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Construct two-way tables

Learning goals

  • Organizes paired categorical data into a two-way table.
  • Finds the totals for each row and column of a two-way table.
  • Checks the grand total against the number of observations.
  • Uses the table to compare categories or prepare relative frequencies.

Click problems to add them to your worksheet.

Construct two-way tables 1
The table shows how students traveled to school and whether they arrived on time. <table><tr><th></th><th>On time</th><th>Late</th><th>Total</th></tr><tr><th>Bus</th><td>\(14\)</td><td>\(6\)</td><td>\(20\)</td></tr><tr><th>Walk</th><td>\(9\)</td><td>\(3\)</td><td>\(12\)</td></tr><tr><th>Total</th><td>\(23\)</td><td>\(9\)</td><td>\(32\)</td></tr></table> a) How many students walked and arrived late? b) How many students walked in total?

Hints

- An interior cell represents students who belong to both its row category and its column category. - A row total is found at the far right of that row.

Solution

1. The Walk row and Late column meet at the cell containing \(3\). 2. The total at the end of the Walk row is \(12\).

Answer

a) \(3\) students. b) \(12\) students.
Construct two-way tables 2
Complete the missing interior count. <table><tr><th></th><th>Uses the library</th><th>Does not use the library</th><th>Total</th></tr><tr><th>Grade \(7\)</th><td>\(18\)</td><td></td><td>\(30\)</td></tr><tr><th>Grade \(8\)</th><td>\(22\)</td><td>\(18\)</td><td>\(40\)</td></tr></table>

Hints

- Work within the Grade \(7\) row. - Subtract the known interior count from the row total.

Solution

1. The two Grade \(7\) interior counts must add to the Grade \(7\) row total of \(30\). 2. The missing count is \(30-18=12\).

Answer

\(12\).
Construct two-way tables 3
Ramon is planning a two-way table for two categorical variables: grade level (Grade 7 or Grade 8) and usual travel method (Walk, Bus, or Car). He considers two layouts: - Layout A: Grade 7 and Grade 8 are rows; Walk, Bus, and Car are columns. - Layout B: Walk, Bus, and Car are rows; Grade 7 and Grade 8 are columns. a) Which layouts are valid two-way-table organizations? b) In each layout, where would the count of Grade 8 students who usually ride the bus appear? c) Explain why switching the row and column variables does not change the paired data being summarized.

Hints

- A two-way table places the categories of one variable along rows and the categories of the other along columns. - Check whether every interior position in each layout represents one grade category paired with one travel category. - Think about what changes, and what stays the same, when a table is transposed.

Solution

1. Each layout places all categories of one variable on one dimension and all categories of the other variable on the other dimension, so both layouts are valid. 2. In Layout A, the count belongs in the Grade 8 row and Bus column. 3. In Layout B, the same count belongs in the Bus row and Grade 8 column. 4. Switching rows and columns changes only the table's orientation; each student still contributes the same grade-and-travel pair.

Answer

a) Both Layout A and Layout B are valid. b) In Layout A, the count is in the Grade 8 row and Bus column. In Layout B, it is in the Bus row and Grade 8 column. c) Switching rows and columns changes the orientation, not which two categories are paired for each student.
Construct two-way tables 4
Maya proposes this layout for a survey of grade level and travel method: <table><tr><th></th><th>Bus</th><th>Grade \(8\)</th></tr><tr><th>Walk</th><td></td><td></td></tr><tr><th>Grade \(7\)</th><td></td><td></td></tr></table> Explain why this layout is not a valid two-way-table organization for the two variables. Describe how the row and column headings should be organized instead. You do not need to supply any counts.

Hints

- Identify which variable each displayed heading belongs to. - In a two-way table, one axis represents one categorical variable and the other axis represents the other variable. - Do not mix a grade category and a travel category on the same axis.

Solution

1. A valid two-way table puts all categories of one variable on one axis and all categories of the other variable on the other axis. 2. Maya's rows mix Walk, which is a travel-method category, with Grade \(7\), which is a grade-level category. 3. Her columns likewise mix Bus with Grade \(8\). 4. One valid organization is Grade \(7\) and Grade \(8\) as the rows and the travel-method categories as the columns. The reverse orientation is also valid.

Answer

The layout is invalid because each axis mixes categories from the two different variables. Put all grade categories on one axis and all travel-method categories on the other; for example, Grade \(7\) and Grade \(8\) as rows and the travel-method categories as columns.
Construct two-way tables 5
A store sorts orders by pickup or delivery and by payment method. One order is delivered and paid for by card. In which cell does it belong? <table><tr><th>Order type</th><th>Cash</th><th>Card</th></tr><tr><th>Pickup</th><td> </td><td> </td></tr><tr><th>Delivery</th><td> </td><td> </td></tr></table>

Hints

- A single cell describes two facts about an order at once. - Find the row and column whose labels match those facts.

Solution

1. Use the row for the order type: Delivery. 2. Use the column for the payment method: Card. 3. Add one tally where that row and column meet.

Answer

The Delivery row and Card column.
Construct two-way tables 6
A bicycle repair stand checks four bikes. Here are the pairs (bike type, fixed that day): Road, yes Mountain, yes Road, no Mountain, yes Complete a two-way table with bike type as rows and fixed that day (yes/no) as columns. Include all totals.

Hints

- Each bicycle contributes to one inside cell. - Count the road and mountain entries separately before adding margins. - Check that the four inside counts add to the number of bicycles.

Solution

1. For Road bikes, one was fixed and one was not. 2. For Mountain bikes, two were fixed and none were left unfixed. 3. The row totals are \(2\) and \(2\), the column totals are \(3\) and \(1\), and the grand total is \(4\).

Answer

<table><tr><th></th><th>Yes</th><th>No</th><th>Total</th></tr><tr><th>Road</th><td>\(1\)</td><td>\(1\)</td><td>\(2\)</td></tr><tr><th>Mountain</th><td>\(2\)</td><td>\(0\)</td><td>\(2\)</td></tr><tr><th>Total</th><td>\(3\)</td><td>\(1\)</td><td>\(4\)</td></tr></table>
Construct two-way tables 7
A garden center sells seed packets and small plants at the counter and online. How many plant purchases were made altogether? <table><tr><th></th><th>Seeds</th><th>Plants</th></tr><tr><th>Counter</th><td>\(6\)</td><td>\(8\)</td></tr><tr><th>Online</th><td>\(3\)</td><td>\(5\)</td></tr><tr><th>Total</th><td>\(9\)</td><td>\(\square\)</td></tr></table>

Hints

- To find a total for one item, would you read across a row or down a column? - Check that purchases from both sales methods are included.

Solution

1. The Plants column has \(8\) counter purchases and \(5\) online purchases. 2. The missing total is \(8+5=13\).

Answer

\(13\) plant purchases.
Construct two-way tables 8
A school surveyed students about interest in mathematics and physics. The four interior counts are shown. <table><tr><th></th><th>Interested in mathematics</th><th>Not interested in mathematics</th><th>Total</th></tr><tr><th>Interested in physics</th><td>\(120\)</td><td>\(130\)</td><td></td></tr><tr><th>Not interested in physics</th><td>\(180\)</td><td>\(70\)</td><td></td></tr><tr><th>Total</th><td></td><td></td><td></td></tr></table> a) Complete all row, column, and grand totals. b) Explain what the counts \(120\) and \(70\) mean. c) How many students are interested in exactly one of the two subjects?

Hints

- Add across each row and down each column. - Read an interior cell by combining its row and column labels. - “Exactly one” uses the two off-diagonal interior cells.

Solution

1. The physics row total is \(120+130=250\), and the not-physics row total is \(180+70=250\). 2. The mathematics column total is \(120+180=300\), and the not-mathematics column total is \(130+70=200\). 3. The grand total is \(250+250=500\). 4. The count \(120\) represents students interested in both subjects. The count \(70\) represents students interested in neither subject. 5. Exactly one subject includes \(130+180=310\) students.

Answer

a) <table><tr><th></th><th>Interested in mathematics</th><th>Not interested in mathematics</th><th>Total</th></tr><tr><th>Interested in physics</th><td>\(120\)</td><td>\(130\)</td><td>\(250\)</td></tr><tr><th>Not interested in physics</th><td>\(180\)</td><td>\(70\)</td><td>\(250\)</td></tr><tr><th>Total</th><td>\(300\)</td><td>\(200\)</td><td>\(500\)</td></tr></table> b) \(120\) students are interested in both subjects; \(70\) students are interested in neither subject. c) \(310\) students.
Construct two-way tables 9
Twelve students recorded how they traveled to school and whether they arrived early or late: Bike–Early, Walk–Early, Bike–Late, Bus–Early, Walk–Late, Bike–Early, Bus–Late, Bike–Early, Walk–Early, Bus–Early, Bike–Late, Walk–Early. Construct a two-way table of counts with travel method as rows and arrival category as columns.

Hints

- Treat each hyphenated response as one paired observation. - Tally one travel row at a time, then check that all observations are counted. - Use row and column sums to verify the grand total.

Solution

1. Tally each paired response into one row and one column. 2. The row counts are Bike: \(3\) early and \(2\) late; Walk: \(3\) early and \(1\) late; Bus: \(2\) early and \(1\) late. 3. Add row and column totals to complete the table.

