-135+420-66+580-293\)

Hints

- Group the terms with negative signs. - Look for pairs that combine to make convenient multiples of \(100\). - Then combine the positive total and the negative total.

Solution

1. Estimate by rounding to the nearest hundred: \(-100+400-100+600-300=500\). 2. Group the negative terms: \(-135-66=-201\). 3. Group the positive terms: \(420+580=1000\). 4. Combine the results: \(1000-201-293=506\).

Answer

Estimate: \(\approx 500\) One efficient grouping: \((420+580)+(-135-66-293)=1000-494=506\) Exact value: \(506\)
Add and subtract rational numbers 261
Make a reasonable estimate, and then evaluate efficiently by rearranging or grouping terms. \(2750-438-1250+637-475\)

Hints

- Look for two large values that nearly cancel when subtracted. - Keep each number together with the sign before it when rearranging. - Group terms so that the intermediate values are easy to calculate.

Solution

1. Estimate by rounding to the nearest hundred: \(2800-400-1300+600-500=1200\). 2. Rearrange and group: \((2750-1250)+(637-438)-475\). 3. Evaluate: \(1500+199-475=1224\).

Answer

Estimate: \(\approx 1200\) One efficient grouping: \((2750-1250)+(637-438)-475\) Exact value: \(1224\)
Add and subtract rational numbers 262
Rewrite without parentheses using simplified notation, and then evaluate: \(1000-(-450)+(-1250)-(+200)\).

Hints

- Replace each subtraction of a negative number with addition. - Group positive and negative terms separately. - Equal opposite amounts cancel to zero.

Solution

1. Rewrite the expression as \(1000+450-1250-200\). 2. Group the positive terms and the negative terms: \((1000+450)-(1250+200)\). 3. Both groups equal \(1450\), so the result is \(0\).

Answer

\(1000+450-1250-200=0\)
Add and subtract rational numbers 263
Consider the expression \(-45+128-55+72\). a) Evaluate the expression efficiently by grouping terms. b) Replace the last number so that the expression has a value of \(0\). What should the new number be?

Hints

- Look for pairs that combine easily. - Keep track of the sign before each number. - Which number is still unknown after you set the total equal to zero?

Solution

1. For a), group convenient terms: \((-45-55)+(128+72)=-100+200=100\). 2. For b), the first three terms total \(-45+128-55=28\). 3. The new last number \(x\) must satisfy \(28+x=0\), so \(x=-28\).

Answer

a) \((-45-55)+(128+72)=100\) b) \(-28\)
Add and subtract rational numbers 264
Consider the expression \(1250-3400+750-600\). a) Evaluate it efficiently by grouping terms. b) If \(-3400\) changes to \(+3400\), by how much does the result change? What is the new result? Explain without repeating the entire calculation.

Hints

- Look for positive and negative terms that combine easily. - How far apart are a negative number and its positive opposite? - Use the result from a) instead of starting the whole sum again.

Solution

1. For a), group the positive terms: \((1250+750)-3400-600=2000-4000=-2000\). 2. Changing a term from \(-3400\) to \(+3400\) increases the sum by \(3400+3400=6800\). 3. The new result is \(-2000+6800=4800\).

Answer

a) \((1250+750)-(3400+600)=-2000\) b) Changing \(-3400\) to \(+3400\) increases the sum by \(3400-(-3400)=6800\), so the new result is \(-2000+6800=4800\).
Add and subtract rational numbers 265
Evaluate each expression step by step. Follow the order of operations. a) \(26-[(41-55)+(82-14)]\) b) \([-18+(72-95)]-(31+29)\)

Hints

- Evaluate the innermost parentheses first. - Replace each set of parentheses with its value before continuing. - Keep careful track of signs in the final subtraction.

Solution

1. In a), \(41-55=-14\) and \(82-14=68\). Then \(-14+68=54\), so \(26-54=-28\). 2. In b), \(72-95=-23\). Then \(-18+(-23)=-41\), and \(31+29=60\). Finally, \(-41-60=-101\).

Answer

a) \(-28\) b) \(-101\)
Add and subtract rational numbers 266
Evaluate each expression using the order of operations. a) \(-32-(74+26)+(-85+35)\) b) \((-94-126)-(-52+318)\)

Hints

- Evaluate each parenthetical expression first. - Pay close attention to subtraction between two grouped expressions. - Write down intermediate values to reduce sign errors.

Solution

1. In a), \(74+26=100\) and \(-85+35=-50\). Then \(-32-100+(-50)=-182\). 2. In b), \(-94-126=-220\) and \(-52+318=266\). Then \(-220-266=-486\).

Answer

a) \(-182\) b) \(-486\)
Add and subtract rational numbers 267
Evaluate \(-240+115+(-60)+85\) efficiently. Name the properties used to regroup the addends.

Hints

- Look for pairs that make convenient hundreds. - Addition allows addends to be reordered and regrouped. - Combine the negative and positive partial sums last.

Solution

1. Use the commutative property to reorder and the associative property to regroup: \([-240+(-60)]+[115+85]\). 2. The partial sums are \(-300\) and \(200\). 3. Therefore, the value is \(-300+200=-100\).

Answer

The value is \(-100\). The commutative and associative properties of addition are used.
Add and subtract rational numbers 268
Evaluate efficiently by rearranging and grouping terms: \(781-495-281+195-100\).

Hints

- Look for numbers with matching ending digits. - Keep each number together with its sign when rearranging. - Form groups that are easy to evaluate mentally.

Solution

1. Rewrite the expression as a sum: \(781+(-495)+(-281)+195+(-100)\). 2. Rearrange and group: \((781-281)+(-495+195)-100\). 3. Evaluate: \(500-300-100=100\).

Answer

\((781-281)+(-495+195)-100=100\)
Add and subtract rational numbers 269
Evaluate \((12-45)-(150+5)\).

Hints

- Evaluate the two parenthetical expressions separately. - In the final step, a positive number is being subtracted from a negative number.

Solution

1. Evaluate the first parentheses: \(12-45=-33\). 2. Evaluate the second parentheses: \(150+5=155\). 3. Subtract the results: \(-33-155=-188\).

Answer

\(-188\)
Add and subtract rational numbers 270
Evaluate \(-(240-1240)-65\).

Hints

- Evaluate the difference inside the parentheses first. - The negative sign outside the parentheses means take the opposite of the value inside. - Then subtract \(65\).

Solution

1. Evaluate inside the parentheses: \(240-1240=-1000\). 2. Take the opposite of the parenthetical value: \(-(-1000)=1000\). 3. Subtract \(65\): \(1000-65=935\).

Answer

\(935\)
Add and subtract rational numbers 271
Consider the expression \((-15)+(-5)-(+12)-(-8)\). a) Evaluate the expression step by step. b) Add parentheses to form \((-15)+(-5)-((+12)-(-8))\). Evaluate the new expression and compare it with the result from part a).

Hints

- Evaluate parentheses before the rest of the expression. - A subtraction sign before a grouped expression affects the entire value of that group. - Evaluate the original and modified expressions separately before comparing them.

Solution

1. In a), \(-15-5-12+8=-24\). 2. In b), evaluate the new parentheses first: \(12-(-8)=20\). 3. Then \(-15-5-20=-40\). 4. The value changed from \(-24\) to \(-40\), so it decreased by \(16\).

Answer

a) \(-24\) b) \(-40\); the value is \(16\) less than the original value.
Add and subtract rational numbers 272
During one level of a video game, Tim's score changes several times. He first earns \(120\) bonus points, then loses \(250\) points, and finally earns another \(40\) points. His score at the end of the level is \(-30\). What was Tim's score at the beginning of the level?

Hints

- Calculate the total change in the score. - You can work backward from the final score one change at a time. - Decide whether the beginning score must have been greater or less than the ending score.

Solution

1. Find the total change in the score: \(120-250+40=-90\). 2. Let \(x\) be the beginning score. Then \(x-90=-30\). 3. Add \(90\) to both sides: \(x=-30+90=60\).

Answer

Tim began the level with \(60\) points.
Add and subtract rational numbers 273
Lena has four number cards: \(16\), \(8\), \(-8\), and \(24\). She may use addition, subtraction, and parentheses. Use all four cards exactly once in each expression. Write two expressions that each equal \(24\), using parentheses in at least one of them.

Hints

- Every card must appear once, so a single card cannot be the whole answer. - Look for parts that cancel each other or combine into convenient totals. - When subtracting a group in parentheses, pay attention to every sign inside it.

Solution

1. One expression is \(24+16-8+(-8)=24\): the last three terms combine to \(0\). 2. Another expression is \((24+16)-(8-(-8))=40-16=24\). 3. Each expression uses all four cards exactly once.

Answer

Two possible expressions are \(24+16-8+(-8)=24\) and \((24+16)-(8-(-8))=24\).
Add and subtract rational numbers 274
At \(6{:}00\) a.m., the temperature is \(-4\,^\circ\text{F}\). It then rises \(7\,^\circ\text{F}\), falls \(2\,^\circ\text{F}\), rises \(3\,^\circ\text{F}\), falls \(8\,^\circ\text{F}\), and falls another \(5\,^\circ\text{F}\). Find the final temperature. Calculate efficiently.

Hints

- Group positive and negative changes. - Look for values that cancel. - Combine the remaining changes with the starting temperature.

Solution

1. The total is \(-4+7-2+3-8-5\). 2. Group \(7+3=10\) and \(-2-8=-10\), which cancel. 3. The remaining value is \(-4-5=-9\).

Answer

\(-9\,^\circ\text{F}\)
Add and subtract rational numbers 275
A research submarine starts at \(-1250\,\text{m}\) relative to sea level. It rises \(450\,\text{m}\), descends \(200\,\text{m}\), rises \(800\,\text{m}\), and descends \(150\,\text{m}\). Find its new position. Calculate efficiently.

