5122318
A sequence is defined by products with alternating factors of \(-2\) and \(-0.5\).
Term 1: \(-2\)
Term 2: \((-2) \cdot (-0.5)\)
Term 3: \((-2) \cdot (-0.5) \cdot (-2)\)
Term 4: \((-2) \cdot (-0.5) \cdot (-2) \cdot (-0.5)\)
The alternating pattern continues.
a) Determine the sign and value of Term 6.
b) Determine the sign and value of Term 7.
c) What is the absolute value of Term 100? Explain.
Hints
- Calculate the first few terms and look for a repeating pattern.
- Track how each new factor changes the preceding term.
- Compare terms in even-numbered and odd-numbered positions.
Solution
1. The first four terms are \(-2, 1, -2, 1\).
2. Each pair of factors has product \((-2) \cdot (-0.5) = 1\), so every even-numbered term is \(1\), and every odd-numbered term is \(-2\).
3. Term 6 is positive and equals \(1\).
4. Term 7 is negative and equals \(-2\).
5. Since \(100\) is even, Term 100 is \(1\), so its absolute value is \(1\).
Answer
a) Positive; \(1\)
b) Negative; \(-2\)
c) \(1\), because every even-numbered term equals \(1\).