Answer

<table><tr><th></th><th>Early</th><th>Late</th><th>Total</th></tr><tr><th>Bike</th><td>\(3\)</td><td>\(2\)</td><td>\(5\)</td></tr><tr><th>Walk</th><td>\(3\)</td><td>\(1\)</td><td>\(4\)</td></tr><tr><th>Bus</th><td>\(2\)</td><td>\(1\)</td><td>\(3\)</td></tr><tr><th>Total</th><td>\(8\)</td><td>\(4\)</td><td>\(12\)</td></tr></table>
Construct two-way tables 10
A school records lunch choice for students in two grades. The tally totals are: - Grade \(7\): \(14\) cafeteria meals, \(9\) packed lunches, \(7\) skipped lunches. - Grade \(8\): \(10\) cafeteria meals, \(12\) packed lunches, \(8\) skipped lunches. Construct a complete two-way table.

Hints

- Choose one variable for rows and the other for columns. - Enter the category counts before calculating totals. - Check that the row-total sum equals the column-total sum.

Solution

1. Use grade levels as rows and the three lunch choices as columns. 2. Enter the six stated counts. 3. Row totals are \(30\) and \(30\); column totals are \(24\), \(21\), and \(15\), for \(60\) students.

Answer

<table><tr><th></th><th>Cafeteria</th><th>Packed</th><th>Skipped</th><th>Total</th></tr><tr><th>Grade \(7\)</th><td>\(14\)</td><td>\(9\)</td><td>\(7\)</td><td>\(30\)</td></tr><tr><th>Grade \(8\)</th><td>\(10\)</td><td>\(12\)</td><td>\(8\)</td><td>\(30\)</td></tr><tr><th>Total</th><td>\(24\)</td><td>\(21\)</td><td>\(15\)</td><td>\(60\)</td></tr></table>
Construct two-way tables 11
The classification tree shows \(60\) students first by grade and then by how they travel to school. Construct a complete two-way table with grade as rows and travel method as columns.
Figure for problem 550085

Hints

- Each path from the root identifies one grade-and-travel combination. - Put the terminal count from each path into the matching interior cell of the table. - Add the completed interior cells to obtain the margins.

Solution

1. Follow the Grade 7 branch: \(18\) students ride the bus and \(14\) walk, for a row total of \(32\). 2. Follow the Grade 8 branch: \(10\) students ride the bus and \(18\) walk, for a row total of \(28\). 3. The bus column total is \(18+10=28\), and the walk column total is \(14+18=32\). 4. The grand total is \(32+28=60\), agreeing with the tree.

Answer

<table><tr><th></th><th>Bus</th><th>Walk</th><th>Total</th></tr><tr><th>Grade \(7\)</th><td>\(18\)</td><td>\(14\)</td><td>\(32\)</td></tr><tr><th>Grade \(8\)</th><td>\(10\)</td><td>\(18\)</td><td>\(28\)</td></tr><tr><th>Total</th><td>\(28\)</td><td>\(32\)</td><td>\(60\)</td></tr></table>
Construct two-way tables 12
The table contains exactly one incorrect total. Identify and correct it. <table><tr><th></th><th>Returned</th><th>Kept</th><th>Total</th></tr><tr><th>Online</th><td>\(16\)</td><td>\(44\)</td><td>\(60\)</td></tr><tr><th>Store</th><td>\(9\)</td><td>\(31\)</td><td>\(40\)</td></tr><tr><th>Total</th><td>\(25\)</td><td>\(74\)</td><td>\(100\)</td></tr></table>

Hints

- Check each row and column independently. - Only one total is wrong, so the four interior counts should remain unchanged.

Solution

1. The row totals are correct: \(16+44=60\) and \(9+31=40\). 2. The returned-column total is correct: \(16+9=25\). 3. The kept-column total should be \(44+31=75\), not \(74\).

Answer

The incorrect entry is the kept-column total. It should be \(75\).
Construct two-way tables 13
Each two-letter code gives a student’s campus and course format. The first letter is North \(N\) or South \(S\); the second is hybrid \(H\) or in-person \(I\). \(NH, SI, NH, NI, SH, NH, SI, NI, SH, NH, SH, SI, NH, NI, SH, NH\) Construct a two-way table of counts.

Hints

- Decode both letters before tallying. - Mark each code in exactly one cell. - Check that the four cell counts total the number of codes.

Solution

1. Tally codes by their first and second letters. 2. North has \(6\) hybrid and \(3\) in-person students; South has \(4\) hybrid and \(3\) in-person students. 3. The column totals are \(10\) hybrid and \(6\) in-person, for \(16\) students.

Answer

<table><tr><th></th><th>Hybrid</th><th>In person</th><th>Total</th></tr><tr><th>North</th><td>\(6\)</td><td>\(3\)</td><td>\(9\)</td></tr><tr><th>South</th><td>\(4\)</td><td>\(3\)</td><td>\(7\)</td></tr><tr><th>Total</th><td>\(10\)</td><td>\(6\)</td><td>\(16\)</td></tr></table>
Construct two-way tables 14
Talia tries to construct a table for \(50\) survey responses. The planned row totals are \(28\) and \(22\), but the planned column totals are \(31\) and \(20\). Can a valid two-way table have these totals? Explain.

Hints

- Compute the grand total in two independent ways. - A valid table cannot count a different number of observations by rows and columns.

Solution

1. The row totals sum to \(28+22=50\). 2. The column totals sum to \(31+20=51\). 3. A two-way table must have the same grand total from rows and columns, so these margins are inconsistent.

Answer

No. The row totals give \(50\), while the column totals give \(51\).
Construct two-way tables 15
A school surveys \(34\) Grade \(7\) students and \(26\) Grade \(8\) students about whether they prefer e-books or printed books. The number of Grade \(7\) students who prefer e-books equals the number of Grade \(8\) students who prefer printed books. Eighteen Grade \(7\) students prefer e-books. Construct the complete table.

Hints

- Place the stated equal counts before subtracting from the row totals. - Complete each grade row separately. - Add the two columns and verify the grand total.

Solution

1. Place \(18\) in both stated equal cells: Grade \(7\) e-books and Grade \(8\) printed books. 2. Grade \(7\) printed books: \(34-18=16\). 3. Grade \(8\) e-books: \(26-18=8\). 4. The column totals are \(18+8=26\) for e-books and \(16+18=34\) for printed books.

Answer

<table><tr><th></th><th>E-books</th><th>Printed books</th><th>Total</th></tr><tr><th>Grade \(7\)</th><td>\(18\)</td><td>\(16\)</td><td>\(34\)</td></tr><tr><th>Grade \(8\)</th><td>\(8\)</td><td>\(18\)</td><td>\(26\)</td></tr><tr><th>Total</th><td>\(26\)</td><td>\(34\)</td><td>\(60\)</td></tr></table>
Construct two-way tables 16
An after-school program has the following club-choice counts: <table><tr><th></th><th>Robotics</th><th>Art</th></tr><tr><th>Grade \(7\)</th><td>\(12\)</td><td>\(8\)</td></tr><tr><th>Grade \(8\)</th><td>\(9\)</td><td>\(11\)</td></tr></table> Four new Grade \(7\) responses arrive: \(3\) choose robotics and \(1\) chooses art. Four new Grade \(8\) responses all choose art. Construct the updated table with totals.

Hints

- Add each new response only to its matching grade-and-club cell. - Recalculate both row totals after updating the four interior cells. - Add each column and verify the new grand total.

Solution

1. Update Grade \(7\): robotics becomes \(12+3=15\), and art becomes \(8+1=9\). 2. Update Grade \(8\): robotics remains \(9\), and art becomes \(11+4=15\). 3. Each grade row totals \(24\). 4. Each club column totals \(24\), for \(48\) responses altogether.

Answer

<table><tr><th></th><th>Robotics</th><th>Art</th><th>Total</th></tr><tr><th>Grade \(7\)</th><td>\(15\)</td><td>\(9\)</td><td>\(24\)</td></tr><tr><th>Grade \(8\)</th><td>\(9\)</td><td>\(15\)</td><td>\(24\)</td></tr><tr><th>Total</th><td>\(24\)</td><td>\(24\)</td><td>\(48\)</td></tr></table>
Construct two-way tables 17
A community garden surveys \(50\) residents from two neighborhoods about whether they compost. Complete the table, including all margins. <table><tr><th></th><th>Composts</th><th>Does not compost</th><th>Total</th></tr><tr><th>North</th><td>\(19\)</td><td>\(8\)</td><td></td></tr><tr><th>South</th><td>\(14\)</td><td></td><td></td></tr><tr><th>Total</th><td></td><td></td><td>\(50\)</td></tr></table>

Hints

- Add the three known interior counts before using the grand total. - Subtract that sum from \(50\) to find the fourth interior cell. - Complete the row and column margins only after all four interior counts are known.

Solution

1. The three known interior cells total \(19+8+14=41\). 2. The missing South noncomposting count is \(50-41=9\). 3. The row totals are \(19+8=27\) for North and \(14+9=23\) for South. 4. The column totals are \(19+14=33\) who compost and \(8+9=17\) who do not, and \(33+17=50\).

Answer

<table><tr><th></th><th>Composts</th><th>Does not compost</th><th>Total</th></tr><tr><th>North</th><td>\(19\)</td><td>\(8\)</td><td>\(27\)</td></tr><tr><th>South</th><td>\(14\)</td><td>\(9\)</td><td>\(23\)</td></tr><tr><th>Total</th><td>\(33\)</td><td>\(17\)</td><td>\(50\)</td></tr></table>
Construct two-way tables 18
Coach Ellis tracks equipment borrowed by the Red and Blue practice groups. She wrote down each request: <table><tr><th>Group</th><th>Equipment</th><th>Number borrowed</th></tr><tr><td>Red</td><td>Cones</td><td>\(6\)</td></tr><tr><td>Blue</td><td>Hurdles</td><td>\(8\)</td></tr><tr><td>Red</td><td>Hurdles</td><td>\(4\)</td></tr><tr><td>Blue</td><td>Cones</td><td>\(7\)</td></tr><tr><td>Red</td><td>Cones</td><td>\(5\)</td></tr><tr><td>Blue</td><td>Hurdles</td><td>\(5\)</td></tr></table> Make a two-way table of the total number borrowed, with practice group as rows and equipment as columns. Include totals.