Hints

- Combine the upward changes. - Compare their total with the starting depth. - Then account for the remaining descents.

Solution

1. The total is \(-1250+450-200+800-150\). 2. The rises total \(450+800=1250\), which cancels the starting position. 3. The remaining changes are \(-200-150=-350\).

Answer

The submarine is at \(-350\,\text{m}\), or \(350\,\text{m}\) below sea level.
Add and subtract rational numbers 276
A club account starts at \(-\$240\). During the quarter, it receives \(\$1550\) in dues, pays \(\$600\) in rent, spends \(\$760\) on equipment, receives a \(\$450\) donation, and pays \(\$300\) for an event. Find the new balance. Calculate efficiently.

Hints

- Group income and expenses. - Look for amounts that make convenient hundreds or thousands. - Combine all signed changes with the starting balance.

Solution

1. The balance is \(-240+1550-600-760+450-300\). 2. Group \(-240-760=-1000\), \(1550+450=2000\), and \(-600-300=-900\). 3. Then \(2000-1000-900=100\).

Answer

The new balance is \(\$100\).
Add and subtract rational numbers 277
Let \(a=-45\), \(b=20\), and \(c=-30\). a) Write and evaluate an expression that subtracts \(c\) from the sum of \(a\) and \(b\). b) Write and evaluate an expression that subtracts the sum of \(a\) and \(b\) from \(c\). c) Compare the results. What general observation can you make?

Hints

- Write each expression with variables before substituting values. - Use parentheses around the sum that is subtracted as a group. - Compare the two results and their signs.

Solution

1. In a), \((a+b)-c=(-45+20)-(-30)=-25+30=5\). 2. In b), \(c-(a+b)=-30-(-45+20)=-30-(-25)=-5\). 3. The results are opposites. In general, reversing the order of a subtraction changes the sign of the difference.

Answer

a) \((-45+20)-(-30)=5\) b) \(-30-(-45+20)=-5\) c) The results are opposites. Reversing the order of a subtraction negates the difference.
Add and subtract rational numbers 278
Which tasks have equal values? Sort the letters into the groups with values \(-25\) and \(-55\). (A) \(-40+15\) (B) \(-40-(-15)\) (C) Subtract \(15\) from \(-40\). (D) Add \(-15\) to \(-40\). (E) \(-40-15\) (F) Add \(15\) to \(-40\). (G) Subtract \(-15\) from \(-40\).

Hints

- Translate each verbal description into an expression. - Subtracting a negative number is the same as adding a positive number. - Evaluate each task before grouping the letters.

Solution

1. A, B, F, and G each equal \(-25\). 2. C, D, and E each equal \(-55\). 3. “Subtract \(x\) from \(y\)” means \(y-x\), while “add \(x\) to \(y\)” means \(y+x\).

Answer

Value \(-25\): A, B, F, G Value \(-55\): C, D, E
Add and subtract rational numbers 279
Evaluate each expression. a) \(-12{,}450+5670\) b) \(34{,}200-(-8950)\) c) \(-7300-12{,}800\) d) \(10^4-100{,}000\)

Hints

- Distinguish signs attached to numbers from operation signs. - Subtracting a negative number becomes addition. - Evaluate the power of ten before subtracting.

Solution

1. In a), \(-12{,}450+5670=-6780\). 2. In b), \(34{,}200-(-8950)=34{,}200+8950=43{,}150\). 3. In c), \(-7300-12{,}800=-20{,}100\). 4. In d), \(10^4=10{,}000\), so \(10{,}000-100{,}000=-90{,}000\).

Answer

a) \(-6780\) b) \(43{,}150\) c) \(-20{,}100\) d) \(-90{,}000\)
Add and subtract rational numbers 280
Insert \(<\), \(>\), or \(=\) to make each statement true. a) \(-3500+1200\mathbin{\square}-3500-1200\) b) \(-800-450\mathbin{\square}-800-(-450)\) c) \(15{,}000-25{,}000\mathbin{\square}-5000-6000\) d) \(-10^3+1\mathbin{\square}0\)

Hints

- Evaluate both sides separately. - For negative numbers, the value with the greater absolute value is smaller. - Compare the results on a number line.

Solution

1. In a), the values are \(-2300\) and \(-4700\), so use \(>\). 2. In b), the values are \(-1250\) and \(-350\), so use \(<\). 3. In c), the values are \(-10{,}000\) and \(-11{,}000\), so use \(>\). 4. In d), \(-10^3+1=-999\), so use \(<\).

Answer

a) \(>\) b) \(<\) c) \(>\) d) \(<\)
Add and subtract rational numbers 281
Write an expression and evaluate it. From the sum of \(-412\) and \(187\), subtract the difference of \(-256\) and \(-58\).

Hints

- Translate “sum” and “difference” into operations. - Use parentheses to keep the two intermediate expressions separate. - The wording “from the sum, subtract the difference” determines the order.

Solution

1. The sum is \(-412+187=-225\). 2. The difference is \(-256-(-58)=-198\). 3. Subtract the results: \(-225-(-198)=-27\).

Answer

\((-412+187)-(-256-(-58))=-27\)
Add and subtract rational numbers 282
Leon claims, “When I subtract a negative number from another negative number, the result is always negative.” Disprove his claim with two examples: 1. One example with a positive result. 2. One example with a result of \(0\). Evaluate both differences.

Hints

- Rewrite subtraction of a negative number as addition. - Try negative numbers with different absolute values. - A number minus itself equals zero.

Solution

1. For a positive result, the number being subtracted can have a greater absolute value than the starting number. For example, \((-2)-(-5)=3\). 2. For a result of zero, subtract a negative number from itself. For example, \((-8)-(-8)=0\). 3. Since neither result is negative, the examples disprove the claim.

Answer

Possible examples are: 1. \((-2)-(-5)=3\) 2. \((-8)-(-8)=0\)
Add and subtract rational numbers 283
Consider \((-14)-(-20)\). a) Evaluate the difference. b) Explain why the result is positive even though both numbers in the expression are negative.

Hints

- Rewrite subtraction of a negative as addition. - Picture the calculation as movement on a number line. - Compare the absolute values of \(-14\) and \(20\).

Solution

1. Rewrite the subtraction: \((-14)-(-20)=-14+20\). 2. Evaluate: \(-14+20=6\). 3. The result is positive because adding \(20\) moves \(20\) units right from \(-14\), crossing zero and ending at \(6\).

Answer

a) \(6\) b) Subtracting \(-20\) is the same as adding \(20\). Since \(20>14\), the result is positive.
Add and subtract rational numbers 284
Use the numbers \(-6\) and \(-10\). 1. Evaluate \((-6)-(-10)\). 2. Evaluate \((-10)-(-6)\). Compare the results. What do you notice about their signs?

Hints

- Rewrite each subtraction of a negative number as addition. - Compare both the signs and absolute values of the results. - Think about what happens when the order in a subtraction is reversed.

Solution

1. \((-6)-(-10)=-6+10=4\). 2. \((-10)-(-6)=-10+6=-4\). 3. The results have the same absolute value but opposite signs. Reversing the order of a subtraction negates the difference.

Answer

1. \(4\) 2. \(-4\) The results have equal absolute values and opposite signs.
Add and subtract rational numbers 285
Write an expression for the description and evaluate it. Subtract \(-150\) from the sum of \(-65\) and \(38\).

Hints

- Translate “sum” into addition. - The wording “subtract \(-150\) from” determines the order. - Subtracting a negative number is the same as adding a positive number.

Solution

1. The expression is \((-65+38)-(-150)\). 2. The sum is \(-65+38=-27\). 3. Then \(-27-(-150)=-27+150=123\).

Answer

\((-65+38)-(-150)=123\)
Add and subtract rational numbers 286
Write an expression for the description and evaluate it. Add the difference of \(16\) and \(-34\) to the difference of \(210\) and \(450\).

Hints

- Separate the description into two differences. - “The difference of \(a\) and \(b\)” means \(a-b\). - Evaluate each grouped difference before adding them.

Solution

1. The expression is \((210-450)+[16-(-34)]\). 2. The first difference is \(210-450=-240\). 3. The second difference is \(16-(-34)=50\). 4. Add the results: \(-240+50=-190\).

Answer

\((210-450)+[16-(-34)]=-190\)
Add and subtract rational numbers 287
Rewrite the expression to make it easy to evaluate. Keep each operation sign with its number when you reorder the terms. \(864 + 257 - 364 + 43\)

Hints

- Look for two numbers with matching final digits that make an easy difference. - Look for two addends that make a multiple of \(100\). - When reordering, move each operation sign with the term that follows it.

Solution

1. Reorder the terms: \(864 - 364 + 257 + 43\). 2. Group convenient pairs: \((864 - 364) + (257 + 43)\). 3. Evaluate: \(500 + 300 = 800\).

Answer

\((864-364)+(257+43)=800\)
Add and subtract rational numbers 288
Evaluate \(30-[(-12+25)-(8-15)]\).

Hints

- Work from the innermost grouping symbols outward. - Write each intermediate value to keep track of the signs. - Subtracting a negative number is the same as adding a positive number.

Solution

1. Evaluate the inner parentheses: \(-12+25=13\) and \(8-15=-7\). 2. Evaluate the brackets: \(13-(-7)=20\). 3. Complete the calculation: \(30-20=10\).

Answer

\(10\)
Add and subtract rational numbers 289
Evaluate each expression using the order of operations. a) \(84-(112-250)\) b) \(-37+(-44+19)+60\) c) \(-(55-92)-(18+24)\)

Hints

- Evaluate parentheses first. - A negative sign outside parentheses takes the opposite of the parenthetical value. - Write each intermediate value before continuing.

Solution

1. In a), \(112-250=-138\), so \(84-(-138)=222\). 2. In b), \(-44+19=-25\), so \(-37-25+60=-2\). 3. In c), \(55-92=-37\) and \(18+24=42\), so \(-(-37)-42=-5\).

