Free Math Worksheets

- Count the unit squares by rows or columns. - You can also split the figure into two rectangles.

1. The bottom row contains \(3\) unit squares. 2. Two more unit squares are above the leftmost square. 3. The area is \(3 + 2 = 5\) square units.

The area is \(5\) square units.

- Count the unit squares inside the figure. - You can separate the figure into a horizontal row and a vertical column without counting the corner square twice.

1. The bottom row contains \(3\) unit squares. 2. Three more unit squares are above the leftmost square. 3. The total is \(3 + 3 = 6\) square units.

\(6\) square units

- Count the unit squares inside each figure. - You can organize the count by splitting a figure into small rectangles.

1. Counting the unit squares in Figure A gives an area of \(5\) square units. 2. Counting the unit squares in Figure B also gives an area of \(5\) square units.

Area of Figure A: \(5\) square units Area of Figure B: \(5\) square units

- Count the unit squares inside each figure. - You may split a figure into smaller rectangles or subtract a missing rectangle from a larger one. - Compare the three areas.

1. Figure A can be split into a vertical rectangle with area \(3\) square units and a horizontal rectangle with area \(2\) square units. Its total area is \(3 + 2 = 5\) square units. 2. Figure B can be split into a vertical rectangle with area \(2\) square units and a horizontal rectangle with area \(3\) square units. Its total area is \(2 + 3 = 5\) square units. 3. Figure C is a \(3 \times 3\) square with a \(1 \times 2\) rectangle removed. Its area is \(9 - 2 = 7\) square units. 4. Figure C has the greatest area.

a) Figure A: \(5\) square units Figure B: \(5\) square units Figure C: \(7\) square units b) Figure C has the greatest area.

- Count the unit squares inside each figure. - You can organize the count by rows or columns. - Compare the three totals to find the matching pair.

1. Figure A is a \(3 \times 2\) rectangle, so its area is \(3 \times 2 = 6\) square units. 2. Figure B has \(3\) unit squares in the bottom row, \(2\) in the middle row, and \(1\) in the top row. Its area is \(3 + 2 + 1 = 6\) square units. 3. Figure C has \(3\) unit squares in the bottom row and \(2\) more above the leftmost square. Its area is \(3 + 2 = 5\) square units. 4. Figures A and B have the same area.

a) Figure A: \(6\) square units Figure B: \(6\) square units Figure C: \(5\) square units b) Figures A and B have the same area.

- Count the unit squares in each figure separately. - You can count by rows or columns. - Compare the two totals.

1. Figure a) is a rectangle with \(2\) rows of \(4\) unit squares. Its area is \(4 + 4 = 8\) square units. 2. Figure b) has \(5\) unit squares in the bottom row and \(3\) in the top row. Its area is \(5 + 3 = 8\) square units. 3. Therefore, the figures have the same area.

Yes. Figures a) and b) each have an area of \(8\) square units.

- Count the unit squares inside each figure. - You can split Figure b) into rectangles. - Compare the two totals.

1. Figure a) is a square with side length \(3\) units, so its area is \(3 \times 3 = 9\) square units. 2. Figure b) can be split into two rectangles with areas \(2 \times 2 = 4\) square units and \(2 \times 3 = 6\) square units. Its total area is \(4 + 6 = 10\) square units. 3. Since \(10 > 9\), Figure b) has the greater area.

Figure b) has an area of \(10\) square units, which is greater than Figure a)''s area of \(9\) square units.

- Count how many unit squares each figure covers. - Break each figure into individual unit squares. - Compare the two counts.

1. Figure a) is a \(3 \times 2\) rectangle, so its area is \(3 \times 2 = 6\) square units. 2. Figure b) can be split into a \(3 \times 1\) rectangle and a \(1 \times 2\) rectangle, so its area is \(3 + 2 = 5\) square units. 3. Since \(6 > 5\), Figure a) has the greater area.

Figure a) has the greater area: \(6\) square units compared with \(5\) square units for Figure b).

- In each column, the tallest aligned stack determines the visible height. - A shorter stack directly behind a taller stack is hidden. - Add the numbers of visible unit squares in the three columns.

1. Find the visible height in each front-view column by choosing the taller aligned stack. 2. The left column has height \(\max(2,1)=2\), the middle column has height \(\max(3,1)=3\), and the right column has height \(\max(1,0)=1\). 3. The front-view area is \(2+3+1=6\) square units.

\(6\) square units