Hints

- Does a pair such as Red–Cones appear more than once in the notes? - Add requests for the same group and the same equipment first. - Check that the row totals and column totals agree.

Solution

1. Combine repeated requests: Red borrowed \(6+5=11\) cones and \(4\) hurdles. Blue borrowed \(7\) cones and \(8+5=13\) hurdles. 2. Red borrowed \(15\) pieces altogether; Blue borrowed \(20\). 3. Cones total \(18\), hurdles total \(17\), and the grand total is \(35\).

Answer

<table><tr><th></th><th>Cones</th><th>Hurdles</th><th>Total</th></tr><tr><th>Red</th><td>\(11\)</td><td>\(4\)</td><td>\(15\)</td></tr><tr><th>Blue</th><td>\(7\)</td><td>\(13\)</td><td>\(20\)</td></tr><tr><th>Total</th><td>\(18\)</td><td>\(17\)</td><td>\(35\)</td></tr></table>
Construct two-way tables 19
A school survey has column totals of \(45\) students who prefer e-books and \(35\) who prefer printed books. Among Grade \(7\) students, \(19\) prefer e-books. Among Grade \(8\) students, \(12\) prefer printed books. Construct the full table.

Hints

- Complete each book-format column from its total. - Add across each grade row only after both columns are filled. - Verify the grand total from the two column totals.

Solution

1. Grade \(8\) e-book preferences: \(45-19=26\). 2. Grade \(7\) printed-book preferences: \(35-12=23\). 3. The Grade \(7\) total is \(19+23=42\), and the Grade \(8\) total is \(26+12=38\). 4. The grand total is \(45+35=80\).

Answer

<table><tr><th></th><th>E-books</th><th>Printed books</th><th>Total</th></tr><tr><th>Grade \(7\)</th><td>\(19\)</td><td>\(23\)</td><td>\(42\)</td></tr><tr><th>Grade \(8\)</th><td>\(26\)</td><td>\(12\)</td><td>\(38\)</td></tr><tr><th>Total</th><td>\(45\)</td><td>\(35\)</td><td>\(80\)</td></tr></table>
Construct two-way tables 20
Priya surveys \(40\) students about two categorical variables: pet type (dog, cat, or no pet) and usual homework location (home or library). She summarizes the results this way: <table><tr><th>Category</th><th>Count</th></tr><tr><td>Dog</td><td>\(18\)</td></tr><tr><td>Cat</td><td>\(12\)</td></tr><tr><td>No pet</td><td>\(10\)</td></tr><tr><td>Home</td><td>\(25\)</td></tr><tr><td>Library</td><td>\(15\)</td></tr></table> Explain why this is not a two-way table for the two variables. Describe a correct row-and-column organization, and state what additional information is needed to fill the interior cells.

Hints

- A two-way table organizes two categorical variables at the same time. - Ask whether each interior position would identify one category from each variable. - Separate marginal totals from joint counts that describe paired categories.

Solution

1. Priya's display lists the marginal counts for pet type and homework location separately. 2. It does not show how the categories pair for the same students, so it does not cross the two variables. 3. One correct organization is pet type as the rows and homework location as the columns; the reverse orientation would also be valid. 4. To fill the interior cells, the paired responses are needed, such as how many dog owners usually work at home, how many dog owners usually work at the library, and so on.

Answer

The display is not a two-way table because it does not cross pet type with homework location. A correct table can use Dog, Cat, and No pet as rows and Home and Library as columns, or the reverse. The joint counts for each paired category combination are needed to fill the interior cells.
Construct two-way tables 21
Lakeview Middle School wants a two-way table with grade level as the columns. The proposed row categories are “Plays soccer” and “Plays basketball.” Some students play both sports, and some play neither. Are those two row categories valid categories of one row variable if every surveyed student must be counted in exactly one row? Explain. Give one valid set of row categories that keeps the sports information and places every student in exactly one row.

Hints

- In a standard two-way count table, one person should contribute to one category of each variable. - Check what happens to a student who belongs to both proposed sport groups. - Also check whether every surveyed student belongs to at least one proposed row category.

Solution

1. The proposed row categories overlap because a student who plays both soccer and basketball would belong in both rows. 2. They are also not exhaustive because a student who plays neither sport would belong in no row. 3. Therefore, the two proposed categories do not form a valid one-variable row partition for a standard two-way table in which each student contributes to exactly one interior cell. 4. One valid row variable is sports-participation group with the categories Soccer only, Basketball only, Both, and Neither.

Answer

No. “Plays soccer” and “Plays basketball” overlap for students who play both and omit students who play neither. One valid row-category set is Soccer only, Basketball only, Both, and Neither.
Construct two-way tables 22
Table A summarizes campus and travel method. <table><tr><th></th><th>Bus</th><th>Walk</th></tr><tr><th>North</th><td>\(14\)</td><td>\(9\)</td></tr><tr><th>South</th><td>\(8\)</td><td>\(11\)</td></tr></table> Jordan transposes the table and proposes Table B. <table><tr><th></th><th>North</th><th>South</th></tr><tr><th>Bus</th><td>\(14\)</td><td>\(8\)</td></tr><tr><th>Walk</th><td>\(11\)</td><td>\(9\)</td></tr></table> Does Table B represent exactly the same paired data as Table A? If not, identify every interior count in Table B that is misplaced and state where each belongs.

Hints

- Match each interior count to the same pair of category labels in both tables. - A transpose changes where a cell appears, but not which two categories that cell represents. - Check the Bus row and Walk row separately rather than comparing row totals alone.

Solution

1. Transposing a two-way table switches the row and column headings but keeps each paired category count attached to the same two categories. 2. The North-Bus count \(14\) and South-Bus count \(8\) are correctly placed in Table B. 3. Table A has North-Walk \(9\), so Table B should place \(9\) in the Walk row and North column. 4. Table A has South-Walk \(11\), so Table B should place \(11\) in the Walk row and South column. 5. Table B has those two Walk counts reversed, so it does not represent exactly the same paired data.

Answer

No. In Table B, the Walk-North entry should be \(9\), and the Walk-South entry should be \(11\). Those two counts are reversed.
Construct two-way tables 23
A school records grade level and preferred device type. The next lesson will compare device preferences **within each grade** by calculating row relative frequencies. Which variable should be placed in the rows of the count table to make that later comparison direct? Which variable should be placed in the columns? Would the opposite orientation still be a valid two-way count table? Explain.

Hints

- Row relative frequencies divide by the total of the row being examined. - Ask which groups should each supply their own denominator for the planned comparison. - Separate whether an orientation is valid from whether it is convenient for a particular conditional comparison.

Solution

1. Row relative frequencies use each row total as the denominator. 2. To compare device preferences within each grade, each grade should therefore form one row. 3. Grade level should be the row variable, and preferred device type should be the column variable. 4. The opposite orientation would still be a valid two-way count table because it would contain the same paired counts, but row relative frequencies in that orientation would compare grades within each device type instead of devices within each grade.

Answer

Put grade level in the rows and device type in the columns. The opposite orientation is still a valid two-way count table, but its row relative frequencies would answer a different conditional question.
Construct two-way tables 24
At a movie theater, six tickets are recorded by seat section and showtime: Balcony–Evening, Floor–Matinee, Floor–Evening, Balcony–Matinee, Floor–Evening, Balcony–Evening. A worker made the table below but counted one ticket twice. Find the incorrect count and give the correct table, including totals. <table><tr><th></th><th>Matinee</th><th>Evening</th></tr><tr><th>Balcony</th><td>\(1\)</td><td>\(3\)</td></tr><tr><th>Floor</th><td>\(1\)</td><td>\(2\)</td></tr></table>

Hints

- Count each ticket as a pair of categories, not as two separate lists. - Compare your four counts with the four cells the worker filled. - Check that the corrected table contains exactly six tickets.

Solution

1. Balcony–Evening appears twice in the list, not three times, so the incorrect count is \(3\) in that cell. 2. The correct inside counts are Balcony: \(1\) Matinee and \(2\) Evening; Floor: \(1\) Matinee and \(2\) Evening. 3. Each row totals \(3\); the columns total \(2\) Matinee and \(4\) Evening. The total is \(6\).

Answer

Balcony–Evening was counted as \(3\) instead of \(2\). <table><tr><th></th><th>Matinee</th><th>Evening</th><th>Total</th></tr><tr><th>Balcony</th><td>\(1\)</td><td>\(2\)</td><td>\(3\)</td></tr><tr><th>Floor</th><td>\(1\)</td><td>\(2\)</td><td>\(3\)</td></tr><tr><th>Total</th><td>\(2\)</td><td>\(4\)</td><td>\(6\)</td></tr></table>
Construct two-way tables 25
Eight museum visitors record their ticket type and whether they used an audio guide: Adult–Yes, Child–No, Senior–Yes, Adult–No, Child–Yes, Adult–Yes, Senior–No, Child–No. Make a two-way table with ticket type as rows and audio guide (Yes/No) as columns. Include totals.

Hints

- Sort the observations by ticket type first. - For each type, count guide users and nonusers separately. - Check both kinds of totals against eight visitors.