Answer

a) \(222\) b) \(-2\) c) \(-5\)
Add and subtract rational numbers 290
Evaluate each expression with nested grouping symbols. a) \(15-[32-(14-50)]\) b) \(-21+[(-45+18)-(-12)]\)

Hints

- Work from the innermost grouping symbols outward. - Record each intermediate result. - Pay close attention when subtracting a negative value.

Solution

1. In a), \(14-50=-36\). Then \(32-(-36)=68\), and \(15-68=-53\). 2. In b), \(-45+18=-27\). Then \(-27-(-12)=-15\), and \(-21+(-15)=-36\).

Answer

a) \(-53\) b) \(-36\)
Add and subtract rational numbers 291
Evaluate \(-35-(15-60)+(-20)\).

Hints

- Evaluate the parentheses first. - Subtracting a negative number becomes addition. - Work one operation at a time.

Solution

1. Evaluate inside the parentheses: \(15-60=-45\). 2. Substitute the result: \(-35-(-45)+(-20)\). 3. Evaluate: \(-35+45-20=-10\).

Answer

\(-10\)
Add and subtract rational numbers 292
Evaluate \((120-250)+(85-(-15))\) step by step.

Hints

- Evaluate the two parenthetical expressions separately. - Subtracting a negative number becomes addition. - Add the two intermediate results with their signs.

Solution

1. Evaluate the first parentheses: \(120-250=-130\). 2. Evaluate the second parentheses: \(85-(-15)=100\). 3. Add the results: \(-130+100=-30\).

Answer

\(-30\)
Add and subtract rational numbers 293
Evaluate \(15-[20+(5-15)]\) step by step.

Hints

- Evaluate the innermost parentheses first. - Keep the sign of the parenthetical result when adding it inside the brackets. - Finish with the subtraction outside the brackets.

Solution

1. Evaluate the inner parentheses: \(5-15=-10\). 2. Evaluate the brackets: \(20+(-10)=10\). 3. Complete the calculation: \(15-10=5\).

Answer

\(5\)
Add and subtract rational numbers 294
Rewrite the expression to make it easy to evaluate. Keep each operation sign with its number when reordering the terms. \(45 - 17 + 55 - 83 + 12\)

Hints

- Group terms to create multiples of \(100\). - Keep each subtraction sign with the number that follows it. - Find the total of the positive terms and the total being subtracted.

Solution

1. Group the positive terms and the amounts being subtracted: \((45 + 55 + 12) - (17 + 83)\). 2. Evaluate the groups: \(112 - 100 = 12\).

Answer

\((45+55+12)-(17+83)=12\)
Add and subtract rational numbers 295
A checking account begins with a balance of \(\$120\). During the morning, \(\$150\) is withdrawn for a purchase, and then another \(\$40\) is withdrawn at an ATM. Use subtraction expressions to find the balance after each withdrawal.

Hints

- A withdrawal decreases the balance. - Find the balance after the first transaction before applying the second. - Spending more money when the balance is already negative makes the balance more negative.

Solution

1. After the purchase, \(120-150=-30\), so the balance is \(-\$30\). 2. After the ATM withdrawal, \(-30-40=-70\), so the balance is \(-\$70\).

Answer

After the purchase: \(\$120-\$150=-\$30\) After the ATM withdrawal: \(-\$30-\$40=-\$70\)
Add and subtract rational numbers 296
Use the numbers \(-12,7,-3,0,-8,2\). a) Order them from greatest to least. b) Which two different numbers give the smallest sum? Write the addition equation. c) Subtract the smallest number from the greatest number. Write the subtraction equation.

Hints

- Place the numbers in order before choosing which to use. - What happens when you add two negative numbers? - In c), keep the sign of the number you subtract.

Solution

1. In order: \(7>2>0>-3>-8>-12\). 2. The two smallest numbers give the least sum: \(-12+(-8)=-20\). 3. The greatest number is \(7\) and the smallest is \(-12\). Their difference is \(7-(-12)=19\).

Answer

a) \(7>2>0>-3>-8>-12\) b) \(-12+(-8)=-20\) c) \(7-(-12)=19\)
Add and subtract rational numbers 297
Use the numbers \(-10,-1,6,-5,3\). Choose from this list for each part. a) Find two different numbers whose sum is \(5\). Write the equation. b) Find two different numbers whose difference is \(11\). Write the subtraction in the correct order. c) Which number makes \(-10+\square=-7\)? Check it by adding.

Hints

- In a), look for a positive number and a negative number that combine to the target. - In b), the order of subtraction matters. - For c), think of the movement needed to reach the given result.

Solution

1. The two numbers adding to \(5\) are \(6\) and \(-1\): \(6+(-1)=5\). 2. The ordered difference is \(6-(-5)=11\). 3. The missing addend is \(3\): \(-10+3=-7\).

Answer

a) \(6+(-1)=5\) b) \(6-(-5)=11\) c) \(3\), since \(-10+3=-7\)
Add and subtract rational numbers 298
A diving robot begins at \(-45\,\text{m}\) relative to sea level and descends \(15\,\text{m}\) each minute. After how many whole minutes will it first be below \(-110\,\text{m}\)?

Hints

- Record the robot's position after each minute. - “Below \(-110\,\text{m}\)” means the position must be less than \(-110\). - How does each descent change the signed position?

Solution

1. Subtract \(15\) for each minute: after \(1\) minute the position is \(-60\,\text{m}\), after \(2\) minutes it is \(-75\,\text{m}\), after \(3\) minutes it is \(-90\,\text{m}\), and after \(4\) minutes it is \(-105\,\text{m}\). 2. After \(5\) minutes, the position is \(-105-15=-120\,\text{m}\). 3. Since \(-120<-110\) and the position after \(4\) minutes is not below \(-110\), the first such time is \(5\) minutes.

Answer

The robot will first be below \(-110\,\text{m}\) after \(5\) minutes.
Add and subtract rational numbers 299
Estimate by rounding to the nearest ten. Then evaluate \(128-57-43+74-110\) exactly using efficient regrouping.

Hints

- Round each number to the nearest ten, keeping its sign. - Look for positive terms that combine into a convenient round number. - Which negative terms can be grouped without changing the value? - Compare the estimate with the exact result.

Solution

1. The estimate is \(130-60-40+70-110=-10\). 2. Regroup the exact expression as \((128+74)+(-57-43)-110\). 3. This gives \(202-100-110=-8\).

Answer

Estimate: approximately \(-10\). Exact: \((128+74)+(-57-43)-110=-8\).
Add and subtract rational numbers 300
Evaluate \(-42+(18-50)+60\).

Hints

- Evaluate the parentheses first. - A positive sign before the parentheses leaves the result unchanged. - Then add from left to right.

Solution

1. Evaluate the parentheses: \(18-50=-32\). 2. Then \(-42+(-32)+60=-74+60=-14\).

Answer

\(-14\)
Add and subtract rational numbers 301
Evaluate \(80-[-30-(25-45)]\).

Hints

- Work from the innermost grouping symbols outward. - Pay attention to every subtraction sign before a grouped value. - Subtracting a negative number becomes addition.

Solution

1. Evaluate the inner parentheses: \(25-45=-20\). 2. Evaluate the brackets: \(-30-(-20)=-10\). 3. Complete the calculation: \(80-(-10)=90\).

Answer

\(90\)
Add and subtract rational numbers 302
Evaluate the four expressions, and then order their values from least to greatest. a) \(-110+(-40)\) b) \(-110-(-40)\) c) \(110+(-110)\) d) \(0-110\)

Hints

- Evaluate all four expressions first. - Among negative numbers, the value with the greater absolute value is smaller. - Use a number line to order the results.

Solution

1. The values are a) \(-150\), b) \(-70\), c) \(0\), and d) \(-110\). 2. From least to greatest, \(-150<-110<-70<0\). 3. The corresponding order is a), d), b), c).

Answer

a) \(-150\) b) \(-70\) c) \(0\) d) \(-110\) Order: \(-150<-110<-70<0\), or a), d), b), c)
Add and subtract rational numbers 303
Rewrite the expression to make it easy to evaluate. Keep each subtraction sign with the number that follows it. \(154 + 78 - 54 - 28\)

Hints

- Look for pairs that make easy differences. - Keep each operation sign with its term when regrouping. - Add the two resulting differences.

Solution

1. Regroup as \((154 - 54) + (78 - 28)\). 2. Evaluate: \(100 + 50 = 150\).

Answer

\((154 - 54) + (78 - 28) = 150\)
Add and subtract rational numbers 304
Evaluate \(-123+57+265-77+43-65\) efficiently using properties of addition.

Hints

- Look for pairs that make convenient hundreds. - Keep each sign attached to its number when reordering. - Use the commutative and associative properties of addition.

Solution

1. Reorder and regroup as \((-123-77)+(57+43)+(265-65)\). 2. The partial sums are \(-200\), \(100\), and \(200\). 3. Therefore, the value is \(-200+100+200=100\).

Answer

\((-123-77)+(57+43)+(265-65)=-200+100+200=100\)
Add and subtract rational numbers 305
Add the difference of \(45\) and \(120\) to the sum of \(-33\) and \(-17\).

Hints

- Translate “difference” and “sum” into operations. - Write the full expression with parentheses. - Evaluate each grouped part first.

Solution

1. The difference is \(45-120=-75\). 2. The sum is \(-33+(-17)=-50\). 3. Adding the results gives \(-75+(-50)=-125\).

Answer

\(-125\)
Add and subtract rational numbers 306
Subtract the sum of \(-215\) and \(90\) from the opposite of \(45\).

Hints

- First find the opposite of \(45\). - The wording “subtract the sum from” determines the order. - Subtracting a negative number is the same as adding a positive number.

