A rectangular flower bed must have an area of exactly \(24\,\text{m}^2\). Its length \(x\) and width \(y\) can vary.
a) Give four different ordered pairs \((x, y)\), in whole meters, that satisfy the area requirement.
b) Describe the relationship between \(x\) and \(y\) mathematically. What happens to the width when the length is tripled?
c) A landscaper claims, “If I double the length and halve the width, the perimeter always stays the same.” Test the claim with an example. Is the landscaper correct?
Hints
- Begin with the area formula for a rectangle.
- In an inverse variation, multiplying one quantity by a factor divides the other by the same factor.
- Calculate the perimeter before and after changing the dimensions in a specific example.
Solution
1. The dimensions must satisfy \(xy = 24\). Four possible ordered pairs are \((1, 24)\), \((2, 12)\), \((3, 8)\), and \((4, 6)\).
2. Solving for the width gives \(y = \frac{24}{x}\), so the relationship is an inverse variation. If the length is tripled, the width is divided by \(3\).
3. Test the perimeter claim using \((x, y) = (4, 6)\). The original perimeter is \(2 \cdot (4 + 6) = 20\,\text{m}\). Doubling the length and halving the width gives dimensions \((8, 3)\), whose perimeter is \(2 \cdot (8 + 3) = 22\,\text{m}\). Since \(20 \ne 22\), the claim is false.
Answer
a) One possible set is \((1, 24)\), \((2, 12)\), \((3, 8)\), and \((4, 6)\).
b) \(y = \frac{24}{x}\), so this is an inverse variation. Tripling the length divides the width by \(3\).
c) No. For example, a \(4\,\text{m}\) by \(6\,\text{m}\) rectangle has perimeter \(20\,\text{m}\), while an \(8\,\text{m}\) by \(3\,\text{m}\) rectangle has perimeter \(22\,\text{m}\).