Solution

1. Adults contribute \(2\) Yes and \(1\) No; seniors contribute \(1\) Yes and \(1\) No. 2. Children contribute \(1\) Yes and \(2\) No. 3. Row totals are \(3\), \(2\), and \(3\); column totals are \(4\) Yes and \(4\) No; total \(8\).

Answer

<table><tr><th></th><th>Yes</th><th>No</th><th>Total</th></tr><tr><th>Adult</th><td>\(2\)</td><td>\(1\)</td><td>\(3\)</td></tr><tr><th>Senior</th><td>\(1\)</td><td>\(1\)</td><td>\(2\)</td></tr><tr><th>Child</th><td>\(1\)</td><td>\(2\)</td><td>\(3\)</td></tr><tr><th>Total</th><td>\(4\)</td><td>\(4\)</td><td>\(8\)</td></tr></table>
Construct two-way tables 26
Ms. Patel surveys \(32\) students. Seven belong to an athletics club, \(15\) play esports at least once a week, and \(16\) do neither. Make a complete two-way table for athletics club membership and weekly esports participation. Include the totals.

Hints

- Think about which cell holds students who do neither activity. - Use the athletics and esports totals to fill the remaining cells. - Check that the four inside counts add to the full class size.

Solution

1. There are \(32-16=16\) students who do at least one activity. 2. The number who do both is \(7+15-16=6\). 3. Athletics only is \(7-6=1\), and weekly esports only is \(15-6=9\). 4. The remaining cell is the given \(16\) students who do neither. The row and column totals are consistent with \(32\).

Answer

<table><tr><th></th><th>Plays esports weekly</th><th>Does not play esports weekly</th><th>Total</th></tr><tr><th>In athletics club</th><td>\(6\)</td><td>\(1\)</td><td>\(7\)</td></tr><tr><th>Not in athletics club</th><td>\(9\)</td><td>\(16\)</td><td>\(25\)</td></tr><tr><th>Total</th><td>\(15\)</td><td>\(17\)</td><td>\(32\)</td></tr></table>
Construct two-way tables 27
A health survey of \(1000\) participants found that \(600\) exercise regularly, \(550\) eat a balanced diet, and \(400\) do both. a) Complete a two-way table of counts. b) How many participants do neither? c) How many do exactly one of the two activities?

Hints

- Begin with the count for participants who are in both categories. - Subtract the “both” count from each category total to find the two “only” cells. - Use the grand total after the other three interior cells are known.

Solution

1. Place \(400\) in the cell for participants who exercise regularly and eat a balanced diet. 2. The number who exercise regularly but do not eat a balanced diet is \(600-400=200\). 3. The number who eat a balanced diet but do not exercise regularly is \(550-400=150\). 4. The number who do neither is \(1000-(400+200+150)=250\). 5. The number who do exactly one activity is \(200+150=350\).

Answer

a) <table><tr><th></th><th>Eats a balanced diet</th><th>Does not eat a balanced diet</th><th>Total</th></tr><tr><th>Exercises regularly</th><td>\(400\)</td><td>\(200\)</td><td>\(600\)</td></tr><tr><th>Does not exercise regularly</th><td>\(150\)</td><td>\(250\)</td><td>\(400\)</td></tr><tr><th>Total</th><td>\(550\)</td><td>\(450\)</td><td>\(1000\)</td></tr></table> b) \(250\) participants. c) \(350\) participants.
Construct two-way tables 28
A veterinary clinic surveyed \(200\) pet owners. Complete the table, then answer the questions. <table><tr><th></th><th>Owns a dog</th><th>Does not own a dog</th><th>Total</th></tr><tr><th>Owns a cat</th><td>\(30\)</td><td></td><td></td></tr><tr><th>Does not own a cat</th><td></td><td>\(55\)</td><td>\(110\)</td></tr><tr><th>Total</th><td>\(85\)</td><td></td><td>\(200\)</td></tr></table> a) Complete the two-way table. b) What do the counts \(30\) and \(55\) mean in context? c) How many respondents own at least one of the two pets?

Hints

- Use the row and column totals to complete one missing entry at a time. - An interior cell combines its row category and column category. - “At least one” can be found by subtracting the “neither” count from the total.

Solution

1. The cat-owner row total is \(200-110=90\), and the no-dog column total is \(200-85=115\). 2. The number who own a cat but not a dog is \(90-30=60\). 3. The number who own a dog but not a cat is \(85-30=55\). 4. The count \(30\) represents owners of both a dog and a cat. The count \(55\) in the lower-right cell represents owners of neither pet. 5. The number who own at least one pet is \(200-55=145\).

Answer

a) <table><tr><th></th><th>Owns a dog</th><th>Does not own a dog</th><th>Total</th></tr><tr><th>Owns a cat</th><td>\(30\)</td><td>\(60\)</td><td>\(90\)</td></tr><tr><th>Does not own a cat</th><td>\(55\)</td><td>\(55\)</td><td>\(110\)</td></tr><tr><th>Total</th><td>\(85\)</td><td>\(115\)</td><td>\(200\)</td></tr></table> b) \(30\) respondents own both pets; \(55\) respondents own neither pet. c) \(145\) respondents.
Construct two-way tables 29
A school surveyed \(25\) students about whether they play a musical instrument and whether they play a sport regularly. The survey found that \(12\) play an instrument, \(15\) play a sport regularly, and \(4\) do neither. a) Create a complete two-way table of counts. b) How many students do both activities? c) What percentage play a sport regularly but do not play an instrument?

Hints

- Use the “neither” count with the row and column totals to find an adjacent cell. - Continue using row and column totals until all four interior cells are known. - For part c), divide the relevant cell by all \(25\) students.

Solution

1. The number who do not play an instrument is \(25-12=13\), and the number who do not play a sport regularly is \(25-15=10\). 2. Since \(4\) students do neither, the number who play a sport but no instrument is \(13-4=9\). 3. The number who do both is \(15-9=6\). 4. The number who play an instrument but no sport is \(12-6=6\). 5. The required percentage is \(\frac{9}{25}=0.36=36\%\).

Answer

a) <table><tr><th></th><th>Plays a sport</th><th>Does not play a sport</th><th>Total</th></tr><tr><th>Plays an instrument</th><td>\(6\)</td><td>\(6\)</td><td>\(12\)</td></tr><tr><th>Does not play an instrument</th><td>\(9\)</td><td>\(4\)</td><td>\(13\)</td></tr><tr><th>Total</th><td>\(15\)</td><td>\(10\)</td><td>\(25\)</td></tr></table> b) \(6\) students. c) \(36\%\).
Construct two-way tables 30
An electronics store reviews \(200\) smartphones that were sold. Of the phones, \(120\) use Android, \(90\) were sold with a screen protector, and \(70\%\) of the Android phones were sold without a screen protector. a) Find the number of Android phones sold with a screen protector. b) Complete a two-way table for the data. c) How many non-Android phones were sold with a screen protector?

Hints

- Convert the percentage within the Android group to a count first. - Use the Android total to find the other Android cell. - Complete the remaining row and column using their totals.

Solution

1. The number of Android phones sold without a screen protector is \(0.70\cdot120=84\). 2. Therefore, the number of Android phones sold with a screen protector is \(120-84=36\). 3. The number of non-Android phones is \(200-120=80\), and the number sold without a screen protector is \(200-90=110\). 4. The number of non-Android phones sold with a screen protector is \(90-36=54\). 5. The remaining cell is \(80-54=26\).

Answer

a) \(36\) Android phones. b) <table><tr><th></th><th>With screen protector</th><th>Without screen protector</th><th>Total</th></tr><tr><th>Android</th><td>\(36\)</td><td>\(84\)</td><td>\(120\)</td></tr><tr><th>Non-Android</th><td>\(54\)</td><td>\(26\)</td><td>\(80\)</td></tr><tr><th>Total</th><td>\(90\)</td><td>\(110\)</td><td>\(200\)</td></tr></table> c) \(54\) non-Android phones.
Construct two-way tables 31
A quality-control team inspects \(1000\) components for a material defect and a shape defect. The team finds that: - \(920\) components do not have a material defect. - \(35\) components have a shape defect but no material defect. - \(20\) components have both defects. a) Complete a two-way table of counts. b) How many components have a shape defect? c) How many components have at most one of the two defects? Explain how you found the number.

Hints

- Find the total with a material defect before completing its row or column. - Add the two shape-defect cells for part b). - “At most one” excludes only the cell for both defects.

Solution

1. Since \(920\) components do not have a material defect, \(1000-920=80\) have a material defect. 2. Of those \(80\), \(20\) also have a shape defect, so \(80-20=60\) have a material defect but no shape defect. 3. The number with a shape defect is \(20+35=55\). 4. The number with neither defect is \(920-35=885\). 5. Having at most one defect means every component except the \(20\) with both defects, so \(1000-20=980\).

Answer

a) <table><tr><th></th><th>Material defect</th><th>No material defect</th><th>Total</th></tr><tr><th>Shape defect</th><td>\(20\)</td><td>\(35\)</td><td>\(55\)</td></tr><tr><th>No shape defect</th><td>\(60\)</td><td>\(885\)</td><td>\(945\)</td></tr><tr><th>Total</th><td>\(80\)</td><td>\(920\)</td><td>\(1000\)</td></tr></table> b) \(55\) components. c) \(980\) components; subtract the \(20\) components with both defects from all \(1000\) components.
Construct two-way tables 32
A survey includes \(40\) students who play a musical instrument and \(50\) students who do not. The pie charts show club membership within each group. Panel a) is for students who play an instrument, and panel b) is for students who do not. Construct a complete two-way table of counts with instrument status as rows and club membership as columns.
Figure for problem 538676

Hints

- Treat each pie chart as a within-row percentage distribution for one instrument-status group. - Use the stated group total with the percentage shown for each slice to recover the corresponding count. - After finding the four interior counts, add rows and columns to check the grand total.