Solution

1. The opposite of \(45\) is \(-45\). 2. The sum is \(-215+90=-125\). 3. Subtract the sum: \(-45-(-125)=80\).

Answer

\(80\)
Add and subtract rational numbers 307
Find the sum of \(-15\), \(42\), and \(-10\). Subtract that sum from the difference of \(-100\) and \(50\).

Hints

- Evaluate the sum and the difference separately. - The final subtraction is difference minus sum. - Subtracting a positive number from a negative number makes the result more negative.

Solution

1. The sum is \(-15+42+(-10)=17\). 2. The difference is \(-100-50=-150\). 3. Subtract the sum from the difference: \(-150-17=-167\).

Answer

\(-167\)
Add and subtract rational numbers 308
Ms. Miller begins the week with \(\$85\) in her checking account. During the week, these transactions occur: 1. A \(\$120\) grocery purchase is debited. 2. A credit of \(\$50\) is deposited. 3. A \(\$30\) bill is paid. Calculate the balance after each transaction. What does the sign of the final balance mean?

Hints

- Apply the transactions in the order given. - Purchases and bill payments decrease the balance; credits increase it. - A positive balance represents available money, while a negative balance represents an overdraft.

Solution

1. After the grocery purchase, the balance is \(85-120=-35\), or \(-\$35\). 2. After the credit, the balance is \(-35+50=15\), or \(\$15\). 3. After the bill payment, the balance is \(15-30=-15\), or \(-\$15\). 4. The negative sign means the account is overdrawn by \(\$15\).

Answer

After the first transaction, the balance is \(-\$35\); after the second, it is \(\$15\); and after the third, it is \(-\$15\). The negative sign means the account is overdrawn by \(\$15\).
Add and subtract rational numbers 309
A weather station records two temperature changes on each of three days. Find the final evening temperature for each day. 1. Monday begins at \(5\,^\circ\text{C}\). The temperature rises \(8\,^\circ\text{C}\), then falls \(10\,^\circ\text{C}\). 2. Tuesday begins at \(-3\,^\circ\text{C}\). The temperature rises \(6\,^\circ\text{C}\), then falls \(7\,^\circ\text{C}\). 3. Wednesday begins at \(-1\,^\circ\text{C}\). The temperature falls \(4\,^\circ\text{C}\), then rises \(5\,^\circ\text{C}\).

Hints

- Picture the temperatures on a vertical number line. - For each change, decide whether to move up or down. - Apply the changes in order from the starting temperature.

Solution

1. Monday: \(5+8-10=3\), so the final temperature is \(3\,^\circ\text{C}\). 2. Tuesday: \(-3+6-7=-4\), so the final temperature is \(-4\,^\circ\text{C}\). 3. Wednesday: \(-1-4+5=0\), so the final temperature is \(0\,^\circ\text{C}\).

Answer

1. \(3\,^\circ\text{C}\) 2. \(-4\,^\circ\text{C}\) 3. \(0\,^\circ\text{C}\)
Add and subtract rational numbers 310
An elevator uses Level \(0\) for street level, positive numbers for levels above street level, and negative numbers for levels below street level. a) The elevator starts on Level \(2\), travels down \(5\) levels, and then travels up \(2\) levels. Where does it stop? b) The elevator is on Level \(-1\) and travels down \(3\) more levels. Where does it stop? c) The elevator is on Level \(-2\) and must travel to Level \(3\). How many levels must it travel upward?

Hints

- Picture the levels on a vertical number line. - Moving up increases the level number, and moving down decreases it. - In part c), find the distance from the starting level to the destination.

Solution

1. For part a), \(2-5+2=-1\), so the elevator stops on Level \(-1\). 2. For part b), \(-1-3=-4\), so the elevator stops on Level \(-4\). 3. For part c), the distance from \(-2\) to \(3\) is \(3-(-2)=5\), so the elevator must travel up \(5\) levels.

Answer

a) Level \(-1\) b) Level \(-4\) c) \(5\) levels upward
Add and subtract rational numbers 311
For each movement on a number line, find the missing value and write the corresponding addition equation. a) Start at \(-5\) and move \(8\) units right. b) Start at \(3.5\) and move \(6\) units left. c) You end at \(-2\) after moving \(4\) units left from an unknown starting point. Find the starting point.

Hints

- Moving right corresponds to adding a positive number. - Moving left corresponds to adding a negative number. - To find an unknown starting point, undo the movement.

Solution

1. For a), moving right means adding \(8\): \(-5+8=3\). 2. For b), moving left means adding \(-6\): \(3.5+(-6)=-2.5\). 3. For c), let the starting point be \(s\). Then \(s+(-4)=-2\), so \(s=2\). The complete equation is \(2+(-4)=-2\).

Answer

a) \(3\); \(-5+8=3\) b) \(-2.5\); \(3.5+(-6)=-2.5\) c) \(2\); \(2+(-4)=-2\)
Add and subtract rational numbers 312
Analyze sums on a number line. a) Which sum lies farther left: \((-12)+7\) or \((-3)+(-3)\)? Calculate and compare. b) A point is at \(-4.8\). What number \(x\) must be added to move it to \(0\)? c) A point at \(-2.4\) is moved to its opposite by adding a number \(y\). Find \(y\) and write the complete equation.

Hints

- The value farther left on a number line is smaller. - A number plus its opposite equals \(0\). - Find the change needed to move from \(-2.4\) to \(2.4\).

Solution

1. For a), \((-12)+7=-5\) and \((-3)+(-3)=-6\). Since \(-6<-5\), \((-3)+(-3)\) lies farther left. 2. For b), add the opposite of \(-4.8\): \(-4.8+4.8=0\). Therefore, \(x=4.8\). 3. For c), the opposite of \(-2.4\) is \(2.4\). The required change is \(2.4-(-2.4)=4.8\), so \(y=4.8\). The equation is \(-2.4+4.8=2.4\).

Answer

a) \((-3)+(-3)\), because \(-6<-5\) b) \(x=4.8\) c) \(y=4.8\); \(-2.4+4.8=2.4\)
Add and subtract rational numbers 313
Complete the table by finding each missing value of \(x\), \(y\), or \(x+y\). <table> <thead> <tr> <th>Item</th> <th>1</th> <th>2</th> <th>3</th> <th>4</th> <th>5</th> </tr> </thead> <tbody> <tr> <td>\(x\)</td> <td>\(-7.2\)</td> <td>\(3 \frac{1}{4}\)</td> <td>\(-0.8\)</td> <td>\(-\frac{5}{6}\)</td> <td>\(-4.15\)</td> </tr> <tr> <td>\(y\)</td> <td>\(4.5\)</td> <td>\(-5 \frac{1}{2}\)</td> <td>\(\square\)</td> <td>\(\frac{1}{3}\)</td> <td>\(4.15\)</td> </tr> <tr> <td>\(x+y\)</td> <td>\(\square\)</td> <td>\(\square\)</td> <td>\(-2\)</td> <td>\(\square\)</td> <td>\(\square\)</td> </tr> </tbody> </table>

Hints

- For each column, decide whether you need to add two rational numbers or find a missing addend. - Fractions need a common denominator before they can be added. - Converting between fractions and decimals can make some calculations easier. - When a sum and one addend are known, subtract the known addend to find the other one.

Solution

1. For item 1, \(-7.2+4.5=-2.7\). 2. For item 2, \(3 \frac{1}{4}+\left(-5 \frac{1}{2}\right)=3 \frac{1}{4}-5 \frac{2}{4}=-2 \frac{1}{4}\). 3. For item 3, \(-0.8+y=-2\), so \(y=-2-(-0.8)=-1.2\). 4. For item 4, \(-\frac{5}{6}+\frac{1}{3}=-\frac{5}{6}+\frac{2}{6}=-\frac{1}{2}\). 5. For item 5, \(-4.15+4.15=0\).

Answer

1) \(-2.7\) 2) \(-2 \frac{1}{4}\) 3) \(y=-1.2\) 4) \(-\frac{1}{2}\) 5) \(0\)
Add and subtract rational numbers 314
Evaluate each expression, then order the results from least to greatest. a) \(-12.5+7.8\) b) \(-\frac{3}{5}-\frac{1}{2}\) c) \(4 \frac{1}{3}+\left(-2 \frac{5}{6}\right)\) d) \(-0.75-(-1.2)\)

Hints

- Evaluate each expression before comparing the results. - Be careful when subtracting a negative number. - Converting all results to the same form can make them easier to compare.

Solution

1. For a), \(-12.5+7.8=-4.7\). 2. For b), \(-\frac{3}{5}-\frac{1}{2}=-\frac{6}{10}-\frac{5}{10}=-\frac{11}{10}=-1.1\). 3. For c), \(4 \frac{1}{3}+\left(-2 \frac{5}{6}\right)=\frac{13}{3}-\frac{17}{6}=\frac{26}{6}-\frac{17}{6}=\frac{9}{6}=1.5\). 4. For d), \(-0.75-(-1.2)=-0.75+1.2=0.45\). 5. Compare the results: \(-4.7<-1.1<0.45<1.5\). Therefore, the order is a), b), d), c).

Answer

a) \(-4.7\) b) \(-1.1\) c) \(1.5\) d) \(0.45\) Order: \(-4.7<-1.1<0.45<1.5\) (parts a), b), d), c)).
Add and subtract rational numbers 315
Evaluate each sum using the commutative and associative properties. For every part, write the regrouped expression you use before giving the result. 1) \((-24) + 15 + (-16) + 35\) 2) \(6.7 + (-3.2) + 1.3 + (-1.8)\) 3) \(-\frac{3}{4} + 2\frac{1}{5} - 0.25 + 0.8\)

Hints

- Keep each signed term intact while changing order. - Search for pairings that produce whole numbers. - Convert a rational number only when the conversion creates a useful pair.

Solution

1. \((-24-16)+(15+35)=-40+50=10\). 2. \((6.7+1.3)+(-3.2-1.8)=8-5=3\). 3. Convert \(-\frac{3}{4}=-0.75\), then \((-0.75-0.25)+(2.2+0.8)=-1+3=2\).

