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Class A recorded \(24\) dots, with each dot representing \(2\) books read. Class B recorded \(18\) dots, with each dot representing \(3\) books read.
Which class read more books? Explain why comparing only the numbers of dots would be misleading.
Hints
- Use the key for each class.
- Multiply each number of dots by the number of books represented by one dot.
- Compare the actual numbers of books, not just the dot counts.
Solution
1. Class A read \(24 \times 2 = 48\) books.
2. Class B read \(18 \times 3 = 54\) books.
3. Class B read \(54 - 48 = 6\) more books. The dot counts cannot be compared directly because the dots use different keys.
Answer
Class B read \(54\) books, which is \(6\) more than Class A’s \(48\) books. The dot counts alone are not comparable because each dot has a different value in the two displays.