Solution

1. In panel a), \(60\%\) of the \(40\) students belong to a club, so \(0.60\cdot40=24\). The remaining \(16\) do not belong to a club. 2. In panel b), \(30\%\) of the \(50\) students belong to a club, so \(0.30\cdot50=15\). The remaining \(35\) do not belong to a club. 3. The club-membership column total is \(24+15=39\), the nonmembership total is \(16+35=51\), and the grand total is \(90\).

Answer

<table><tr><th></th><th>Belongs to a club</th><th>Does not belong to a club</th><th>Total</th></tr><tr><th>Plays an instrument</th><td>\(24\)</td><td>\(16\)</td><td>\(40\)</td></tr><tr><th>Does not play an instrument</th><td>\(15\)</td><td>\(35\)</td><td>\(50\)</td></tr><tr><th>Total</th><td>\(39\)</td><td>\(51\)</td><td>\(90\)</td></tr></table>
Construct two-way tables 33
A community center surveys \(38\) teens about chess club and art club. Nine belong to both clubs, \(7\) belong to neither, and \(22\) belong to exactly one club. Of those in exactly one club, \(13\) are in chess only. Construct a complete two-way table.

Hints

- Split the “exactly one” count into chess only and art only. - Put the both and neither counts in the two diagonal cells they describe. - Add rows and columns, then verify that the four interior cells total the survey size.

Solution

1. Chess only is \(13\), so art only is \(22-13=9\). 2. Place \(9\) in the both cell and \(7\) in the neither cell. 3. The chess row total is \(9+13=22\), and the not-chess row total is \(9+7=16\). 4. The column totals are \(18\) and \(20\), and \(9+13+9+7=38\), matching the survey size.

Answer

<table><tr><th></th><th>In art club</th><th>Not in art club</th><th>Total</th></tr><tr><th>In chess club</th><td>\(9\)</td><td>\(13\)</td><td>\(22\)</td></tr><tr><th>Not in chess club</th><td>\(9\)</td><td>\(7\)</td><td>\(16\)</td></tr><tr><th>Total</th><td>\(18\)</td><td>\(20\)</td><td>\(38\)</td></tr></table>
Construct two-way tables 34
A robotics event has \(40\) first-time participants and \(40\) returning participants. Among first-time participants, \(60\%\) finish the challenge. Eighteen returning participants finish. Construct a complete table for participant type and completion.

Hints

- Convert the within-group percentage into a count using that row total. - Complete each row before adding column totals.

Solution

1. First-time finishers: \(0.60\cdot 40=24\); first-time nonfinishers: \(40-24=16\). 2. Returning nonfinishers: \(40-18=22\). 3. Column totals are \(42\) finishers and \(38\) nonfinishers.

Answer

<table><tr><th></th><th>Finished</th><th>Did not finish</th><th>Total</th></tr><tr><th>First-time</th><td>\(24\)</td><td>\(16\)</td><td>\(40\)</td></tr><tr><th>Returning</th><td>\(18\)</td><td>\(22\)</td><td>\(40\)</td></tr><tr><th>Total</th><td>\(42\)</td><td>\(38\)</td><td>\(80\)</td></tr></table>
Construct two-way tables 35
A transit study first records three travel modes: <table><tr><th></th><th>Rain</th><th>No rain</th></tr><tr><th>Car</th><td>\(8\)</td><td>\(5\)</td></tr><tr><th>Bus</th><td>\(11\)</td><td>\(6\)</td></tr><tr><th>Walk</th><td>\(7\)</td><td>\(3\)</td></tr></table> Construct a new two-way table with rows “Car” and “Not car.” Include all totals.

Hints

- The new “Not car” category combines two original rows. - Add corresponding cells before calculating totals.

Solution

1. Keep the Car row as \(8\) and \(5\). 2. Combine Bus and Walk: rain \(11+7=18\), no rain \(6+3=9\). 3. The row totals are \(13\) and \(27\); column totals are \(26\) and \(14\).

Answer

<table><tr><th></th><th>Rain</th><th>No rain</th><th>Total</th></tr><tr><th>Car</th><td>\(8\)</td><td>\(5\)</td><td>\(13\)</td></tr><tr><th>Not car</th><td>\(18\)</td><td>\(9\)</td><td>\(27\)</td></tr><tr><th>Total</th><td>\(26\)</td><td>\(14\)</td><td>\(40\)</td></tr></table>
Construct two-way tables 36
At a museum workshop, \(45\) adults and \(30\) youths attend. Among adults, twice as many attend the morning session as the evening session. Altogether, \(46\) people attend in the morning. Construct a complete two-way table.

Hints

- Translate “twice as many” into a \(2:1\) ratio for the adult row. - Use the overall morning total after completing the adult row. - Complete the youth row, then verify the evening and grand totals.

Solution

1. Split the \(45\) adults in a \(2:1\) ratio: \(30\) attend in the morning and \(15\) attend in the evening. 2. Youth morning attendance is \(46-30=16\). 3. Youth evening attendance is \(30-16=14\). 4. The evening total is \(15+14=29\), and the grand total is \(45+30=75\).

Answer

<table><tr><th></th><th>Morning</th><th>Evening</th><th>Total</th></tr><tr><th>Adults</th><td>\(30\)</td><td>\(15\)</td><td>\(45\)</td></tr><tr><th>Youths</th><td>\(16\)</td><td>\(14\)</td><td>\(30\)</td></tr><tr><th>Total</th><td>\(46\)</td><td>\(29\)</td><td>\(75\)</td></tr></table>
Construct two-way tables 37
Three science classes each have \(20\) students. In Class A, \(12\) choose the lab option. In Class B, \(11\) choose the project option. Class C has \(5\) project students. Construct the complete table.

Hints

- Complete each class row from its total of \(20\). - After the interior cells are complete, add down each option column. - Check that the row and column totals agree on the grand total.

Solution

1. Class A project students: \(20-12=8\). 2. Class B lab students: \(20-11=9\). 3. Class C lab students: \(20-5=15\). 4. The lab total is \(12+9+15=36\), the project total is \(8+11+5=24\), and the grand total is \(60\).

Answer

<table><tr><th></th><th>Lab</th><th>Project</th><th>Total</th></tr><tr><th>Class A</th><td>\(12\)</td><td>\(8\)</td><td>\(20\)</td></tr><tr><th>Class B</th><td>\(9\)</td><td>\(11\)</td><td>\(20\)</td></tr><tr><th>Class C</th><td>\(15\)</td><td>\(5\)</td><td>\(20\)</td></tr><tr><th>Total</th><td>\(36\)</td><td>\(24\)</td><td>\(60\)</td></tr></table>
Construct two-way tables 38
A survey receives \(70\) forms, but \(6\) forms omit one of the two categorical answers and are excluded from a two-way table. Of the usable forms, \(34\) are from Grade \(7\); \(22\) of those select “Yes.” Eighteen Grade \(8\) students select “Yes.” Construct the table for the usable responses.

Hints

- First determine how many responses are usable. - Complete the Grade \(7\) row, then use the grand total to find the Grade \(8\) row total. - Complete the second row and add the columns.

Solution

1. The table includes \(70-6=64\) usable responses. 2. Grade \(7\) “No” responses: \(34-22=12\). 3. Grade \(8\) has \(64-34=30\) usable responses. 4. Grade \(8\) “No” responses: \(30-18=12\). 5. The column totals are \(22+18=40\) “Yes” responses and \(12+12=24\) “No” responses.

Answer

<table><tr><th></th><th>Yes</th><th>No</th><th>Total</th></tr><tr><th>Grade \(7\)</th><td>\(22\)</td><td>\(12\)</td><td>\(34\)</td></tr><tr><th>Grade \(8\)</th><td>\(18\)</td><td>\(12\)</td><td>\(30\)</td></tr><tr><th>Total</th><td>\(40\)</td><td>\(24\)</td><td>\(64\)</td></tr></table>
Construct two-way tables 39
A recreation center surveys \(40\) weekday visitors and \(50\) weekend visitors. Seventy percent of weekday visitors use the pool, while \(36\%\) of weekend visitors use it. Construct a complete table of counts.

Hints

- Apply each percentage only to its own group total. - Subtract each pool-user count from its row total to find the nonusers. - Add the two rows by columns and verify the grand total.

Solution

1. Weekday pool users: \(0.70\cdot40=28\). 2. Weekday nonusers: \(40-28=12\). 3. Weekend pool users: \(0.36\cdot50=18\). 4. Weekend nonusers: \(50-18=32\). 5. The column totals are \(28+18=46\) pool users and \(12+32=44\) nonusers, for \(90\) visitors.

Answer

<table><tr><th></th><th>Uses the pool</th><th>Does not use the pool</th><th>Total</th></tr><tr><th>Weekday</th><td>\(28\)</td><td>\(12\)</td><td>\(40\)</td></tr><tr><th>Weekend</th><td>\(18\)</td><td>\(32\)</td><td>\(50\)</td></tr><tr><th>Total</th><td>\(46\)</td><td>\(44\)</td><td>\(90\)</td></tr></table>
Construct two-way tables 40
A certification test has \(42\) morning examinees and \(30\) evening examinees. Two-thirds of the morning group pass, and \(43\) examinees pass altogether. Construct a complete table.