Answer

1) \((-24-16)+(15+35)=10\) 2) \((6.7+1.3)+(-3.2-1.8)=3\) 3) \((-0.75-0.25)+(2.2+0.8)=2\)
Add and subtract rational numbers 316
Evaluate each sum by choosing and showing pairings that avoid converting every term to one representation. 1) \(0.375 - 5\frac{1}{2} + \frac{5}{8} + 4.5\) 2) \(-8.1 + 2\frac{3}{7} + 1.1 + 5\frac{4}{7}\) 3) \(11\frac{1}{9} - 4.9 - 2\frac{1}{9} - 5.1\)

Hints

- Look for compatible values already in the same representation. - Convert only the term needed to form a particularly simple pair. - Show the pairings in your answer.

Solution

1. Use \(0.375=\frac{3}{8}\): \(\left(\frac{3}{8}+\frac{5}{8}\right)+(-5.5+4.5)=1-1=0\). 2. \((-8.1+1.1)+\left(2\frac{3}{7}+5\frac{4}{7}\right)=-7+8=1\). 3. \(\left(11\frac{1}{9}-2\frac{1}{9}\right)+(-4.9-5.1)=9-10=-1\).

Answer

1) \(\left(\frac{3}{8}+\frac{5}{8}\right)+(-5.5+4.5)=0\) 2) \((-8.1+1.1)+\left(2\frac{3}{7}+5\frac{4}{7}\right)=1\) 3) \(\left(11\frac{1}{9}-2\frac{1}{9}\right)+(-4.9-5.1)=-1\)
Add and subtract rational numbers 317
A small snack stand records its daily revenue and expenses. The daily net is \(\text{revenue}-\text{expenses}\). A positive result is a profit, and a negative result is a loss. a) Calculate the daily net for each day. b) Find the total net for all four days. <table> <thead> <tr> <th>Day</th> <th>Revenue</th> <th>Expenses</th> <th>Daily net</th> </tr> </thead> <tbody> <tr> <td>Monday</td> <td>\(\$145\)</td> <td>\(\$162\)</td> <td></td> </tr> <tr> <td>Tuesday</td> <td>\(\$210\)</td> <td>\(\$185\)</td> <td></td> </tr> <tr> <td>Wednesday</td> <td>\(\$95\)</td> <td>\(\$130\)</td> <td></td> </tr> <tr> <td>Thursday</td> <td>\(\$178\)</td> <td>\(\$178\)</td> <td></td> </tr> </tbody> </table>

Hints

- What sign should the net have when expenses are greater than revenue? - Calculate the difference for each day first. - Then add all four signed daily results.

Solution

1. Monday: \(145-162=-17\), so the daily net is \(-\$17\). 2. Tuesday: \(210-185=25\), so the daily net is \(\$25\). 3. Wednesday: \(95-130=-35\), so the daily net is \(-\$35\). 4. Thursday: \(178-178=0\), so the daily net is \(\$0\). 5. The total net is \(-17+25-35+0=-27\), or \(-\$27\).

Answer

a) Monday: \(-\$17\); Tuesday: \(\$25\); Wednesday: \(-\$35\); Thursday: \(\$0\) b) The total net is \(-\$27\).
Add and subtract rational numbers 318
At \(6{:}00\) a.m. on a winter day, the temperature is \(-6\,^\circ\text{F}\). a) By noon, the temperature rises \(11\,^\circ\text{F}\). What is the noon temperature? b) By late evening, the temperature drops \(8\,^\circ\text{F}\) from the noon value. What is the evening temperature? c) Find the difference between the highest and lowest of the morning, noon, and evening temperatures.

Hints

- Picture the temperatures on a vertical number line. - Translate “rises” and “drops” into operations. - To find the difference between the highest and lowest values, find their distance on the number line. - Compare all three temperatures before answering part c).

Solution

1. The noon temperature is \(-6+11=5\,^\circ\text{F}\). 2. The evening temperature is \(5-8=-3\,^\circ\text{F}\). 3. The highest temperature is \(5\,^\circ\text{F}\), and the lowest is \(-6\,^\circ\text{F}\). Their difference is \(5-(-6)=11\,^\circ\text{F}\).

Answer

a) \(5\,^\circ\text{F}\) b) \(-3\,^\circ\text{F}\) c) \(11\,^\circ\text{F}\)
Add and subtract rational numbers 319
Julia and Tom compare their checking account balances. - Julia has \(\$12\), so her balance is \(+\$12\). - Tom's account is overdrawn by \(\$8\), so his balance is \(-\$8\). a) What is the difference between their current balances? b) Julia buys a book for \(\$15\). What is her new balance? c) Tom deposits \(\$10\). What is his new balance? d) After these changes, who has the greater balance, and what is the difference between the balances?

Hints

- A negative balance is less than a positive balance. - A purchase decreases a balance, while a deposit increases it. - A difference between balances is their distance on a number line. - Subtracting a negative number is equivalent to adding its opposite.

Solution

1. The initial difference is \(12-(-8)=20\), or \(\$20\). 2. Julia's new balance is \(12-15=-3\), or \(-\$3\). 3. Tom's new balance is \(-8+10=2\), or \(\$2\). 4. Since \(2>-3\), Tom has the greater balance. The new difference is \(2-(-3)=5\), or \(\$5\).

Answer

a) \(\$20\) b) \(-\$3\) c) \(\$2\) d) Tom has the greater balance, and the difference is \(\$5\).
Add and subtract rational numbers 320
Determine which value lies farther left on the number line. Value A: the sum of the opposite of \(2\frac{3}{5}\) and the reciprocal of \(0.5\) Value B: the result of subtracting the sum of \(0.6\) and \(-3\frac{1}{2}\) from \(-1.4\)

Hints

- A smaller number lies farther left on the number line. - Find the opposite and reciprocal in Value A. - Evaluate the grouped sum in Value B before subtracting it.

Solution

1. For Value A, the opposite of \(2\frac{3}{5}=2.6\) is \(-2.6\), and the reciprocal of \(0.5\) is \(2\). Thus A is \(-2.6+2=-0.6\). 2. For Value B, first find the sum: \(0.6+(-3.5)=-2.9\). Then \(-1.4-(-2.9)=1.5\). 3. Since \(-0.6<1.5\), Value A lies farther left.

Answer

Value A lies farther left because \(-0.6<1.5\).
Add and subtract rational numbers 321
Find each requested value. a) Evaluate \((+7)-(-15)\). b) What number must be subtracted from \(-3.8\) to get \(-10\)? c) Subtract \(+1 \frac{3}{4}\) from \(-2 \frac{1}{2}\).

Hints

- Subtracting a negative number is the same as adding its opposite. - For b), represent the unknown number with a variable or a blank. - For mixed numbers, a common denominator can make the subtraction easier.

Solution

1. For a), subtracting a negative is addition: \(7-(-15)=7+15=22\). 2. For b), let the missing number be \(x\). Then \(-3.8-x=-10\), so \(x=-3.8-(-10)=6.2\). 3. For c), use a common denominator: \(-2 \frac{1}{2}-1 \frac{3}{4}=-\frac{10}{4}-\frac{7}{4}=-\frac{17}{4}=-4 \frac{1}{4}\).

Answer

a) \(22\) b) \(6.2\) c) \(-4 \frac{1}{4}\), or \(-4.25\)
Add and subtract rational numbers 322
Explore how changing the order affects subtraction. Let \(x=-6.2\) and \(y=-3.4\). a) Find \(x-y\). b) Find \(y-x\). c) Compare your answers from a) and b). What do you notice? d) Kertu claims, “When you subtract one negative number from another negative number, the result is always positive.” Give a counterexample to show that the claim is false.

Hints

- Substitute the negative values carefully and pay attention to both operation signs and number signs. - Compare the absolute values and signs of the results in a) and b). - One counterexample is enough to disprove a statement that claims something is always true.

Solution

1. For a), \(x-y=-6.2-(-3.4)=-6.2+3.4=-2.8\). 2. For b), \(y-x=-3.4-(-6.2)=-3.4+6.2=2.8\). 3. The two results are opposites: they have the same absolute value and opposite signs. 4. One counterexample is \((-10)-(-2)=-10+2=-8\). Since the result is negative, the claim is false.

Answer

a) \(-2.8\) b) \(2.8\) c) The results are opposites. d) Example: \((-10)-(-2)=-8\). The result is negative, so the claim is false.
Add and subtract rational numbers 323
Evaluate each expression. Write each result as a simplified fraction or mixed number. 1) \(\left(-\frac{7}{8}\right)-\left(+\frac{1}{8}\right)-(-3)\) 2) \(\left(+\frac{2}{5}\right)-\left(-\frac{1}{2}\right)-\left(+\frac{9}{10}\right)\) 3) \(\left(-2 \frac{1}{4}\right)-\left(-\frac{3}{4}\right)-(+1)\)

Hints

- Subtracting a number is the same as adding its opposite. - Check whether the fractions already have a common denominator before finding a new one. - You can write whole numbers as fractions when that helps combine terms. - Converting mixed numbers to improper fractions can make some calculations easier.

Solution

1. For 1), rewrite subtraction of a negative as addition: \(-\frac{7}{8}-\frac{1}{8}+3=-1+3=2\). 2. For 2), use denominator \(10\): \(\frac{4}{10}+\frac{5}{10}-\frac{9}{10}=0\). 3. For 3), \(-2 \frac{1}{4}+\frac{3}{4}-1=-1 \frac{1}{2}-1=-2 \frac{1}{2}\).

Answer

1) \(2\) 2) \(0\) 3) \(-2 \frac{1}{2}\)
Add and subtract rational numbers 324
a) Write three different subtractions using positive fractions or decimals: one with a positive answer, one with zero, and one with a negative answer. You may choose new numbers each time. Show the calculations. b) Let \(a\) and \(b\) be positive rational numbers. When is \(a-b\) positive, zero, or negative? Compare \(a\) and \(b\) using \(<\), \(=\), or \(>\). c) If you add \(0.5\) to both \(a\) and \(b\), will the difference change? Explain.

Hints

- Compare the two numbers in each example, not just the sign of the answer. - What changes when the first number is larger, equal to, or smaller than the second? - For c), try changing both numbers in one of your examples before explaining the general case.

Solution

1. For example, \(5.8-2.3=3.5\) is positive, \(1.5-1.5=0\), and \(0.2-0.7=-0.5\) is negative. 2. The difference is positive when \(a>b\), zero when \(a=b\), and negative when \(a<b\). 3. The difference does not change: \((a+0.5)-(b+0.5)=a-b\). Adding the same amount to both numbers leaves their difference unchanged.

Answer

a) Examples: positive \(5.8-2.3=3.5\); zero \(1.5-1.5=0\); negative \(0.2-0.7=-0.5\). b) Positive: \(a>b\); zero: \(a=b\); negative: \(a<b\). c) No. \((a+0.5)-(b+0.5)=a-b\); adding the same amount to both numbers does not change the difference.
Add and subtract rational numbers 325
The expressions are \(A=a-b+c\) and \(B=a-(b+c)\). Evaluate and compare them for each assignment. a) \(a=10\), \(b=-4\), \(c=2\) b) \(a=-3.5\), \(b=1.5\), \(c=-5\)

Hints

- Use parentheses when substituting negative values. - Evaluate the parentheses in \(B\) before subtracting. - Compare the final values on a number line.

Solution

1. For a), \(A=10-(-4)+2=16\), while \(B=10-((-4)+2)=12\). Thus, \(A>B\). 2. For b), \(A=-3.5-1.5+(-5)=-10\), while \(B=-3.5-(1.5+(-5))=0\). Thus, \(A<B\).

Answer

a) \(A=16\), \(B=12\), so \(A>B\). b) \(A=-10\), \(B=0\), so \(A<B\).
Add and subtract rational numbers 326
Evaluate \(T=-x-(y-z)\) for each set of rational numbers. a) \(x=\frac{2}{3}\), \(y=-\frac{1}{6}\), \(z=\frac{1}{2}\) b) \(x=-2\frac{1}{4}\), \(y=1\frac{3}{8}\), \(z=-0.5\)

Hints

- Convert mixed numbers and decimals to fractions. - Use common denominators for addition and subtraction. - Pay close attention to the negative sign in front of \(x\). - Work inside the parentheses first.

Solution

1. For part a), \(T=-\frac{2}{3}-\left(-\frac{1}{6}-\frac{1}{2}\right)=-\frac{2}{3}-\left(-\frac{2}{3}\right)=0\). 2. For part b), convert the values to fractions: \(x=-\frac{9}{4}\), \(y=\frac{11}{8}\), and \(z=-\frac{1}{2}\). 3. Then \(T=-\left(-\frac{9}{4}\right)-\left(\frac{11}{8}-\left(-\frac{1}{2}\right)\right)=\frac{18}{8}-\frac{15}{8}=\frac{3}{8}\).

Answer

a) \(0\) b) \(\frac{3}{8}\)
Add and subtract rational numbers 327
Let \(a\) and \(b\) be rational numbers. a) Under what condition is \(a - b > a\)? Explain why and give a numerical example. b) Under what condition does \(a - b = a + b\)? Justify your answer algebraically.

Hints

- Subtract the common term \(a\) from both sides. - Subtracting a negative number is equivalent to adding a positive number. - In part b), collect all terms containing \(b\) on one side.

Solution

1. For a), subtract \(a\) from both sides of \(a - b > a\): \(-b > 0\). This is equivalent to \(b < 0\). 2. Subtracting a negative number increases the original value. For example, \(7 - (-3) = 10\), and \(10 > 7\). 3. For b), subtract \(a\) from both sides: \(-b = b\). 4. Add \(b\): \(0 = 2b\). Divide by \(2\): \(b = 0\). The value of \(a\) can be any rational number.

Answer

a) \(b<0\). Subtracting a negative number adds a positive amount. For example, \(7-(-3)=10>7\). b) \(b=0\), because \(a-b=a+b\) implies \(-b=b\), then \(0=2b\), so \(b=0\).
Add and subtract rational numbers 328
An elevator labels street level as \(0\), levels above it with positive integers, and parking levels below it with negative integers. A passenger enters on Level \(5\) and makes these trips in order: 1. Down \(7\) levels 2. Up \(3\) levels 3. Down \(4\) levels 4. Up \(2\) levels a) On which level does the passenger end? b) What is the lowest level reached during the entire trip? c) How many levels apart are the highest and lowest points of the trip?

Hints

- Record the current level after each move. - Moving down is a negative change, and moving up is a positive change. - Include the starting level when identifying the highest and lowest points. - Find the distance between the highest and lowest signed values.

Solution

1. Track each position: \(5-7=-2\), \(-2+3=1\), \(1-4=-3\), and \(-3+2=-1\). The final position is Level \(-1\). 2. The visited levels are \(5,-2,1,-3,-1\). The least value is \(-3\), so the lowest level reached is Level \(-3\). 3. The highest level is \(5\), and the lowest is \(-3\). Their distance is \(5-(-3)=8\) levels.

Answer

a) Level \(-1\) b) Level \(-3\) c) \(8\) levels
Add and subtract rational numbers 329
Analyze each statement about subtracting rational numbers. a) Can \(x-y\) be greater than \(x\)? Explain or give an example. b) If \(a<0\) and \(b<0\), must \(a-b\) be negative? Give examples that show what can happen. c) If \(x<0\), is \(x-(-x)\) positive? Explain.

Hints

- Subtracting a negative number changes the result differently from subtracting a positive one. - In part b), try two negative numbers in both orders, and then try equal numbers. - In part c), first decide whether \(-x\) is positive or negative.

Solution

1. In a), subtracting a negative increases the value. For example, \(5-(-2)=7>5\). 2. In b), no. For example, \(-2-(-5)=3\) is positive, \(-5-(-2)=-3\) is negative, and \(-3-(-3)=0\). The sign depends on which negative number is farther from zero. 3. In c), \(-x\) is positive because \(x<0\). Subtracting this positive number makes the negative starting value even smaller. For example, \(-3-(-(-3))=-3-3=-6\). Thus the result is negative, not positive.

Answer

a) Yes. For example, \(5-(-2)=7>5\). b) No. For example, \(-2-(-5)=3\), \(-5-(-2)=-3\), and \(-3-(-3)=0\). c) No. When \(x<0\), \(-x>0\), so \(x-(-x)<0\).
Add and subtract rational numbers 330
Use the number line. a) Write the value of each point \(A\), \(B\), and \(C\) as both a decimal and a fraction in simplest form or a mixed number. b) Find the distance from \(A\) to \(B\) and from \(B\) to \(C\).
Figure for problem 531808

Hints

- Determine the value of one small interval. - Use the point’s position relative to \(0\) to determine its sign. - Distance is the absolute value of the difference between two coordinates. - Convert quarters to decimals or decimals to fractions as needed.

Solution

1. There are \(4\) equal intervals between consecutive integers, so each interval represents \(0.25=\frac{1}{4}\). 2. Point \(A\) is at \(-1.75=-\frac{7}{4}=-1\frac{3}{4}\). 3. Point \(B\) is at \(-0.5=-\frac{1}{2}\). 4. Point \(C\) is at \(0.25=\frac{1}{4}\). 5. The distance from \(A\) to \(B\) is \(\left|-0.5-(-1.75)\right|=1.25=\frac{5}{4}\). 6. The distance from \(B\) to \(C\) is \(|0.25-(-0.5)|=0.75=\frac{3}{4}\).

Answer

a) \(A=-1.75=-\frac{7}{4}\); \(B=-0.5=-\frac{1}{2}\); \(C=0.25=\frac{1}{4}\) b) \(AB=1.25=\frac{5}{4}\); \(BC=0.75=\frac{3}{4}\)
Add and subtract rational numbers 331
Each number outside the triangle is the sum of the two corner numbers next to it. Find the two missing corner numbers and the missing side number. Show a subtraction for each missing corner.
Figure for problem 531914

Hints

- Each outside number joins two neighboring corner values. - Use a known sum and one corner to work backward to the other corner. - Once both bottom corners are known, calculate the bottom side.

Solution

1. The top corner is \(-1.2\). The bottom-right corner is \(-2.7-(-1.2)=-1.5\). 2. The bottom-left corner is \(1.9-(-1.2)=3.1\). 3. The bottom side is the sum of the two bottom corners: \(-1.5+3.1=1.6\).

Answer

Bottom-right corner: \(-2.7-(-1.2)=-1.5\) Bottom-left corner: \(1.9-(-1.2)=3.1\) Bottom side: \(-1.5+3.1=1.6\)
Add and subtract rational numbers 332
Find all three missing results. Show each calculation as an equation.
Figure for problem 531916

Hints

- What happens to a result when a negative number is subtracted? - Could either lower branch have a negative value? Check its signs. - Use the completed lower branches to check the final operation.

Solution

1. In the left branch, \(8-(-23)=31\). 2. In the right branch, \(-12+5=-7\). 3. At the top, \(31-(-7)=38\).

Answer

Left result: \(8-(-23)=31\) Right result: \(-12+5=-7\) Top result: \(31-(-7)=38\)
Add and subtract rational numbers 333
The plot shows the temperature at a mountain weather station from \(6{:}00\) a.m. to \(4{:}00\) p.m. on a winter day. Three students wrote different expressions to determine the temperature at \(4{:}00\) p.m. Lucas: \(-3-1+2+3+4+2+0-1-3-4-2\) Clara: \(-3+(2+3+4+2)-(1+1+3+4+2)\) Jonas: \(-3-1+11-10\) a) Evaluate each expression. What temperature does each expression give for \(4{:}00\) p.m.? b) Explain how each student grouped or represented the hourly temperature changes shown in the plot.
Figure for problem 532186

Hints

- What does the initial \(-3\) in each expression represent on the plot? - Find the temperature change from one marked hour to the next. - Compare how the three expressions group the same signed changes.