Hints

- Convert the fraction of the morning row into a count. - Complete the morning row, then use the overall pass total. - Complete the evening row and verify both columns.

Solution

1. Morning passes: \(\frac{2}{3}\cdot42=28\). 2. Morning failures: \(42-28=14\). 3. Evening passes: \(43-28=15\). 4. Evening failures: \(30-15=15\). 5. The failure total is \(14+15=29\), and the grand total is \(72\).

Answer

<table><tr><th></th><th>Pass</th><th>Fail</th><th>Total</th></tr><tr><th>Morning</th><td>\(28\)</td><td>\(14\)</td><td>\(42\)</td></tr><tr><th>Evening</th><td>\(15\)</td><td>\(15\)</td><td>\(30\)</td></tr><tr><th>Total</th><td>\(43\)</td><td>\(29\)</td><td>\(72\)</td></tr></table>
Construct two-way tables 41
The counts are \(13\) urban bus riders, \(7\) urban train riders, \(5\) rural bus riders, and \(15\) rural train riders. Construct two equivalent tables: one with location as rows and one with transportation as rows.

Hints

- Keep each paired count attached to the same two category labels. - Switching orientation transposes the interior cells but does not change the data.

Solution

1. With location as rows, place Urban \((13, 7)\) and Rural \((5, 15)\). 2. With transportation as rows, transpose the interior counts: Bus \((13, 5)\) and Train \((7, 15)\). 3. Both tables represent the same \(40\) observations.

Answer

Location as rows: <table><tr><th></th><th>Bus</th><th>Train</th><th>Total</th></tr><tr><th>Urban</th><td>\(13\)</td><td>\(7\)</td><td>\(20\)</td></tr><tr><th>Rural</th><td>\(5\)</td><td>\(15\)</td><td>\(20\)</td></tr><tr><th>Total</th><td>\(18\)</td><td>\(22\)</td><td>\(40\)</td></tr></table> Transportation as rows: <table><tr><th></th><th>Urban</th><th>Rural</th><th>Total</th></tr><tr><th>Bus</th><td>\(13\)</td><td>\(5\)</td><td>\(18\)</td></tr><tr><th>Train</th><td>\(7\)</td><td>\(15\)</td><td>\(22\)</td></tr><tr><th>Total</th><td>\(20\)</td><td>\(20\)</td><td>\(40\)</td></tr></table>
Construct two-way tables 42
A festival has \(40\) local visitors and \(45\) out-of-town visitors. Local visitors choose indoor and outdoor events in a ratio of \(3:2\). Out-of-town visitors choose indoor and outdoor events in a ratio of \(1:2\). Construct a complete two-way table.

Hints

- Convert each row ratio into its total number of equal parts. - Use the corresponding row total to find one part. - Complete both rows before adding the columns.

Solution

1. For local visitors, the \(3:2\) ratio has \(5\) equal parts, so each part is \(40\div5=8\). This gives \(24\) indoor and \(16\) outdoor visitors. 2. For out-of-town visitors, the \(1:2\) ratio has \(3\) equal parts, so each part is \(45\div3=15\). This gives \(15\) indoor and \(30\) outdoor visitors. 3. The indoor total is \(24+15=39\). 4. The outdoor total is \(16+30=46\), and the grand total is \(85\).

Answer

<table><tr><th></th><th>Indoor</th><th>Outdoor</th><th>Total</th></tr><tr><th>Local</th><td>\(24\)</td><td>\(16\)</td><td>\(40\)</td></tr><tr><th>Out-of-town</th><td>\(15\)</td><td>\(30\)</td><td>\(45\)</td></tr><tr><th>Total</th><td>\(39\)</td><td>\(46\)</td><td>\(85\)</td></tr></table>
Construct two-way tables 43
A community center surveys \(30\) teen members and \(42\) adult members about whether they plan to volunteer. Altogether, \(36\) members answer “Yes,” and one-third of all “Yes” responses come from teens. Construct the complete table.

Hints

- Apply the fraction to the total number of “Yes” responses. - Complete the “Yes” column before subtracting within each age-group row. - Add the “No” column and verify the grand total.

Solution

1. Teen “Yes” responses: \(\frac{1}{3}\cdot36=12\). 2. Adult “Yes” responses: \(36-12=24\). 3. Teen “No” responses: \(30-12=18\). 4. Adult “No” responses: \(42-24=18\). The “No” total is \(36\), and the grand total is \(72\).

Answer

<table><tr><th></th><th>Yes</th><th>No</th><th>Total</th></tr><tr><th>Teens</th><td>\(12\)</td><td>\(18\)</td><td>\(30\)</td></tr><tr><th>Adults</th><td>\(24\)</td><td>\(18\)</td><td>\(42\)</td></tr><tr><th>Total</th><td>\(36\)</td><td>\(36\)</td><td>\(72\)</td></tr></table>
Construct two-way tables 44
Three clubs each send \(20\) students to choose one of three sessions. Club A sends \(8\) to Coding and \(5\) to Design. Club B sends \(6\) to Coding and \(9\) to Design. Club C sends \(10\) to Coding and \(4\) to Design. Construct a complete \(3\times3\) two-way table including the Research session and all totals.

Hints

- Each club row must total \(20\). - Find the Research count separately for each club. - Add each session column and verify the grand total.

Solution

1. Club A Research: \(20-8-5=7\). 2. Club B Research: \(20-6-9=5\). 3. Club C Research: \(20-10-4=6\). 4. The Coding total is \(8+6+10=24\), and the Design total is \(5+9+4=18\). 5. The Research total is \(7+5+6=18\), and the grand total is \(60\).

Answer

<table><tr><th></th><th>Coding</th><th>Design</th><th>Research</th><th>Total</th></tr><tr><th>Club A</th><td>\(8\)</td><td>\(5\)</td><td>\(7\)</td><td>\(20\)</td></tr><tr><th>Club B</th><td>\(6\)</td><td>\(9\)</td><td>\(5\)</td><td>\(20\)</td></tr><tr><th>Club C</th><td>\(10\)</td><td>\(4\)</td><td>\(6\)</td><td>\(20\)</td></tr><tr><th>Total</th><td>\(24\)</td><td>\(18\)</td><td>\(18\)</td><td>\(60\)</td></tr></table>
Construct two-way tables 45
A school surveys \(100\) students about grade level and how they travel to school. Overall, \(30\%\) are Grade \(7\) students who ride the bus, \(18\%\) are Grade \(7\) students who walk, and \(12\%\) are Grade \(8\) students who ride the bus. Construct the complete count table.

Hints

- Use the total of \(100\) to convert each overall percentage directly to a count. - Find the fourth interior count from the grand total. - Add the grade rows and travel columns to complete the margins.

Solution

1. Because the survey total is \(100\), the three given percentages correspond to counts of \(30\), \(18\), and \(12\). 2. The missing Grade \(8\) walking count is \(100-(30+18+12)=40\). 3. The grade totals are \(30+18=48\) for Grade \(7\) and \(12+40=52\) for Grade \(8\). 4. The travel totals are \(30+12=42\) bus riders and \(18+40=58\) walkers.

Answer

<table><tr><th></th><th>Bus</th><th>Walk</th><th>Total</th></tr><tr><th>Grade \(7\)</th><td>\(30\)</td><td>\(18\)</td><td>\(48\)</td></tr><tr><th>Grade \(8\)</th><td>\(12\)</td><td>\(40\)</td><td>\(52\)</td></tr><tr><th>Total</th><td>\(42\)</td><td>\(58\)</td><td>\(100\)</td></tr></table>
Construct two-way tables 46
A school lunch survey initially shows \(20\) Grade \(7\) cafeteria choices, \(10\) Grade \(7\) packed-lunch choices, \(14\) Grade \(8\) cafeteria choices, and \(16\) Grade \(8\) packed-lunch choices. One Grade \(7\) response was mistakenly entered as cafeteria instead of packed lunch. Construct the corrected table with totals.

Hints

- A corrected classification moves one response rather than adding or deleting it. - Adjust the two affected Grade \(7\) cells in opposite directions. - Recalculate the two choice columns while keeping both grade totals fixed.

Solution

1. Reclassifying one response moves it between cells; it does not change the number of Grade \(7\) responses. 2. Grade \(7\) cafeteria decreases from \(20\) to \(19\), and Grade \(7\) packed lunch increases from \(10\) to \(11\). 3. The Grade \(8\) counts remain \(14\) and \(16\). 4. The corrected column totals are \(19+14=33\) cafeteria choices and \(11+16=27\) packed lunches, for \(60\) responses.

Answer

<table><tr><th></th><th>Cafeteria</th><th>Packed lunch</th><th>Total</th></tr><tr><th>Grade \(7\)</th><td>\(19\)</td><td>\(11\)</td><td>\(30\)</td></tr><tr><th>Grade \(8\)</th><td>\(14\)</td><td>\(16\)</td><td>\(30\)</td></tr><tr><th>Total</th><td>\(33\)</td><td>\(27\)</td><td>\(60\)</td></tr></table>
Construct two-way tables 47
Students rate a workshop after attending either online or in person: <table><tr><th></th><th>Agree</th><th>Maybe</th><th>Disagree</th></tr><tr><th>Online</th><td>\(12\)</td><td>\(5\)</td><td>\(3\)</td></tr><tr><th>In person</th><td>\(8\)</td><td>\(4\)</td><td>\(6\)</td></tr></table> Recode the responses into “Agree” and “Does not agree,” then construct the new table with totals.