Solution

1. Lucas's expression gives \(-3-1+2+3+4+2+0-1-3-4-2=-3\). 2. Clara's expression gives \(-3+(2+3+4+2)-(1+1+3+4+2)=-3+11-11=-3\). 3. Jonas's expression gives \(-3-1+11-10=-3\). Therefore, all three expressions give a final temperature of \(-3\,^{\circ}\text{C}\). 4. Lucas lists every hourly change in order. Clara groups all increases together and all decreases together. Jonas groups consecutive phases: an initial \(1\)-degree decrease, an \(11\)-degree increase, no change, and a final \(10\)-degree decrease.

Answer

a) Each expression equals \(-3\), so the temperature at \(4{:}00\) p.m. is \(-3\,^{\circ}\text{C}\). b) Lucas uses each hourly change. Clara groups positive changes and negative changes. Jonas combines consecutive changes into longer warming and cooling phases.
Add and subtract rational numbers 334
The plot shows the air temperature measured at the same time on seven consecutive days at a mountain weather station. Two meteorologists summarize the week: Mr. Frost writes \(T_1=-4+2+3-1-3+2+3\). Ms. Degree writes \(T_2=(2+3+2+3)-(1+3)\). Evaluate both expressions and explain what information each result gives about the weather station.
Figure for problem 533192

Hints

- Start with the point for Day 1. - Relate positive and negative numbers to increases and decreases between marked days. - Compare \(T_1\) with the final plotted temperature and \(T_2\) with the overall change.

Solution

1. For \(T_1\), \(-4+2+3-1-3+2+3=2\). The expression starts with the Day 1 temperature and applies each daily change, so \(2\,^{\circ}\text{C}\) is the temperature on Day 7. 2. For \(T_2\), \((2+3+2+3)-(1+3)=10-4=6\). The first group is the total of all increases, and the second group is the total of all decreases. The result \(6\,^{\circ}\text{C}\) is the net temperature change from Day 1 to Day 7.

Answer

\(T_1=2\,^{\circ}\text{C}\); this is the temperature on Day 7. \(T_2=6\,^{\circ}\text{C}\); this is the net temperature change from Day 1 to Day 7.
Add and subtract rational numbers 335
A hiking group is planning a route through the mountains. The bar graph shows the elevation of each stop in feet. a) Read the elevations of the six stops from the graph. b) Find the elevation change between each pair of consecutive stops. Use a negative sign for a descent. c) Find the sum of all the elevation changes from part b). d) A hiker says, “The finish is only \(300\,\text{ft}\) above the start, so we climb only \(300\,\text{ft}\) in all.” Explain why this statement is incorrect.
Figure for problem 535092

Hints

- Read each bar using the y-axis scale. - Subtract each elevation from the next elevation in route order. - Add the signed changes for the net change. - Add only positive changes to find total ascent. - Descents affect net change but not the amount already climbed.

Solution

1. The elevations are Start, \(600\,\text{ft}\); A, \(1500\,\text{ft}\); B, \(2600\,\text{ft}\); C, \(1400\,\text{ft}\); D, \(2300\,\text{ft}\); Finish, \(900\,\text{ft}\). 2. The consecutive changes are \(1500-600=+900\,\text{ft}\), \(2600-1500=+1100\,\text{ft}\), \(1400-2600=-1200\,\text{ft}\), \(2300-1400=+900\,\text{ft}\), and \(900-2300=-1400\,\text{ft}\). 3. Their sum is \(900+1100-1200+900-1400=300\,\text{ft}\), which is the net change from start to finish. 4. Total climbing includes only the positive changes: \(900+1100+900=2900\,\text{ft}\). Descents reduce the net change but do not erase the climbing already completed.

Answer

a) Start: \(600\,\text{ft}\); A: \(1500\,\text{ft}\); B: \(2600\,\text{ft}\); C: \(1400\,\text{ft}\); D: \(2300\,\text{ft}\); Finish: \(900\,\text{ft}\) b) \(+900\,\text{ft}\), \(+1100\,\text{ft}\), \(-1200\,\text{ft}\), \(+900\,\text{ft}\), \(-1400\,\text{ft}\) c) \(+300\,\text{ft}\) d) The route includes \(2900\,\text{ft}\) of total ascent. The \(300\,\text{ft}\) value is only the net elevation change.
Add and subtract rational numbers 336
Find each missing starting number for the subtraction shown on the number line.
Figure for problem 535154

Hints

- Work backward from the ending value. - Undo a leftward jump by adding its length. - Check each answer by performing the subtraction from left to right.

Solution

1. In a), solve \(x-35=-10\). The starting number is \(-10+35=25\). 2. In b), solve \(x-60=-20\). The starting number is \(-20+60=40\). 3. In c), solve \(x-15=-45\). The starting number is \(-45+15=-30\).

Answer

a) \(25\) b) \(40\) c) \(-30\)
Add and subtract rational numbers 337
Complete each chain of jumps on the number line. Find every value in a box.
Figure for problem 535170

Hints

- Work one jump at a time. - Use a known middle value to work both forward and backward. - When reversing a jump, use the opposite operation.

Solution

1. In a), \(-50+120=70\), and \(70+(-90)=-20\). 2. In b), \(x+(-40)=10\), so \(x=50\). Then \(10+60=70\). 3. In c), the middle value satisfies \(y+(-70)=-60\), so \(y=10\). The starting value satisfies \(x+30=10\), so \(x=-20\).

Answer

a) \(70\) and \(-20\) b) \(50\) and \(70\) c) \(-20\) and \(10\)
Add and subtract rational numbers 338
Each brick in the number wall is the sum of the two bricks directly below it. Find all three missing numbers. Show how you found the missing number in the bottom row.
Figure for problem 535187

Hints

- Can a negative number and a positive number have a positive sum? - Test a possible bottom number by adding it to its neighbor. - Check each higher brick against the two numbers supporting it.

Solution

1. The first brick in the middle row gives \(-15+x=9\), so the missing bottom number is \(x=9-(-15)=24\). 2. The other middle brick is \(24+7=31\). 3. The top brick is \(9+31=40\).

Answer

Bottom row: \(24\), since \(9-(-15)=24\) Middle row: \(31\) Top: \(40\)
Add and subtract rational numbers 339
Use the number line to find the missing starting value.
Figure for problem 535255

Hints

- Read the signed jump and endpoint from the diagram. - Undo the jump to recover the starting value.

Solution

1. The diagram shows an unknown start, a jump of \(-50\), and ending value \(-12\). 2. Solve \(x+(-50)=-12\), giving \(x=38\).

Answer

\(38\)
Add and subtract rational numbers 340
Use the number line to find the missing intermediate and ending values.
Figure for problem 535256

Hints

- Read the start and each signed jump directly from the diagram. - Find the first landing before applying the second jump.

Solution

1. The diagram starts at \(-15\) and first jumps \(+25\), landing at \(10\). 2. From \(10\), the next jump is \(-40\), landing at \(-30\).

Answer

Intermediate value: \(10\) Ending value: \(-30\)
Add and subtract rational numbers 341
The number-line diagram shows a temperature in the morning, its change by noon, and its change from noon to evening. What is the evening temperature?
Figure for problem 535259

Hints

- Read the starting temperature and both signed jumps from the diagram. - Follow the jumps in order from morning to noon to evening. - A positive jump raises the temperature and a negative jump lowers it.

Solution

1. The diagram shows a morning temperature of \(-8\,^\circ\text{F}\) and a rise of \(15\,^\circ\text{F}\). By noon, \(-8+15=7\), so the temperature is \(7\,^\circ\text{F}\). 2. The next jump is \(-4\,^\circ\text{F}\), so by evening \(7-4=3\). The evening temperature is \(3\,^\circ\text{F}\).

Answer

\(3\,^\circ\text{F}\)
Add and subtract rational numbers 342
The number line shows a temperature change from the previous evening to the morning low. Find the previous evening's temperature.
Figure for problem 535276

Hints

- Read the endpoint and signed jump from the number line. - Work backward from the morning low by reversing the displayed change. - Check that applying the displayed change to your answer reaches the shown endpoint.

Solution

1. Let the starting temperature be \(x\). The number line shows a fall of \(15\,^{\circ}\text{F}\) to \(-6\,^{\circ}\text{F}\), so \(x-15=-6\). 2. Add \(15\) to both sides: \(x=-6+15=9\). 3. The previous evening's temperature was \(9\,^{\circ}\text{F}\).

Answer

\(9\,^{\circ}\text{F}\)
Add and subtract rational numbers 343
Divide the six number cards into two groups of three so that the sums of the groups are equal. \(1.2,\ \frac{3}{10},\ -1.5,\ 0.8,\ -0.2,\ -\frac{3}{5}\)

Hints

- Find the sum of all six numbers first. - Convert the fractions to decimals. - Look for three numbers that sum to half the total.

Solution

1. Write \(\frac{3}{10}=0.3\) and \(-\frac{3}{5}=-0.6\). 2. The sum of all six numbers is \(0\), so each group must have sum \(0\). 3. One group is \(1.2, 0.3, -1.5\), whose sum is \(0\). 4. The remaining group is \(0.8, -0.2, -0.6\), whose sum is also \(0\).

Answer

Group 1: \(1.2, \frac{3}{10}, -1.5\) Group 2: \(0.8, -0.2, -\frac{3}{5}\)
Add and subtract rational numbers 344
Decide whether each claim is true or false. Explain. a) If you add twice the opposite of a number to the original number, the result is the opposite of the original number. b) Two different integers can have the same opposite.