Hints

- Keep the Agree column unchanged. - Combine Maybe and Disagree separately within each attendance group. - Recalculate the margins after recoding.

Solution

1. Keep the Agree counts of \(12\) and \(8\). 2. Combine Maybe and Disagree: Online has \(5+3=8\), and In person has \(4+6=10\) responses in “Does not agree.” 3. The row totals are \(20\) and \(18\); the column totals are \(20\) and \(18\), for \(38\) students.

Answer

<table><tr><th></th><th>Agree</th><th>Does not agree</th><th>Total</th></tr><tr><th>Online</th><td>\(12\)</td><td>\(8\)</td><td>\(20\)</td></tr><tr><th>In person</th><td>\(8\)</td><td>\(10\)</td><td>\(18\)</td></tr><tr><th>Total</th><td>\(20\)</td><td>\(18\)</td><td>\(38\)</td></tr></table>
Construct two-way tables 48
A school surveys \(27\) Grade \(7\) students and \(33\) Grade \(8\) students about whether they will volunteer at a school event. The two grades have the same number of “Yes” responses, and there are \(34\) “No” responses altogether. Construct the table.

Hints

- Find the total number of “Yes” responses from the grand total and the “No” total. - Split that column equally between the two grades. - Complete each grade row and verify the “No” column.

Solution

1. The grand total is \(27+33=60\), so the “Yes” total is \(60-34=26\). 2. Equal “Yes” counts split \(26\) into \(13\) for each grade. 3. Grade \(7\) “No” responses: \(27-13=14\). 4. Grade \(8\) “No” responses: \(33-13=20\), and \(14+20=34\) checks the stated total.

Answer

<table><tr><th></th><th>Yes</th><th>No</th><th>Total</th></tr><tr><th>Grade \(7\)</th><td>\(13\)</td><td>\(14\)</td><td>\(27\)</td></tr><tr><th>Grade \(8\)</th><td>\(13\)</td><td>\(20\)</td><td>\(33\)</td></tr><tr><th>Total</th><td>\(26\)</td><td>\(34\)</td><td>\(60\)</td></tr></table>
Construct two-way tables 49
Three neighborhoods contribute \(25\), \(20\), and \(30\) responses to a transit survey. Across all neighborhoods, \(40\) residents prefer the bus. Neighborhood \(1\) has \(16\) bus responses, and Neighborhood \(2\) has \(9\). Construct the table.

Hints

- Use the bus column total to find the missing bus count. - Complete each neighborhood row from its row total. - Add the train column after the interior counts are complete.

Solution

1. Neighborhood \(3\) bus responses: \(40-16-9=15\). 2. Neighborhood \(1\) train responses: \(25-16=9\). 3. Neighborhood \(2\) train responses: \(20-9=11\). 4. Neighborhood \(3\) train responses: \(30-15=15\). 5. The train total is \(9+11+15=35\), and the grand total is \(75\).

Answer

<table><tr><th></th><th>Bus</th><th>Train</th><th>Total</th></tr><tr><th>Neighborhood \(1\)</th><td>\(16\)</td><td>\(9\)</td><td>\(25\)</td></tr><tr><th>Neighborhood \(2\)</th><td>\(9\)</td><td>\(11\)</td><td>\(20\)</td></tr><tr><th>Neighborhood \(3\)</th><td>\(15\)</td><td>\(15\)</td><td>\(30\)</td></tr><tr><th>Total</th><td>\(40\)</td><td>\(35\)</td><td>\(75\)</td></tr></table>
Construct two-way tables 50
Fifty devices are classified by location and condition. The records show \(18\) indoor-working, \(7\) indoor-needs-repair, \(12\) outdoor-working, and \(9\) outdoor-needs-repair devices. Four devices have condition “Not recorded,” split equally between locations. Construct a table with three condition columns.

Hints

- Treat “Not recorded” as an explicit category rather than discarding it. - Use the equal split before adding row totals.

Solution

1. Split the \(4\) not-recorded conditions equally: \(2\) indoor and \(2\) outdoor. 2. Indoor total is \(18+7+2=27\); outdoor total is \(12+9+2=23\). 3. Condition totals are \(30\) working, \(16\) needs repair, and \(4\) not recorded.

Answer

<table><tr><th></th><th>Working</th><th>Needs repair</th><th>Not recorded</th><th>Total</th></tr><tr><th>Indoor</th><td>\(18\)</td><td>\(7\)</td><td>\(2\)</td><td>\(27\)</td></tr><tr><th>Outdoor</th><td>\(12\)</td><td>\(9\)</td><td>\(2\)</td><td>\(23\)</td></tr><tr><th>Total</th><td>\(30\)</td><td>\(16\)</td><td>\(4\)</td><td>\(50\)</td></tr></table>
Construct two-way tables 51
The data list contains one accidental duplicate. Each entry is student ID–campus–travel method: 101–North–Bus, 102–North–Walk, 103–South–Walk, 104–North–Bus, 105–South–Bus, 104–North–Bus, 106–South–Walk, 107–North–Bus, 108–South–Walk. Remove the duplicate ID and construct the table.

Hints

- Check student IDs before tallying campus and travel categories. - Remove only the repeated record, not both copies of that student. - Tally the remaining records and verify the grand total decreased by one.

Solution

1. ID \(104\) appears twice with the same campus and travel method, so count it once. 2. North has \(3\) bus riders and \(1\) walker. 3. South has \(1\) bus rider and \(3\) walkers. 4. Each campus row and each travel column totals \(4\), for \(8\) students.

Answer

<table><tr><th></th><th>Bus</th><th>Walk</th><th>Total</th></tr><tr><th>North</th><td>\(3\)</td><td>\(1\)</td><td>\(4\)</td></tr><tr><th>South</th><td>\(1\)</td><td>\(3\)</td><td>\(4\)</td></tr><tr><th>Total</th><td>\(4\)</td><td>\(4\)</td><td>\(8\)</td></tr></table>
Construct two-way tables 52
A quality-control team checks \(50\) components for a material defect and a surface defect. Of the \(50\) components, \(28\) have a material defect and \(31\) have a surface defect. No other information is given. a) What is the smallest possible number of components that could have both defects? Construct a complete two-way table that shows this case. b) What is the largest possible number of components that could have both defects? Construct a complete two-way table that shows this case.

Hints

- Think about what limits the overlap: it cannot be larger than either defect group. - For the smallest overlap, try to place as many components as possible in the two single-defect cells while keeping the grand total fixed. - Check each proposed extreme by completing all four interior cells and making sure no count is negative.

Solution

1. Let \(b\) be the number with both defects. Then material-only is \(28-b\), surface-only is \(31-b\), and neither is \(50-[b+(28-b)+(31-b)]=b-9\). 2. Every cell count must be nonnegative. From \(b-9\ge 0\), the overlap must be at least \(9\). This minimum gives material-only \(19\), surface-only \(22\), and neither \(0\). 3. The overlap cannot exceed either defect total, so it cannot exceed \(28\). This maximum gives material-only \(0\), surface-only \(3\), and neither \(19\). 4. Both endpoint tables have the required row total \(28\), column total \(31\), and grand total \(50\).

Answer

a) Smallest possible overlap: \(9\). <table><tr><th></th><th>Surface defect</th><th>No surface defect</th><th>Total</th></tr><tr><th>Material defect</th><td>\(9\)</td><td>\(19\)</td><td>\(28\)</td></tr><tr><th>No material defect</th><td>\(22\)</td><td>\(0\)</td><td>\(22\)</td></tr><tr><th>Total</th><td>\(31\)</td><td>\(19\)</td><td>\(50\)</td></tr></table> b) Largest possible overlap: \(28\). <table><tr><th></th><th>Surface defect</th><th>No surface defect</th><th>Total</th></tr><tr><th>Material defect</th><td>\(28\)</td><td>\(0\)</td><td>\(28\)</td></tr><tr><th>No material defect</th><td>\(3\)</td><td>\(19\)</td><td>\(22\)</td></tr><tr><th>Total</th><td>\(31\)</td><td>\(19\)</td><td>\(50\)</td></tr></table>
Construct two-way tables 53
A library has \(34\) East Branch registrations and \(26\) West Branch registrations. There are \(35\) online registrations in all. At the East Branch, online registrations exceed in-person registrations by \(8\). Construct a complete two-way table.

Hints

- Represent the two East Branch cells with expressions whose difference is \(8\). - Use the East row total to determine those two counts. - Then use the online total and West row total to finish the table.

Solution

1. Let East in-person registrations be \(x\). Then East online registrations are \(x+8\). 2. Since the East total is \(34\), \(x+(x+8)=34\), so \(2x=26\), \(x=13\), and East online registrations are \(21\). 3. West online registrations are \(35-21=14\). 4. West in-person registrations are \(26-14=12\). The in-person column total is \(13+12=25\), and the grand total is \(60\).

Answer

<table><tr><th></th><th>Online</th><th>In person</th><th>Total</th></tr><tr><th>East Branch</th><td>\(21\)</td><td>\(13\)</td><td>\(34\)</td></tr><tr><th>West Branch</th><td>\(14\)</td><td>\(12\)</td><td>\(26\)</td></tr><tr><th>Total</th><td>\(35\)</td><td>\(25\)</td><td>\(60\)</td></tr></table>
Construct two-way tables 54
A school records grade level and preferred workshop in this partial table. The two workshop column totals are equal. Find \(x\) and complete the table. <table><tr><th></th><th>Coding</th><th>Design</th><th>Total</th></tr><tr><th>Grade \(7\)</th><td>\(x\)</td><td>\(18\)</td><td></td></tr><tr><th>Grade \(8\)</th><td>\(26\)</td><td>\(2x\)</td><td></td></tr><tr><th>Total</th><td></td><td></td><td></td></tr></table>

Hints

- Write an expression for each workshop column total. - Use the statement that the two column totals are equal. - Substitute the solved value before calculating row and grand totals.

Solution

1. The Coding column total is \(x+26\), and the Design column total is \(18+2x\). 2. Set the equal column totals equal: \(x+26=18+2x\). 3. Solving gives \(x=8\), so the four interior counts are \(8\), \(18\), \(26\), and \(16\). 4. The row totals are \(26\) and \(42\); each column total is \(34\), and the grand total is \(68\).

Answer

\(x=8\). <table><tr><th></th><th>Coding</th><th>Design</th><th>Total</th></tr><tr><th>Grade \(7\)</th><td>\(8\)</td><td>\(18\)</td><td>\(26\)</td></tr><tr><th>Grade \(8\)</th><td>\(26\)</td><td>\(16\)</td><td>\(42\)</td></tr><tr><th>Total</th><td>\(34\)</td><td>\(34\)</td><td>\(68\)</td></tr></table>
Construct two-way tables 55
A school knows that \(30\) Grade \(7\) students and \(20\) Grade \(8\) students were surveyed. It also knows that \(25\) students ride the bus and \(25\) walk. No interior count is given. Can the four grade-and-travel counts be determined uniquely? Give two different valid completions.

Hints

- Choose one grade-and-travel cell and use the margins to force the other three. - Try a different starting count while keeping all entries nonnegative. - If both completions satisfy every margin, the interior table is not unique.

Solution

1. The row and column totals constrain the table, but one interior count can still vary. 2. One valid completion has Grade \(7\) counts \((15, 15)\) and Grade \(8\) counts \((10, 10)\). 3. Another valid completion has Grade \(7\) counts \((20, 10)\) and Grade \(8\) counts \((5, 15)\). Both have the required margins.

Answer

No. One completion is <table><tr><th></th><th>Bus</th><th>Walk</th><th>Total</th></tr><tr><th>Grade \(7\)</th><td>\(15\)</td><td>\(15\)</td><td>\(30\)</td></tr><tr><th>Grade \(8\)</th><td>\(10\)</td><td>\(10\)</td><td>\(20\)</td></tr><tr><th>Total</th><td>\(25\)</td><td>\(25\)</td><td>\(50\)</td></tr></table> Another is <table><tr><th></th><th>Bus</th><th>Walk</th><th>Total</th></tr><tr><th>Grade \(7\)</th><td>\(20\)</td><td>\(10\)</td><td>\(30\)</td></tr><tr><th>Grade \(8\)</th><td>\(5\)</td><td>\(15\)</td><td>\(20\)</td></tr><tr><th>Total</th><td>\(25\)</td><td>\(25\)</td><td>\(50\)</td></tr></table>
Construct two-way tables 56
A community center surveys \(90\) members about whether they plan to volunteer. Teens make up \(40\%\) of the respondents. Overall, “Yes” and “No” responses are in a ratio of \(5:4\). Among teens, two-thirds answer “Yes.” Construct a complete table by age group and response.

Hints

- Determine the two age-group totals first. - Convert the overall response ratio into “Yes” and “No” column totals. - Use the within-teen fraction, then subtract from the row and column margins to complete the adult row.

Solution

1. The teen total is \(0.40\cdot90=36\), so the adult total is \(90-36=54\). 2. The \(5:4\) response ratio has \(9\) equal parts, so each part represents \(90\div9=10\) responses. 3. The overall response totals are \(5\cdot10=50\) “Yes” and \(4\cdot10=40\) “No.” 4. Teen “Yes” responses: \(\frac{2}{3}\cdot36=24\). 5. Teen “No” responses: \(36-24=12\). 6. Adult “Yes” responses: \(50-24=26\), and adult “No” responses: \(40-12=28\). These total \(54\) adults.

Answer

<table><tr><th></th><th>Yes</th><th>No</th><th>Total</th></tr><tr><th>Teens</th><td>\(24\)</td><td>\(12\)</td><td>\(36\)</td></tr><tr><th>Adults</th><td>\(26\)</td><td>\(28\)</td><td>\(54\)</td></tr><tr><th>Total</th><td>\(50\)</td><td>\(40\)</td><td>\(90\)</td></tr></table>
Construct two-way tables 57
An initial school travel table has North campus: \(10\) bus riders and \(14\) walkers; South campus: \(16\) bus riders and \(8\) walkers. One walker was assigned to North but belongs to South. Then one South campus student changes from bus to walking after the record is verified. Construct the final table.

Hints

- Apply the two corrections in the order stated. - Moving a student between campuses changes row totals; changing travel method within one campus changes column totals. - Verify that the grand total remains constant.

Solution

1. Move one walker from North to South: North becomes \((10, 13)\), and South becomes \((16, 9)\). 2. Reclassify one South response from bus to walking: South becomes \((15, 10)\). 3. The final campus totals are \(23\) and \(25\); the travel totals are \(25\) bus riders and \(23\) walkers. 4. The grand total remains \(48\) because neither correction adds or removes a student.

Answer

<table><tr><th></th><th>Bus</th><th>Walk</th><th>Total</th></tr><tr><th>North</th><td>\(10\)</td><td>\(13\)</td><td>\(23\)</td></tr><tr><th>South</th><td>\(15\)</td><td>\(10\)</td><td>\(25\)</td></tr><tr><th>Total</th><td>\(25\)</td><td>\(23\)</td><td>\(48\)</td></tr></table>
Construct two-way tables 58
A climbing gym recorded these 12 visits by day and session: Weekday–Morning, Weekend–Evening, Weekday–Evening, Weekend–Morning, Weekday–Morning, Weekend–Evening, Weekend–Evening, Weekday–Morning, Weekend–Morning, Weekday–Evening, Weekend–Evening, Weekday–Morning. A worker made the table below. Check it against the visit list. Make any corrections needed, including totals, and explain what the worker got wrong. <table><tr><th></th><th>Morning</th><th>Evening</th><th>Total</th></tr><tr><th>Weekday</th><td>\(3\)</td><td>\(3\)</td><td>\(6\)</td></tr><tr><th>Weekend</th><td>\(3\)</td><td>\(3\)</td><td>\(6\)</td></tr><tr><th>Total</th><td>\(6\)</td><td>\(6\)</td><td>\(12\)</td></tr></table>

Hints

- Count each day-and-session pair from the list, rather than counting days and sessions separately. - Compare each of your four counts with the worker's four inside cells. - What information might be lost when you check only the totals?

Solution

1. Count complete day-session pairs in the visit list: Weekday–Morning occurs \(4\) times, Weekday–Evening \(2\), Weekend–Morning \(2\), and Weekend–Evening \(4\). 2. The worker's four inside counts are wrong even though every shown total is correct. 3. In the corrected table, both row totals are \(6\) and both column totals are \(6\). Totals cannot show whether visits were placed in the right joint categories.

Answer

All four inside counts are wrong, even though the totals agree with the visit list. <table><tr><th></th><th>Morning</th><th>Evening</th><th>Total</th></tr><tr><th>Weekday</th><td>\(4\)</td><td>\(2\)</td><td>\(6\)</td></tr><tr><th>Weekend</th><td>\(2\)</td><td>\(4\)</td><td>\(6\)</td></tr><tr><th>Total</th><td>\(6\)</td><td>\(6\)</td><td>\(12\)</td></tr></table> The totals match in both tables, so only checking the original paired records reveals the error.
Construct two-way tables 59
At a museum gift shop, each receipt is for either one postcard or one book. The staff made this table: <table><tr><th></th><th>Cash</th><th>Card</th><th>Total</th></tr><tr><th>Postcard</th><td>\(12\)</td><td>\(8\)</td><td>\(20\)</td></tr><tr><th>Book</th><td>\(6\)</td><td>\(14\)</td><td>\(20\)</td></tr><tr><th>Total</th><td>\(18\)</td><td>\(22\)</td><td>\(40\)</td></tr></table> Then the staff found three mistakes: - Two book purchases paid in cash had been counted as postcards paid in cash. - Three postcard purchases paid by card had each been counted twice. - One book purchase paid by card had not been counted. Make the corrected two-way table, including totals. Which corrections change the table's grand total?

Hints

- For each correction, decide whether a receipt moves between cells, is removed, or is added. - Fix the inside cells before calculating the new totals. - Which changes affect the number of purchases, rather than just where they are counted?

Solution

1. Move \(2\) cash purchases from Postcard to Book: those cells become \(10\) and \(8\). The grand total does not change. 2. Remove the \(3\) extra Postcard–Card counts, leaving \(5\). 3. Add the missed Book–Card purchase, giving \(15\). 4. The row totals are \(15\) and \(23\); the column totals are \(18\) and \(20\); the grand total is \(38\). Removing duplicates and adding the missed purchase change that total; correcting the category does not.

Answer

<table><tr><th></th><th>Cash</th><th>Card</th><th>Total</th></tr><tr><th>Postcard</th><td>\(10\)</td><td>\(5\)</td><td>\(15\)</td></tr><tr><th>Book</th><td>\(8\)</td><td>\(15\)</td><td>\(23\)</td></tr><tr><th>Total</th><td>\(18\)</td><td>\(20\)</td><td>\(38\)</td></tr></table> Removing the three duplicate counts lowers the total. Adding the missed purchase raises it. Moving two purchases between categories does not change the total.

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