Hints

- Represent the original number with a variable. - Pair one copy of the number with one copy of its opposite. - Think of opposites as reflections across zero.

Solution

1. Let the number be \(n\). Then \(n+2(-n)=n-2n=-n\), so a) is true. 2. Every integer has exactly one opposite. If two integers had the same opposite, taking the opposite again would show that the integers are equal. Therefore, b) is false.

Answer

a) True; \(n+2(-n)=-n\). b) False; each integer has exactly one opposite.
Add and subtract rational numbers 345
Write one subtraction expression with a value of \(-35\) for each condition. a) Both numbers are positive integers. b) The starting number is a negative integer, and the number being subtracted is a positive integer. c) Both numbers are negative integers.

Hints

- For part a), the number being subtracted must be greater than the starting number. - Rewrite subtraction of a negative number as addition. - Choose one number first, and then determine what must be subtracted to reach \(-35\).

Solution

1. For a), the number being subtracted must be \(35\) greater than the starting number. One example is \(10-45=-35\). 2. For b), choose a negative starting number and a positive number whose distances from zero total \(35\). One example is \(-20-15=-35\). 3. For c), subtracting a negative adds its opposite. One example is \(-50-(-15)=-35\).

Answer

Possible answers are: a) \(10-45=-35\) b) \(-20-15=-35\) c) \(-50-(-15)=-35\)
Add and subtract rational numbers 346
Simon claims, “When I subtract one integer from another integer, the result is always less than the first integer.” Is Simon correct? Use at least two integer examples to justify your answer.

Hints

- Test a positive number, zero, and a negative number as the number being subtracted. - Subtracting a negative number is the same as adding its opposite. - One counterexample is enough to disprove an “always” statement, but provide two examples as requested.

Solution

1. Simon’s claim is not true for every integer being subtracted. 2. Subtracting a negative number makes the result greater. For example, \(5-(-3)=8\), and \(8>5\). 3. Subtracting zero leaves the first number unchanged. For example, \(5-0=5\). 4. The result is less than the first integer only when a positive integer is subtracted.

Answer

No. For example, \(5-(-3)=8\), which is greater than \(5\), and \(5-0=5\), which is equal to \(5\). The result is less than the first integer only when a positive integer is subtracted.
Add and subtract rational numbers 347
Consider the expressions: (I) \((-48)-(-122)\) (II) \((-210)-(+90)\) a) Rewrite each subtraction as addition and evaluate. b) What number must be subtracted from each answer in part a) to get \(10\)? c) For each answer in part a), what number must be subtracted to get its opposite?

Hints

- To subtract a number, add its opposite. - The opposite of a number has the same distance from zero and the opposite sign. - For parts b) and c), write an equation in the form \(\text{starting value}-x=\text{target value}\).

Solution

1. In a), (I) is \((-48)+122=74\), and (II) is \((-210)+(-90)=-300\). 2. In b), solve \(74-x=10\) to get \(x=64\). Solve \(-300-x=10\) to get \(x=-310\). 3. In c), the opposite of \(74\) is \(-74\). Solving \(74-x=-74\) gives \(x=148\). The opposite of \(-300\) is \(300\). Solving \(-300-x=300\) gives \(x=-600\).

Answer

a) (I) \(74\); (II) \(-300\) b) (I) \(64\); (II) \(-310\) c) (I) \(148\); (II) \(-600\)
Add and subtract rational numbers 348
Consider the expressions: (I) \((-15)-(+85)\) (II) \((+40)-(+110)\) a) Rewrite each subtraction as addition and evaluate. b) What number must be subtracted from the value of (I) to get the value of (II)? c) What number must be subtracted from the value of (II) to get the opposite of the value of (I)?

Hints

- Evaluate both expressions before answering parts b) and c). - Find the opposite of the value of Expression (I). - Represent the missing number in each subtraction with a variable.

Solution

1. In a), (I) is \((-15)+(-85)=-100\), and (II) is \(40+(-110)=-70\). 2. In b), solve \(-100-x=-70\). This gives \(x=-30\). 3. In c), the opposite of \(-100\) is \(100\). Solve \(-70-y=100\) to get \(y=-170\).

Answer

a) (I) \(-100\); (II) \(-70\) b) \(-30\) c) \(-170\)
Add and subtract rational numbers 349
Place the signs \(+\) and \(-\) and the digits \(4\), \(5\), \(8\), and \(9\) in the boxes so that every digit and sign is used exactly once. \(\square\square\square+\square\square\square\) Find an arrangement that makes the sum a) as large as possible, b) as small as possible.

Hints

- The sum contains one positive and one negative two-digit number. - To maximize the result, maximize the positive number and minimize the absolute value of the negative number. - To minimize the result, reverse that strategy.

Solution

1. The two terms must be one positive two-digit number and one negative two-digit number. 2. To maximize the sum, make the positive number as large as possible while keeping the negative number’s absolute value as small as possible: \((+98)+(-45)=53\). 3. To minimize the sum, reverse the signs: \((-98)+(+45)=-53\).

Answer

a) \((+98)+(-45)=53\) b) \((-98)+(+45)=-53\)
Add and subtract rational numbers 350
Place the signs \(+\) and \(-\) and the digits \(1\), \(2\), \(3\), and \(4\) in the boxes so that every symbol is used exactly once. \(\square\square\square+\square\square\square\) Which arrangement gives a result closest to \(0\)? Give the expression and its value.

Hints

- Divide the four digits into two pairs systematically. - Form two-digit numbers from each pair and compare their absolute values. - The sum is closest to zero when those absolute values are as close as possible.

Solution

1. The expression is the sum of one positive and one negative two-digit number, so its distance from zero is the difference between their absolute values. 2. Check the possible digit pairings. The closest pair is \(31\) and \(24\), whose difference is \(7\). 3. Therefore, \((+31)+(-24)=7\) or \((-31)+(+24)=-7\). Both results are \(7\) units from zero.

Answer

\((+31)+(-24)=7\) or \((-31)+(+24)=-7\)
Add and subtract rational numbers 351
Evaluate each expression one set of parentheses at a time. a) \(145-(34+156-20)-(55+45)\) b) \(-(-760+140)-[(24-110)+480]\)

Hints

- Evaluate the innermost parentheses first. - A negative sign outside parentheses changes the sign of the value inside. - Check the sign of every intermediate result.

Solution

1. In a), \(34+156-20=170\) and \(55+45=100\). Then \(145-170-100=-125\). 2. In b), \(-760+140=-620\), so \(-(-620)=620\). Also, \(24-110=-86\), and \(-86+480=394\). Therefore, \(620-394=226\).

Answer

a) \(-125\) b) \(226\)
Add and subtract rational numbers 352
Consider the expression \(12-(+8)-(-15)+(-5)\). a) Evaluate the expression. b) Add one pair of parentheses so that the expression has a value of \(-6\). Write the modified expression and verify its value.

Hints

- A subtraction sign before parentheses subtracts the value of the entire group. - Try grouping two or three consecutive terms. - The new result must be less than the original result.

Solution

1. In a), \(12-8+15-5=14\). 2. For b), group the last three signed terms: \(12-((+8)-(-15)+(-5))\). 3. The grouped expression has value \(8+15-5=18\). 4. Therefore, \(12-18=-6\).

Answer

a) \(14\) b) \(12-((+8)-(-15)+(-5))=-6\)
Add and subtract rational numbers 353
Consider the expression \(-40-(-10)-(+20)+(-5)\). a) Evaluate the expression. b) Add one pair of parentheses in two different ways so that each new expression has a value different from the value in part a). Write both new expressions and their values.

Hints

- The new parentheses must enclose at least one operation to affect the value. - Parentheses following a subtraction sign are especially likely to change the result. - Try several placements and evaluate each modified expression.

Solution

1. In a), \(-40+10-20-5=-55\). 2. One possible new expression is \(-40-((-10)-(+20))+(-5)\). Its value is \(-40-(-30)-5=-15\). 3. Another possible new expression is \(-40-(-10)-((+20)+(-5))\). Its value is \(-40+10-15=-45\). 4. Both values differ from \(-55\).

Answer

a) \(-55\) b) Possible answers: \(-40-((-10)-(+20))+(-5)=-15\) \(-40-(-10)-((+20)+(-5))=-45\)
Add and subtract rational numbers 354
Consider the expression \(2500 - [750 - (150 - 50)]\). First evaluate the expression. Then determine how its value changes if each of the four numbers is increased by \(10\). Explain why.

Hints

- Evaluate the expression from the innermost grouping outward. - Track how each inner difference changes before considering the outer subtraction. - Recall what happens when both numbers in a subtraction increase by the same amount.

Solution

1. Evaluate from the innermost grouping outward: \(150 - 50 = 100\), \(750 - 100 = 650\), and \(2500 - 650 = 1850\). 2. Increasing both numbers in \(150 - 50\) by \(10\) leaves that difference unchanged. 3. The value of \(750 - (150 - 50)\) increases by \(10\), because only its first number has a net increase. 4. In the outer subtraction, both the first number and the value being subtracted increase by \(10\). Therefore, the final difference remains \(1850\).

Answer

The original value is \(1850\), and it remains unchanged.
Add and subtract rational numbers 355
Write an expression with grouping symbols for the description, and then evaluate it. From the opposite of the sum of \(-315\) and \(105\), subtract the difference of \(45\) and \(-82\).

Hints

- The opposite of a number has the same absolute value and the opposite sign. - Use grouping symbols to separate the sum and the difference. - Evaluate the grouped expressions before the final subtraction.

Solution

1. The sum is \(-315+105=-210\), so its opposite is \(210\). 2. The difference is \(45-(-82)=127\). 3. The expression is \(-[(-315)+105]-[45-(-82)]\). 4. Evaluate: \(210-127=83\).

Answer

\(-[(-315)+105]-[45-(-82)]=83\)

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